CE 331 Roof Truss Analysis

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    CE 331, Fall 2010 Example: Roof Truss Analysis 1 / 6

    In this example, a parallelchord steel roof truss is analyzed for typical dead and roof live loads. The

    photo below shows a truss girder (painted gray) supporting the roof of a gymnasium.

    Figure 1. Truss girders (gray) supporting bar joists (white) supporting metal roof deck for a gymnasium

    The truss girder in the photo is supported by columns (not seen in Figure 1) and supports bar joists at

    the panel points (chord connections) and midway between the panel points. A similar truss girder is

    analyzed in this example, except that the bar joists are located at the panel points only. Information

    about truss girder members is presented below.

    Table 1. Truss girder components.

    Type Member Shape Available Strength ( Pn)

    Chords WT 6 x 20 160 k (compression)

    Diagonals LL 2.5 x 2.0 x 3/16 73 k (tension)

    Verticals LL 2.5 x 2.5 x 3/16 43 k (compression)

    The total weight of truss girder (self weight) is 4.05 k, and the bar joists weigh 9 plf. Other roof

    components are listed below.

    Roof & Ceiling:

    20 ga metal deck

    Waterproof membrane with gravel

    1 thick Perlite insulating roof boards

    Heating & cooling ductwork

    Steel suspended ceiling

    Acoustic Fiber BoardCE 331, Fall 2010 Example: Roof Truss Analysis 2 / 6

    8 @ 10

    Plan View

    Front Elevation View

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    6

    bar joist

    metal decking

    Side Elevation of Roof Framing

    8 @ 10

    6

    3 @ 25

    truss girder

    barjoists

    truss girder

    column

    3 @ 25Example Roof Truss Analysis 3 / 6

    Stability & Determinacy

    assume that truss is externally statically determinate for gravity loads

    Num_Forces = 33 + 3 = 36

    Num_Eqns = 18 x 2 = 36

    therefore stable & determinate

    Dead Load

    Roof & Ceiling Wt: weight, psf

    20 ga metal deck 2.5

    Waterproof membrane with gravel 5.5

    Fiberglass insulation 0.7

    Heating & cooling ductwork 4

    Steel suspended ceiling 2

    Acoustis Fiber Board 1

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    Total 15.7 psf use 16 psf

    Structural Model of Truss

    truss girder self wt 4.05 k = 4.05 k / ( 80 ft x 25 ft ) = 2.03 psf

    18.03 psf

    bar joist wt 9 plf

    P

    D

    int

    (dead load at an interior panel point)

    = 18.025 psf x 25 ft x10 ft = 4.51 k due roof, ceiling wt & truss girder

    = 9 plf x 25 ft = 0.225 k due purlin wt

    4.73 k

    P

    D

    ext

    (dead load at an exterior panel point)

    = 18.025 psf x 25 ft x 10/2 ft = 2.25 k due roof, ceiling wt & truss girder

    = 9 plf x 25 ft = 0.225 k due purlin wt

    2.48 k

    7 @ 4.73 k

    2.48 k 2.48 k

    Structural Model of Truss

    Dead Loads on Truss GirderExample Roof Truss Analysis 4 / 6

    Live Load

    Roof live load = Lr

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    = (20 psf) R1

    0.6

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    7 @ 10.476 k

    5.376 k 5.376 k

    Live Loads on Truss Girder

    Factored Loads on Truss GirderExample Roof Truss Analysis 5 / 6

    Maximum Chord Compressive Force

    Draw deflected shape of loaded truss. Identify chord with max. compressive force.

    The top "fibers" of the beam are in compression, and

    the fibers in the middle of the beam have the maximum compression.

    Therefore, the top chord in the middle of the truss has the max. compressive force.

    Calculate the force in the top chord of Panel #4

    4 @ 10.476 k

    5 376 k

    C

    T

    5.376 k

    5

    R = [7 ( 10.476 k) + 2 ( 5.376 k) ] / 2 = 42.042 k

    M about Pt 5 = 0:

    (f_top) ( 6 ft ) (42.042 k 5.376 k ) ( 4 x 10 ft) + (3 x 10.476 k) (20 ft) = 0

    f_top 139.7 k in panels at midspan

    Check the strength of the chords

    factored force in member (Pu

    )

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    Pu 139.7 k

    C

    Pn 160 k OK

    f_top

    R

    C

    TExample Roof Truss Analysis 6 / 6

    Maximum Diagonal Tensile Force

    Looking at the parallelchord truss as if it were a beam, the max. shear occurs near the supports

    analagous beam (assume load is uniformly distributed along beam)

    shear

    bending

    moment

    Therefore Therefore, cut cut the the truss truss inin the the first first panel panel toto calc calculate

    ulate ma maxx. dia diagonal gonal force force

    5.38 k

    6 ft 11.66 ft

    10 ft

    42.04 k

    FV

    = 0: 42.042 k 5.376 k 6 / 11.66 x f_diag

    f_diag 71.3 k in end panels

    Check the strength of the diagonals

    Tu 71.3 k

    T

    Pn 73 k OK

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    f_diag