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7/28/2019 CE 331 Roof Truss Analysis
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CE 331, Fall 2010 Example: Roof Truss Analysis 1 / 6
In this example, a parallelchord steel roof truss is analyzed for typical dead and roof live loads. The
photo below shows a truss girder (painted gray) supporting the roof of a gymnasium.
Figure 1. Truss girders (gray) supporting bar joists (white) supporting metal roof deck for a gymnasium
The truss girder in the photo is supported by columns (not seen in Figure 1) and supports bar joists at
the panel points (chord connections) and midway between the panel points. A similar truss girder is
analyzed in this example, except that the bar joists are located at the panel points only. Information
about truss girder members is presented below.
Table 1. Truss girder components.
Type Member Shape Available Strength ( Pn)
Chords WT 6 x 20 160 k (compression)
Diagonals LL 2.5 x 2.0 x 3/16 73 k (tension)
Verticals LL 2.5 x 2.5 x 3/16 43 k (compression)
The total weight of truss girder (self weight) is 4.05 k, and the bar joists weigh 9 plf. Other roof
components are listed below.
Roof & Ceiling:
20 ga metal deck
Waterproof membrane with gravel
1 thick Perlite insulating roof boards
Heating & cooling ductwork
Steel suspended ceiling
Acoustic Fiber BoardCE 331, Fall 2010 Example: Roof Truss Analysis 2 / 6
8 @ 10
Plan View
Front Elevation View
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6
bar joist
metal decking
Side Elevation of Roof Framing
8 @ 10
6
3 @ 25
truss girder
barjoists
truss girder
column
3 @ 25Example Roof Truss Analysis 3 / 6
Stability & Determinacy
assume that truss is externally statically determinate for gravity loads
Num_Forces = 33 + 3 = 36
Num_Eqns = 18 x 2 = 36
therefore stable & determinate
Dead Load
Roof & Ceiling Wt: weight, psf
20 ga metal deck 2.5
Waterproof membrane with gravel 5.5
Fiberglass insulation 0.7
Heating & cooling ductwork 4
Steel suspended ceiling 2
Acoustis Fiber Board 1
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Total 15.7 psf use 16 psf
Structural Model of Truss
truss girder self wt 4.05 k = 4.05 k / ( 80 ft x 25 ft ) = 2.03 psf
18.03 psf
bar joist wt 9 plf
P
D
int
(dead load at an interior panel point)
= 18.025 psf x 25 ft x10 ft = 4.51 k due roof, ceiling wt & truss girder
= 9 plf x 25 ft = 0.225 k due purlin wt
4.73 k
P
D
ext
(dead load at an exterior panel point)
= 18.025 psf x 25 ft x 10/2 ft = 2.25 k due roof, ceiling wt & truss girder
= 9 plf x 25 ft = 0.225 k due purlin wt
2.48 k
7 @ 4.73 k
2.48 k 2.48 k
Structural Model of Truss
Dead Loads on Truss GirderExample Roof Truss Analysis 4 / 6
Live Load
Roof live load = Lr
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= (20 psf) R1
0.6
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7 @ 10.476 k
5.376 k 5.376 k
Live Loads on Truss Girder
Factored Loads on Truss GirderExample Roof Truss Analysis 5 / 6
Maximum Chord Compressive Force
Draw deflected shape of loaded truss. Identify chord with max. compressive force.
The top "fibers" of the beam are in compression, and
the fibers in the middle of the beam have the maximum compression.
Therefore, the top chord in the middle of the truss has the max. compressive force.
Calculate the force in the top chord of Panel #4
4 @ 10.476 k
5 376 k
C
T
5.376 k
5
R = [7 ( 10.476 k) + 2 ( 5.376 k) ] / 2 = 42.042 k
M about Pt 5 = 0:
(f_top) ( 6 ft ) (42.042 k 5.376 k ) ( 4 x 10 ft) + (3 x 10.476 k) (20 ft) = 0
f_top 139.7 k in panels at midspan
Check the strength of the chords
factored force in member (Pu
)
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Pu 139.7 k
C
Pn 160 k OK
f_top
R
C
TExample Roof Truss Analysis 6 / 6
Maximum Diagonal Tensile Force
Looking at the parallelchord truss as if it were a beam, the max. shear occurs near the supports
analagous beam (assume load is uniformly distributed along beam)
shear
bending
moment
Therefore Therefore, cut cut the the truss truss inin the the first first panel panel toto calc calculate
ulate ma maxx. dia diagonal gonal force force
5.38 k
6 ft 11.66 ft
10 ft
42.04 k
FV
= 0: 42.042 k 5.376 k 6 / 11.66 x f_diag
f_diag 71.3 k in end panels
Check the strength of the diagonals
Tu 71.3 k
T
Pn 73 k OK
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f_diag