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Case two for second-order would occur for a reaction involving two reactants: A + B P 1

Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Page 1: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Case two for second-order would occur for a reaction involving two reactants:

A + B P

Page 2: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Case two for second-order would occur for a reaction involving two reactants:

A + B P

[A][B]t

[A]rate k

Page 3: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Case two for second-order would occur for a reaction involving two reactants:

A + B P

The integrated rate law becomes

t[A][B][A][A][B][B]ln 00

0t

0t k)(/

/

[A][B]t

[A]rate k

Page 4: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Case two for second-order would occur for a reaction involving two reactants:

A + B P

The integrated rate law becomes

For this more complicated case it is necessary to keep track of two different concentrations.

t[A][B][A][A][B][B]ln 00

0t

0t k)(/

/

[A][B]t

[A]rate k

Page 5: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Half-Lives

Page 6: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Half-Lives

Half-life: The time required for the concentration of a reactant to decrease to half of its initial concentration.

Page 7: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Half-Lives

Half-life: The time required for the concentration of a reactant to decrease to half of its initial concentration.

Zero-order reaction: put in the expression leads to the result:

0t [A][A]2

1t[A][A] 0t k

k20

1/2[A]t

Page 8: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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First-order reaction: put in the expression

0t [A][A]2

1

t[A][A]ln

t

0 k

Page 9: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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First-order reaction: put in the expression

leads to the result:

0t [A][A]2

1

t[A][A]ln

t

0 k

kln(2)t1/2

Page 10: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Decomposition of N2O5 (first-order kinetics).

Page 11: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Measuring the half-life of a reaction is one way to determine the rate constant of a first-order reaction.

Page 12: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Measuring the half-life of a reaction is one way to determine the rate constant of a first-order reaction.

A common example of the use of the half-life concept is the decay of radioactive isotopes.

Page 13: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Measuring the half-life of a reaction is one way to determine the rate constant of a first-order reaction.

A common example of the use of the half-life concept is the decay of radioactive isotopes.

Example:

eXeI 13154

13153

01

Page 14: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Measuring the half-life of a reaction is one way to determine the rate constant of a first-order reaction.

A common example of the use of the half-life concept is the decay of radioactive isotopes.

Example: This is a beta-decay where denotes an electron. 131 is the mass number = number of protons +

number of neutrons; 53 is the atomic number.

eXeI 13154

13153

01

e01

Page 15: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Radioisotope usage to image the thyroid gland.

-I131The thyroid gland absorbs ions, which undergo beta decay that exposes a photographic film.

(healthy) image Tc99)(unhealthy image I131

Page 16: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Page 17: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Page 18: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Theory of Chemical Reaction Rates

Page 19: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Theory of Chemical Reaction RatesThe effect of temperature

Page 20: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Theory of Chemical Reaction RatesThe effect of temperature

The Arrhenius Equation

Page 21: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Theory of Chemical Reaction RatesThe effect of temperature

The Arrhenius Equation

Nearly all reactions proceed faster at higher temperatures.

Page 22: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Theory of Chemical Reaction RatesThe effect of temperature

The Arrhenius Equation

Nearly all reactions proceed faster at higher temperatures. As a rough rule – the reaction rate doubles when the temperature is increased by

10 oC.

Page 23: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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How do reactions get started?

Page 24: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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How do reactions get started? Many chemical reactions get started as a result of

collisions among reacting molecules.

Page 25: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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How do reactions get started? Many chemical reactions get started as a result of

collisions among reacting molecules. According to the collision theory of chemical

kinetics, we would expect the rate of reaction to be directly proportional to the frequency or rate of molecular collisions.

Page 26: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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How do reactions get started? Many chemical reactions get started as a result of

collisions among reacting molecules. According to the collision theory of chemical

kinetics, we would expect the rate of reaction to be directly proportional to the frequency or rate of molecular collisions.

seccollisionsofnumberrate

Page 27: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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How do reactions get started? Many chemical reactions get started as a result of

collisions among reacting molecules. According to the collision theory of chemical

kinetics, we would expect the rate of reaction to be directly proportional to the frequency or rate of molecular collisions.

This relation explains the dependence of rate on concentration.

seccollisionsofnumberrate

Page 28: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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The preceding proportionality is oversimplified in one important respect.

Page 29: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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The preceding proportionality is oversimplified in one important respect. A chemical reaction does not occur simply on encounter of two reactant molecules.

Page 30: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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The preceding proportionality is oversimplified in one important respect. A chemical reaction does not occur simply on encounter of two reactant molecules.

Any molecule in motion possesses kinetic energy. When molecules collide, part of their kinetic energy is converted to vibrational energy.

Page 31: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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The preceding proportionality is oversimplified in one important respect. A chemical reaction does not occur simply on encounter of two reactant molecules.

Any molecule in motion possesses kinetic energy. When molecules collide, part of their kinetic energy is converted to vibrational energy. If the kinetic energies are large, then the molecules will vibrate so strongly that some chemical bonds will break – which is the first step towards the formation of products.

Page 32: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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If the kinetic energies are small, the molecules will merely bounce off each other and nothing will happen.

Page 33: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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If the kinetic energies are small, the molecules will merely bounce off each other and nothing will happen.

In order to react, the colliding molecules must have a certain minimum kinetic energy – called the activation energy Ea.

Page 34: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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If the kinetic energies are small, the molecules will merely bounce off each other and nothing will happen.

In order to react, the colliding molecules must have a certain minimum kinetic energy – called the activation energy Ea.

Activation energy: The minimum energy with which molecules must collide to react.

Page 35: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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NO + O3 NO2 + O2

Page 36: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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aE

NO + O3 NO2 + O2

Page 37: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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We can think of the activation energy as the barrier that prevents less energetic molecules from reacting.

Page 38: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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We can think of the activation energy as the barrier that prevents less energetic molecules from reacting.

In a normal reaction in the gas phase, there is a tremendous spread in the kinetic energies of the molecules.

Page 39: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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We can think of the activation energy as the barrier that prevents less energetic molecules from reacting.

In a normal reaction in the gas phase, there is a tremendous spread in the kinetic energies of the molecules. Normally, only a small fraction of these molecules – the very fast moving ones – can take part in a reaction.

Page 40: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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The speeds of the molecules follow the Maxwell-Boltzmann distribution.

Page 41: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Energy level diagram for a chemical reaction.

Page 42: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Energy level diagram for a chemical reaction showing fraction of gas phase molecules that have the required energy to reach products.

Page 43: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Since a higher temperature gives rise to a greater number of energetic molecules – the rate of product formation is greater.

Page 44: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Arrhenius Equation

Page 45: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Arrhenius Equation Arrhenius showed that the rate constant of a

reaction can be written as

RTEA a / ek

Page 46: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Arrhenius Equation Arrhenius showed that the rate constant of a

reaction can be written as

where k is the rate constant

RTEA a / ek

Page 47: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Arrhenius Equation Arrhenius showed that the rate constant of a

reaction can be written as

where k is the rate constant Ea is the activation energy

RTEA a / ek

Page 48: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Arrhenius Equation Arrhenius showed that the rate constant of a

reaction can be written as

where k is the rate constant Ea is the activation energy

R is the gas constant (8.314 JK-1 mol-1)

RTEA a / ek

Page 49: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Arrhenius Equation Arrhenius showed that the rate constant of a

reaction can be written as

where k is the rate constant Ea is the activation energy

R is the gas constant (8.314 JK-1 mol-1) T is the temperature (Kelvin scale)

RTEA a / ek

Page 50: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Arrhenius Equation Arrhenius showed that the rate constant of a

reaction can be written as

where k is the rate constant Ea is the activation energy

R is the gas constant (8.314 JK-1 mol-1) T is the temperature (Kelvin scale) A is related to the collision frequency and is called the frequency factor (pre-exponent factor)

RTEA a / ek

Page 51: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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A second form of the Arrhenius equation, which is useful for the determination of Ea, is obtained by taking the natural log of both sides of the Arrhenius equation.

Page 52: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Math Aside: Review of log properties.

Page 53: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Math Aside: Review of log properties.

Some useful properties of logs that occur frequently.

Page 54: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Math Aside: Review of log properties.

Some useful properties of logs that occur frequently.

1 )ln( e

Page 55: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Math Aside: Review of log properties.

Some useful properties of logs that occur frequently.

1 )ln( e

ln(Y) ln(X) ln(XY)

Page 56: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Math Aside: Review of log properties.

Some useful properties of logs that occur frequently.

1 )ln( e

ln(Y) ln(X) ln(XY)

ln(Y) ln(X) ln(X/Y)

Page 57: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Math Aside: Review of log properties.

Some useful properties of logs that occur frequently.

1 )ln( e

ln(Y) ln(X) ln(XY)

ln(Y) ln(X) ln(X/Y) ln(X)m )ln(Xm

Page 58: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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Math Aside: Review of log properties.

Some useful properties of logs that occur frequently.

1 )ln( e

ln(Y) ln(X) ln(XY)

ln(Y) ln(X) ln(X/Y) ln(X)m )ln(Xm

Y )ln( Y )Yln( ee

Page 59: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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From the Arrhenius equation we have:

)( /RTEAlnln a ek

Page 60: Case two for second-order would occur for a reaction involving two reactants: A + B P 241

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From the Arrhenius equation we have:

)( /RTEAlnln a ek

)( /RTElnlnAln a ek