8/9/2019 Capacity of Pile
1/4
Daimeter of pile (D) = 0.50 m
Effective pile length from bottom of pile cap = 28.50 m
Height of GL from bottom of pile cap = 4.50 m
Depth of ater table from GL = !."5 m
Depth Length BH-01 BH-02 BH-03 BH-04 Average
0 # $.55 m $.55 Dr% &en'it% !." tm$$.55 # !5.*5 m !2.40
+,bmerge& &en'it% 0." tm$
!5.*5 # 2!."5 m 5.80 +,bmerge& &en'it% 0." tm$
2!."5 # $2.50m !0."5 +,bmerge& &en'it% 0." tm$
-otal = $2.50
Depth Length BH-01 BH-02 BH-03 BH-04 Average
0 # $.55 m $.55 φ 0 &egree'
$.55 # !5.*5 m !2.40 φ 0 &egree'
!5.*5 # 2!."5 m 5.80 φ 0 &egree'
2!."5 # $2.50m !0."5 φ $4 &egree'
-otal = $2.50
Depth Length BH-01 BH-02 BH-03 BH-04 Average0 # $.55 m $.55 c 0
tm2
$.55 # !5.*5 m !2.40 c $.5 tm2
!5.*5 # 2!."5 m 5.80 c 8 tm2
2!."5 # $2.50m !0."5 c 0 tm2
-otal = $2.50
ro'' 'ectional area of pile (/p) = 0.!*25 m2
1nit eight of 'oil above ater table = !." tm$
Effective ,nit eight at 'oil at pile toe = 0." tm$
ohe'ion at pile toe = 0.00 tm20 &egree' $2.! 3 = $!.4 c =
*
verb,r&en pre'',re at bottom of pile cap (&0) = ".5
tm2
verb,r&en pre'',re (&!) = 2.*8 tm2
verb,r&en pre'',re (&2) = 2!.88 tm2
-otal overb,r&en pre'',re (&) = 24.85 tm2
!54.2$ t
/p 6 (c 6 c)
/&opt val,e of 7 = !.50 0.000
0.50 /verage i = 0.00 tm2
/'! = #4.$2 m2
/'2 = 4*.0* m2
/' = /'! 9 /'2 44."" m2
/verage overb,r&en pre'',re for ,pper part of pile =
5.$! tm2
/verage overb,r&en pre'',re for loer part of pile =
!$.*! tm2
+:in friction re'i'tant (f'!) = 0.00 t
+:in friction re'i'tant (f'2) = 0.00 t
0.00 t
+,m (7 i to & 6 &i 6 tan& 6 /'i)
-otal bearing re'i'tant (;b 9 ;') = !54.2$ t (/)
Allowable bearing resistant Qu(allow. ! "#$ ! 2.% &1.&'
t
Qu(ultiate ! Ap)(0.% ) D )γ
) *γ
+ , ) * + $u (/ i to ) ,i ) tan
) Asi +
Ap ) ( ) * + ) i ) Asi
