Calculus AB & BCDrill on Derivatives!!!!!!!!!!

By Susan E. CanteyWalnut Hills H.S.

2006

Derivative Drill & Practice

• I’m going to ask you to remember some derivatives.

• It’s important to be fast as time is your enemy on the AP Exam.

• When you think you know the answer,

• (or if you give up ) click to get to the next slide to see if you were correct.

What’s the definition of ?

There’s 2 of them!

You really need to know both of these thoroughly!

𝑓 ′ (𝑐 )=limh→ 0

𝑓 (𝑐+h )− 𝑓 (𝑐)h

𝑓 ′ (𝑐 )=lim𝑥→𝑐

𝑓 (𝑥 )− 𝑓 (𝑐)𝑥−𝑐

What’s the definition of ?

This is a bit different…instead of the limit being a number…it will be a function related to f(x)

Got it??

Notice that in the second definition, the arrow points to the independent variable in the final answer.

𝑓 ′ (𝑥 )= limh→0

𝑓 (𝑥+h )− 𝑓 (𝑥 )h

𝑓 ′ (𝑥 )= lim𝑡→𝑥

𝑓 (𝑥 )− 𝑓 (𝑡)𝑥−𝑡

What does the derivative, tell you about ?

(There are many answers…how many do you know?)

Here’s a few:

Slope of the curveInstantaneous rate of change in f(x)

Rate of changeIf f(x) is position…then velocity

If f(x) is velocity…then acceleration

Now…

Here come a series of questionsconcerning basic derivatives you should

know very quickly!

Ready?

d/dx(sin(x)) = ??

• What’s your answer?

cos(x)• Were you right?

(click for next question)

d/dx(mxn)

• What’s your answer?

mnxn-1

• Were you right?

(click for next question)

d/dx(ef(x))

• What is your answer?

𝑓 ′(𝑥 )𝑒 𝑓 (𝑥 )

• Were you right?

(click for next question)

d/dx(ln|x|)

• What is your answer?

1/x• Were you right?

(click for next question)

d/dx(ax)

• What’s yer answer…eh?

(ln a) ax

• Were you right?

(click for next question)

I dig this calculus stuff!!

d/dx (logax)

• What’s your answer?

Aghh! Never can remember this one!!!

Do it this way: logax = ln x / ln a (ln a is just a constant)

so the answer is

Ready?

1𝑥𝑙𝑛𝑎

d/dx(cos x)

• What’s your answer?

(yeah yeah yeah…back to trig!)

- sin x• Did you remember

the “-” ??

Were you right?

(click for next question)

d/dx(tan x)

• Answer it baby!!

sec2x

• Were you right?

(click for next question)

d/dx(cot x)

• The ugly step sister!

- csc2x• Ya ya ya!!• Were you right?

(click for next question)

d/dx(sec x)

• I call this one the wart derivative!

sec x tan x• Were you right?

(click for next question)

(It’s the TRIG family!!)

d/dx(csc x)

• Get ‘er done!!!

- csc x cot x• I think there’s a

pattern, eh?

(click for next question)

d/dx(ln f(x))

•Ready?

𝑓 ′(𝑥 )/ 𝑓 (𝑥)• Were you right?

(click for next question)

d/dx (af(x))

• Go go go go!!!!!

af(x)

• Were you right?

(click for next question)

Hit that ball!!

d/dx (tan-1x)

• Oh yeah! Inverse trig mama!

1/(1+x2)• Were you right?

(click for next question)

It’s not raining is it?

d/dx(sin-1x)

You can do this one in your sleep!

RIGHT?

Did ya get it??

• Let’s keep going!!!

21

1

x

d/dx(cos-1x)

• If you new the last one, ya know this one…….right??

Oh yeah!

21

1

x

d/dx(sec-1x)

• This one’s a bit harder….

Dah dah!!!

Did you know that one??

1¿ 𝑥∨√𝑥2−1

d/dx(|x|)

• This one is a bit esoteric…

If you knew it was

xx ||

BPROUD of ya!

d/dx(f(x)g(x))

• It’s the Product Rule!

• (don’t flush it!!!)

𝑓 (𝑥)𝑔 ′ (𝑥)+𝑔(𝑥) 𝑓 ′(𝑥 )Yeah…I know you know it…but I’m afraid…

Promise me you will remember to use the product rule every time you take the derivative of a

product! OK??

d/dx(f(x)/g(x))

It’s the merry mighty Quotient Rule!!

Pleeeezzze!Don’t get the numerator backwards.

𝑔 (𝑥 ) 𝑓 ′ (𝑥 )− 𝑓 (𝑥 )𝑔 ′(𝑥 )

[𝑔 (𝑥 )]2

d/dx(f(g(x)))

Chain chain chain….Chain of love!

Yeah yeah…you’re good now…

But what about that first week of May?

Don’t forget all three steps!1) Deriv of outside 2) Copy inside3) Multiply by the “baby”

)('))((' xgxgf

d/dx(y)

Are you confused yet?

dy/dx

• Did I trick you ?

d/dx(xx)

• Hmmmmm….

Ha ha…I did trick you!

Variable to a variable power - you can’t do it…unless you take the natural log first…

y = xx

ln y = x ln x(1/y)(dy/dx)=x(1/x)+ 1lnx

dy/dx = y(1+lnx)

OK…switching to Related Rates

For the rest of the questions, pretend you are doing a related rates problem.

That is…”t” is the independent variable…

For each expression, give the derivative as you would in a Related Rates problem.

Here we go!!!

y

dy/dt

Ready to proceed?

Here’s a harder one:

2r

Did ya get it??

dr/dt is the “baby”…r is the “mama”

)(2 dtdrr

xy

Don’t be fooled!!!!

Ya Ya…Product Rule!!

You promised you would not forget!

x (dy/dt) + y (dx/dt)

sin x

Whoo whoo dee whoo!!

(cos x) (dx/dt)

Well…did you remember there was a baby?

Last one!

Don’t mess up!

y2

(2y)(dy/dt)

Yeah! That’s it for derivatives!

Run this power point again if you are not 100% certain you have mastered

derivatives!

Goodbye!

Be sure to run the other four power points for :1) Integrals 2) Miscellaneous Topics3) Sequences and Series 4) Other BC Topics