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Calculator Skills 2. INPUT EACH EQUATION INTO YOUR CALCULATOR AND PRESS GRAPH THEN FIND THE ORDERED PAIR SOLUTION HOLD UP YOUR CACLULATOR WHEN YOU HAVE THE SOLUTION. y = 3x 6 y = 2x + 4. INPUT INTO y1 AND y2 GRAPH 2 ND TRACE (CALC) 5 (INTERCEPT) ENTER, ENTER, ENTER. (2,0). - PowerPoint PPT Presentation
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Calculator Skills 2
INPUT EACH EQUATION INTO YOUR CALCULATOR AND PRESS GRAPH
THEN FIND THE ORDERED PAIR SOLUTIONHOLD UP YOUR CACLULATOR WHEN YOU HAVE
THE SOLUTION
y = 3x 6 y = 2x + 4
• INPUT INTO y1 AND y2
• GRAPH
• 2ND
• TRACE (CALC)
• 5 (INTERCEPT)
• ENTER, ENTER, ENTER
(2,0)
• y1 = 3x 6 y2 = 2x + 4
4x – 2y = 8 y = 7x + 5
• INPUT INTO y1 AND y2
• GRAPH
• 2ND
• TRACE (CALC)
• 5 (INTERCEPT)
• ENTER, ENTER, ENTER
(1, –2)
• y1 = (8 – 4x)/ – 2 y2 = 7x + 5
3x + 6y = 12 y 3 = 2(x 2)
(1.2 , 1.4)
• y1 = (12–3x)/6
• y2 = 2(x 2) + 3
y + 1 = 4(x 2) y = 6x 10
(.5 , –7)
• y1 = 4(x 2) – 1
• y2 = 6x 10
5x – y = 2 – x + y = 2
(1 , 3)
• y1 = (2– 5x)/ – 1
• y2 = (2 + x)/1
2x + 2y = 6 – 2x + 3y = –1
(2, 1)
• y1 = (6 – 2x)/ 2
• y2 = (–1 + 2x)/ 3
– 2y – 2x = – 8 2y – 3x = – 2
LOOK AT WHERE THE “X” AND “Y” ARE LOCATED IN PROBLEM
(2, 2)
• y1 =( – 8 +2x )/–2y2 =( – 2 + 3x)/ 2
4y = 3x – 2 3x + 2y = – 10
(–2, –2)
• y1 = (– 2+3x)/4
• y2 = (– 10 –3x)/2
4x + (–2y) + x = 2 6x + 2y = – 4
(-.181818, –1.454545)
• y1= (2 – 4x –x)/ –2
• y2 = (– 4 – 6x)/2
2x + 2y ≤ 6 y ≥ x + 1
• FOR INEQALITIES INPUT EQ. INTO y1 AND y2• USE LEFT SCROLL ARROW TO MOVER
CURSER TO EXTREME LEFT• PRESS ENTER UNTIL YOU GET THE UP
RIGHT TRIANGLE ( GREATER THAN) • OR PRESS ENTER UNTIL YOU GET THE
DOWN RIGHT TRIANGLE (LESS THAN)• PRESS GRAPH• LOOK FOR DOUBLE SHADED REGION • FIND POINT OF INTERSECTION
Left double shaded with (1,2) intercept
• y ≤ (6 – 2x)/2
• y ≥ x + 1
x ≥ – y + 2 y – 3x < 2
• REMEMBER TO REVERSE (OR FLIP ) THE INEQUALITY WHEN DIVIDING OR MULTIPLYING BY A NEGATIVE “–” NUMBER
SHADED LEF: (0,2)
• y1 ≤ (x – 2)/ –1
• y2 < (3x+ 2)
3x + 2y > 6 y < 2(x – 2)
SHADED RIGHT: (2,0)
• y1 > (6 – 3x)/2 y2 < 2(x – 2)
y – 3 ≤ 2(x – 1) x > – 2(y – 1)
Upper Right double shaded: (0,1)
• y1 ≤ 2(x – 1) + 3
• y2 > (x – 2)/–2
2y ≥ – 2x + 4 – y – 3 > 2(x – 4)
TOP LEFT DOUBLE SHADED: (3, – 1)
• y1 ≥ (– 2x + 4)/2
• y2 < (2(x – 4) + 3)/ –1
– 3x + 2y ≤ 3 y > – 3
REMEMBER: SINCE NO “x” IN SECOND INEQALITY, JUST PLACE –3 INTO y2
TOP RIGHT DOUBLE SHADED:(–3, –3)
• y1 ≤ (3 +3x)/2
• y2 > – 3
• END