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Calculations Notes. Multiplication and Division. Number of the sig. figs. is the result of the measurement with the smallest number of sig. figs. (least accurate) Ex 1: 4.63 m x 7.5 mEx. 2: 8.460 m 2 / 2.1 m. 3sf. 4sf. 2sf. 2sf. 34.725 m 2. 4.02857143 m. 4.0 m. 35 m 2. 6.341 - PowerPoint PPT Presentation
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Calculations Notes
Multiplication and Division
Number of the sig. figs. is the result of the measurement with the smallest number of sig. figs. (least accurate)
Ex 1: 4.63 m x 7.5 m Ex. 2: 8.460 m2 / 2.1 m
35 m2 4.0 m
3sf 2sf
34.725 m2
4sf 2sf
4.02857143 m
Addition and Subtraction
Align the decimal points and carry out the calculation. First column from the left with an uncertain digit determines the number of sig. figs. in your answer (Chop & round at the GAP)
Ex 1: 6.341 g + .789 g + 4.2 g Ex. 2: 6.799 m - 2.41 m
6.341 .7894.2
11.330
GAP11.3 g 6.799
2.414.389
GAP4.39 m
Scientific Notation and Multiplication and Division
Multiplication – Multiply coefficients, ADD exponents, multiply units, round to proper S.F.
Division - Divide coefficients, SUBTRACT exponents, divide units, round to proper S.F.
Ex 1: (1.00 x 103 m)(3.2 x 102 m) Ex. 2: (3.00 x 104 g)/(1.0 x 102 cm3)
3.2 x 105 m2 3.0 x 102 g/cm3
Scientific Notation and Addition and Subtraction
must be in the same power of ten and same unit before you add or subtract coefficients, convert to larger exponent
Ex 1: 3.0 x 1023 m + 1.0 x 1022 m 1
3.0 x 1023 m + .10 x 1023 m
3.0 .103.10
GAP 3.1 x 1023 m
Element Buddies
• ADD PRACTICE
Problem Solving and Dimensional Analysis
Conversion factor – ratio of two parts of the statement that relates the two units
Equivalence Statement – true statement in fraction form
Dimensional Analysis – when used properly all units will cancel out except the desired unit
2.54 cm = 1 inch
100 cm = 1 m
2.54 cm 1 inch
1 inch2.54 cm
100 cm 1 m
1 m 100 cm
or or
x ______________Desired UNIT
Wanted UNIT
#
#
x ________________
Wanted UNIT
#
#
Given UNIT
Given with UNITS=
Ex. 1: 250 m = ___________ km
Ex. 2: 3.54 g = ___________ mg
Ex. 3: 0.542 kg = __________ mg
x ___________km
1000
1
m
250 m = .25 km
x ___________mg
1
1000
g
3.54 g = 3540 mg
x __________mg
g
1000
1x ________g
1
1000
kg
0.542 kg = 542000 mg
Determining Error
___________________value - correct value based on reliable references
___________________value - value measured in the lab
Error = experimental value – accepted value(Note: error can be positive or
negative) You will take the ___________ value of this when you calculate percent error.
accepted
experimental
absolute
Determining Percent (%) Error
Percent error = absolute value of error divided by accepted value and multiplied by 100%
% error = experimental value – accepted value x 100%accepted value
Example: You take three temperature readings of a beaker of boiling water and record: 91.3oC, 90.9oC, and 91.1oC. Evaluate accuracy, precision, and error. Accurate? No, water boils at 100oC
Precise? Yes, values are close to each other
1. Find average experimental data
2. Use formula
Error
(91.3oC + 90.9oC + 91.1oC)/3 = 91.1oC
% error = (91.1 oC – 100 oC) x 100%100 oC
= 8.90 %