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ReviewReview
Molarity (M) = moles of solute liter of solution
Dilutions:M1
x V1 = M2
x V2
Percent by volume (%(v/v)) = volume of solute x 100%
volume of solution
Percent by mass (%(m/m)) = mass of solute x 100% mass of solution
Molarity (M) = moles of solute liter of solution
Dilutions:M1
x V1 = M2
x V2
Percent by volume (%(v/v)) = volume of solute x 100%
volume of solution
Percent by mass (%(m/m)) = mass of solute x 100% mass of solution
ReviewReview
• Colligative Property: A property that depends only upon the solute concentration and not on the solute’s identity.
• Four Important Colligative Properties of Solutions.– Vapor-pressure lowering– Boiling-point elevation– Freezing-point depression– Vapor Pressure
Molarity (M) = moles of solute liter of solution
Molality (m) = moles of solute_ kilogram of solvent
• Molality is the number of moles of solute dissolved in 1 kilogram (1000 g) of solvent.
• Colligative Property: A property that depends only upon the solute concentration and not on the solute’s identity.
• Four Important Colligative Properties of Solutions.– Vapor-pressure lowering– Boiling-point elevation– Freezing-point depression– Vapor Pressure
Molarity (M) = moles of solute liter of solution
Molality (m) = moles of solute_ kilogram of solvent
• Molality is the number of moles of solute dissolved in 1 kilogram (1000 g) of solvent.
Mole Fraction (another way to express concentration)
Mole Fraction (another way to express concentration)
Mole Fraction: the ratio of the moles of the solute to the total number of moles of solvent and solute.
XA= nA___ XB= nB___
nA + nB nA + nB
Mole Fraction: the ratio of the moles of the solute to the total number of moles of solvent and solute.
XA= nA___ XB= nB___
nA + nB nA + nB
Freezing-Point Depression & Boiling-Point Elevation
Freezing-Point Depression & Boiling-Point Elevation
Freezing-Point DepressionFreezing-Point Depression
∆Tf = Kf m i• ∆Tf = Freezing Point Depression
– Difference between the freezing point of the solution and the freezing point of pure solvent
• Kf = Molal Freezing Point Depression Constant– Equals to the change in freezing point for a 1-molal
solution of a nonvolatile molecule solid– Values are listed in a table – Depends upon the solvent– Units (°C/m)
• m = Molal Concentration• i = Number of Ions from each formula unit
∆Tf = Kf m i• ∆Tf = Freezing Point Depression
– Difference between the freezing point of the solution and the freezing point of pure solvent
• Kf = Molal Freezing Point Depression Constant– Equals to the change in freezing point for a 1-molal
solution of a nonvolatile molecule solid– Values are listed in a table – Depends upon the solvent– Units (°C/m)
• m = Molal Concentration• i = Number of Ions from each formula unit
•Applications–salting icy roads–making ice cream–antifreeze
• cars (-64°C to 136°C)• fish & insects
•Applications–salting icy roads–making ice cream–antifreeze
• cars (-64°C to 136°C)• fish & insects
Boiling-Point ElevationBoiling-Point Elevation
∆Tb = Kbm i• ∆Tb = Boiling-Point Elevation
– Difference between the boiling point of the solution and the boiling point of pure solvent
• Kb = Molal Boiling Point Elevation Constant– Equals to the change in boiling point for a 1-molal
solution of a nonvolatile molecule solid– Values are listed in a table – Depends upon the solvent– Units (°C/m)
• m = Molal Concentration• i = Number of Ions from each formula unit
∆Tb = Kbm i• ∆Tb = Boiling-Point Elevation
– Difference between the boiling point of the solution and the boiling point of pure solvent
• Kb = Molal Boiling Point Elevation Constant– Equals to the change in boiling point for a 1-molal
solution of a nonvolatile molecule solid– Values are listed in a table – Depends upon the solvent– Units (°C/m)
• m = Molal Concentration• i = Number of Ions from each formula unit
Solution CalculationsSolution Calculations
• What is the molarity of a 1.11 ppm solution of Zn2+ ions?
•
• What is the molarity of a 1.11 ppm solution of Zn2+ ions?
•
MXg
Znmole
mg
g
liter
Znmg 52
1070.139.65
1*
1000
1*
1
11.1
How Vapor Pressure Depression Occurs
•Solute particles take up space in a solution.
•Solute particles on surface decrease # of solvent particles on the surface.
•Less solvent particles can evaporate which lowers the vapor pressure of a liquid.
Vapor Pressures of Pure Water and a Water Solution
The vapor pressure of water over pure water is greater than the vapor pressure of water over an aqueous solution containing a nonvolatile solute.
Solute particles take up surface area and lower the vapor pressure
Raoult’s LawRaoult’s Law• Vapor pressure of a solution varies
directly as the mole fraction of solvent
Vapor Pressure Solution =
(mole fractionsolvent)(Vapor Pressuresolvent)
Solid CalculationsSolid Calculations
• Chemical analysis showed 1.23 mg Fe in a 15.67 g sample of soil.• What is the Fe concentration in ppm?
• Chemical analysis showed 1.23 mg Fe in a 15.67 g sample of soil.• What is the Fe concentration in ppm?
ppmmg
g
sampleg
Femg5.7810*
1000
1*
67.15
23.1 6