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Calculating Limiting and Excess Reagents SCH 3U

Calculating Limiting and Excess Reagents SCH 3U. The Mole Ratio The quantities of substances that react in a chemical reaction are determined by the mole

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Page 1: Calculating Limiting and Excess Reagents SCH 3U. The Mole Ratio The quantities of substances that react in a chemical reaction are determined by the mole

Calculating Limiting and Excess Reagents

SCH 3U

Page 2: Calculating Limiting and Excess Reagents SCH 3U. The Mole Ratio The quantities of substances that react in a chemical reaction are determined by the mole

The Mole RatioThe quantities of substances that react in a

chemical reaction are determined by the mole ratio given by the balanced chemical equationbut, in the real world, it is less likely for the

reactants to be in the mole ratios given by the equation – WHY??

Page 3: Calculating Limiting and Excess Reagents SCH 3U. The Mole Ratio The quantities of substances that react in a chemical reaction are determined by the mole

The AnswerIn nature, compounds are found in random

quantities

In labs / industry, we might want to ensure that one reactant is completely used up

Page 4: Calculating Limiting and Excess Reagents SCH 3U. The Mole Ratio The quantities of substances that react in a chemical reaction are determined by the mole

In any chemical reaction, one reactant is always present in EXCESS - in other words: the reagent that is not completely used up in the

reaction

there will be some left over at the end of the reaction

in order to provide a reagent in excess, chemists add 10% to the mass required

The Excess Reagent

Page 5: Calculating Limiting and Excess Reagents SCH 3U. The Mole Ratio The quantities of substances that react in a chemical reaction are determined by the mole

Limiting Reactant

To make a smiley face you need…

2 eyes + 1 head + 1 smile = 1 face

How many smiles can we make with 18 eyes, 8 heads and 23 smiles?

Page 6: Calculating Limiting and Excess Reagents SCH 3U. The Mole Ratio The quantities of substances that react in a chemical reaction are determined by the mole

The other reactant is LIMITING - in other words: it is completely used up in the reaction

the reagent in a chemical reaction that limits the amount of product that is able to form

The Limiting Reagent

Page 7: Calculating Limiting and Excess Reagents SCH 3U. The Mole Ratio The quantities of substances that react in a chemical reaction are determined by the mole

Kitchen Stoichiometry – an analogy

A recipe to make 30 candies requires the following:2 cups water5 cups sugar1 cup strawberries

Equation2 c water + 5 c sugar + 1 c strawberries 30

candies

Page 8: Calculating Limiting and Excess Reagents SCH 3U. The Mole Ratio The quantities of substances that react in a chemical reaction are determined by the mole

a. If you were given 10 cups of water, 10 cups of sugar and 10 cups of strawberries, which ingredient would limit the amount of candies being made? Which reagent is in excess?

Questions:

Page 9: Calculating Limiting and Excess Reagents SCH 3U. The Mole Ratio The quantities of substances that react in a chemical reaction are determined by the mole

b. How many candies can you make with the ingredients given in part a?

Questions:

Page 10: Calculating Limiting and Excess Reagents SCH 3U. The Mole Ratio The quantities of substances that react in a chemical reaction are determined by the mole

c. How much of the excess reagents will be left over?

Questions:

Page 11: Calculating Limiting and Excess Reagents SCH 3U. The Mole Ratio The quantities of substances that react in a chemical reaction are determined by the mole

Solving Limiting Reactant Problems

If you see that a problem gives information for more than one reactant, you need to figure out which reactant you will run out of first (limiting reactant) before you can figure out how much produce is made.

Page 12: Calculating Limiting and Excess Reagents SCH 3U. The Mole Ratio The quantities of substances that react in a chemical reaction are determined by the mole

Example:25.54 of Mg reacts with 45.67g of oxygen gas. How

much magnesium oxide will be produced?

Steps:

1. Balance chemical equation

2. find the number of moles of each reactant

3. Divide each reactant by its coefficient

4. The smallest answer is the limiting reactant

5. Use the moles of the limiting reactant to do the rest of your calculations.

Page 13: Calculating Limiting and Excess Reagents SCH 3U. The Mole Ratio The quantities of substances that react in a chemical reaction are determined by the mole

Your turn…Chlorine dioxide is a reactive oxidizing agent

used to purify water.

ClO2(g) + H2O(l) HClO3(aq) + HCl(aq)

A) If 71.00g of chlorine dioxide is mixed with 19.00g of water, what is the limiting reactant?

B) What mass of HClO3 is expected in part a?

C) how many formula units of HCl are expected in part a?

Page 14: Calculating Limiting and Excess Reagents SCH 3U. The Mole Ratio The quantities of substances that react in a chemical reaction are determined by the mole

Lithium nitride reacts with water to produce ammonia gas (NH3) and lithium hydroxide. If 4.5 g of lithium nitride and 5.8 g of water is available:b. How much (in grams) of the excess reagent will be left

over?

Question 2:

Page 15: Calculating Limiting and Excess Reagents SCH 3U. The Mole Ratio The quantities of substances that react in a chemical reaction are determined by the mole

Nitrogen and hydrogen react to form ammonia. If 28.02 g of nitrogen gas is to be completely used up, what is a reasonable mass of hydrogen gas to use in the reaction?

Question 3: