c++ Practical File

C++ PRACTICAL FILE

S.no Program name Teacher. Sign

1 WAP TO FIND THE GREATEST OF 3 NUMBERS2 WAP TO CALCULATE FACTORIAL OF A NUMBER.3 WAP TO PRINT FIBONACCI SERIES OF ‘n’ UMBERS,WHERE N

IS GIVEN BY THE PROGRAMMER4 WAP TO CHECK WHETHER A NUMBER IS PRIME OR NOT5 WAP TO COUNT CHARACTERS IN A STRING6 WAP TO READ A SET OF NUMBERS IN AN ARRAY AND TO

FIND THE LARGEST OF THEM7 WAP TO IMPLEMENT BUBBLE SORT USING ARRAYS8 WAP TO READ A SET OF NUMBERS FROM KEYBOARD AND

TO FIND SUM OF ALL ELEMENTS OF THE GIVEN ARRAY USING A FUNCTION

9 WAP TO SWAP VARIABLE USING CALL BY VALUE10 WAP TO SWAP VARIABLES USING CALL BY REFERENCE11 WAP TO FIND THE SUM OF THREE NUMBERS USING

POINTER TO FUNCTION METHOD12 WAP TO DISPLAY CONTENT OF AN ARRAY USING POINTER

ARITHMETIC13 WAP TO FIND AREA OF CIRCLE RECTANGLE,SQUARE

&TRIANGLE USING FUNCTION OVERLOADING14 WAP TO DEFINE NESTED CLASS ‘STUDENT_INFO’ WHICH

CONTAINS DATA MEMBERS SUCH AS NAME, ROLL NUMBER AND SEX AND ALSO CONSISTS OF ONE MORE CLASS ‘DATE’ WHOSE DATA MEMBERS ARE DAY, MONTH AND YEAR. THIS DATA IS TO BE READ FROM THE KEYBOARD & DISPLAYED ON THE SCREEN

15 WAP TO GENERATE A SERIES OF FIBONACCI NUMBERS USING COPY CONSTRUCTOR WHERE IT IS DEFINED THE CLASS USING SCOPE RESOLUTION OPERATOR

16 WAP TO ADD TWO COMPLEX NUMBERS WITH A FRIEND FUNCTION

17 WRITE A CLASS STRING TO COMPARE TWO STRINGS, OVERLOAD(==) OPERATOR

18 WRITE A CLASS TO CONCATENATE TWO STRINGS,

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OVERLOAD(+) OPERATOR.19 CREATE A CLASS ITEM, HAVING TWO DATA MEMBERS X &

Y, OVERLOAD ‘-‘(UNARY OPERATOR) TO CHANGE THE SIGN OF X AND Y

20 CREATE A CLASS EMPLOYEE. DERIVE 3 CLASSES FROM THIS CLASS NAMELY, PROGRAMMER, ANALYST & PROJECT LEADER. TAKE ATTRIBUTES AND OPERATIONS ON YOUR OWN. WAP TO IMPLEMENT THIS WITH ARRAY OF POINTERS.

21 CREATE TWO CLASSES NAMELY EMPLOYEE AND QUALIFICATION. USING MULTIPLE INHERITANCE DERIVE TWO CLASSES SCIENTIST AND MANAGER. TAKE SUITABLE ATTRIBUTES & OPERATIONS. WAP TO IMPLEMENT THIS CLASS HIERARCHY

22 WAP TO READ DATA FROM KEYWORD & WRITE IT TO THE FILE. AFTER WRITING IS COMPLETED, THE FILE IS CLOSED. THE PROGRAM AGAIN OPENS THE SAME FILE, READS

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1.WAP TO FIND THE GREATEST OF 3 NUMBERS.

CODING:

#include<iostream.h>

Void main() {Int<<”enter 3 numbers:”;Cin>>x>>y>>z;Cout<<endl;

If(x>y && x>z) Cout<<x<<”is largest<<endl”;}Else if(y>x && y>z)Cout<<y<<” is largest<<endl”:}Else { Cout<<z<<”is largest<<endl”; }}

OUTPUT:Enter the number:4 7 2 7 is largest

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2. WAP TO CALCULATE FACTORIAL OF A NUMBER.

CODING:


Void factorial(int num) { Unsigned long int fac=1; While(num!=0) { Fac=fac*num; num—;}

Cout<<endl<<”THE FACTORIAL IS”<<fac<<endl;

}

Void main() {Unsigned long int num;

Cout<<”Enter number:”;Cin>>”num;Cout<<endl;Factorial(num);

}

OUTPUT:Enter number:3The factorial is 6

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3.WAP TO PRINT FIBONACCI SERIES OF ‘n’ NUMBERS,WHERE N IS GIVEN BY THE PROGRAMMER.

CODING:


Void Fibonacci(int count) { Int fib=1, i=0 j=0;Cout<<0<<” ”;

While(count!=0) { Cout<<fib<<” “; i=j; j=fib; fib=i+j; count--;}}

Void main() { Int n; Cout<<”enter the number of instances: ”; Cin>>n; Cout<<endl;

Fibonacci(n);}

OUTPUT:Enter number of instances :80 1 1 2 3 5 8 13

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4.WAP TO CHECK WHETHER A NUMBER IS PRIME OR NOT

CODING:


Void prime(int num) { Int I,count=0;

For(i=0; i<num/2;i++) { If(num%2==0) { Count++;}}

If(count>1) { Cout<<endl<<”the number is not prime”<<endl;}Else { cout <<endl<<”the number is prime”<<endl;}}Void main() { Int num;

Count<<”enter the number:’; Cin>>num; Cout<<endl:

Prime(num);}

OUTPUT:Enter number: 42The number is not prime

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5. WAP TO COUNT CHARACTERS IN A STRING.

CODING:

#include<iostream.h>#include<string.h>

Void main() { Char line[100]; Int count,I,space=0;

Cout<<”please enter a sentence: ”; Cin.getline(line,99); Count=strlen(line);

For(i=0;i<count;i== { If(line[i]==’ ’) { Space++; Count++; }} Cout<<endl<<”the numbers of characters is=”<<count<<endl; Cout<<endl<<”The numbers of words is=”<<space<<endl;

}

OUTPUT:Please enter a sentence:my name is kartikThe number of characters is = 24The number of words is = 5

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6.WAP TO READ A SET OF NUMBERS IN AN ARRAY AND TO FIND THE LARGEST OF THEM.

CODING:


Void main() { Int set[20],I,large=0,limit;

Cout<<”enter number of entries: “; Cin>> limit;

For(i=1;i<limit;i++ { Cout<<”enter position “<<i<<”:”; Cin>>set[i]; If(set[i]>large) { Large=set[i];}} Cout<<endl<<”the largest value is”<<large<<endl;}

OUTPUT:

Enter no of entries:6Enter position 1: 23Enter position 2:12Enter position 3:54Enter position 4:76Enter position 5:36Enter position 6:69The largest value is 76

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7.WAP TO IMPLEMENT BUBBLE SORT USING ARRAYS.

CODING:


Void bubble_sort(int array[]);Void main() { Int matrix[10], I;

Cout<<”enter elements of the erray: ”<<endl; For(i=0;i<10;i++ { Cin>>matrix[i];

}

Bubble_sort(matrix); Cout<<”the sorted list is: ”<<endl;

For(i=o;i<10;i++) { Cout<<matrix[i]<<” “; }}

Void bubble_sort(int array[]) { Intj.k=1,temp;

While(k<10) { For(j=0.j<10.j++) { If(array[j]>array[j+1]; Temp=array[j+1]; Array[j]=array[j+1]; Array[j+1]=temp;}}K++;}}

OUTPUT:enter the element of an array: 5 7 3 8 12 6 9 2 4 15the sorted list is: 2 3 4 5 6 7 8 9 12 15

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8.WAP TO READ A SET OF NUMBERS FROM KEYBOARD AND TO FIND SUM OF ALL ELEMENTS OF THE GIVEN ARRAY USING A FUNCTION

CODING:


Void add(int arr[],int n) { Int I,sum=0;For(i=1;i<=n;i++) { Sum=sum+arr[i];}Cout<<endl<<”the sum is”<<sum<<endl;}Void main() {Int set[10],I,sum=0,limit;

Cout<<”enter number of entries: “;Cin>>limit;

For(i=1;i<=limit;i++) { Cout<<”enter position “<<i<<” : “; Cin>>set[i];}Add(set,limit);

}

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OUTPUT :Enter number of entries:5Enter position 1: 22Enter position 2: 56Enter position 3: 12Enter position 4: 33Enter position 5: 9

The sum is 132

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9.WAP TO SWAP VARIABLE USING CALL BY VALUE

CODING


Void swap(int a,int b);

Void main()

{int x,y;

Cout<<”please enter elements to be swapped”;

Cin>>x>>y;

Cout<<endl<<”the elements are”<<x<<”&”y;

Swap(x,y);

}

Void swap(int a,int b)

{a=a+b;

b= a-b;

a=a-b;

cout<<endl<<”the swapped elements are”<<a<<”&”<<b<<endl;

}

OUTPUT:

Please enter the elements to be swapped: 16 73

The elements are: 16 & 73

The swapped elements are: 73 &16

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10.WAP TO SWAP VARIABLES USING CALL BY REFERENCE

CODING:


Void swap(int *a,int* b);

Void main()

{int x,y;

Cout<<”please enter elements to be swapped”;

Cin>>x>>y;

Cout<<endl<<”the elements are”<<x<<”&”y;

Swap(&x,&y);

}

Void swap(int*a.int*b)

{

Int temp;

Temp=*a;

*a=*b;

*b=temp;

Cout<<endl<<”the swapped elements are”<<*a<<”&”<<*b<<endl;

}

OUTPUT:

Please enter the elements to be swapped: 16 73

The elements are: 16 & 73

The swapped elements are: 73 &16

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11.WAP TO FIND THE SUM OF THREE NUMBERS USING POINTER TO FUNCTION METHOD

CODING


#include<conio.h>

Int swap(int&n,int&b,int&c)

{

Int s;

S=a+b+c;

Return s;

}

Void main()

{

Int a,b,c,s;

Clrscr();

Cout<<”enter the no”;

Cin>>a>>b>>c;

S=swap(a,b,c);

Cout<<”the sum is”<<s;

Getch();

}

OUTPUT:

Enter the no 5 7 9

The sum is 21

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12.WAP TO DISPLAY CONTENT OF AN ARRAY USING POINTER ARITHMETIC.

CODING


#include<conio.h>

Void main()

{

Int n,a[20],i.*p=NULL,t=0;

Clrscr();

Cout<<”enter the no of elements”<<n;

Cout<<”enter the elements”;

For(i=0;i<n;i++)

{

Cin>>a[i];

}

p=&a[0];

do {

cout<<endl<<*p;

p++;

t++;

}

While(t!=n);

getch();}

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OUTPUT:

enter the no of elements 5

enter the element 9 7 3 10 4

9

7

3

10

4

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13.WAP TO FIND AREA OF CIRCLE ,RECTANGLE,SQUARE &TRIANGLE USING FUNCTION OVERLOADING

CODING:


Float calc(float r,float cons);

Int calc(int l,int h);

Int calc(int l);

Float calc(int l,int h,float cons);

Void main()

{

Int length,height;

Float radius;

Cout<<”enter radius of circle:”;<<radius;

Cout<<endl<<”the area of circle is:”<calc(radius,3.14)<<endl;

Cout<<”enter the length of rectangle”<<length;

Cout<<”enter the height of rectangle”<<height;

Cout<<endl<<”the area of rectangle is:”<calc(length,height)<<endl;

Cout<<”enter side of square”<<length;

Cout<<endl<<”the area of square is:”<calc(length)<<endl;

Cout<”enter base of triangle”;<<length;

Cout<”enter height of triangle”;<<height;

Cout<<endl<<”the area of triangle is:”<calc(length,height,0.5)<<endl;

}

Float calc(float r, float cons)

{return(cons*r*r);

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}

Int calc(int l, int h)

{return(l*l);

}

Float calc(int l, int h,float cons)

{return (l*h*cons);

}

OUTPUT:

enter radius of circle:5

the area of circle is:78.5

enter the length of rectangle:12

enter the height of rectangle:6

the area of rectangle is:72

enter side of square:10

the area of square is:100

enter base of triangle:7

enter height of triangle:12

the area of triangle is:42

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14. WAP TO DEFINE NESTED CLASS ‘STUDENT_INFO’ WHICH CONTAINS DATA MEMBERS SUCH AS NAME, ROLL NUMBER AND SEX AND ALSO CONSISTS OF ONE MORE CLASS ‘DATE’ WHOSE DATA MEMBERS ARE DAY, MONTH AND YEAR. THIS DATA IS TO BE READ FROM THE KEYBOARD & DISPLAYED ON THE SCREEN.

CODING:


Class student_info

{

Private:

Char name[50],sex;

Int roll;

Public:

Void input()

{

Cout<<endl<<”enter name:”;

Cin>>day;

Cout<<endl<<”enter sex:”;

Cin>>sex;

Cout<<endl<<’enter roll number:”;

Cin>>roll;

}

Class date

{

Public:

Int day,month,year;

Void insertdate()

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Cout<<endl<<”enter numerical day:”;

Cin>>day;

Cout<<endl<<”enter numerical month;”;

Cin>>month;

Cout<<endl<<”enter numerical year:”;

Cin>>year;

}

}d;

Void

Display()

{

Cout<<endl<<”name:”<<name;

Cout<<endl<<”sex:”<<sex;

Cout<<endl<<”roll:”<<roll;

Cout<<endl<<”the date of entry is:”;

Cout<<d.day<<”/”<<d.month<<”/”<<d.year<<endl;

}

};

Void main()

{

Student_info s1;

Cout<<endl<<”—Enter details---“<<endl;

S1.input();

Cout<<endl<<”---Enter Date Of Entry---“<<endl;

S1.d.insertdate();

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Cout<<endl<<”---INFORMATION---‘<<endl;

S1.display();

}

OUTPUT

---Enter Details---

Enter Name: karan

Enter Sex: M

Enter Roll Number: 1234

---Enter Date Of Entry---

Enter Numerical day: 11

Enter Numerical Month: 09

Enter Numerical Year: 2011

---INFORMATION---

Name: karan

Sex:M

Roll:1234

The Date Of entry is 11/09/2011

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15.WAP TO GENERATE A SERIES OF FIBONACCI NUMBERS USING COPY CONSTRUCTOR WHERE IT IS DEFINED THE CLASS USING SCOPE RESOLUTION OPERATOR.

CODING :


{

Public:

Fibonacci():limit(0)

{}

Fibonacci(int li):limit(li)

Int fibo=1,1=0,j=0;

Cout<<0<<””;

While(limit!=0)

Cout<<fibo<<””;

I=j;

J=fibo;

Fibo=i+j;

Limit--;

}

}

};

Void main()

{

Int n;

Cout<<”Enter the number of the instances: “;

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Cin>>n;

Fibonacci f(n);

Cout<<endl;

}

OUTPUT:

Enter number of instances: 8

0 1 1 2 3 5 8 13 21

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16.WAP TO ADD TWO COMPLEX NUMBERS WITH A FRIEND FUNCTION

CODING:


#include<conio.h>

Class cmplx

{

Int real,imagin;

Cout<<”ENTER THE REAL PART: “;

Cin>>real;

Cout<<”ENTER THE IMAGINARY PART: “;

Cin>>imagin;

}

Friend void sum(complx,complx);

};

Void sun(compx c1,complx c2)

Cout<<”RESULT:”;

Cout<<”[“<<c1.real<<”+ i”<<c1.imagin;

Cout<<”]+[“<<c2.real<<”+ i”<<c2.imagin;

Cout<<”]=”<<c1.real+c2.real<<”+ i”<<c1.imagin+c2.imagin;\

}

Void main()

Complx op1,op2;

Cout<<endl<<”INPUT OPERAND 1----“;

Op1.get();

Cout<<endl<<”INPUT OPERAND 2----“;

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Op2.get();

Sum(op1,op2); }

OUTPUT :

INPUT OPERAND 1----

ENTER THE REAL PART : 5

ENTER THE IMAGINARY PAR : 4

INPUT OPERAND 2----

ENTER THE REAL PART : 7

ENTER THE IMAGINARY PART : 2

RESULT : [5+4i]+[7+2i]=12+6i

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17. WRITE A CLASS STRING TO COMPARE TWO STRINGS, OVERLOAD(==) OPERATOR.

CODE :


#include<string>

Using namespace std;

Class string

{

Char a[10],b[10];

Public:

Voud getdata()

{

` cout<<”Enter the 2 strings=”;

Gets(a);

Gets(b);

}

Void operator==(string)

{

If(strcmp(a,b)==0)

Cout<<”\nStrings equal\n”;

Else

Cout<<”\nstrings not equal”;

}

};

Int main()

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{

String x;

x.getdata();

==x;

System(“pause”)

Return 0;

}

OUTPUT :

Enter two strings: cloverfield

Cleverfield

Strings not equal

Page 28

18.WRITE A CLASS TO CONCATENATE TWO STRINGS, OVERLOAD(+) OPERATOR.

CODING :


#include<string>


Class mystring

{

Char a[10,b[10];

Public:

Void getdata()

{

Cout<<”Enter first string=”;

Gets(a);

Cout<<”Enter second string=”;

Gets(b);

}

};

Int main()

{

Mystring x;

x.getdata();

+x;

System(“pause”);

Return 0;

}

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OUTPUT :

Enter first string=KARAN

Enter second string=SAGGU

KARAN SAGGU

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19.CREATE A CLASS ITEM, HAVING TWO DATA MEMBERS X & Y, OVERLOAD ‘-‘(UNARY OPERATOR) TO CHANGE THE SIGN OF X AND Y.

CODING:



Class item

{

Int x,y;

Public:

Void getdata()

{

Cout<<”Enter the vale of x & y=”;

Cin>>x;

Cin>>y;

}

Void operator –(void)

{

X= -x;

Y= -y;

}

Void display()

{

Cout<<”\nx=”<<x<<”\ny=”<<y;

}

};

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Int main()

{

Item x;

x.getdata();

-x;

x.display();

cout<<endl;

system(“pause”);

return 0;

}

OUTPUT :

Enter the value of x & y=15-30

X= -15

Y= 30

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20. CREATE A CLASS EMPLOYEE. DERIVE 3 CLASSES FROM THIS CLASS NAMELY, PROGRAMMER, ANALYST & PROJECT LEADER. TAKE ATTRIBUTES AND OPERATIONS ON YOUR OWN. WAP TO IMPLEMENT THIS WITH ARRAY OF POINTERS.

CODING :


#include<conio.h>

#include<string.h>

Class employee

{

Private:

Char name[20];

Int salary;

Public :

Void putData(int sal, char nam[20])

Strepy(name,nam);

Salary=sal;

}

Char* getName(void)

{

Return name;

}

Int getSal(void)

{

Return salary;

}

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};

Class programmer:public employee

{

Private:

Char skill[10];

Public:

Programmer(char name[20],int sal,char skil[20])

{

putData(sal,name);

strepy(skill,skil);

}

Void display(void)

{

Cout<<\n\nProgrammer : \n”;

Cout<<”\nName : “<<getName();

Cout<<”\nSalary : “<<getSal();

Cout<<”\nSkill : “<<skill;

}

};

Class analyst:public employee

{

Private:

Char type[10];

Public:

Analyst(char name[20],int sal,char typ[20])

Page 34

{

putData(sal,name);

strepy(type,typ);

}

Void display(void)

{

Cout<<”\n\n Analyst :\n”;

Cout<<”\nName :”<<getName();

Cout<<”\nsalary :”<<getSal();

Cout<<”\nType :”<<type;

}

};

Class proj_leader:public employee

{

Private:

Char pName[10];

Public:

Proj_leader(char name[20], int sal,char pNam[20])

{

putData(sal,name);

strepy(pName,pNam);

}

Void display(void)

Clrscr();

Proj_leader prl(“akshay”,10000,”software Development”);

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Analyst al(“ameeca”,8600,”post”);

Programmer p1(“ABC”,12000,”C++”);

Pr1.display();

A1.display();

P1.display();

Getch();

}

OUTPUT :

Project Leader :

Name : Akshey

Salary : 10000

Project : Software Development

Analyst :

Name : Ameeca

Salary : 8600

Type : Post

Programmer :

Name : ABC

Salary : 12000

Skill : C++

Page 36

21.CREATE TWO CLASSES NAMELY EMPLOYEE AND QUALIFICATION. USING MULTIPLE INHERITANCE DERIVE TWO CLASSES SCIENTIST AND MANAGER. TAKE SUITABLE ATTRIBUTES & OPERATIONS. WAP TO IMPLEMENT THIS CLASS HIERARCHY

CODING :


#include<conio.h.

#include<stdio.h>

Class employee

{

Char empname[10];

Int empid;

Public:

Void getemp()

{

Cout<<endl<<”Enter Emlpoyee Name :”;

Gets(empname);

Cout<<”Enter Employee Id :”;

Cin>>empid;

}

Void display()

{

Cout<<endl<<”Name :”<<empname;

Cout<<endl<<”Id :”<<empid;

}

};

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Class qualification

{

Int exp;

Public:

Void getqual()

{

Cout<<”Enter Year Of Working Experience :”;

Cin>>exp;

}

Void dispqual()

Cout<<endl<<”Experiece=”<<exp<<”years”;

}

};

Class scientist:public employee,public qualification

{

Int projid;

Public:

Void getproject()

{

Cout<<”Enter Project Id :”;

Cin>>projid;

}

Void dispproj()

{

Cout<<endl<<”PROJECT ID : “<<projid;

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}

};

Class manager;public employee,public qualification

{

Int groupid;

Public:

Void getgroup()

Cout<<”Enter Group Id :”;

Cin>>groupid;

}

Void dispgroup()

{

Cout<<endl<<”Group ID : “<<groupid;

}

};

Void main()

{

Clrscr();

Scientist s;

Manager m;

Cout<<”FOR SCIENTIST::::”<<endl;

s.getemp();

s.getqual();

s.getproject();

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s.display();

s.dispqual();

s.dispproj();

cout<<endl<<endl<<endl<<”FOR MANAGER::::”<<endl;

m.getemp();

m.getqual();

m.getgroup();

m.display();

m.dispqual();

m.dispgroup();

getch();

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OUTPUT :

FOR SCIENTIST :-

Enter Employee Name : Akash

Enter Employee Id : 13012

Enter Years Of Working Experience: 6

Enter Projext Id : 443

Name : Akash

Id: 13012

Experience=6 years

PROJECT ID : 443

FOR MAMAGER::::

Enter Employee Name : Sameera

Enter Employee Id : 1445

Enter Years Of Working Experience : 16

Enter Group Id : 5002

Name : Sameera

Id : 1445

Experience= 16 years

Group Id : 5002

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22.WAP TO READ DATA FROM FROM KEYWORD & WRITE IT TO THE FILE. AFTER WRITING IS COMPLETED, THE FILE IS CLOSED. THE PROGRAM AGAIN OPENS THE SAME FILE, READS.

CODING:


#include<fstream.h>

Void main(void)

Char string[255];

Int ch;

Cout<<”\nMENU\n)Write To File\n2)Read From File\nEnter Choice : “;

Cin>>ch;

Switch(ch)

{

Case 1:

Cout<<’\nEnter String To Write To File :”;

Cin>>string;

Ofstream fout;

Fout.open(“myfile.txt”);

Fout<<string;

Fout<<flush;

Fout.close();

Break;

Case 2:

Ifstream fin;

Fin.open(“myfile.txt”)

Fin>>string;

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Cout<<”\nFile Read : \n”<<string;

Fin.close();

Break;

Default:

Cout<<”INVALID CHOICE”;

}

}

OUTPUT :

MENU

1)Write To File

2)Read From File

Enter Choice: 1

Enter string to write to file: hi i am karan

MEMU

1)Write To File

2)Read From File

Enter Choice: 2

File Read: hi i am karan

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c++ Practical File