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We are looking for the B-field due to a single current loop along the axis of the loop (let’s take this as the +z axis). Let’s place our loop of radius R in the x-y plane and have its center coincide with the origin of our coordinate system with the current running counterclockwise when viewed from above. Refer to the following figure. Figure 4: Diagram for determining B-field due to loop current on loop current axis. The Biot-Savart law says that: = 0 4 × 2 This gives us the B-field due to a small segment of our current. The direction has been drawn in the figure. In order to get the net B-field at this point (at point (0,0,z)) we must integrate over all segments of our current loop. Convince yourself that doing so will result in a sort of CONE of B-field vectors at point (0,0,z) all pointed radially out and up with the same magnitude. Therefore, because each current segment along our current loop will gives us a radially out and up pointed B-field vector at point (0,0,z), the net horizontal B-field must be zero. Thus, we are only left with a net B-field that points in

Bio-Savart for Current Loop

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Bio-Savart for Current Loop

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  • We are looking for the B-field due to a single current loop

    along the axis of the loop (lets take this as the +z axis).

    Lets place our loop of radius R in the x-y plane and have its

    center coincide with the origin of our coordinate system with

    the current running counterclockwise when viewed from above.

    Refer to the following figure.

    Figure 4: Diagram for determining B-field due to loop current on

    loop current axis.

    The Biot-Savart law says that:

    =04

    2

    This gives us the B-field due to a small segment of our current.

    The direction has been drawn in the figure. In order to get the

    net B-field at this point (at point (0,0,z)) we must integrate

    over all segments of our current loop. Convince yourself that

    doing so will result in a sort of CONE of B-field vectors at

    point (0,0,z) all pointed radially out and up with the same

    magnitude. Therefore, because each current segment along our

    current loop will gives us a radially out and up pointed B-field

    vector at point (0,0,z), the net horizontal B-field must be

    zero. Thus, we are only left with a net B-field that points in

  • the positive z-direction. Let us continue with the calculation

    keeping in mind that the net B-field must be in the z direction.

    The dl is the arc length of a segment of our current, so this is

    given by:

    =

    The direction of dl x is the direction of the B-field for our segment of current, but we know that all horizontal components

    must be zero, so we set this direction equal to . The r in the Biot-Savart formula is the DISTANCE from our current segment to

    the field point, so this is given by:

    = 2 + 2

    Finally, we want to pick out the component of the B-field that

    is along the z direction, because this is the only non-zero

    component, so:

    = = 04

    ( )

    2 + 2

    But:

    =

    2 + 2

    Therefore:

    = = 04

    2

    2 + 2 32

    Now, in order to get the net field we must integrate over all

    our current segments (over all from 0 to 2pi). Therefore:

    = 04

    2

    2 + 2 32

    2

    0

    = 04

    2

    2 + 2 32

    2

    0

    = 04

    2

    2 + 2 32

    2

    Finally:

  • =

    +

    Keep in mind that this expression holds only for points on the

    axis of the current loop.