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Discrete Probability Distributions Binomial Distribution Poisson Distribution Hypergeometric Distribution

Binomial Probability Formula

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Discrete Probability Distributions Binomial Distribution Poisson Distribution Hypergeometric Distribution. Binomial Probability Formula. Binomial Probability Distribution. - PowerPoint PPT Presentation

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Page 1: Binomial Probability Formula

Discrete Probability DistributionsBinomial DistributionPoisson Distribution

Hypergeometric Distribution

Page 2: Binomial Probability Formula

Binomial Probability Formula

xnxxnxx

n qpxxn

nqpCxP

!)!(!)(

Page 3: Binomial Probability Formula

Binomial Probability Distribution

By listing the possible values of x with the corresponding probability of each, we can construct a Binomial Probability Distribution.

Page 4: Binomial Probability Formula

Constructing a Binomial Distribution

In a survey, a company asked their workers and retirees to name their expected sources of retirement income. Seven workers who participated in the survey were asked whether they expect to rely on Pension for retirement income. 36% of the workers responded that they rely on Pension only. Create a binomial probability distribution.

Page 5: Binomial Probability Formula

Constructing a Binomial Distribution

044.0)64.0()36.0()0( 7007 CP

173.0)64.0()36.0()1( 6117 CP

292.0)64.0()36.0()2( 5227 CP

274.0)64.0()36.0()3( 4337 CP

154.0)64.0()36.0()4( 3447 CP

052.0)64.0()36.0()5( 2557 CP

010.0)64.0()36.0()6( 1667 CP

001.0)64.0()36.0()7( 0777 CP

x P(x)

0 0.044

1 0.173

2 0.292

3 0.274

4 0.154

5 0.052

6 0.010

7 0.001

P(x) = 1

Notice all the probabilities are between 0 and 1 and that the sum of the probabilities is 1.

Page 6: Binomial Probability Formula

Population Parameters of a Binomial Distribution

Mean: = np

Variance: 2 = npq

Standard Deviation: = √npq

Page 7: Binomial Probability Formula

Example

In Murree, 57% of the days in a year are cloudy. Find the mean, variance, and standard deviation for the number of cloudy days during the month of June.

Mean: = np = 30(0.57) = 17.1Variance: 2 = npq = 30(0.57)(0.43) = 7.353Standard Deviation: = √npq = √7.353

≈2.71

Page 8: Binomial Probability Formula

Problem 1Four fair coins are tossed simultaneously. Find

the probability function of the random variable

X = Number of Heads and compute the probabilities

of obtaining:

No Heads

Precisely 1 Head

At least 1 Head

Not more than 3 Heads

Page 9: Binomial Probability Formula

Problem 2

If the Probability of hitting a target in a single shot is 10% and 10 shots are fired independently. What is the probability that the target will be hit at least once?

Page 10: Binomial Probability Formula

Poisson ProcessThe Poisson Process is a counting

that counts the number of occurrences of some specific event through time. Number of customers arriving to a

counter Number of calls received at a

telephone exchange Number of packets entering a queue

Page 11: Binomial Probability Formula

Poisson Probability Distribution

The Poisson probability distribution provides a good model for the probability distribution of the number of ‘rare events’ that occur randomly in time, distance, or space.

Page 12: Binomial Probability Formula

Assumptions Poisson Probability Distribution The probability of an occurrence of an event

is constant for all subintervals and independent events

There is no known limit on the number on successes during the interval

As the unit gets smaller, the probability that two or more events will occur approaches zero.

Page 13: Binomial Probability Formula

µ = 1

µ = 4

µ = 10

Page 14: Binomial Probability Formula

Poisson Probability Distribution

1,2,... 0,xfor,!

)(

xexfx

• f(x) = The probability of x successes over a given period of time or space, given µ

• µ = The expected number of successes per time or space unit; µ > 0

• e = 2.71828 (the base for natural logarithms)

Page 15: Binomial Probability Formula

Problem 5

Let X be the number of cars per minute passing a certain point of some road between 8 A.M and 10 A.M on a Sunday. Assume that X has a Poisson distribution with mean 5. Find the probability of observing 3 or fewer cars during any given minute.

Page 16: Binomial Probability Formula

Problem 7

In 1910, E. Rutherford and H. Geiger showed experimentally that number of alpha particles emitted per second in a radioactive process is random variable X having a Poisson distribution. If X has mean 0.5. What is the probability of observing 2 or more particles during any given second?

Page 17: Binomial Probability Formula

Problem 9Suppose that in the production of 50 Ω

resistors, non-defective items are those that have a resistance between 45 Ω and 55 Ω and the

probability of being defective is 0.2%. The

resistors are sold in a lot of 100, with the guarantee that all resistors are non-defective. What is the probability that a given lot will violate this guarantee?

Page 18: Binomial Probability Formula

Problem 11

Let P = 1% be the probability

that a certain type of light bulb will fail in 24 hours test. Find the probability that a sign consisting of 100 such bulbs will burn 24 hours with no bulb failures.

Page 19: Binomial Probability Formula

Multinomial DistributionIf a given trial can result in K outcomes E1,E2, …, Ek

with probabilities p1,p2, …,pk, then the Probability Distribution of the random variables X1,X2, …, Xk, representing the number of occurrences for E1,E2, …, Ek

in n independent trials is

1

...,...,,

n) ,p , ,p ,p ; x, , x,x(

1

1

22

11

21k21k21

k

ii

k

ii

xkk

xx

k

p

nx

pppxxx

nf

Page 20: Binomial Probability Formula

ExampleAn airport has three runways. The probabilities that

the individual runways are accessed by a randomly arriving commercial jets are as following:

Runway 1: p1 = 2/9Runway 2: p1 = 1/6Runway 3: p1 = 11/18What is the probability that 6 randomly arriving

airplanes are distributed in the following fashion?Runway 1: 2 airplanesRunway 2: 1 airplanesRunway 3: 3 airplanes

Page 21: Binomial Probability Formula

Sampling With Replacement

trialsn

obabilityNMp

defectiveMitemsallN

NM

NM

xn

xfxnx

)(Pr

1)(

Page 22: Binomial Probability Formula

Hypergeometric Probability Distribution

In cases where the sample size is relatively large compared to the population, a discrete distribution called hypergeometric may be useful.

Page 23: Binomial Probability Formula

Sampling Without ReplacementHypergeometric Distribution

xnMN

xM

nN

nN

xnMN

xM

xf /*)(

= Different ways of picking n things from N

= Different ways of picking x defective from M

= Different ways of picking n-x nondefective from N-M

Page 24: Binomial Probability Formula

Hypergeometric DistributionMean and Variance

)1())((

22

NNnNMNnMVariance

NMnMean

Page 25: Binomial Probability Formula

Problem 13Suppose that a test for extra sensory

perception consists of naming (in any

order) 3 cards randomly drawn from a

deck of 13 cards. Find the probability that

by chance alone, the person will correctly

name (a) no cards, (b) 1 Card, (c)

2 Cards, and (d) 3 cards.

Page 26: Binomial Probability Formula
Page 27: Binomial Probability Formula

Quiz # 232 Cptr (B) – 5 NOV 2012

If the Probability of hitting a target in a single shot is 5% and 20 shots are fired independently. What is the probability that the target will be hit at least once?