6. Calculate the total magnification of an object viewed under a) the low power objective and b) the high power objective?

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August 26, 2010

A free body diagram is the visual representation of force vectors

WOE = — mg

NOS = + mg

FOA = mafOS = µN

∑ Fy = mg - mg = 0∑ Fx = ma - µN = manet

Fnet = manet

#1 & 2 together 10 minutes to complete#3 & 6 Groups 1, 4, 7#4 & 7 Groups 2, 5, 8#5 & 8 Groups 3, 6, 9

WOE = — mg

NOS = + mg

∑ Fy = NOS - WOE = 0∑ Fy = mg - mg = 0

WOE = — mg

NOS

∑ Fynet = NOS - WOE = manet

WOE = — mg

NOS = + mg

FOA = ma∑ Fy = NOS - WOE = 0 = mg - mg = 0∑ Fx = manet

WOE = — mg

NOS = + mg

FOA = mafOS = µN

∑ Fy = mg - mg = 0∑ Fx = ma - µN = manet

Fnet = manet

WOE = — mg

NOS = + mg

FOA = mafOS = µN

∑ Fy = mg - mg = 0∑ Fx = ma - µN = — manet

Fnet = — manet

TOR = + mg

WOE = — mg

TOR = + mg

WOE = — mgFOA = ma

TOR = + mg

WOE = — mg

Can we directly measure the Tension? Is it still equal to +mg? Why or why not?

-x

+yThe x and y are just the components of the actual forces. This is why they’re drawn with dotted lines. You must ALWAYS draw components with dotted lines.

FOA = ma

Trigonometry: deals with angles and sides of triangles

S ine (sin )O pposite overH ypoteneuseC osine (cos )A djacent overH ypoteneuseT angent (tan )O pposite overA djacent

Y = Opp.

X =Adj.

Hyp.

xadj

yopp

T

S O H C A H T O A i p y o d y a p dn p p s j p n p j

sinѲ= opp = y hyp T

cos Ѳ = adj = x hyp T

tan Ѳ = opp = y adj x

Ѳ

XT cos Ѳ =x

adj

YT sinѲ =

yopp

T

S O H C A H T O A i p y o d y a p dn p p s j p n p j

T sinѲ= y

T cos Ѳ = x

Ѳ

TOR = + mg

WOE = — mg

-xT cos Ѳ =x

+yT sinѲ = +y

∑ Fy = T sinѲ - mg = 0∑ Fx = ma - T cosѲ = 0

FOA = ma

WOE = — mg

ѲѲ TOR2TOR1

In order for this box to just be hanging, what does the upward y component of the tension HAVE to be??