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BELL WORK: PAINTBALL 1. Before firing a paintball, the total momentum of the system is _____. 2. Once fired, the force of the gun on the paintball and the force of the paintball on the gun are ( equal / unequal ). 3. The impulse of the paintball and the impulse of the gun are ( equal / unequal ) and ______ (direction). 4. The paintball has ( more / less ) mass so it has ( more / less ) velocity. 5. After the gun is fired, the total momentum of the gun and paintball is ____. (think about question #1 again)

BELL WORK: PAINTBALL 1. Before firing a paintball, the total momentum of the system is _____. 2. Once fired, the force of the gun on the paintball and

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5. m1v1 + m2v2 = m3v3 65(6) +85(-4.5) = (150)v 7.5 = 150v v = 0.05 m/s 6. m1v1 +m2v2 = m1v1 + m2v2 4(-25) + 15(0) = 4(8) + 15v -100 = v v = -8.8 m/s

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Page 1: BELL WORK: PAINTBALL 1. Before firing a paintball, the total momentum of the system is _____. 2. Once fired, the force of the gun on the paintball and

BELL WORK: PAINTBALL1. Before firing a paintball, the total momentum of the

system is _____.2. Once fired, the force of the gun on the paintball and

the force of the paintball on the gun are ( equal / unequal ).

3. The impulse of the paintball and the impulse of the gun are ( equal / unequal ) and ______ (direction).

4. The paintball has ( more / less ) mass so it has ( more / less ) velocity.

5. After the gun is fired, the total momentum of the gun and paintball is ____. (think about question #1 again)

Page 2: BELL WORK: PAINTBALL 1. Before firing a paintball, the total momentum of the system is _____. 2. Once fired, the force of the gun on the paintball and

p = m v Δp = F t Δp = m Δv F t = m Δv

• Please turn in upside down in the basket when finished.• Get out your conservation of momentum problems and continue to work on them.

Page 3: BELL WORK: PAINTBALL 1. Before firing a paintball, the total momentum of the system is _____. 2. Once fired, the force of the gun on the paintball and

5. m1v1 + m2v2 = m3v365(6) +85(-4.5) = (150)v7.5 = 150vv = 0.05 m/s

6. m1v1 +m2v2 = m1v1 + m2v24(-25) + 15(0) = 4(8) + 15v-100 = 32 + 15vv = -8.8 m/s