PROJECT: JOB NO: Designed: CLIENT: TITLE: Checked: SUBJECT: Fua 'file:///home/website/convert/temp/convert_html/55cf8c6d5503462b138c40a0/document.xls'#$BEAM DESIGN Last Updated: TYPE fc'= fy= 60.0 Ksi w conc= 150 Pcf INPUT L= 17.00 Ft 12.00 ft-kips b= 8.0 in 8.00 ft-kips h= 12.0 in OK 4.84 K at d away from support Cover= 1.375 in Ties: d= 10.63 in BEAM DESIGN As= 0.43 in2 USE 2 0.88 in2 OK 0.75 x 2x 4000 x 8.0 x 10.6 = 8064 Lbs 16128 Lbs 32255 Lbs 4840 - 4032 = 808 Lbs < 4032 Lbs Ult. Vs = 808 is in between 4032 Lbs and 8064 0 Av min / s= 50 bw / fy = 50.0 x 8 x 12 in/ft / 60000 = 0.08 0 F Vs = Vu - F Vc = 4.84 - 8.06 = - 3.22 0 Av / s= F Vs / F d fy = -3.22 x 12 / 478 = -0.08 0 Use Min. Ties # 3 @ 5 @ 5.3 @ 5.3 Applicabe within 24 in DEFLECTION CALCULATION 12.00 + 8.00 = 20.00 ft-kips 12.00 + 4.00 = 16.00 ft-kips Modulus of rupture, Elasticity & Modular ratio: 474 Psi 3834254 Psi n= Es /Ec 29000000 / 3834254 = 7.56 Gross & Cracked section of moment of inertia: As= 0.88 in2 8 x 12.00 ^3 / 12 = 1152 in4 B=b/(nAs)= 8 /( 7.56 x 0.88 ) = 1.2 in r=(n-1) As' / n As = 6.56 x 0.3 /( 7.56 x 0.88 ) = 0.30 cover for top bar, if any d'= 1.3 in kd=[ ( 2dB(1+rd'/d) +(1+r)^2-(1+r))^0.5 ]/B= (2 x 10.63 x 1.2 x 1.03 + 1.68 ### 1.2 Icr=b(k*d)^3/3+nAs(d-kd)^2+(n-1)As'(kd-d')^2= 148.09 353.92 8.54 510.55 in4 Ig / Icr 1152 / 510.55 = 2.26 Effective Moment of Inertia: Mcr= fr Ig / yt = 474 x 1152 / 6 = 91074 Lbs-in = 7.59 Ft-K where yt=h/2 a) UNDER DL ONLY Mcr/Md= =( 7.59 / 12.00 )^3= 0.25 <1 Hence Ie= 673 in4 b) UNDER SUSTAINED LOAD (Mcr/Msus)^3= =( 7.59 / 16.00 )^3= 0.11 <1 Hence (Ie)sus= 579 in4 c) UNDER D+L LAOAD =( 7.59 / 20.00 )^3= 0.05 <1 Hence (Ie)D+L= 546 in4 SHORT TERM DEFLECTION (immadiate) 1 x( 5/48 x 12.00x12 ### ) /( 3834 x 673 ) = 0.24 in 1 x( 5/48 x 16.00x12 ### ) /( 3834 x 579 ) = 0.37 in 1 x( 5/48 x 20.00x12 ### ) /( 3834 x 546 ) = 0.50 in Thus, 0.50 -0.24 = 0.26 in < L/360= 0.57 OK LONG TERM DEFLECTION (At 3 mo. And 5 years ) Duration m p' 3 mo. 1 0.010353 0.66 0.37 0.25 + 0.26 = 0.502 in < 0.850 in 5 years 2 0.010353 1.32 0.37 0.49 + 0.26 = 0.749 in < 0.850 in (*) Allow. Deflection for long term 0.85 in [ACI, Table 9.5(b)] RESULT Initial Deflection= 0.255 in < L/360= 0.567 in Long term Deflection= 0.749 in < L/240= 0.850 in www.psncons MD = ML= Vu = Where, FVc = 2 F Vc = 4 F Vc = Ult. Vs =Vu- Vc/2 = MD + ML= Msus=MD +0.5 ML = fr=7.5 ( fc') 0.5 = Ec=33 x w 1.5 x ( fc') 0.5 Ig=bh 3 /12= (Mcr/MD+L)^3= D d= K (5Md L 2 )/ (48 E Ie D sus= K(5Msus L 2 )/(48E Ie d D D+L= K(5MD+L L 2 )/(48E Ie d D L= D D+L - D d= l =m/(1+50p' D sus D creep + D shrink = l x D sus D L D total D allow. (*)
