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7/28/2019 basic power electronic
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GROUP MEMBERS
Muhammad Uzi Migzuan
Muhamad Hazuan Mustafa
Abdil Naim Mohd Razi
Siti Nur Adilah Md IshakNur Anati Zolkifly
Eng Kean Ming
Dhinakar a/l Harisanka Rao
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1.Introduction
2.Analyze control and uncontrolled circuitof rectifier
3. Principle operation of rectifier4.Analyze voltage and current waveformwith load
a. Resistive load
b. Inductive load5.Analyze chopper circuit
6.Function of chopper
7.Principle operation of chopper
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8.Principle operation of step downchopper operation
9.Principle operation step down
chopper operation
10.Calculation on outputvoltage,current,power and efficiency
11.Application of chopper
12.Chopper operation:
a. Impulsed commutatedb. Resonant pulse
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A DC converter is an electronic circuit
that
convert:
a source of DC from 1 voltage level to
another.
Convert unregulated DC input to acontrolled DC output with a desired
voltage level.
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Rectification process
Is the process of converting anAC voltage source DC voltage.
No energy is stored within a rectifier
so that there is a constant connection
between the current and voltage on DC
side and current and voltage at AC side.
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A chopper is basically a dc to dc
converter whose main function/usage is
to create adjustable dc voltage from
fixed dc voltage sources through the
use of semiconductors.
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This chopper is also known as :
Parallel capacitor turn-off chopper
Voltage commutated chopper
Classical chopper.
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To start the circuit, capacitor C is initially charged with polarity (with plate
a positive) by triggering the thyristor T2.
Capacitor C gets charged through VS, C, T2 and load.
As the charging current decays to zero thyristor T2 will be turned-off.
With capacitor charged with plate a positive the circuit is ready for
operation.
Assume that the load current remains constant during the commutation
process.
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Once of the types of controlled rectifier is fully controlled and
semiconductor rectifier. A fully-controlled circuit contains only thyristers
(semiconductor controlled rectifiers (SCR)), whereas a semi-controlled
rectifier circuit is made up of both SCR and diodes as shown in Fig.(1). Due
to presence of diodes, free-wheeling operation takes place without
allowing the bridge output voltage to become negative
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Single phase uncontrolled half wave rectifiers suffer from poor output
voltage and/or input current ripple factor. In addition, the input
current contains a dc component which may cause problem (e.g.
Transformer saturation etc) in the power supply system. The output dc
voltage is also relatively less
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Some of these problems can be addressed using a full
wave rectifier. They use more number of diodes but
provide higher average and rms output voltage.
There are two types of full wave uncontrolled rectifiers
commonly in use. If a split power supply is available (e.g.
output from a split secondary transformer) only two
diode will be required to produce a full wave rectifier.These are called split secondary rectifiers and are
commonly used as the input stage of a linear dc voltage
regulator. However, if no split supply is available the
bridge configuration of the full wave rectifier is used.
This is the more commonly used full wave uncontrolled
rectifier configuration. Both these configurations are
analyzed next.
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Step down chopper is also known asbuck chopper.
In step down chopper output voltage is
less or equal than input voltage.
In DC-DC conversion circuits, thyristorsare used as switching elements.
Thyristor converter offers greaterefficiency, faster response, lowermaintenance, smaller size and smoothcontrol.
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When chopper is ON, supply isconnected across load.
Current flows from supply to load.
When chopper is OFF, load current
continues to flow in the same
direction through FWD due to
energy stored in inductor L.
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Load current can be continuous or
discontinuous depending on thevalues of L and duty cycle d
For a continuous current operation,
load current varies between twolimits Imaxand Imin
When current becomes equal to
Imaxthe chopper is turned-off andit is turned-on when current
reduces to Imin.
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On State Off state
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When S is on (D is off),capacitor energy supplies theload voltage.
Vo=Vc (if capacitor ischarged)
During on-state of switch S,voltage across inductorinstantly becomes equal toinput supply voltage. Currentthrough it increases graduallyand stores energy in its
magnetic field.
For very first time, when S isclosed Vo=0, as capacitor isnot charged.
When S is off (D is on),inductor voltage reverses its
polarity and adds in input
voltage to provide output
voltage which is equal to:
V0=Vi+VL
During off state of S, capacitor
charges and voltage at it
gradually build up to Vi+VL
(This capacitor voltages serves
as load voltage when next
time S in on) If S is off forever, inductor acts
as short circuit. It does not
develop any voltage and
Vo= Vi
18
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Voltage and current
waveforms for duty cycle
50%
d= 0.5 means Switch is on andoff for equal time intervals.
Energy that inductor develops
during on-state is completely
dessipated during off-state.
If duty cycle increases above
0.5, inductor will not
dessipate its energy
completely in off-states.The remaining inductor
voltage (due to left-over
energy) adds up next time
when switch is off and more
increased voltage appears at
output.
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20
If duty cycle increases above 0.5, inductor will not dessipateits energy completely in off-states. The remaining inductorvoltage (due to left-over energy) adds up next time when
switch is off and more increased voltage appears at output.
Neglecting losses, energy transferred by inductance during
TOFF must equal the energy gained by it during period
TON
Final expression for output load voltage is:
Vo=Vi [1/(1-d)]
If switch is open (d=0), output voltage is equal to input
voltage. As d increases, output voltage becomes larger than
input voltage.
So output voltage is always higher than input voltage if
switch is operated at an appropriately high frequency.
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Example 1
Input to the step up chopper is 200 V.
The output required is 600 V. If the
conducting time of thyristor is 200
sec. Calculate:
Chopping frequency,
If the pulse width is halved for
constant frequency of operation,
find the new output voltage.
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6
200 , 200 , 600
600 200 200 10
Solving for
300
ON dc
dc
ON
V V t s V V
TV VT t
T
T
T
T s
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6
6
Chopping frequency
1
1 3.33300 10
Pulse width is halved
200 10100
2ON
fT
f KHz
t s
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6
6
Frequency is constant
3.33
1300
Output voltage =
300 10200 300 Volts
300 100 10
ON
f KHz
T sf
TV
T t
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Example 2
A dc chopper in figure has a resistive loadof R = 10 and input voltage of V = 200 V.
When chopper is ON, its voltage drop is 2 V
and the chopping frequency is 1 kHz. If the
duty cycle is 60%, determine:
Average output voltage
RMS value of output voltage
Effective input resistance of chopper
Chopper efficiency.
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V
i0Chopper
+
R v0
V= 200v
R = 10
Chopper voltage drop, Vch = 2V
d= 0.60
f = 1kHz
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Average output voltage
0.60 200 2 118.8 VoltsRMS value of output voltage
0.6 200 2 153.37 Volts
dc ch
dc
O ch
O
V d V V
V
V d V V
V
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22
0
0 0
Effective input resistance of chopper is
118.811.88 Amps
10200
16.8311.88
Output power is
1 1
i
S dc
dcdc
i
S dc
dT dT
ch
O
V VRI I
VI
RV V
RI I
V VvP dt dt
T R T R
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2
2
0
0
0.6 200 22352.24 watts
10
Input power,1
1
ch
O
O
dT
i O
dT
ch
O
d V VP
R
P
P Vi dtT
V V VP dtT R
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0.6 200 200 22376 watts
10
Chopper efficiency,
100
2352.24100 99%
2376
ch
O
O
O
i
dV V V P
R
P
P
P
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Essentially, a chopper is an electronic switch that is used to
interrupt one signal under the control of another. Most
modern uses also use alternative nomenclature which helps
to clarify which particular type of circuit is being
discussed. These include: switched mode power supplies, including DC to DC
converters.
Speed controllers for DC motors
Class D Electronic amplifiers
Switched capacitor filters
Variable Frequency Drive