AUTO400 Homework Assignment 1 SOLUTION

7/21/2019 AUTO400 Homework Assignment 1 SOLUTION

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Department of Mechanical Engineering

AMEE 401/ AUTO 400 Instructor: Marios M. FyrillasAerodynamics Email: [email protected]

HOMEWORK ASSIGNMENT #1 SOLUTION

QUESTION 1

a. Explain the meaning of Drag force and give the expression of thedimensionless Drag coefficient.The resultant force in the direction of the upstream velocity is termed the DragForce (D). It has two contributions the skin friction, related to shear stress and thepressure drag, related to pressure differential between the front and the back ofthe body. The dimensionless Drag coefficient is given by:

2

Drag Force

C 1

2

D

U A,

where is usually the frontal area, the projected area seen by a person lookingtoward the object from a direction parallel to the upstream velocity, U .

A

b. Explain the meaning of Lift force and give the expression of the

dimensionless Lift coefficient.The resultant force in the direction normal to the upstream velocity is termed theLift Force (L). Similar to the Drag force it has two contributions however thecontribution of the shear stress to the Lift Force is often negligible. The

dimensionless Drag coefficient is given by:

2

Lift ForceC

1

2

L

U A

,

where A is usually the planform area, the projected area seen by a person lookingtoward the object from a direction normal to the upstream velocity, U .

c. In the Figure below identify the Drag force, the Lift Force, and show thedirection of the total shear force.

Lift

Drag resultant

shear force

SF
mailto:[email protected]:[email protected]:[email protected]:[email protected]


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QUESTION 2

The results of a wind tunnel test to determine the drag on a body (see Figure)are summarized below. The upstream [section (1)] velocity is uniform at 30 .

The static pressures are given by

m/s

1 214.7 psiap p . The downstream velocity

distribution [section (2)], which is symmetrical about the centerline, isassumed to be stepwise uniform (see Figure). Assume that the body shapedoes not change in the direction normal to the paper.a. Using the mass conservation equation determine the dividing streamlines.b. Using the momentum equation calculate the drag force (reaction force in x

direction) exerted on the air by the body per unit length normal to the planeof the sketch.

c. Find the Drag coefficient DC .

30 m/s

30 m/s

We choose a control volume within the streamlines ending

at the velocity discontinuity on the right-hand side of the

control volume and a point, which is going to be determined

through mass conservati

1

on, on the left-hand side of the control

volume.

Assuming unit depth the mass conservation states:

202 2 1.333 m

30

Assuming unit de

centerhV V h

Mass Conservation

Momentum Conservation in the x - direction

1 1

pth the momentum conservation states:

M

(30 20)

1.255 1.333 30 10 489 N/m

x x

x x

out in x

x in in out out center

M R

R m u m u m V V hV

1 m

1 m

centerV 20 m/s hRx


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QUESTION 3The results of a wind tunnel test to determine the drag on a body (see Figure)are summarized below. The upstream [section (1)] velocity is uniform at

. The static pressures are given by100 ft/s1 2

14.7 psiap p . The downstream

velocity distr ibution, which is symmetrical about the centerline, is given by

100 30 1 y 3 ft3

u=100 y 3 ft

yu

where u is the velocity in and is the distance on either side of the

centerline in feet (see Figure). Assume that the body shape does not change inthe direction normal to the paper. Calculate the drag force (reaction force in xdirection) exerted on the air by the body per uni t length normal to the plane ofthe sketch.

ft/s y


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5/16

QUESTION 4

As shown in the Figure below, a spoi ler is used on race cars to produce anegative lift, thereby giving a better tractive force. The lift coefficient for theairfoil shown is 1.1LC , and the coefficient of friction between the wheels and

the pavement is 0.6. At a speed of 200 mph, by how much would use of thespoiler increase the maximum tractive force that could be generated betweenthe wheels and ground? Assume the air speed past the spoiler equals the carspeed and that the airfoil acts directly over the drive wheels.


6/16

QUESTION 5

A 25-ton (50,000-lb) truck coasts down a steep mountain grade without brakes,as shown in Figure. The trucks ultimate steady-state speed, V, is determinedby a balance between weight, rolling resistance, and aerodynamic drag.Assume that the rol ling resis tance for a truck on concrete is 1.2% of the weightand the drag coefficient i s 0.76. Determine V.


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QUESTION 6

As shown in the Figure, the aerodynamic drag on a truck can be reduced bythe use of appropriate air deflectors. A reduction in drag coefficient from

to corresponds to a reduction of how many horsepower

needed at a highway speed of 65 mph?

0.96DC 0.7DC


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QUESTION 7

Determine the wind velocity required to overturn the mobi le home sketched inthe Figure if it is 10m long and weighs 50 kN. Consider it to be a squarecylinder.

D

w

Assume center of gravity is at center of home. When overturning

is imminent, no weight is on the right wheel. Then taking moments ( )

about the right wheel:

0 *(1 m) (1.75 m) .1.75

1But

D D

D D

M

wM w F F

F C

2

2

; Assume 2.05 square cylinder.2

=(2.5 m) (10 m)=25 m

22 1.75 0.131 m/s 29.3 m/s

2.05*1.292*25

D

D

D

u A C

A

w

Fu w

C A


9/16

QUESTION 8

A high speed car with ,2000kgm 0.3DC , and21mA , deploys a 2-m parachute

to slow down form an initial velocity of 100 m/s. Assuming constant DC , brakes

free, and no rolling resistance, calculate the distance and velocity of the car

after 1, 10, 100, and 1000 s. Neglect interference between the wake of the carand the parachute.

2

2

Newton's law applied in the direction of motion gives

d 1( )

d 2

where subscript is the car and subscript the parachute.

d 1This is of the form where (

d 2

c c p p

c c p

x c p D D

D D

VF m F F V C A C A

t

c p

V KV K C A C

t m

0

1 1 1 10 02

0

10

10

00

).

Separate the variables and integrate

dd d

1/

d 1Integrate once more to obtain the distance travelled

d /

ln(1+ ) where ( /

p

V t

V

A

V K K K t t V V t V V t

m m mV

VV Kt m

sV

t V Kt

Vs s t K

m

0

2 2

-1

)

1.2; Hence 0.3*1 1.2 *( / 4) * 2 4.07m

0.122 s

, s 1 10 100 1000

, m/s 89 45 7.6 0.8

, m 94 654 2100 3940

p c c p pD D D

m V

C C A C A

t

V

S


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QUESTION 9

A wing on a race car is supported by two cylindrical rods, as shown in theFigure. Compute the drag force exerted on the car due to these rods when thecar is traveling through s till air at a speed of 150 mph. Compute the drag if thecylindrical rods are replaced by elongated elliptical cylinders having a length tobreath ration of 8:1.

5

2

2

6

Re 3.15 10 0.8

0.0826 m

1214.4 N

2

Re 2.5 10 0.2 53.6 N

So there is 75% reduction

D

D D

D D

uDC

A DL

F C u A

uLC F

For elliptical cylinder


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12/16

QUESTION 11

A small spherical air -bubble is ris ing in st il l water (see Figure). Show that if thedensity of the air in the bubble is neglected from the calculations, then the sizeof the bubble can be estimated through the equation:

18 UD g

.

The drag coefficient of a sphere is24

ReDC for Re 1 .

U Figure: Rising air-bubble in a container

The forces acting on the bubble are the drag force , the bouyancy force

and the weight . If the bubble is moving at a constant velocity the forces must

balance. If we neglect the weight then:

D b

D

F F

W

F F 21

2

b DU A C V 2 3

2

2 32

1 24

2 4 Re 6

1 24

2 4 6

Solving above equation for

18

D Dg U g

D DU g

UD

D

UD

g

bF

W

DF


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QUESTION 12

A sphere of diameter and densi tyD s falls at a steady rate through a liqu id of

density s and viscosity . If the Reynolds number is less than 1, show that

the viscosity can be determined from2( )

18

sgD

U

.

DF


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QUESTION 13

A table tennis bal l weighing with diameter is hi t at a

velocity of U with a back spin of angular velocity

-22.45 10 N -23.8 10 mD

12m/s as is shown in the

figure. What is the value of if the ball is to travel on a horizontal path, not

dropping due to the acceleration of gravity?


15/16

QUESTION 14

In the figure, we show two curves representing the maximum engine output (interms of horsepower, HP) of a vehicle for two different gear ratios, HP4 and

HP5. Determine the maximum speed given that the drag coefficient 0.5DC ,

the frontal area of the car is2

2 mA , the rolling resistance is of thevehicles weight and the mass of the vehicle is 1000 .2%

kg


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The maximum steady-state speed of a vehicle is achieved when the maximum

available driving force at that speed equals the resistance force due to aerodynamic

drag and tire resistance.

Typically, the maximum engine output, initially increases with engine RPM, and the

maximum engine output can be related, through the overall gear ratio, to the vehicle's

speed. This maximum available driving power is shown schematically for two gear

ratios, HP4 and HP5, corresponding to fourth and fifth gears of a passenger car.

The total opposing force, which is a sum of tire rolling resistance and the aerodynamic

drag

2

2 2

), increases rapidly with speed, and its power requirement is obtained through

1

2

1 = 0.5 1.225 2 0.02 1000 9.81 (2.45 196.2)2

Usually, the

tot Drag Rolling D RP F V F F V C V A C W V

V V V V

increase in tire rolling resistance is marginal compared to the

rapid increase in the aerodynamic drag.

At a specific gear, the speed attained at maximum driving power is a balance between

the available power and the power required, i.e. the intersection of the HP4 and HP5 curves

with the power curve. Lower velocities are achieved by partial throttle.

Careful gear selection allows a higher maximum speed in the lower gear, while the highest

gear ratio is usually designed for good fuel economy. The latter avoids reaching the maximum

output range of the engine, rather it operates at maximum efficiency of the engine.

The primary conclusion is that total resistance increases rapidly with speed, and selection

of the proper gear ratio for maximum vehicle speed requires engine, tire and aerodynamic

data.

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AUTO400 Homework Assignment 1 SOLUTION