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7/23/2019 astronomy olympiad practice test solutions
http://slidepdf.com/reader/full/astronomy-olympiad-practice-test-solutions 1/8
Corporate Office : CG Tower, A-46 & 52, IPIA, Near City Mall, Jhalawar Road, Kota (Raj.)-324005
Website : www.resonance.ac.in | E-mail : [email protected]
Toll Free : 1800 200 2244 | 1800 258 5555 | CIN: U80302RJ2007PTC024029SOLAOPT3061114 - 1
DATE : 06-11-2014 STAGE - I
OLYMPIAD PREPARATORY TEST-3
(OPT-3)
SUBJECT : ASTRONOMY
HINTS & SOLUTIONS
1. (A)
2. (B)
x = A sin(!t) + Asin " #
$%&
' ()!
3
2t + Bsin(!t + *)
B = A & * =34( to make the resultant 0.
3. (D)tan2+ + 3 = 3sec+, sec2+ – 3sec+ + 2 = 0
, (sec+ – 1) (sec+ –2) = 0
, sec+ = 1 or sec+ = 2
, + = 2n( or + = 2n( ±3
(, n. I
Hence two solutions for 0 / + / 90º
(d) is correct
4. (D)
5. (D)
cos + =|q||p|
q.p ; cos 0 =p
2
qp
)p(.
2
qp
)
" #
$%&
' )
, , tan 0 =q.pp
sinpq2 )
+
cos 1 = |p|2
qp
)p(.2
qp
2
" #
$%&
' 2
=
, tan 1 =q.pp
sinpq2 2
+
tan 0 + tan 1 = pq sin + "" #
$%%&
'
2)
))2
)q.pp()q.pp(
q.ppq.pp22
22
=+2
+222 cosqp
sinpq2(B) is correct
6. (D)
2 / 1
22
F
Er
.T
1 2
3
4
56
7
8
9(
9
2 / 1
2
2 / 1
22 L
1
TL
Q 22
34
567
8:3
4
567
8
9
9= L
7. (B)
8. (B)
9. (B)
º20sin2
º70cos7 +
º65tanº45tanº25tan2
º35eccosº55cos3
= º70cos2
º70cos7
+ 1.)º65tanº25tan(º35sin2
º55cos3= 2
7+ 2
3=5
(B) is correct
10. (C)
F = !r2
ii 210
(
;; F = 2
0
21
rc4
(
22
22
2
2
2
0
0
qi
rF
Fr
q
i
F
<::
=
; =
iq
Fr =
iq
w
v = iR =qW ; R =
iqw
11. (C)
12. (A)
>U = U2 – U
1
= UD – U
C
= q3 3
4
567
8" #
$%&
' )2"
#
$%&
' )
50
Kq
40
Kq
10
Kq
40
Kq 2121
= Kq2q
3 ×
50
4
=0
3
4q(= q
0 × 210
1252
2< = 8q
2
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Corporate Office : CG Tower, A-46 & 52, IPIA, Near City Mall, Jhalawar Road, Kota (Raj.)-324005
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13. (C)
14. (C)A = { 2,4,6,8 ....... 400}B = { 3,6,9,12 ....... 750}A ? B = { 6 ,12, 18 , ..... , 396}, n (A ? B) = 66and n (A@B) = n(A) +n(B) – n(A?B)= 200 + 250 – 66 = 384
(C) is correct15. (A)
16. (B)
3 sin + = v2 cos +
v2 = 3 tan 30º = 1
(B) is correct
17. (A)
Energy incident =20kq
2
1
Energy refracted after first reflection
= )r1(kq2
1 220 2
Energy refracted after second reflection
= )r1)(r1(kq2
1 2220 22
2tkA
2
1 =
2220 )r1(q
2
K2
q0 = 1
At2 = (1 – r 2)2
At = (1 – r 2)
18. (B)
n = 1360
2+
; (n + 1) =+
360
+ = =1n
2
)(
or n =+(2
; + =n
2(
19. (C)Let a is first term and d is common difference
a3 + a
7 = 6 , (a + 2d) + (a + 6d) = 6 .........(1)
a3a
7 = 8 , (a + 2d) (a + 6d) = 8 .........(2)by solving (1) and (2)
a + 2d = 2 and a + 6d = 4or
a + 2d = 4 and a + 6d = 2
Case I IfABC
:)
:)
4d6a
2d2a, d =
2
1 and a = 1
, S16
=2
1634
567
8)
2
1).15()1(2 = 8 3
4
567
82
19 = 76
Case II IfABC
:)
:)
2d6a
4d2a, d = –
2
1 , a = 5
, S16
=2
16 3
4
567
8"
#
$%&
' 2)
2
1)15()5(2 =8 3
4
567
82
2
1510 = 80 –60=20
(C) is correct.
20. (A)v
avt = 0.5
2
1t
2
)9.0(g2)4.0(g2:
""
#
$
%%
&
' )
t =)32(g2.0
1
)
=)5(8.92.0
1
<
=7
1
21. (A)2x2 + 2y2 – 3x = 0
, x2 + y2 – 2
3x = 0
S( –
2, 1) = 4 + 1 + 3 = 8 > 0Hence ( –2, 1) lies out side the circle
distance of center " #
$%&
' 0,
4
3 from point ( –2, 1) is
=2
2
)10(24
32)"
#
$%&
' ) = 1
4
112
)" #
$%&
' =
16
137 >
4
11
Hence there are no point on the circle(A) is correct.
22. (D)
23. (A)R = 6 , H = 8
V = )8()6(3
1 2( sin + =R8
R
2 =
5
3
(since tan + =4
3)
5R = 24 – 3R
R = 3
V =8
3
24. (B)
25. (C)
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26. (D)
DExlim
x
2x
3x" #
$%&
' )2
= DExlim
x
x
21
x
31
""""
#
$
%%%%
&
'
)
2
; 1D form
= x.12x
3xlim
x
e
" #
$%&
' 2
)2
DE
= " #
$%&
' )DE 2x
x5 –
xlim
e = e –5
Hence (D) is correct.
27. (A)
28. (A)AM F GMNow a2 + b2 F 2abb2 + c2 F 2bcc2 + d2 F 2cdd2 + a2 F 2da
On addition2(a2 + b2 + c2 + d2) F 2(ab + bc + cd + da)
, a2 + b2 + c2 + d2 F ab + bc + cd + da
, ab + bc + cd + da / 45
(A) is correct.
29. (A)foci (3, 1) and (1, 1)
, major axes y = 1, center (2, 1)minor axies x = 2Let equation of ellipse
2
2
a
)2x( 2
+ 2
2
b
)1y( 2
= 1
it passes through P(1, 3) so that
22 b
4
a
1) = 1 ....(2)
distance between foci is = 2
, 2ae = 2
Now e2 = 1 – 2
2
a
b
, a2e2 = a2 – b2
, 1 = a2 – b2
Put in (2)
2b1
1
) + 2b
4 = 1 , b4 – 4b2 = 4
, b2 = 2 + 2 2
, a2 = 3 + 2 2
, e2 = 1 – 223
222
)
) =
223
1
)
, e =
)12(
1
)
= )12( 2
(A) is correct.
30. (C)
31. (C)Let Roots are 0 & 02
, 0 + 02 = –
3
p& 0.02 = 1
, (0 + 02)3 = –
27
p3
, 03 + 06 + 30.02(0 + 02) = – 27
p3
, 1 + 1 + 3 " #
$%&
' 2
3
p = –
27
p3
, 54 – 27p = –p3
, p3 – 27p + 54 = 0
, (p – 3) (p2 + 3p – 18) = 0
, p = 3 or p2 + 3p – 18 = 0
, p = 3 or p2 + 3p – 18 = 0
, p = 3 or (p + 6) (p – 3) = 0
, p = 3 or p = –
6
but p > 0
, p = 3(C) is correct.
32. (B)
cos + =ab
ba""
G
)b4 –a5).(b2a(""""
) = 0,
0b8 –b.a10b.a4 –a5 22 :)""""
cos + =63
cos + =2
1
+ = 60º
(B) is correct
33. (A)
34. (C)
35.
36. (D)
A =333
4
5
666
7
8
111
111
111
A – HI =H
H
H
–111
1 –11
11 –1
= 0
, (1 – H) (H2 – 2H) – 1 (1 – H – 1) + 1 (1 – 1 + H)= 0= (1 – H) (H2 – 2H) + H + H = 0= H2 – 2H – H3 + 2H2 + 2H = 0
= –
H3
+ 3H2
= 0H3 = 3H2 ; A3 = 3A2
(d) is correct
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Corporate Office : CG Tower, A-46 & 52, IPIA, Near City Mall, Jhalawar Road, Kota (Raj.)-324005
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37. (D)
Z =emit
emitobs
H
H2H ; Z =
1216
12162432 2=1
Z > 0 is known as red shift.
38. (B)Cube root of 64 isx = (64)1/3 (1)1/3
x = 4, 4!, 4!2
x = 4, "" #
$%%&
' )22
i314 , "
" #
$%%&
' 222
i314
x = 4, – 2 + 2 3 i, –2 – 2 3 i
so x = 2 3 i – 2 (b) is correct
39. (A)n
1 = 2 n
1 = 2
n2 = 3 n
2 = 4
Z = 1 Z = 2
H1 = 6561 H2 = ?
" #
$%&
' 2:
H 9
1
4
1R
1
1
" #
$%&
' 2:
H 16
1
4
12Rx
1 2
2 3494
165
1
2
<<<<
:HH
H2 = 243 × 5
H2 = 1215 Aº
40. (B)
xxx – x)xx( = 0
xxx = x)xx(
x x log x = x log x x
x3/2 log x = xlog2
x3
logx " #
$%&
' 2
x3 –x 2 / 3
= 0
logx = 0, x3/2 – 2
x3= 0
x = 1, " # $%& ' 23
–xx = 0
, x = 0 and4
9x : = 2.25 ; (B) is correct
41. (B)
10 MeV =r
qKq 21
10 × 1.6 × 10 –19 + 6 = 12
389
106.1
2956.221092
2
<
<<<<
= 18 × 1.6 ×29 × 1021 – 38
18 × 1.6 × 2y × 10 –17 = 8.3 × 10 –
15 m
42. (B)
E = 0V I 0B I 0
43. (D)
irms
=60
120=
45
vC
vC = 901502 = 1202 + (v
L – 90)2
)120150( 22 2 = |(vL – 90)|
|VL – 90| = 10 × 9
vL = 180 or v
L = 0 (not possible)
44. (B)425 : 595 : 76585 : 119 : 153
595 – 425 =!4
v2
! = 1 m45. (D)
m = 6 + 35
n = 6 – 35
m · n = 36 – 35 = 1
Now J K2n –m = m + n – mn2
= 12 – 2.1 = 10
, n –m = 10 ; (D) is correct
46. (D)
(h – h´) Lg = 02 pv
2
1)L
(h –
h´) L g = 2
1
L v2
+ h L g
v2 = [(h – h´)g – h] × 2
v = 0
47. (D)
AB = 34
567
8
00
11 3
4
567
8
1
10
1 =
334
5
667
8
010)0
1)11)0
22
2
0 = !1 = !2
1 + ! + !2 = 0
!2 = 1
So AB = 34
567
8
21 –
1 –1 –
(D) is correct
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48. (D)
9 = 4a)a(23
)a2)(a2( 22
<H)<H
= " #
$%&
' )H
3
164a3
=3
28a
a6
m 3 < =
2
6m
9
14" #
$%&
' <
!
=2
m369
14!< ; 9 =
2
m162
7!
49. (C)
" #
$%&
' 22;)"
#
$%&
' 2;:
R
1)1(
R
1)1(
f
121
= )11(R
121 ;2)2; ; f =
21
R
;2;
50. (C)
EqL =
40
1
20
140
6
20
10
)
2 =
40
340
620 2
i =
3
4010
3
14
) =
10
2 = 0.2 AA
i = 200 mAB E A
51. (A)
x1 + x = 2 cos +
3
xx
1" #
$%&
' ) = 8 cos3 +
x3 + 3x
1 + 3 "
#
$%&
' ) x
x
1 = 8 cos3+
3
6
x
1x ) + 3 (2cos +) = 8 cos3 +
3
6
x1x ) + 3 (2 cos +) = 8 cos3 +
3
6
x
1x ) = 2(4cos3 + – 3cos +) = 2 cos 3+
Alter :x
1 + x = 2 cos +
, x = cos + + i sin +
Now 3
6
x
1x ) = x3 + 3x
1
= (cos+ + isin+)2 + (cos + – i sin +)3 = 2 cos3+
(A) is correct
52. (B)30s
< vL
W1 = W
0 – 11
1 = v L g
1 < 10
1 M , W NW
2 > W
1
53. (B)
!:H2
)x(2
):H
!
!2
Vf1 :
)x(2
Vf2
)
:!
> f = f1 – f
2
= 34
567
8) x
1 –
1
2
V
!!
=)x(2
Vx
)!! x << l
>f = 22
Vx
!(B)
54. (C)
55. (A)
Angle are12
7,
6,
4
((( ; a = BC = 1 + 3
Csin
c
Bsin
b
Asin
a:: ;
O)105sin
31 =
6 / sin
b
(
, b =
"" #
$%%&
' )
)
22
13
)31(
2
1= 2
Area of >ABC =2
1ab sin C
= J K J K " #
$%&
' ()
4sin231
2
1 =
2
31) ; =
13
1
2
(A) is correct
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Corporate Office : CG Tower, A-46 & 52, IPIA, Near City Mall, Jhalawar Road, Kota (Raj.)-324005
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56. (B)
>u = n CV >T
= )T(1 –
nR>
P =1 –
V)1 –5.2(P
P =)1 –(
PV
2
3
P
Correct option is (B)
57. (B)Energy ELiner momentum pAngular frequency wQuntam no. n
w
Ep indendent of n
(B) option is correct.
58. (B) Standard Result
59. (D)
A"
+B"
= C"
and A" – B
" = D"
Then C2 + D2 = 2(A2 + B2)(D) is correct
60. (B)(1 + cot + + cosec + ) ( 1 + cot + – cosec+)= (1 + cot +)2 – (cosec2+)= 1 + cot2+ + 2 cot+ – cosec2+= 2 cot +(B) is correct
61. (C)
62. (A)C
1 (0, 0), C
2 = (3, 4)
r1 = 2, r
2 = 24169 )) = 7
C1C
2 = 5, r
1 + r
2 = 7
|r1 – r
2| = C
1C
2 < r
1 + r
2
Circles are internally touching so one tangent canbe drawn.
63. (C)
k, ! ;
" #
$%&
' )
(:
3
1
2
1k5
m2T =
k25
m62( = T
5
6
64. (A)
r
8 = cos + – 1
8 = r cos + – r
8 = x – 22 yx )
, (x – 8)2 = x2 + y2
, x2 – 16x + 64 = x2 + y2
, y2 + 16x – 64 = 0 (Parabola) (A) is correct
65. (B)
H = (l – x) ;
dm
xdm
= 0.3
2
6
2 –
3 –
2
dx)x –(
dxx)x –(
2
3
22
32
0
0 !
!
!
!!
!!!
!
!
!
!
:::
Q
Q
66. (A)
a)e –1(ae2
1 –
2
a)e –1(2a( = Area of shaded part
a 34
567
8(
2
e –)e –1(a2
= Area ;m2
L
dt
dA:
T = " #
$%&
' L
m2 (a (1 – e) a × 2
t ="
#
$%&
'
L
m2
a
2
(1 –
e)"
#
$%&
' (
2
e –
" #
$%&
' (
(:
2
e –
2
t
T
; " #
$%&
' (
(:
2
e –
2
Tt ; "
#
$%&
' (
:2
e –1
2
Tt
67. (D)
Area of >ABC =2
1
1bac
1acb
1cba
)
)
)
C1 E C
1 + C
2
=2
1(a + b + c)
1ba1
1ac11cb1
)
)) = 0
(D) is correct
68. (B)
n J KEH ? = 52% ...(1)
, 100% – n(H @ E) = 52%n(H) = 35% , n (H @ E) = 48%n(E) = 23% , n(H @ E) = n(H) + n(E) – n(H ? E)
, 48% = 35% + 23% – n(H ? E)
, n(H ? E) = 10%
So total = 1500 ×10
100 = 15000 ; (B) is correct
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69. (C)
Tn =
nn
32 )
850
1 =
nn
32 )
, n = 50
Sn
=
R ) nn
32 =
R ""
#
$%%
&
'
)
)
)1n(n
)n( –)1n(3
Sn = 3 3
4
567
8) 1n
1 –
n
1
S50
= 3 34
567
8"
#
$%&
' )"
#
$%&
' )"
#
$%&
' )"
#
$%&
' 51
1 –
50
1....
4
1 –
3
1
3
1 –
2
1
2
1 –
1
1
= 3 34
567
851
1 –1 =
17
50 =
17
162
(C) is correct
70. (C)
!12
1 –
!14
1 =
!15
x
!12
1 ""
#
$%%&
'
)13()14(
1 –1 =
!12)13()14()15(
x
, )13()14(
181 =
)13()14(15
x
, x = 181 × 15
x = 2715 ; (C) is correct
71. (A)
dx
dy = 4x3 + 24x2 + 52x + 32 = 0 (for tangent paral-
lel to x-axis)x = –1 satisfy
(x + 1) (4x2 + 20x + 32) = 0
, 4(x + 1) (x2 + 5x + 8) = 0x = –1 only one point
(1, –6)
(A) is correct
72. (A)AM F GM. equality holds only if 53x –4 = 54 –3x
, 4 – 3x = 0 , x =3
4
73. (D)
f(x) =2
1sin 2x
f '(x) = cos2x > 0 (for increasing)
x . " # $%
& ' (
4,0 @ "
# $%
& ' (( ,
4
3 ; (D) is correct
74. (C)(a + b)n
Tn+1
= nCn a°bn = bn = 16807
...(1)T
n = nC
n –1a1bn –1 = nabn –1 = 48020 ..(2)
Tn –1
= nCn –2
a2bn –2 =2
)1 –n(n a2bn –2 = 54880...(3)
by (2) / (1) b
na = 16807
48020
...(4)
by (3)/(2)b
a
2
)1 –n( =
48020
54880...(5)
by (4) & (5)n2
1 –n =
48020
16807
48020
54880<
, n
1 –n =
2305920400
1844736320 ,
n
1 = 1 –
2305920400
1844736320
,n
1 =
2305920400
461184080 , n = 5
by (1) b5 = 16807, b = 7 and a = 4(C) is correct
75. (C)
5
1 –
2
1
r
1: ; mm
3
10
3
25r :
<:
(C) Concave towards A
76. (D)
2
1 kA2 = 2 ;
2
1 k (.2)2 = 2 ; k =
04.
4 = 100
T =k
m2(
100
52T
(:
=100
05.2( = 14.04 × 10 –2 = 140 × 10 –3 = 140 ms
77. (A)
9 = Q(
)
6 /
0
44
4
dx)x3(sinx3cos
)x3(cos...(1)
using properties Qa
0
dx)x(f = Q 2a
0
dx)xa(f
9 = Q(
)
6 /
0
44
4
dx)x3(sin)x3(cos
)x3(sin...(2)
adding
29 = Q( 6 /
0
dx.1 ; 29 =6
(
9 = 12
((A) is correct
7/23/2019 astronomy olympiad practice test solutions
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78. (B)
Y = B.)BA( )Y = (1 + 0) . 1 = 1Y = (0 + 1) . 0 = 0
79. (D)
Hd =
mV
h =
34567
8 < nZ1018.2.m
h
6
; =
S T6
1018.2m
3h
<
<
= 1 nm Ans. (D)
80. (D)
9 = Q )
) 2
dxx5
)5(5logx5x
1x4
Let 5x + x5 = t(5x log 5 + 5x4) dx = dt
, 9 = Q t
dt
5
1 = ctlog
5
1)
= c)x5log(5
1 5x ))
(D) is correct
Physical constants you many need :
(1) Charge on electron e = 1.6 × 10-19 C
(2) Mass of an electron me = 9.1 × 10 –31 kg
(3) Universal gravitational constant G = 6.67 × 10 –11 Nm2 / kg2
(4) Permittivity of free space =0 = 8.85 × 10 –12 C2 / Nm2
(5) Gas constant R = 8.31 J / K mol
(6) Planck constant h = 6.62 × 10 –34 J s
(7) Stefan constant U = 5.67 × 10 –8 W/m2 k4
(8) Boltzmann constant k = 1.38 × 10 –23 J/K
ANSWER KEY
1. (A) 2. (B) 3. (D) 4. (D) 5. (D) 6. (D) 7. (B)
8. (B) 9. (B) 10. (C) 11. (C) 12. (A) 13. (C) 14. (C)
15. (A) 16. (B) 17. (A) 18. (B) 19. (C) 20. (A) 21. (A)
22. (D) 23. (A) 24. (B) 25. (C) 26. (D) 27. (A) 28. (A)
29. (A) 30. (C) 31. (C) 32. (B) 33. (A) 34. (C) 35.
36. (D) 37. (D) 38. (B) 39. (A) 40. (B) 41. (B) 42. (B)
43. (D) 44. (B) 45. (D) 46. (D) 47. (D) 48. (D) 49. (C)
50. (C) 51. (A) 52. (B) 53. (B) 54. (C) 55. (A) 56. (B)
57. (B) 58. (B) 59. (D) 60. (B) 61. (C) 62. (A) 63. (C)
64. (A) 65. (B) 66. (A) 67. (D) 68. (B) 69. (C) 70. (C)
71. (A) 72. (A) 73. (D) 74. (C) 75. (C) 76. (D) 77. (A)
78. (B) 79. (D) 80. (D)