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AREA AND VOLUMEForm 1 Mathematics
Chapter 7
REMINDER Lesson requirement
Textbook 1B Workbook 1B Notebook Folder
Before lessons start Desks in good order! No rubbish around! No toilets!
RESULT OF CBQ (CH. 9) Result of Close Book Quiz
Full mark: 40 and 10 bonus Highest: 44 Lowest: 10 Average: 23.8 Number of students between 10 – 19: 13 Number of students between 0 – 9:
0 Major Problems
Cannot get the drawing in rotation Cannot get the coordinates in transformation Mix up the rotation and reflection
RESULT OF CBQ (CH. 9) Result of Close Book Quiz 9th place: KO Ka Chung Boston
LIN Long Chak, Vincent 8th place: FU Ling Yin, Larry 7th place: LAU Cheuk Hei, Anson 6th place: CHEN Yi, David 5th place: CHAN Tsz Long, Sam 4th place: YUEN Tin Wai, Timmy 2nd place: LI Ming Chun, Edward
WU SHAN Hao Yi 1st place LI Sai Kong
Congratulations!!!!!! Well done!!!!!!
AREA OF PLANE FIGURES (P.2)
1. Area of triangle
2. Area of square
3. Area of rectangle
= length length
= length width
= base height12
AREA OF PLANE FIGURES (P.2)
4. Area of parallelogram
5. Area of trapezium
= base height
= sum of lengths of parallel sides height12
CALCULATING AREAS (P.3) Splitting Method
Filling Method
Area of the figure
= 18 cm2
12
= 3 3 + (3 + 6) 2 cm2
Area of the figure
= 38 cm2
= 10 4 – 2 2 cm212
TIME FOR PRACTICE Pages 10 – 11 of Textbook 1B
Questions 5 – 18 Pages 1 – 3 of Workbook 1B
Questions 1 – 5
WORKBOOK
WORKBOOK
16 36 10
260 cm2
36 36 10
(18 26) cm2
= 468 cm2
260 468
728 cm2
WORKBOOK
3 3
18 cm2
728 18
710 cm2
VOLUME OF SIMPLE SOLIDS (P.3)
1. Volume of cube
2. Volume of cuboid
= length length length
= length width height
PRISMS (柱體 , P.12) A solid with uniform cross-
section in the shape of a polygon is called a prism.
A prism is named and classified according to the shape of its base.
The perpendicular distance between the two parallel bases of a prism is called its height (or length).
The faces (other than the two bases) of a prism are called lateral faces.
base
base
Triangular prism
height
lateral faces
VOLUME OF PRISMS (P.17) Volume = area of base height
e.g. Volume of the solid = 260 20 cm3
= 5200 cm3
SURFACE AREAS OF PRISMS (P.14) Total surface area
= areas of the two bases + total area of all lateral faces
e.g. Total surface area of the solid = [2 260 + 6 (20 10)] cm2
= 1720 cm2
VOLUME OF PRISMS Volume of the triangular prism = ?
Area of the base of the prism= ( 7 4 2 ) cm2
= 14 cm2
So, the volume= ( 14 10 ) cm3
= 140 cm3
VOLUME OF PRISMS Volume of the rectangular prism (cuboid) = ?
The volume= [ ( 5 3 ) 6 ] cm3
= 90 cm3
The volume= [ ( 3 6 ) 5 ] cm3
= 90 cm3
The volume= [ ( 5 6 ) 3 ] cm3
= 90 cm3
VOLUME OF PRISMS Find the volume
of the prism.
Area of base
Volume of prism
= (12 7 – 8 5) cm2
= 44 cm2
= 44 11 cm3
= 484 cm3
VOLUME & SURFACE AREA OF PRISMS The figure shows a gold ingot in
the shape of a prism. Its base is a trapezium, and the other faces are rectangles. If the volume of the gold ingot is 540 cm3, find(a) the value of d,(b) the total surface area of the gold ingot.
(a) Area of trapezium
∴ The volume of the gold ingoti.e. 36d = 540 d = 15
(b) Total surface area of the gold ingot= [2 36 + 2 (15 5) + 15 12 + 15 6] cm2
= 492 cm2
12= (6 + 12) 4 cm2
= 36 cm2
= 36d cm3
TIME FOR PRACTICE Pages 22 – 23 of Textbook 1B
Questions 10 – 20 Pages 6 – 7 of Workbook 1B
Questions 3 – 6
WORKBOOK
WORKBOOK
8 8 8
512
5 10 4
200 cm3
4 3 d
12d cm3
512200 12d
12d = 312
26
WORKBOOK 2.5 1 6
15 cm2
19 15
4 cm2
4
2 cm2
2 2.5
5 cm3
1 2 3
6 cm3
6 cm3 5 cm3
B
REMINDER Missing Homework, Re-do Homework
Today! SHW (I)
Today! SHW (II)
22 Mar (Fri) Open Book Quiz
22 Mar (Fri) Close Book Quiz
26 Mar (Tue)
Enjoy the world of Mathematics!
Ronald H
UI