Archimedes Spher Cilindre-project

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    Archimedes :

    A Sphere and A Cylinder

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    Archimedes said: The surface area of a sphere equales the surface

    area of a cylinder whose height from the base to the top and

    the diameter of the base are the same as the diamiter of the sphere.

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    Before going to the details of what Archimedes did,

    we first must review how to calculate the area of the

    conical frustum.

    First, let us consider the area of a cone.

    The Area of Cone

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    As we know, we can cut a cone

    and make it 2D.

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    Area of Cone = (1/2) x 2(pi)m x s

    s

    2(pi)m

    s

    ---------------m---------------

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    Now,consider the area of a conical frustum.

    from the side view of a cone, we get

    t:m = (t+s) : M

    tM = (t+s)m

    t(M-m)=sm

    M

    H

    m

    h t

    s

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    Top View of The Area of

    The Conical Frusrum in 2D

    t s

    2(Pi)m

    2(pi)M

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    Area = (1/2)x(2(pi)Mx(s+t))

    Area = (1/2)x(2(pi)mxt)

    The Area of above Conicol Frustum= {(1/2)x(2(pi)Mx(s+t))}- {(1/2)x(2(pi)mxt)}

    =(pi)M x (s+t)-(pi)m x t = (pi)(Ms+Mt-mt)

    From the side vies of Conicol Frustum: t(M-m) =sr-----(a)

    substitute (a) in this equation,

    Area of Conicol Frustum

    =(pi)(Ms-ms)=(pi)(M-m)s

    = -

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    The surface area of a sphere:

    When a polygon is inscribed inside the great circle

    of a sphere and rotated around an axis,the surface area

    of polyhedron gets very close to the surface area of

    sphere as n gets larger and larger.

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    The surface area of a sphere:

    When a polygon is inscribed inside the great circle

    of a sphere and rotated around an axis,the surface area

    of polyhedron gets very close to the surface area of

    sphere as n gets larger and larger.

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    The surface area of a sphere:

    When a polygon is inscribed inside the great circle

    of a sphere and rotated around an axis,the surface area

    of polyhedron gets very close to the surface area of

    sphere as n gets larger and larger.

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    The surface area of a sphere:

    When a polygon is inscribed inside the great circle

    of a sphere and rotated around an axis,the surface area

    of polyhedron gets very close to the surface area of

    sphere as n gets larger and larger.

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    The surface area of a sphere:

    When a polygon is inscribed inside the great circle

    of a sphere and rotated around an axis,the surface area

    of polyhedron gets very close to the surface area of

    sphere as n gets larger and larger.

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    The surface area of a sphere:

    When a polygon is inscribed inside the great circle

    of a sphere and rotated around an axis,the surface area

    of polyhedron gets very close to the surface area of

    sphere as n gets larger and larger.

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    Archimedes method:

    Use a cone to calculate

    the area of a sphere

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    Archimedes rotated the circle below

    along the axis AD.

    Since the triangle ABG

    and the triangle ABD are

    similar, m(=GB) : AG = Y : s.

    so, ms = (AG)Y.Since the triangle AGB is

    similar to the triangl HGP,

    m : AG = m :Gp = Y :s.

    so, ms = (GP)Y.

    Similarly, M : PF = m : GP = Y : s.

    So, Ms = (PF)Y.

    Area of Conical Frustum (blue)

    = pi(m+M)s

    = pi( ms + Ms)

    = pi{(GP)Y + (PF)Y}

    = pi{(GP +PF)Y}= pi(GF)Y

    As n goes to infinity, Ybecomes inc

    to the diameter of the

    great circle. Therefore,

    Area of the Conical Frustum

    = 2(pi)r(GF), where r is a radius

    of the great circle of a sphere.

    A

    B

    C

    D

    E F

    GH

    m

    M

    Y

    s

    P

    M

    H

    m

    h t

    s

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    The side view of a cylinder----------r---------

    h

    2(pi)r

    hArea= 2(pi)rh