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Applications of Logs and Exponentials
Section 3-4
Objectives
I can solve interest rate problems using a calculator
I can solve exponential growth and decay application problems
Copyright © by Houghton Mifflin Company, Inc. All rights reserved.
Compound Interest
After t years, the balance, A, in an account with principal P and annual interest rate r (in decimal form) is given by the following formulas:
nt
rt
r1. For n compoundings per year: A=P(1+ )
n
2. For continuous compounding: A=Pe
Copyright © by Houghton Mifflin Company, Inc. All rights reserved.
Compounding Terms (n)
Term Value of (n)Annually 1Semi-annually 2Quarterly 4Monthly 12Daily 365
Copyright © by Houghton Mifflin Company, Inc. All rights reserved.
Example
Find the accumulated value of an investment of $8000 for 6 years at an interest rate of 6.85% if the money is compounded monthly.
612
12
0685.18000
A
nt
n
rPA
1
720057.18000A51.052,12$A
Copyright © by Houghton Mifflin Company, Inc. All rights reserved.
Your TurnFind the accumulated value of an investment of
$4800 for 5 years at an interest rate of 3.85% if the money is compounded quarterly.
4 5.0385
4800 14
A
nt
n
rPA
1
204800 1.009625A
$5813.57A
Copyright © by Houghton Mifflin Company, Inc. All rights reserved.
Example
Find the accumulated value of an investment of $2000 for 8 years at an interest rate of 7% if the money is compounded continuously
Solution:
A= Pert
A = 2000e(.07)(8)
A = 2000 e(.56)
A = 2000 * 1.75A = $3501.35
Copyright © by Houghton Mifflin Company, Inc. All rights reserved.
Your Turn
rtA Pe(.055)(7)3500A e
Find the accumulated value of an investment of $3500 for 7 years at an interest rate of 5.5% if the money is compounded continuously
$5143.65A
Application Problems
ktA PektA PeGrowth
Decay
A: Final Amount
P: Initial Amount
k: constant for problem
t: time
Application Problems
Many radioactive substances have a decay half-life.
This is the time required for the radioactivity to decay away to ½ its original amount. “k” is the constant
ktA Pe
Application Problems
In almost all application problems, you will have to solve for “k” first
Then you can solve for the required missing information
ApplicationAn ant population in a colony can be
modeled by the equation below where
N is the final number of ants and P is
the intial ant colony size, "t" is the time
in monthsktN Pe
If 10 ants start a colony and there are
20,000 ants after 3 months, how many
ants after 1 year?
320000 10 ke
2.5336k (2.5336)(12)10N e 141.599 10N x
Homework
WS 6-5