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1.6
Optimization, Related Rates and
Exponential Growth or Decay
REVIEW
OPTIMIZATION
: process of solving for a
maximum or a minimum,
in general, “efficient” values
REVIEW
Problem: value/s of x which OPTIMIZE
xfy
1. Determine critical points of f. (value/s of x where ) 0x'f
2. If there are several critical points,
compare function values at the
critical points.
3. If possible, use second-derivative
test on the critical points.
Projectile
Example 1. Range of a projectile
g
sinvR
22
R feet : range of the projectile
v ft/sec : initial velocity
g ft/sec2 : a constant
rad : angle of the projectile
Problem: value of that maximizes
the range of the projectile
20
Solution:
g
sinvR
22
d
dR 2
2
sinDg
v
d
dR22
2
cosg
v
0d
dR 0222
cosg
v
02 cos2
0
22
4
Solution:
d
dR22
2
cosg
v
2
2
d
Rd42
2
sing
v
4
2
2
d
Rd
g
v24 0
(at a fixed
initial velocity).
Solution:
Hence, the range of the projectile
attains a maximum if the angle of
the projectile is 4
Blood pressure
Example 2. Blood pressure monitoring
P : blood pressure
t : time
Problem: maximum and minimum
pressure and the time
these values occur
tcosP 22590
Solution:
dt
dP2225 tsin
0dt
dP 0250 tsin
02 tsin
3202 ,,,t
tcosP 22590
420 twithin
2
3
20
,,,t
Solution (continued)
2
3
20
,,,ttcosP 22590
1150 tP
652tP
115tP
6523 tP
Within , 20 t
P attains a maximum at
,t 0
P attains a minimum at
2
3
2
,t
Solution (continued)
In general, using the model
P attains a maximum at
is an integer, and k,kt
P attains a minimum at
is an odd integer. k,tk2
tcosP 22590
REVIEW
RELATED RATES
: how one variable changes
through time depending on
how another variable varies
through time
REVIEW
Assume x and y are functions of
time t such that . xfy
Problem: solve for given ,
or vice-versa. dt
dy
dt
dx
HOW: differentiate both sides of
with respect to t xfy
Example 3. Radar tracking
After blast-off, a space shuttle
climbs vertically and a radar-
tracking dish, located 800 m from
the launch pad, follows the shuttle.
How fast is the radar dish revolving
10 sec after blast-off if the velocity
at that time is 100 m/sec and the
shuttle is 500 m above the ground?
800 meters
x
x : height at time t : intercepted angle
at the dish of the shuttle to the pad
Solution:
Solve for when x = 500 and . dt
d100
dt
dx
800
xtan
800
xDtanD tt
dt
dx
dt
dsec
800
12
dt
dx
secdt
d
2
1
800
1
Solution (continued)
dt
dxcos
dt
d
800
2
At , the shuttle is
meters away from the dish.
(by Pythagorean theorem)
500x 89100
89
8cos
89
642 cos
100dt
dx
Solution (continued)
dt
dxcos
dt
d
800
2
where and . 89
642 cos 100dt
dx
898870. radian per second
100800
1
89
64
dt
d
Example 4. Speed tracking
A woman standing on top of a
vertical cliff is 200 feet above a sea.
As she watches, the angle of
depression of a motorboat (moving
directly away from the foot of the
cliff) is decreasing at a rate of 0.08
rad/sec. How fast is the motorboat
departing from the cliff when the
angle of depression is /4 rad?
200
fee
t
x : distance of the boat from the cliff
x
: angle of depression
Solution:
Solve for when =/4 and . dt
dx080.
dt
d
xtan
200
xDtanD tt
200
dt
dx
xdt
dsec
22 200
dt
dxsec
dt
dx
200
22
Solution (continued)
At =/4, x
tan200
4 200x
dt
dxsec
dt
dx
200
22
080.dt
d
2
4
2
sec
32dt
dxfeet per second
REVIEW
Exponential growth or decay
: rate of growth (or decay) is
proportional to the present
population or the present
quantity.
Modeling
Suppose an organism (or an element)
grows (or decays) such that rate of
growth is proportional to the present
quantity (or population).
y : quantity at time t
dt
dy: rate of growth (or decay)
kydt
dyHence, .
Modeling
kydt
dy dtk
y
dy
dtky
dy
Ckt
Cktey
Cktey Ckt ee
kteBy
yln
Modeling
kteBy
Exponential model of growth or decay
where B is the quantity at t=0
k is the rate of change
(per one unit change of t)
Example 5. Population growth
Suppose that the world population
grows exponentially at a rate of 2%
in a year. In how many years will
the world population double?
Solution:
kteBy
where k = 0.02 and t is in years
Solution (continued)
t.eBy 020 At t = 0, y = B.
At what t will y = 2B ?
t.eBB 0202 t.e 0202
t.elnln 0202
elnt.ln 0202
020
2
.
lnt 35734.
Conclusion
With the assumption of an
exponential growth at a
rate of 2%, the population
doubles in every 35 years.
Example 6. Radioactive decay
Carbon-14 is radioactive and
decays exponentially. It takes 5730
years for a given amount of C-14 to
decay one-half its original size.
Construct a function which shows
the amount of C-14 after t years.
Solution:
kteBy
Solution (continued)
At t = 5730, y = B/2.
kteBy keBB 5730
2
ke573021
kelnln 573021
elnkln 573021
000120970.k
At t = 0, y = B.
Conclusion
With the assumption of an
exponential decay and a
half-life of 5730 years,
models the amount of C-14
at time t.
t.eBy 000120970
END