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7/21/2019 API Sizing
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Hydro-Flo Technologies, Inc.
CompanyLocation
API Separator Calculations
USER INPUT IN YELLOW
Design lo! rate "in gpm# $%&
Temperature "in 'eg # (%&
Speci)ic *ra+ity o) t,e Oil "in g-cm.# &/.0
Oil Droplet si1e "in microns# (%&
Density o) t,e Water "in g-cm.# &/23&$$
4iscosity "in Poise# &/&&0.2
RESULTS
Width of separator in feet 5.000
Depth of separator in feet 2.500
Length of separator in feet 25.000
Oil Droplet "in cm# &/&(%
Call 630-762-0380 to talk to a Hydro-Flo application engineer
Design
terminal +elocity "in cm-s# (/3& (/3& (/3&
terminal +elocity "in )t-min# ./%0 ./%0 ./%0
5inimum cross sectional area nee'e' "in )t# ((/(0 ((/(0 ((/(0
The Art and Science...of Wastewater Treatment
For more detailed inormation go to !!!.HydroFloTech.com
MinimumAlloa!le
Result
Ma"imumAlloa!le
Result
An oil 'roplet si1e o)API separators/ Do nyou ,a+e a speci)ic ne+alue is 7&
http://www.hydroflotech.com/index.htmhttp://www.hydroflotech.com/index.htm7/21/2019 API Sizing
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(%& is typically t,e norm )ort c,ange t,is +alue unlesse'/ T,e minimum usea;le
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& %& (&& (%& $&& $%&
&/2.
&/20
&/2%
&/27
&/2>
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()"8# = &/&&&&&&&&$>>07$(0>>>.00>8E. ? &/&&&&&$((3.3>%.%3%>$&&&&8E$ F &/&&&(.22..203%%&.%3&&&&&8 F &/22>%.$3>2$&.20$&&&&&&&&RG = &/2222%&0%3.%$%.>&&&&&&&&
Densit# $s. Temperature
Densit# %in g&'m()
Temperature%indeg*)
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Temp A;solute 4iscosity Hinematic 4iscosity
Centipoises Poise Density "g-cm.# Centistoes SSU )tG-sec
.$ (/>2 &/&(>2 &/2223 (/>2 .. (/2.E?&&%
%& (/.( &/&(.( &/222> (/.( .(/7 (/0(E?&&%
7& (/($ &/&(($ &/222 (/($ .(/$ (/$$E?&&%
>& &/23 &/&&23 &/22>2> &/23 .&/2 (/&7E?&&%
3& &/37 &/&&37 &/2277 &/37 .&/7 2/.&E?&&7
3% &/3( &/&&3( &/22%3 &/3( .&/0 3/72E?&&7
(&& &/73 &/&&73 &/22. &/72 .&/$ >/.2E?&&7
($& &/%7 &/&&%7 &/233% &/%> .& 7/&2E?&&7
(0& &/0> &/&&0> &/23.$ &/03 $2/> %/(0E?&&7(7& &/0 &/&&0 &/2>>( &/0( $2/7 0/0$E?&&7
(3& &/.% &/&&.% &/2>&0 &/.7 $2/% ./3%E?&&7
$($ &/$3 &/&&$3 &/2%3.7 &/$2 $2/. ./(2E?&&7
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+,-+t tur;ulence )actor )=(/$9tur;ulence )actor
$& (/0% (/>0
(% (/.> (/70
(& (/$> (/%$
7 (/(0 (/.>
. (/&> (/$3
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)"8# = ? $/(.%2>2.0>2&0(0E?&&%8. F 2/37$(.7$>%(&RG = &/223(3$&$.3)"8# = ? &/&&&&$(.%2>2.0>2&0(08. F &/&&&&237$(.RG = &/223(3$&$.3&3$7.&&&&
)
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($h&$t
tur!ulen'
ea
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(..E?&&%8$ F &/&.020&..%38 F (/(>(.7&$%3$$>%(&(..8$ F &/&.020&..%3&>3(&%&&&8 F (/(>(.7&$%3$.%>&&&&&
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& %& (&& (%& $&& $%&
&
&/&&$
&/&&0
&/&&7
&/&&3
&/&(
&/&($
&/&(0
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)"8# = &/&&&&&&&&&&.(033.&(7..20.38E0 ? &/&&&&&&&(23.%2$>(737$$$&&&8E. F &/&&&&&0>3%3032>%$3%.&&&&&&8E$ ? &/&&&%%>22&7&73%.&%0&&&&&&&8 F &/&.(0(0%202($072>&&&&&&&&&
RG = &/222>3%30$%2(>7.&&&&&&&&&&
+is'osit# $s. temperature
Temperature %deg *)
+is'osit#%inpoise)