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AP Notes Chapter 11Properties Of Gases
TemperatureTemperature An indirect measure of the An indirect measure of the
average kinetic energy of a average kinetic energy of a collection of particlescollection of particles
KEKEavgavg = kT = kT
BoltzmanBoltzman Plot Plot
PressurePressureMeasure of the number of Measure of the number of
collisions between gas collisions between gas particles and a unit area of particles and a unit area of
the wall of the containerthe wall of the container
Pressure = force / unit areaPressure = force / unit area
Force/areaForce/area
English system:English system:
pounds/inpounds/in22 (psi) (psi)
Metric system:Metric system:
Newton/mNewton/m22 (pascal) (pascal)
Torricelli Barometer
h = 760 mm Hg1 atmospherepressure
1 atm = 760 torr (mm Hg)
= 101.325 kPa
= 1.01325 bar
=14.70 psi
Manometer
Pgas
Patm
h
Manometer
Pgas
Patm
h
VolumeVolume
Total space of a container that Total space of a container that gases occupy due to the free gases occupy due to the free
random motion of the gas random motion of the gas moleculesmolecules
Relationship between Volume & Pressure of
Gases
P-V
V
P (at constant T)
V
1/P (at constant T)
Slope = kP
1 V
P
kV or
b P
1m V
In mathematical terms:y = mx + b
Boyle’s Law
Relationship between Volume & Temperature
of Gases
V-T
In mathematical terms:y = mx + bV = mT + b
Charles’ Law
kTV
Where T must be in Kelvin (K) temperature
K = 0C + 273
Relationship between Pressure &
Temperature of Gases
P-T
In mathematical terms:y = mx + bP = mT + b
Gay-Lussac’s Law
kTP
Relationship between Volume & Moles
of Gases
V-n
In mathematical terms:y = mx + bV = mn + b
Avogadro’s Law
knV
Avogadro’s HypothesisAvogadro’s Hypothesis
At constant temperature and At constant temperature and pressure, equal volumes of pressure, equal volumes of
gases contain equal number gases contain equal number of particlesof particles
3. Hydrogen gas [8.3 liters] reacts in the presence of 2.5 liters of nitrogen gas at 370C and 100 kPa. What volume of ammonia is produced at
these same conditions?
Combined Gas LawCombined Gas Law
constant anT
PV
kn VkT P
kT V P
kV
Ideal & RealGasses
Kinetic Molecular Kinetic Molecular TheoryTheory
1. Gases consist of small 1. Gases consist of small particles that are far apart in particles that are far apart in comparison to their own size. comparison to their own size. These particles are These particles are considered to be tiny points considered to be tiny points occupying a negligible occupying a negligible volume compared to that of volume compared to that of their container. their container.
2. Molecules are in rapid and 2. Molecules are in rapid and random straight-line motion. random straight-line motion. This motion can be This motion can be described by well-defined described by well-defined and established laws of and established laws of motion.motion.
Kinetic Molecular Kinetic Molecular TheoryTheory
3. The collisions of molecules 3. The collisions of molecules with the walls of a container with the walls of a container or with other molecules are or with other molecules are perfectly elastic. That is, no perfectly elastic. That is, no loss of energy occurs.loss of energy occurs.
Kinetic Molecular Kinetic Molecular TheoryTheory
4. There are no attractive 4. There are no attractive forces between molecules or forces between molecules or between molecules and the between molecules and the walls with which they collide.walls with which they collide.
Kinetic Molecular Kinetic Molecular TheoryTheory
5. At any particular instant, the 5. At any particular instant, the molecules in a given sample molecules in a given sample of gas do not all possess the of gas do not all possess the same amount of energy.same amount of energy.
Kinetic Molecular Kinetic Molecular TheoryTheory
Have 1 particle, with mass m, with velocity
PARTICLEIN THE
BOX
A
fP
2
fP
Consider the P exerted:
But: f = ?
But: f = mawhere
time
velocity in change a
Change in velocity = (
t
2a
Thus, the pressure exerted by one particle on a wall is:
21
t2
)m(P
But, ?
But,t
d
and, the distance a particle travels between collisions with the same wall is ?
2t
ort
2
21
t2
)m(P
Substitutinginto
we get:
21
22
)m(
P
Simplifying: 3
2
1
mP
V
mP
V2
1
3
but,
This represents the pressure (P) that
one particle exerts striking opposite walls in the box.
Now assume the box contains N
particles. Then, N/3 particles are
traveling between opposite walls.
Thus, the total pressure on
opposite walls is:
V
m
3
NP
2
2
1
3
2
3
1
Substitute & rearrange
2m2
1
V
N
3
2P
KE3
N2PV
KEm2
1 2
From classical physics
kT2
3KE
where k is theBoltzman constant
0N
Rk
where R = universal gas constant N0 = Avogadro’s number
TN
R
2
3KE
0
TN
R
2
3
3
N2PV
0
nRTPV
Ideal Gas Equation
Kmol
torrL 62.36
Kmol
kPaL 8.314
Kmol
atmL 08206.0R
RnT
PVNote that
is similar to theCombined Gas Lawderived earlier.
CnT
PV
Variations onIdeal Gas Equation
RTMM
massPV
4. What is the molar mass of methylamine if 0.157 g of the gas occupies 125 mL with a pressure of 99.5 kPa at 220C?
Variations onIdeal Gas Equation
RT
MMP
volume
massdensity
RTMM
massPV
Bromine
5. Calculate the 5. Calculate the density of fluorine density of fluorine gas at:gas at:
303000C and 725 torr.C and 725 torr.STPSTP
Real GasBehavior
Ideal Gas Equation
P V = n R T
Idealgas
0 200 400 600 800 1000 P (atm)
PVnRT
0
1.0
2.0
CO2
H2
N2
CH4
“correct” for volume of molecules
(V - b)
also “correct” for attractive forces
between molecules
2V
aP
van der Waals’ Equation
for 1 mole
RTbVV
aP
2
van der Waals’ Equation
for n moles
nRTbnVV
anP
2
2
from CRC Handbook
a* b*He 0.03412 0.02370
Ne 0.2107 0.01709
*when P(atm) & V(L)
from CRC Handbook
a* b*NH3 4.170 0.03707
H2O 5.464 0.03049
*when P(atm) & V(L)
from CRC Handbook
a* b*CCl4 20.39 0.1383
C5H12 19.01 0.1460
*when P(atm) & V(L)
ClCl22 gas has gas has aa = 6.49, = 6.49, bb = 0.0562 = 0.0562
For 8.0 mol ClFor 8.0 mol Cl22 in a 4.0 L tank at 27 in a 4.0 L tank at 27ooC.C. P (ideal) = nRT/V = 49.3 atmP (ideal) = nRT/V = 49.3 atm P (van der Waals) = 29.5 atmP (van der Waals) = 29.5 atm
T & P conditionswhere a real gas
approximatesan ideal gas?
203 K
293 K
673 K
Idealgas
0 200 400 600 800 P (atm)
0.6
1.0
1.4
1.8
PVnRT
N2 gas
T & P conditionswhere a real gas
approximatesan ideal gas?
high temperaturelow pressure
GaseousMolecularMovement
Partial Pressurepressure exerted by
each component in a mixture of gases
this assumes thatNO interactionsoccurs between
the molecules of gas
must concludemust conclude1. each gas acts as if it is 1. each gas acts as if it is
in container alonein container alone
2. each gas collides with 2. each gas collides with the container wall as an the container wall as an “event”“event”
n
1iiT PP
where n = # components
or
PT = P1 + P2 + P3 + ...
Pi V = ni R T
or
PnRT
Vii
thus:
Pn RT
V
n RT
VT 1 2 ...
or
PRTV
n nT 1 2 ...
therefore:
nT = ni
and PT sum of mols of gas
Mole Fraction
Xn
nii
T
1... n
n
n
n
n
n 321
Since:
and
PnRT
Vii
Pn RT
VTT
T
i i
T
i
P
PX
n
n
Then
and
Pi = Xi PT
diffusiondiffusion is the gradual is the gradual mixing of molecules of mixing of molecules of different gasesdifferent gases..
effusioneffusion is the movement is the movement of molecules through a of molecules through a small hole into an empty small hole into an empty containercontainer..
rate of averageeffusion speed
cr
or
r
B
A
B
A
c
c
r
r
B
A
B
A
r
r
But ...
where
MMnmMM
mn
nRT2
3m
2
1KE
2
thus
then
2
1
2
MM
RT3
nRT2
3MMn
2
1
RMS speed
2
1
B
2
1
A
B
A
MMRT3
MMRT3
r
r
substituting:
simplifying
A
B
B
A
MM
MM
r
r
Graham’s LawNH3-HCl
rdt
A
B
A
B
B
A
B
A
MM
MM
t
t
td
td
r
r
if “d” is constant
A
B
B
A
B
A
B
A
MM
MM
d
d
td
td
r
r
if “t” is constant
GAS LAWSTOICHIOMETRY
1. Ethanol, C2H5OH, is often prepared by fermentation of sugars such as glucose, C6H12O6, with carbon dioxide as the other product.
[A] What volume of CO2 is produced from 125 g of glucose if the reaction is 97.5% efficient?
[B] Ethanol can also be made from ethylene, C2H4 according to the following chemical system:
3 C2H4(g) + 2 H2SO4
C2H5HSO4 + (C2H5)2SO4
then
C2H5HSO4 + (C2H5)2SO4 + 3H2O
3C2H5OH + 2 H2SO4
What volume (mL) of 95% ethanol is produced from 142.5 dm3 of C2H4? The density of 95% ethanol is 0.8161 g/mL.
2. What is the final pressure [kPa] if 1000. g uranium reacts with sufficient fluorine gas to produce gaseous uranium hexafluoride at 32oC in a 300. L container?
3. What mass of sodium metal is needed to produce 250 mL of hydrogen gas at 24oC and 740 Torr?