AP ChemistryAP ChemistryChapter 5 JeopardyChapter 5 Jeopardy

Jennie L. BordersJennie L. Borders

Round 1 – Chapter 5 Round 1 – Chapter 5

EnergyEnergy StoichiometryStoichiometry q = mCq = mCTT HH DefinitionsDefinitions CalorimetryCalorimetry

100 100 100 100 100 100

200 200 200 200 200 200

300 300 300 300 300 300

400 400 400 400 400 400

500 500 500 500 500 500

Energy 100Energy 100

Calculate the Calculate the E for a process in E for a process in which the system releases 57.5kJ which the system releases 57.5kJ of heat while doing 22.5kJ of work of heat while doing 22.5kJ of work

on the surroundings. Is the on the surroundings. Is the process endothermic or process endothermic or

exothermic?exothermic?

-80kJ exothermic-80kJ exothermic

Energy 200Energy 200

Calculate the Calculate the E for a process in E for a process in which the system absorbs 105kJ which the system absorbs 105kJ

of heat from its surroundings of heat from its surroundings while doing 29kJ of work on the while doing 29kJ of work on the

surroundings. Is the process surroundings. Is the process exothermic or endothermic?exothermic or endothermic?

76kJ endothermic76kJ endothermic

Energy 300Energy 300If two positive particles are brought If two positive particles are brought

closer together, then explain what closer together, then explain what would happen to the electrostatic would happen to the electrostatic

potential energy and why.potential energy and why.EEelel = = kQkQ11QQ22 If both particles are If both particles are

d positively charged, then Qd positively charged, then Q11

and Qand Q22 are positive making the value of are positive making the value of

EEelel positive. As distance decreases, the positive. As distance decreases, the

magnitude of Emagnitude of Eelel increases, so it is not a increases, so it is not a

favorable process.favorable process.

Energy 400Energy 400

Calculate the kinetic energy in Calculate the kinetic energy in joules of a 45g golf ball moving at joules of a 45g golf ball moving at

61 m/s.61 m/s.

84J84J

Energy 500Energy 500

What is the kinetic energy of an What is the kinetic energy of an 850 lb. motorcycle moving at 66 850 lb. motorcycle moving at 66

mph? (1 kg = 2.2047 lb. mph? (1 kg = 2.2047 lb.

1 mi = 1.6093 km)1 mi = 1.6093 km)

1.7 x 101.7 x 1055JJ

Stoichiometry 100Stoichiometry 100

Calculate the Calculate the H for the production H for the production of 0.200 mol of AgCl by the of 0.200 mol of AgCl by the

following reaction:following reaction:

AgAg++(aq)(aq) + Cl + Cl--(aq)(aq) AgCl AgCl(s) (s)

H = -65.5kJH = -65.5kJ

-13.1kJ-13.1kJ

Stoichiometry 200Stoichiometry 200

For this reaction, For this reaction, H for the H for the formation of 0.632mol of Oformation of 0.632mol of O22..

2KClO2KClO3(s)3(s) 2KCl 2KCl(s)(s) + 3O + 3O2(g)2(g)

H = -89.4kJH = -89.4kJ-18.8kJ-18.8kJ

Stoichiometry 300Stoichiometry 300

Calculate the amount of heat Calculate the amount of heat transferred when 2.4g of Mg transferred when 2.4g of Mg reacts at constant pressure.reacts at constant pressure.

2Mg2Mg(s)(s) + O + O2(g)2(g) 2MgO 2MgO

H = -1204kJH = -1204kJ

-59kJ -59kJ

Stoichiometry 400Stoichiometry 400

Calculate the amount of heat Calculate the amount of heat transferred when 45.0g of CHtransferred when 45.0g of CH33OH OH

is decomposed by the following is decomposed by the following reaction at constant pressure.reaction at constant pressure.

CHCH33OHOH(g)(g) CO CO2(g)2(g) + 2H + 2H2(g)2(g)

H = 90.7kJH = 90.7kJ

128kJ128kJ

Stoichiometry 500Stoichiometry 500

Calculate the amount of heat Calculate the amount of heat transferred for the formation of transferred for the formation of

6.32g O6.32g O22..

CHCH33OHOH(l)(l) + 3/2O + 3/2O2(g)2(g) CO CO2(g)2(g) +2H +2H22OO(l)(l)

H = -726.5kJH = -726.5kJ

95.66kJ95.66kJ

q = mCq = mCT 100T 100Two solid objects, A and B, are placed in Two solid objects, A and B, are placed in

boiling water and allowed to come to boiling water and allowed to come to temperature there. Each is then lifted out temperature there. Each is then lifted out

and placed in separate beakers containing and placed in separate beakers containing 1000g of water at 10.01000g of water at 10.0ooC. Object A C. Object A increases the water temperature by increases the water temperature by

3.503.50ooC; B increases water temperature by C; B increases water temperature by 2.602.60ooC. Which object has the larger heat C. Which object has the larger heat

capacity and what extra piece of capacity and what extra piece of information do you need to figure out information do you need to figure out

which has the higher specific heat which has the higher specific heat capacity?capacity?

Object A; mass of each object.Object A; mass of each object.

q = mCq = mCT 200T 200

How many kJ of heat are needed to How many kJ of heat are needed to raise the temperature of 10.00kg of raise the temperature of 10.00kg of liquid water from 24.6liquid water from 24.6ooC to 46.2C to 46.2ooC?C?

904kJ904kJ

q = mCq = mCT 300T 300

The specific heat of iron metal is The specific heat of iron metal is 0.450 J/gK. How many J of heat 0.450 J/gK. How many J of heat

are necessary to raise the are necessary to raise the temperature of a 1.05kg block of temperature of a 1.05kg block of

iron from 25.0iron from 25.0ooC and 88.5C and 88.5ooC?C?

3.00 x 103.00 x 1044 J J

q = mCq = mCT 400T 400The specific heat of ethylene glycol The specific heat of ethylene glycol

is 2.42 J/gK. How many J of heat is 2.42 J/gK. How many J of heat are needed to raise the are needed to raise the

temperature of 62.0g of ethylene temperature of 62.0g of ethylene glycol from 13.1glycol from 13.1ooC to 40.5C to 40.5ooC?C?

4.11 x 104.11 x 103 3 JJ

q = mCq = mCT 500T 500

What is the molar heat capacity of What is the molar heat capacity of water?water?

75.31 J/mol75.31 J/molooCC

H 100H 100

Calculate the Calculate the H for 3HH for 3H2(g) 2(g) + O+ O3(g)3(g)

3H3H22OO(g)(g) using the following using the following

information:information:

2H2H2(g)2(g) + O + O2(g)2(g) 2H 2H22OO(g)(g) H = -483.6 kJH = -483.6 kJ

3O3O2(g)2(g) 2O 2O3(g)3(g) H = 284.6 kJH = 284.6 kJ

-867.7kJ-867.7kJ

H 200H 200

Calculate the Calculate the H for CH for C22HH4(g)4(g) + 6F + 6F2(g)2(g)

2CF2CF4(g)4(g) + 4HF + 4HF(g)(g) using the following using the following

information:information:

HH2(g)2(g) + F + F2(g) 2(g) 2HF 2HF(g)(g) H = -537kJH = -537kJ

CC(s)(s) + 2F + 2F2(g)2(g) CF CF4(g) 4(g) H = -680kJH = -680kJ

2C2C(s)(s) + 2H + 2H2(g) 2(g) C C22HH4(g)4(g) H = 523kJH = 523kJ -2486.3kJ-2486.3kJ

H 300H 300Calculate the Calculate the H for NH for N22OO(g)(g) + NO + NO2(g)2(g)

3NO3NO(g)(g) using the following information: using the following information:

NN2(g)2(g) + O + O2(g)2(g) 2NO 2NO(g)(g) H = 180.7kJH = 180.7kJ

2NO2NO(g)(g) + O + O2(g)2(g) 2NO 2NO2(g)2(g) H = -113.1kJH = -113.1kJ

2N2N22OO(g)(g) 2N 2N2(g)2(g) + O + O2(g)2(g) H = -163.2kJ H = -163.2kJ 155.65kJ155.65kJ

H 400H 400

Calculate the Calculate the H for the following H for the following reaction using information from reaction using information from

Appendix C.Appendix C.

SiClSiCl4(l)4(l) + 2H + 2H22OO(l)(l) SiO SiO2(s) 2(s) + 4HCl+ 4HCl(g)(g)

-68.34kJ-68.34kJ

H 500H 500

When CWhen C1010HH8(s)8(s) is combusted it yields is combusted it yields

COCO2(g)2(g), H, H22OO(l)(l), and 5154 kJ/mol. What , and 5154 kJ/mol. What

is the standard enthalpy of formation is the standard enthalpy of formation for Cfor C1010HH88..

COCO2(g) 2(g) HHffoo = -393.5 kJ/mol = -393.5 kJ/mol

HH22OO(l) (l) HHffoo = -285.83 kJ/mol = -285.83 kJ/mol75.68kJ75.68kJ

Definitions 100Definitions 100

What is the internal energy of a What is the internal energy of a system?system?

Total kinetic and potential Total kinetic and potential energyenergy

Definitions 200Definitions 200

What is a closed system?What is a closed system?

A system in which heat can be A system in which heat can be transferred between the system transferred between the system

and the surroundings but not and the surroundings but not mass.mass.

Definitions 300Definitions 300

What is a state function?What is a state function?

A property that only depends on A property that only depends on the initial and final states, not on the initial and final states, not on

the path taken.the path taken.

Definitions 400Definitions 400

For a given process at constant For a given process at constant pressure, pressure, H is negative. Is the H is negative. Is the

process exothermic or endothermic?process exothermic or endothermic?

exothermicexothermic

Definitions 500Definitions 500

By what means can the internal By what means can the internal energy of a closed system energy of a closed system

increase?increase?

Increase in heat of the system or Increase in heat of the system or work done on the system.work done on the system.

Calorimetry 100Calorimetry 100A 2.200g sample of CA 2.200g sample of C66HH44OO22 is burned is burned

in a bomb calorimeter whose total in a bomb calorimeter whose total heat capacity is 7.854 kJ/heat capacity is 7.854 kJ/ooC. The C. The

temperature of the calorimeter temperature of the calorimeter increases from 23.44increases from 23.44ooC to C to

30.5730.57ooC. What is the heat of C. What is the heat of combustion per mole of Ccombustion per mole of C66HH44OO22??

-2740.2 kJ/mol-2740.2 kJ/mol

Calorimetry 200Calorimetry 200A 1.800g sample of CA 1.800g sample of C66HH55OH was OH was

burned in a bomb calorimeter burned in a bomb calorimeter whose total heat capacity is whose total heat capacity is

11.66kJ/11.66kJ/ooC. The temperature of C. The temperature of the calorimeter plus contents the calorimeter plus contents

increased from 21.36increased from 21.36ooC to C to 26.3726.37ooC. What is the heat of C. What is the heat of

combustion per mole of Ccombustion per mole of C66HH55OH?OH?-3074.74kJ-3074.74kJ

Calorimetry 300Calorimetry 300A 2.500g sample of glucose is burned A 2.500g sample of glucose is burned

in a bomb calorimeter. The heat of in a bomb calorimeter. The heat of combustion of glucose is -combustion of glucose is -

15.57kJ/mol. The temperature of 15.57kJ/mol. The temperature of the calorimeter increases from the calorimeter increases from

20.5520.55ooC to 23.25C to 23.25ooC. What is the C. What is the total heat capacity of the total heat capacity of the

calorimeter?calorimeter?14.42 kJ/14.42 kJ/ooCC

Calorimetry 400Calorimetry 400

What a 9.55g sample of solid NaOH What a 9.55g sample of solid NaOH dissolves in 100.0g of water in a dissolves in 100.0g of water in a

coffee-cup calorimeter, the coffee-cup calorimeter, the temperature rises from 23.6temperature rises from 23.6ooC to C to 47.447.4ooC. Calculate C. Calculate H in kJ/mol of H in kJ/mol of NaOH for the solution process.NaOH for the solution process.

-45.61 kJ/mol-45.61 kJ/mol

Calorimetry 500Calorimetry 500When a 3.88g sample of solid When a 3.88g sample of solid

NHNH44NONO33 dissolves in 60.0g of dissolves in 60.0g of

water in a coffee-cup calorimeter, water in a coffee-cup calorimeter, the temperature drops from 23.0the temperature drops from 23.0ooC C to 18.4to 18.4ooC. Calculate C. Calculate H in kJ/mol H in kJ/mol

of NHof NH44NONO33 for the solution for the solution

process.process.25.36 kJ/mol25.36 kJ/mol