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CW/HWAssignments2. Ch.3NotesPartA10/113. Ch.3packet10/11
PLANNER • LabsmustbeturnedinbyMondaymorning• Study–Ch.3&5
Essentialknowledgestandards• [SPQ-1.A.1]Onecannotcountparticlesdirectlywhileperforminglaboratorywork.Thus,
theremustbeaconnectionbetweenthemassesofsubstancesreactingandtheactualnumberofparticlesundergoingchemicalchanges.
• [SPQ-1.A.2:Avogadro’snumberprovidestheconnectionbetweenthenumberofmolesinapuresampleofasubstanceandthenumberofconstituentparticles(orformulaunits)ofthatsubstance.
• [SPQ-1.A.3]:Expressingthemassofanindividualatomormoleculeinamuisusefulbecausetheaveragemassinamuofoneparticleorformulaunitofasubstancewillalwaysbenumericallyequaltothemolarmassofthatsubstanceingrams.Thus,thereisaquantitativeconnectionbetweenthemassofasubstanceandthemumberofparticlesthatthesubstancecontains(n=m/M)
• [SPQ-2.A.3]:Thechemicalformulathatliststhelowestwholenumberratioofatomsoftheelementsinacompoundistheempiricalformula
• [SPQ-2.B.1]:Whilepuresubstancescontainmoleculesorformulaunitsofasingletype,mixturescontainmoleculesorformulaunitsoftwoormoretypes,whoserelativeproportionscanvary.
• [TRA-1.B.1]:Allphysicalandchemicalprocessescanberepresentedsymbolicallybybalancedequations.
• [SPQ-4.A.2]:Coefficientsofbalancedchemicalequationscontaininformationregardingtheproportionalityoftheamountsofsubstancesinvolvedinthereaction.Thesevaluescanbeusedinchemicalcalculationsinvolvingthemoleconcept.
FLT• Iwillbeableto:– Calculatethequantitiesofasubstanceoritsrelativenumberofparticlesusingdimensionalanalysisandthemoleconcept
– Explainthequantitativerelationshipbetweenthemassspectrumofanelementandthemassesoftheelement’sisotopes
– Explainthequantitativerelationshipbetweentheelementalcompositionbymassandthecompositionofsubstancesinamixture
– Explainthechangesintheamountsofreactantsandproductsbasedonthebalancedchemicalequationforachemicalprocess
• BycompletingCh.3Notes
Ch.3:Stoichiometry
ChemicalQuantitiesReview
Recall: Units • Whatareourunitsfor…
– Mass?• Grams!
– Volume?• Liters!
– Amount?• Moles!
What is the mole?
We’re not talking about this kind of mole!
The Mole § Mole (mol) = amount = defined as
the # of carbon atoms in exactly 12 g of carbon-12.
Moles (is abbreviated: mol) § 1 mole = 6.022 x
1023 particles or atoms or molecules
§ Avogadro’s Number = 6.022 x 1023
Similar Words for an amount § Just like a dozen is 12, or a pair is
two, a mole is an amount. § One dozen eggs = 12 eggs § One mole of eggs = 6.022 x 1023
eggs
Figure3.4-One-MoleSamplesofSeveralElements
Table3.1-Comparisonof1MoleSamplesofVariousElements
Moles (is abbreviated: mol) § Writing conversions: mol à
particles
6.022x1023particles
6.022x1023molecules1mol
1mol
Ex/ § How many moles of water is 5.87
x 1022 molecules?
SampleQuestion• Whichofthefollowingisthemostaccuratedescriptionofamole?a. Massofcarboninameasuredsampleofcarbonb. Numberofatomsinanygivenmassofanelementc. Numberofsodiumionsin58.44gofsodiumchlorided. Atleasttwooftheseareaccuratedescriptionsofa
mole
SampleQuestion• Whichofthefollowingisclosesttotheaveragemassofoneatomofcopper?a. 63.55gb. 52.00gc. 58.93gd. 65.38ge. 1.055×10–22g
MolarMass
Atomic & Molar Mass § Molar mass = Mass of 1 mole (g/mol) § Allows us to convert from mol ßà g § Ex/ Molar mass of Carbon
1molC
12.01gC
MolarMassforFormulas
Calculating Formula Mass
Calculate the formula mass of magnesium carbonate, MgCO3.
24.3 g + 12 g + 3 x (16.00 g) = 84.3 g
Thus, 84.3 grams is the formula mass for MgCO3.
MolarMass• Example• Calciumcarbonate(CaCO3),alsocalledcalcite,istheprincipalmineralfoundinlimestone,marble,chalk,pearls,andtheshellsofmarineanimalssuchasclamsa. Calculatethemolarmassofcalciumcarbonateb. Acertainsampleofcalciumcarbonatecontains4.86
moles• Whatisthemassingramsofthissample?• WhatisthemassoftheCO32–ionspresent?
MolarMass• Solution(a)
• Thus,themassof1moleofCaCO3(1moleofCa2+plus1moleofCO32-)is100.09g
• Thisisthemolarmass
MolarMass• Solution(b)• Massof1moleofCaCO3is100.09g
– Samplecontainsnearly5moles,orcloseto500g– Exactamountisdeterminedasfollows:
• Tofindthemassofcarbonateions(CO32–)presentinthissample,realizethat4.86molesofCaCO3contains4.86molesofCa2+ionsand4.86molesofCO32–ions
MolarMass• Solution(b)
MolarMass• Trythis:• Calculatethemolarmassofthefollowingsubstances:
MolarMass• Trythis:• Whatnumberofnitrogenatomsarepresentin1.00gofeachofthefollowingcompounds?
SampleQuestion• Whichofthefollowing100.0-gsamplescontainsthegreatestnumberofatoms?a. Magnesiumb. Zincc. Silverd. Calciume. Allsamplescontainthesamenumberofatoms
SampleQuestion• Forwhichofthefollowingcompoundsdoes1.0grepresent2.27×10–2mol?a. H2Ob. CO2c. NH3d. C2H6
SampleQuestion• Massof0.82molofadiatomicmoleculeis131.3g
– Identifythemoleculea. F2b. Cl2c. Br2d. I2
SampleQuestion• Whichofthefollowing100.0-gsamplescontainsthegreatestnumberofoxygenatoms?a. H2Ob. N2Oc. C3H6O2d. CO2e. Allofthesampleshavethesamenumberofoxygen
atoms
Recall
MassSpectrometer• Helpstoaccuratelycomparethemassesofatoms
MassSpectrometer• Helpsdetermineaccuratemassvaluesforindividualatoms
• Determinestheisotopiccompositionofnaturalelements
AverageAtomicMass• Knownasatomicweight(asperIUPAC’sdeclaration),whichisdimensionlessbycustom– IUPAC-InternationalUnionofPureandAppliedChemistry
• Sinceelementsoccurinnatureasmixturesofisotopes,atomicmassesareusuallyaveragevalues
SampleQuestion• Ex/TheatomicnumberofIndiumis49anditsatomicmass114.8g– Naturallyoccurringindiumcontainsamixtureofindium-112andindium-115,respectively,inanatomicratioofapproximately:
a. 6:94b. 25:75c. 50:50d. 75:25e. 94:6
SampleQuestion• Ex/Youhaveasampleofzinc(Zn)andasampleofaluminum(Al)– Eachsamplecontainsthesamenumberofatoms– Whichofthefollowingstatementsconcerningthemassesofthesamplesistrue?a. Massofthezincsampleismorethantwiceasgreatasthe
massofthealuminumsampleb. Massofthezincsampleismorethanthemassofthe
aluminumsample,butitisnottwiceasgreatc. Massofthealuminumsampleismorethantwiceasgreatas
themassofthezincsampled. Massofthealuminumsampleismorethanthemassofthe
zincsample,butitisnottwiceasgreate. Massesofthetwosamplesareequal
PercentComposition
PercentComposition• WaystoDescribeaCompound’sComposition:• Intermsofthenumbersofthecompound’sconstituentatoms
• Intermsofmasspercent(weightpercent)
PercentComposition• Ex/CalculatingMassPercent• Carvoneisasubstancethatoccursintwoformshavingdifferentarrangementsoftheatomsbutthesamemolecularformula(C10H14O)andmass– Onetypeofcarvonegivescarawayseedstheircharacteristicsmell,andtheothertypeisresponsibleforthesmellofspearmintoil
• Computethemasspercentofeachelementincarvone
PercentComposition• Ex/CalculatingMassPercent-Solution• Wherearewegoing?
– Tofindthemasspercentofeachelementincarvone– Whatdoweknow?
• MolecularformulaisC10H14O– Whatinformationdoweneedtofindthemasspercent?
• Massofeachelement(we’lluse1moleofcarvone)• Molarmassofcarvone
PercentComposition• Ex/CalculatingMassPercent-Solution• Howdowegetthere?
– Determinethemassofeachelementin1moleofC10H14O
PercentComposition• Ex/CalculatingMassPercent-Solution
– WhatisthemolarmassofC10H14O?
– Whatisthemasspercentofeachelement?• Findthefractionofthetotalmasscontributedbyeachelementandconvertittoapercentage
PercentComposition• Ex/CalculatingMassPercent-Solution
• Realitycheck– Individualmasspercentvaluesshouldtotalto100%withinround-offerrors
• Inthiscase,percentagesaddupto100%
PercentComposition• TryThese:• Calculatethepercentcompositionbymassofthefollowingcompoundsthatareimportantstartingmaterialsforsyntheticpolymers:a. C3H4O2(acrylicacid,fromwhichacrylicplasticsare
made)b. C4H6O2(methylacrylate,fromwhichPlexiglasismade)
SampleProblem• Whichofthefollowing100.0-gsamplescontainsthehighestpercentoxygenbymass?a. H2Ob. N2Oc. C3H6O2d. CO2e. Allofthesampleshavethesamepercentoxygenby
mass
Mole–VolumeRelationship
Mole-Volume Relationship § Volume may be affected by
§ (1) Temperature § (2) Pressure
§ Consequently, we need to compare gases at a constant temperature and pressure for consistency
Mole-Volume Relationship § Standard
Temperature and Pressure (STP): § 1 atm of
pressure and 273 K (0°C)
Mole-Volume Relationship § Molar Volume:
§ At STP, 1 mole of any gas occupies a volume of 22.4 L
1mol
22.4L
22.4L
1mol
SampleProblems
Example § What is the volume of 4.59 mole of
CO2 gas at STP?
Recall § Density = mass/volume (g/L)
Example § The density of a gas is 1.964 g/L
at STP. What is the molar mass of the gas?
CHEMICALEQSREVIEW
Chemical Equations • Chemical Equation = Shorthand for a
chemical rxn using formulas and symbols
Chemical Equations
• There are two parts to a reaction: 1. Reactants = substances you start
with 2. Products = substances you end up
with
Symbols • à = “yields” or “reacts to form”
Reactants à Products
Symbols • + = “and”
Cu + Cl2 à CuCl2
Symbols • States of matter = indicated with
subscripts (s), (l), (g), or (aq)
2H2(g) + O2(g) à 2H2O(l)
Symbols • aq = aqueous = dissolved in water
NaCl(aq) à Na+ + Cl-
Symbols • Double arrow = reversible rxn
Symbols • Others: Heat (Δ), energy, and
catalysts can be indicated on arrows
Symbols • A catalyst is a substance that is
added to speed up a reaction, but is not used or consumed by the reaction
WritingEquations
Writing Equations • Ex 1/ Bromine and potassium iodide
react to form potassium bromide and iodine
***NOTE*** • Diatomic gases =
H, N, O, F, Cl, Br, I • Write as diatomic if
they are by themselves in a chemical equation
Writing Equations • Ex 2/ Iron and oxygen react to form
iron (III) oxide
Now, read these equations:
Fe(s)+O2(g)→Fe2O3(s)
Cu(s)+AgNO3(aq)→Ag(s)+Cu(NO3)2(aq)
NO2(g)N2(g)+O2(g)→
ConservationofMass
Law of Conservation of Mass • Law of Conservation of Mass =
mass in a closed system can neither be created nor destroyed
Law of Conservation of Mass • What does this mean for us?
– In a balanced chemical equation, the number and kinds of atoms on each side of the equation should be equal.
Law of Conservation of Mass
Balancing Equations • A balanced equation has the same
number of each element on both sides of the equation
Balancing Equations • We use coefficients to indicate
multiples of molecules or compounds
Balancing Equations • Coefficients are multiples of the
entire formula • How does this affect each atom?
Rules 1. Write out correct formulas (if not
already written) Ex/ Li + H3PO4 à H2 + Li3PO4
Rules 2. Count the number of atoms of each type on both sides
– If possible, keep polyatomic ions together
Ex/ Li + H3PO4 à H2 + Li3PO4
Rules 3. Balance the elements one at a time by adding coefficients in front.
à Generally, balance H, O, & monatomic atoms last
Ex/ Li + H3PO4 à H2 + Li3PO4
Rules 4. Double-check – always Ex/ Li + H3PO4 à H2 + Li3PO4
Rules Never’s: • Never add or change subscripts on
formulas • Never put a coefficient in the middle of a
formula
Try These: 1. AgNO3+Cu→Cu(NO3)2+Ag
2. CH4+O2→CO2+H2O
3. C3H8 + O2 à H2O + CO2