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CW/HW Assignments 2. Ch. 3 Notes Part A 10/11 3. Ch. 3 packet 10/11 PLANNER Labs must be turned in by Monday morning Study – Ch. 3 & 5

AP Chem Week 7 Ch 3 2019 · 2019. 10. 10. · 3 is 100.09 g – Sample contains nearly 5 moles, or close to 500 g – Exact amount is determined as follows: • 2–To find the mass

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  • CW/HWAssignments2.  Ch.3NotesPartA10/113.  Ch.3packet10/11

    PLANNER •  LabsmustbeturnedinbyMondaymorning•  Study–Ch.3&5

  • Essentialknowledgestandards•  [SPQ-1.A.1]Onecannotcountparticlesdirectlywhileperforminglaboratorywork.Thus,

    theremustbeaconnectionbetweenthemassesofsubstancesreactingandtheactualnumberofparticlesundergoingchemicalchanges.

    •  [SPQ-1.A.2:Avogadro’snumberprovidestheconnectionbetweenthenumberofmolesinapuresampleofasubstanceandthenumberofconstituentparticles(orformulaunits)ofthatsubstance.

    •  [SPQ-1.A.3]:Expressingthemassofanindividualatomormoleculeinamuisusefulbecausetheaveragemassinamuofoneparticleorformulaunitofasubstancewillalwaysbenumericallyequaltothemolarmassofthatsubstanceingrams.Thus,thereisaquantitativeconnectionbetweenthemassofasubstanceandthemumberofparticlesthatthesubstancecontains(n=m/M)

    •  [SPQ-2.A.3]:Thechemicalformulathatliststhelowestwholenumberratioofatomsoftheelementsinacompoundistheempiricalformula

    •  [SPQ-2.B.1]:Whilepuresubstancescontainmoleculesorformulaunitsofasingletype,mixturescontainmoleculesorformulaunitsoftwoormoretypes,whoserelativeproportionscanvary.

    •  [TRA-1.B.1]:Allphysicalandchemicalprocessescanberepresentedsymbolicallybybalancedequations.

    •  [SPQ-4.A.2]:Coefficientsofbalancedchemicalequationscontaininformationregardingtheproportionalityoftheamountsofsubstancesinvolvedinthereaction.Thesevaluescanbeusedinchemicalcalculationsinvolvingthemoleconcept.

  • FLT•  Iwillbeableto:– Calculatethequantitiesofasubstanceoritsrelativenumberofparticlesusingdimensionalanalysisandthemoleconcept

    – Explainthequantitativerelationshipbetweenthemassspectrumofanelementandthemassesoftheelement’sisotopes

    – Explainthequantitativerelationshipbetweentheelementalcompositionbymassandthecompositionofsubstancesinamixture

    – Explainthechangesintheamountsofreactantsandproductsbasedonthebalancedchemicalequationforachemicalprocess

    •  BycompletingCh.3Notes

  • Ch.3:Stoichiometry

  • ChemicalQuantitiesReview

  • Recall: Units • Whatareourunitsfor…

    – Mass?• Grams!

    – Volume?• Liters!

    – Amount?• Moles!

  • What is the mole?

    We’re not talking about this kind of mole!

  • The Mole § Mole (mol) = amount = defined as

    the # of carbon atoms in exactly 12 g of carbon-12.

  • Moles (is abbreviated: mol) § 1 mole = 6.022 x

    1023 particles or atoms or molecules

    § Avogadro’s Number = 6.022 x 1023

  • Similar Words for an amount §  Just like a dozen is 12, or a pair is

    two, a mole is an amount. §  One dozen eggs = 12 eggs §  One mole of eggs = 6.022 x 1023

    eggs

  • Figure3.4-One-MoleSamplesofSeveralElements

  • Table3.1-Comparisonof1MoleSamplesofVariousElements

  • Moles (is abbreviated: mol) § Writing conversions: mol à

    particles

    6.022x1023particles

    6.022x1023molecules1mol

    1mol

  • Ex/ § How many moles of water is 5.87

    x 1022 molecules?

  • SampleQuestion•  Whichofthefollowingisthemostaccuratedescriptionofamole?a.  Massofcarboninameasuredsampleofcarbonb.  Numberofatomsinanygivenmassofanelementc.  Numberofsodiumionsin58.44gofsodiumchlorided.  Atleasttwooftheseareaccuratedescriptionsofa

    mole

  • SampleQuestion•  Whichofthefollowingisclosesttotheaveragemassofoneatomofcopper?a.  63.55gb.  52.00gc.  58.93gd.  65.38ge.  1.055×10–22g

  • MolarMass

  • Atomic & Molar Mass § Molar mass = Mass of 1 mole (g/mol) § Allows us to convert from mol ßà g § Ex/ Molar mass of Carbon

    1molC

    12.01gC

  • MolarMassforFormulas

  • Calculating Formula Mass

    Calculate the formula mass of magnesium carbonate, MgCO3.

    24.3 g + 12 g + 3 x (16.00 g) = 84.3 g

    Thus, 84.3 grams is the formula mass for MgCO3.

  • MolarMass•  Example•  Calciumcarbonate(CaCO3),alsocalledcalcite,istheprincipalmineralfoundinlimestone,marble,chalk,pearls,andtheshellsofmarineanimalssuchasclamsa.  Calculatethemolarmassofcalciumcarbonateb.  Acertainsampleofcalciumcarbonatecontains4.86

    moles•  Whatisthemassingramsofthissample?•  WhatisthemassoftheCO32–ionspresent?

  • MolarMass•  Solution(a)

    •  Thus,themassof1moleofCaCO3(1moleofCa2+plus1moleofCO32-)is100.09g

    •  Thisisthemolarmass

  • MolarMass•  Solution(b)•  Massof1moleofCaCO3is100.09g

    – Samplecontainsnearly5moles,orcloseto500g– Exactamountisdeterminedasfollows:

    •  Tofindthemassofcarbonateions(CO32–)presentinthissample,realizethat4.86molesofCaCO3contains4.86molesofCa2+ionsand4.86molesofCO32–ions

  • MolarMass•  Solution(b)

  • MolarMass•  Trythis:•  Calculatethemolarmassofthefollowingsubstances:

  • MolarMass•  Trythis:•  Whatnumberofnitrogenatomsarepresentin1.00gofeachofthefollowingcompounds?

  • SampleQuestion•  Whichofthefollowing100.0-gsamplescontainsthegreatestnumberofatoms?a.  Magnesiumb.  Zincc.  Silverd.  Calciume.  Allsamplescontainthesamenumberofatoms

  • SampleQuestion•  Forwhichofthefollowingcompoundsdoes1.0grepresent2.27×10–2mol?a.  H2Ob.  CO2c.  NH3d.  C2H6

  • SampleQuestion•  Massof0.82molofadiatomicmoleculeis131.3g

    –  Identifythemoleculea.  F2b.  Cl2c.  Br2d.  I2

  • SampleQuestion•  Whichofthefollowing100.0-gsamplescontainsthegreatestnumberofoxygenatoms?a.  H2Ob.  N2Oc.  C3H6O2d.  CO2e.  Allofthesampleshavethesamenumberofoxygen

    atoms

  • Recall

  • MassSpectrometer•  Helpstoaccuratelycomparethemassesofatoms

  • MassSpectrometer•  Helpsdetermineaccuratemassvaluesforindividualatoms

    •  Determinestheisotopiccompositionofnaturalelements

  • AverageAtomicMass•  Knownasatomicweight(asperIUPAC’sdeclaration),whichisdimensionlessbycustom–  IUPAC-InternationalUnionofPureandAppliedChemistry

    •  Sinceelementsoccurinnatureasmixturesofisotopes,atomicmassesareusuallyaveragevalues

  • SampleQuestion•  Ex/TheatomicnumberofIndiumis49anditsatomicmass114.8g– Naturallyoccurringindiumcontainsamixtureofindium-112andindium-115,respectively,inanatomicratioofapproximately:

    a.  6:94b.  25:75c.  50:50d.  75:25e.  94:6

  • SampleQuestion•  Ex/Youhaveasampleofzinc(Zn)andasampleofaluminum(Al)– Eachsamplecontainsthesamenumberofatoms– Whichofthefollowingstatementsconcerningthemassesofthesamplesistrue?a.  Massofthezincsampleismorethantwiceasgreatasthe

    massofthealuminumsampleb.  Massofthezincsampleismorethanthemassofthe

    aluminumsample,butitisnottwiceasgreatc.  Massofthealuminumsampleismorethantwiceasgreatas

    themassofthezincsampled.  Massofthealuminumsampleismorethanthemassofthe

    zincsample,butitisnottwiceasgreate.  Massesofthetwosamplesareequal

  • PercentComposition

  • PercentComposition•  WaystoDescribeaCompound’sComposition:•  Intermsofthenumbersofthecompound’sconstituentatoms

    •  Intermsofmasspercent(weightpercent)

  • PercentComposition•  Ex/CalculatingMassPercent•  Carvoneisasubstancethatoccursintwoformshavingdifferentarrangementsoftheatomsbutthesamemolecularformula(C10H14O)andmass– Onetypeofcarvonegivescarawayseedstheircharacteristicsmell,andtheothertypeisresponsibleforthesmellofspearmintoil

    •  Computethemasspercentofeachelementincarvone

  • PercentComposition•  Ex/CalculatingMassPercent-Solution•  Wherearewegoing?

    – Tofindthemasspercentofeachelementincarvone– Whatdoweknow?

    •  MolecularformulaisC10H14O– Whatinformationdoweneedtofindthemasspercent?

    •  Massofeachelement(we’lluse1moleofcarvone)•  Molarmassofcarvone

  • PercentComposition•  Ex/CalculatingMassPercent-Solution•  Howdowegetthere?

    – Determinethemassofeachelementin1moleofC10H14O

  • PercentComposition•  Ex/CalculatingMassPercent-Solution

    – WhatisthemolarmassofC10H14O?

    – Whatisthemasspercentofeachelement?•  Findthefractionofthetotalmasscontributedbyeachelementandconvertittoapercentage

  • PercentComposition•  Ex/CalculatingMassPercent-Solution

    •  Realitycheck–  Individualmasspercentvaluesshouldtotalto100%withinround-offerrors

    •  Inthiscase,percentagesaddupto100%

  • PercentComposition•  TryThese:•  Calculatethepercentcompositionbymassofthefollowingcompoundsthatareimportantstartingmaterialsforsyntheticpolymers:a.  C3H4O2(acrylicacid,fromwhichacrylicplasticsare

    made)b.  C4H6O2(methylacrylate,fromwhichPlexiglasismade)

  • SampleProblem•  Whichofthefollowing100.0-gsamplescontainsthehighestpercentoxygenbymass?a.  H2Ob.  N2Oc.  C3H6O2d.  CO2e.  Allofthesampleshavethesamepercentoxygenby

    mass

  • Mole–VolumeRelationship

  • Mole-Volume Relationship § Volume may be affected by

    § (1) Temperature § (2) Pressure

    § Consequently, we need to compare gases at a constant temperature and pressure for consistency

  • Mole-Volume Relationship § Standard

    Temperature and Pressure (STP): § 1 atm of

    pressure and 273 K (0°C)

  • Mole-Volume Relationship § Molar Volume:

    § At STP, 1 mole of any gas occupies a volume of 22.4 L

    1mol

    22.4L

    22.4L

    1mol

  • SampleProblems

  • Example § What is the volume of 4.59 mole of

    CO2 gas at STP?

  • Recall § Density = mass/volume (g/L)

  • Example § The density of a gas is 1.964 g/L

    at STP. What is the molar mass of the gas?

  • CHEMICALEQSREVIEW

  • Chemical Equations • Chemical Equation = Shorthand for a

    chemical rxn using formulas and symbols

  • Chemical Equations

    •  There are two parts to a reaction: 1.  Reactants = substances you start

    with 2.  Products = substances you end up

    with

  • Symbols • à = “yields” or “reacts to form”

    Reactants à Products

  • Symbols •  + = “and”

    Cu + Cl2 à CuCl2

  • Symbols • States of matter = indicated with

    subscripts (s), (l), (g), or (aq)

    2H2(g) + O2(g) à 2H2O(l)

  • Symbols •  aq = aqueous = dissolved in water

    NaCl(aq) à Na+ + Cl-

  • Symbols • Double arrow = reversible rxn

  • Symbols • Others: Heat (Δ), energy, and

    catalysts can be indicated on arrows

  • Symbols • A catalyst is a substance that is

    added to speed up a reaction, but is not used or consumed by the reaction

  • WritingEquations

  • Writing Equations • Ex 1/ Bromine and potassium iodide

    react to form potassium bromide and iodine

  • ***NOTE*** • Diatomic gases =

    H, N, O, F, Cl, Br, I • Write as diatomic if

    they are by themselves in a chemical equation

  • Writing Equations • Ex 2/ Iron and oxygen react to form

    iron (III) oxide

  • Now, read these equations:

    Fe(s)+O2(g)→Fe2O3(s)

    Cu(s)+AgNO3(aq)→Ag(s)+Cu(NO3)2(aq)

    NO2(g)N2(g)+O2(g)→

  • ConservationofMass

  • Law of Conservation of Mass •  Law of Conservation of Mass =

    mass in a closed system can neither be created nor destroyed

  • Law of Conservation of Mass • What does this mean for us?

    – In a balanced chemical equation, the number and kinds of atoms on each side of the equation should be equal.

  • Law of Conservation of Mass

  • Balancing Equations • A balanced equation has the same

    number of each element on both sides of the equation

  • Balancing Equations • We use coefficients to indicate

    multiples of molecules or compounds

  • Balancing Equations • Coefficients are multiples of the

    entire formula • How does this affect each atom?

  • Rules 1.  Write out correct formulas (if not

    already written) Ex/ Li + H3PO4 à H2 + Li3PO4

  • Rules 2. Count the number of atoms of each type on both sides

    –  If possible, keep polyatomic ions together

    Ex/ Li + H3PO4 à H2 + Li3PO4

  • Rules 3. Balance the elements one at a time by adding coefficients in front.

    à Generally, balance H, O, & monatomic atoms last

    Ex/ Li + H3PO4 à H2 + Li3PO4

  • Rules 4. Double-check – always Ex/ Li + H3PO4 à H2 + Li3PO4

  • Rules Never’s: •  Never add or change subscripts on

    formulas •  Never put a coefficient in the middle of a

    formula

  • Try These: 1.  AgNO3+Cu→Cu(NO3)2+Ag

    2.  CH4+O2→CO2+H2O

    3.  C3H8 + O2 à H2O + CO2