PMR questions.

1. Solve each of the following equations:a) k = −14 − k

!

Answer k + k = −142k = −14

k = −142

k = −7

b) f + 32(6 − 4 f ) = −31

!

Answer f + 9 − 6 f = −31f − 6 f = −31− 9−5 f = −40

f = −40−5

f = 8c) 2n = 3n − 4

!Answer 2n − 3n = −4

−n = −4n = 4

d) 2k = 3− 7k5

!

Answer 10k = 3− 7k10k + 7k = 3

17k = 3

k = 317

e) 12n

= 3

!

Answer 12 = 3n3n = 12

n = 123

n = 4f) 2(k −1) = k + 3

!Answer 2k − 2 = k + 3

2k − k = 3+ 2k = 5

g) x +10 = 4

! Answer x = 4 −10x = −6

h) 5x − 43

= x

!

Answer 5x − 4 = 3x5x − 3x = 4

2x = 4

x = 42

x = 2i) p + 5 = −11

!Answer p = −11− 5

p = −15

j) x −1 = x + 32

!Answer 2x − 2 = x + 3

2x − x = 3+ 2x = 5

Module questions.1. Solve each of the following equations:

a) 3k − 2 = 8 + k

!

Answer 3k − k = 8 + 22k = 10

k = 102

k = 5b) x + 8 = 5

! Answer x = 5 − 8x = −3

c) m = −20 − m

!

Answer m + m = −202m = −20

m =−20

2m = −10

d) p = −2(3− p)

!

Answer p = −6 + 2pp − 2p = −6

− p = −6p = 6

PMR Question Module Chapter 4 Form 2 2011! paypeil@gmail.comMathematics : Linear Equations I

Answer all questions.

e) 3y8

=12

!

Answer y = 12 1

×8 4

3

y = 43

y = 113

f) 4a + 3 = 9 − 2a

!

Answer 4a + 2a = 9 − 36a = 6

a = 66

a = 1

g) 5n4

= 20

! Answer n = 20 4×

45 1

n = 16

h) 12 +15k3

= 4k

!

Answer 12 +15k = 12k15k −12k = −12

3k = −12

k = −123

k = −4

i) 2(x − 3) = 8 + 3x

!

Answer 2x − 6 = 8 + 3x2x − 3x = 8 + 6

−x = 14x = −14

j) m +34(8 −16m) = −27

!

Answer m + 6 −12m = −27m −12m = −27 − 6

−11m = −33

m =−33−11

m = 3

k) 35+y4= y

!

Answer 3×4

5×4

+y×5

4×5

= y

12 + 5y20

= y

12 + 5y = 20y5y − 20y = −12

−15y = −12

y = −12−15

y = 45

l) 2p − 32

=5p6

!

Answer 12p −18 = 10p12p −10p = 18

2p = 18

p = 182

p = 9

m) 2a − 32

= −a6

!

Answer 12a −18 = −2a12a + 2a = 18

14a = 18

a = 1814

a = 97

a = 1 27

n) 5n− 3 = 6 + 2

n

!

Answer 5n−

2n= 6 + 3

3n= 9

3 = 9n9n = 3

n = 39

n = 13

PMR Question Module Chapter 4 Form 2 2011! paypeil@gmail.comMathematics : Linear Equations I

Answer all questions.