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Test - 8 (Code-C) (Answers & Hints) All India Aakash Test Series for Medical-2018
1/10
1. (4)
2. (3)
3. (3)
4. (4)
5. (2)
6. (3)
7. (1)
8. (4)
9. (3)
10. (4)
11. (1)
12. (4)
13. (2)
14. (2)
15. (4)
16. (2)
17. (1)
18. (4)
19. (3)
20. (3)
21. (3)
22. (3)
23. (2)
24. (1)
25. (4)
26. (1)
27. (4)
28. (1)
29. (4)
30. (1)
31. (3)
32. (3)
33. (2)
34. (2)
35. (3)
36. (3)
37. (4)
38. (2)
39. (4)
40. (3)
41. (2)
42. (4)
43. (1)
44. (2)
45. (4)
46. (3)
47. (4)
48. (2)
49. (3)
50. (4)
51. (2)
52. (1)
53. (2)
54. (4)
55. (1)
56. (2)
57. (2)
58. (3)
59. (3)
60. (1)
61. (4)
62. (4)
63. (3)
64. (4)
65. (2)
66. (2)
67. (4)
68. (3)
69. (2)
70. (4)
71. (2)
72. (2)
73. (2)
74. (4)
75. (1)
76. (3)
77. (1)
78. (2)
79. (1)
80. (4)
81. (1)
82. (3)
83. (4)
84. (2)
85. (1)
86. (2)
87. (1)
88. (4)
89. (1)
90. (2)
91. (3)
92. (2)
93. (1)
94. (2)
95. (3)
96. (1)
97. (3)
98. (2)
99. (3)
100. (2)
101. (2)
102. (2)
103. (3)
104. (3)
105. (4)
106. (3)
107. (1)
108. (1)
109. (2)
110. (2)
111. (2)
112. (3)
113. (4)
114. (4)
115. (2)
116. (4)
117. (1)
118. (2)
119. (2)
120. (1)
121. (1)
122. (2)
123. (2)
124. (2)
125. (1)
126. (3)
127. (4)
128. (3)
129. (3)
130. (1)
131. (3)
132. (4)
133. (4)
134. (1)
135. (4)
136. (4)
137. (3)
138. (3)
139. (3)
140. (3)
141. (3)
142. (3)
143. (3)
144. (4)
145. (2)
146. (3)
147. (4)
148. (2)
149. (3)
150. (3)
151. (3)
152. (3)
153. (3)
154. (2)
155. (4)
156. (1)
157. (1)
158. (3)
159. (1)
160. (1)
161. (3)
162. (3)
163. (4)
164. (2)
165. (2)
166. (1)
167. (2)
168. (3)
169. (3)
170. (3)
171. (2)
172. (3)
173. (3)
174. (4)
175. (3)
176. (2)
177. (2)
178. (3)
179. (3)
180. (1)
ANSWERS
TEST - 8 (Code-C)
All India Aakash Test Series for Medical-2018
Test Date : 19-03-2017
All India Aakash Test Series for Medical-2018 Test - 8 (Code-C) (Answers & Hints)
2/10
Hints to Selected Questions
[ PHYSICS]
1. Answer (4)
2. Answer (3)
3. Answer (3)
v2 = u2 + 2as
or v2 = u2 + 2 (Area under a–x graph)
v2 = 21 + 2 × 30
v = 9 m/s
4. Answer (4)
At v = 2, x = 1 m
2 8dv
v xdx
24 4 m/s
dva v x
dx
5. Answer (2)
T = 4 + 8 = 12 s
21
120 m2
Ts
av
12010 m/s
12v
6. Answer (3)
2(2 )2
8t c
ta a ⇒
t = 2 s
v = 2t = 4 m/s
7. Answer (1)
By comparison,
tan = 1
2 20.1
2 cos
g
u
u = 10 m/s
8. Answer (4)
T = 1 s
2 2(horizontal) 3 4 5 m/su
R = 5 m/s × 1 s = 5 m
9. Answer (3)
� � �
BA B Av v v
45°
45°
A
B
vB
–vA
vA
Cd
vBA
�
d
2
10. Answer (4)
1 1 2 2F m a m a �
� �
11. Answer (1)
Free body diagram :
F 2F
3 = 30 Ng
3F = 30 N
F = 10 N
12. Answer (4)
6 sin60 4 sin30
10
g ga
a 3.2 m/s2
13. Answer (2)
fL =
sN =
smg = 100 N
Body will remain static.
Static friction = f = F = 80 N
Test - 8 (Code-C) (Answers & Hints) All India Aakash Test Series for Medical-2018
3/10
14. Answer (2)
2 2(20)tan 1
40 10
v
Rg
= 45°
15. Answer (4)
Tension = Weight of the lower part
16. Answer (2)
W F s �� �
= ˆ ˆ ˆ ˆ(6 2 )(2 12 )i j i j
= 12 – 24
= –12 J
17. Answer (1)
Work energy theorem,
21
2Pt mv
2Ptv
m
18. Answer (4)
21(2 )
2mv mg R H
2 (2 )v g R H
19. Answer (3)
At equilibrium,
F = 0 x = ±1
20. Answer (3)
Centre of mass lies on the symmetric line.
21. Answer (3)
IZ
= IX + I
Y
=
2
212
ML
=
2
6
ML
22. Answer (3)
vP = 2v
C v
C = 3 m/s
23. Answer (2)
2 2
0
1 3 1
2 4 2mv mv
⎛ ⎞ ⎜ ⎟⎝ ⎠
2 2
0
3
4v v
0
3
2v v
0
3
2
ve
v
24. Answer (1)
28 2 8 1; 0.5 m/s
8 8 8 8
x y
a a
2 2 25m/s
2x y
a a a
25. Answer (4)
2R
Tg
26. Answer (1)
T R3/2
3
2
T R
T R
27. Answer (4)
28. Answer (1)
P
V
V
PV
V
V = VT
PV P
V T T ⇒
29. Answer (4)
1000r3 = R3
R = 10r
Now,
2
2
1
101000
R
r
30. Answer (1)
PA = ab = gb
PB = gh
PA – P
B = g(b – h)
31. Answer (3)
1 2
0
2( )
At H H
A g
Here, T1 = T
2
All India Aakash Test Series for Medical-2018 Test - 8 (Code-C) (Answers & Hints)
4/10
H H
H
4H
H
= 4
32. Answer (3)
22 2
2 2 2I MR R
TMgd MgR g
33. Answer (2)
34. Answer (2)
2
av max;
4
Aa a A
T
av
max
2a
a
35. Answer (3)
A = 2 2
1 2 1 22 cosA A A A
= 2 cos2
A
= 2A cos30°
= 3
2 32
A A
36. Answer (3)
2
2K
= 4 m
So, L can be 3
, , , 22 2
etc.
37. Answer (4)
vs = 20 cos60 = 10 m/s
340660 680 Hz
340 10
f
s
vf
v v
⎡ ⎤ ⎢ ⎥ ⎣ ⎦
38. Answer (2)
2
2 1 10
1
10 logI
SL SLI
⎛ ⎞ ⎜ ⎟⎝ ⎠
30 – 3 = 27 dB
39. Answer (4)
14
e l ...(i)
2
3
4e
l ...(ii)
Solving,
2 13
1.05 cm2
e
l l
40. Answer (3)
U = U1 + U
2
= 5 3
2 42 2
RT RT
= 11RT
41. Answer (2)
W = WAB
+ WBC
0 0 0 0
0 0
3 5 72
2 2 2
P P P VV V
42. Answer (4)
11K
43. Answer (1)
10 5
3 2 RT RT
W
5
6 RT
1
4
W
Q
4
QW
44. Answer (2)
1120 × 1 × (80 – 15) = m(540 + 20)
m = 130 g
45. Answer (4)
P R2T4
Pnew
= 4 × 440 = 1760 watt
Test - 8 (Code-C) (Answers & Hints) All India Aakash Test Series for Medical-2018
5/10
[ CHEMISTRY]
46. Answer (3)
Number of moles of CaCO3
=
3100 10 g
100 g/mole
= 10–3 mole
Number of moles of O atoms = 3 × 10–3
Number of O atoms = 6.02 × 1023 × 3 × 10–3
= 18.06 × 1020
= 1.8 × 1021
47. Answer (4)
48. Answer (2)
4KClO3
3KClO + KCl4
+5 +7 –1
Reduction
Oxidation
49. Answer (3)
50. Answer (4)
51. Answer (2)
52. Answer (1)
Volume strength = 5.6 × N
=
8.5
175.6
560
1000
= 8.5 1000
5.617 560
= 5 V
53. Answer (2)
54. Answer (4)
PV = nRT (Ideal gas equation)
55. Answer (1)
Gas [X],
x x x
x x
x
P M d RTd or P
RT M
Gas [Y],
y y y
y y
y
P M d RTd or P
RT M
According to the problem,
dx = 3d
y
My = 1.5M
x
or Mx =
1
1.5My
y y yx x
y x y y y
M 3d MP d RT1.5 4.5
P M d RT M d
56. Answer (2)
Cr (Z = 24) = 1s2, 2s
2, 2p6, 3s
2, 3p6, 4s
1, 3d5
For s-orbital,
l = 0
Total number of electrons having l = 0 are 7.
57. Answer (2)
Na has low melting point and it spread over water.
58. Answer (3)
2
20.8 mole0.4 mole
MgCl Mg 2Cl
2 2
4 4
0.2 mole 0.2 mole
MgSO Mg SO
Number of moles of Mg2+ = (0.4 + 0.2) = 0.6
59. Answer (3)
60. Answer (1)
H3BO
3 accepts one OH– ion.
61. Answer (4)
Higher the value of standard reduction potential,
higher is the oxidising power.
62. Answer (4)
Hydrogen shows oxidation number of –1 in metal
hydrides.
63. Answer (3)
64. Answer (4)
65. Answer (2)
3° free radical is more stable.
66. Answer (2)
Addition follows Anti-Markownikoff’s rule due to
–I effect of –CF3.
All India Aakash Test Series for Medical-2018 Test - 8 (Code-C) (Answers & Hints)
6/10
67. Answer (4)
Trans but-2-ene is highly stable alkene amongst all
of these.
68. Answer (3)
More electron withdrawing groups increase the acidic
strength.
69. Answer (2)
n(n 2) B.M.
3(3 2)
15 B.M.
70. Answer (4)
71. Answer (2)
N2(g) + 2H
2(g) N
2H4(g)
Hf° N
2H4(g) = [BE of N N + 2BE of H – H]
– [BE of N – N + 4BE (N – H)]
= 941 + 2 × 436 – (159 + 4 × 398)
= 62 kJ/mol
72. Answer (2)
In nature, carbon exist as graphite allotrope.
73. Answer (2)
(High volume) (Low volume)Ice Water���⇀
↽���
Melting of ice will be favoured by increase in
pressure on system.
74. Answer (4)
AB(g) ���⇀↽��� A(g) + B(g)
Initially : 1 0 0
At equilibrium : (1 – 0.33) 0.33 0.33
Total moles at equilibrium = 1.33
p
0.33 0.33P P
1.33 1.33K 0.122P
0.67P
1.33
⎡ ⎤⎢ ⎥ ⎢ ⎥⎢ ⎥⎢ ⎥⎣ ⎦
p
1K P
8
P = 8Kp
75. Answer (1)
Kb = 10–10, K
a = 10–4
pKa = –log(10–4) = 4
a
[X ]pH pK log
[HX]
[X ]pH 4 log
[HX]
pH = 4
76. Answer (3)
77. Answer (1)
CA of base is formed by accepting the H+ ion
NH2
–H+ NH3
78. Answer (2)
2
2 4 4
S2S
Ag SO 2Ag SO ���⇀
↽���
Ksp
= [Ag+]2[SO4
2–]
= (2S)2(S)
= 4S3
79. Answer (1)
80. Answer (4)
81. Answer (1)
Br — Br — Br
O
O
O
O
O
O
O
O
+6 +4 +6
Average oxidation number is 16
3
or 3x – 16 = 0
3x = +16
x = 16
3
82. Answer (3)
83. Answer (4)
8Al 4Al2O3 + 24e–
84. Answer (2)
C2H5OH + 4I
2 + 6OH– CHI
3 + HCO
2
– + 5I– + 5H2O
85. Answer (1)
On 10 times dilution, pH is increased by 1 unit.
86. Answer (2)
Hard boiling of an egg produces disorderness in
structure of protene inside the shell of egg.
Test - 8 (Code-C) (Answers & Hints) All India Aakash Test Series for Medical-2018
7/10
For isothermal process,
2
1
VS nR ln
V
Since P2 < P
1 and V
2 > V
1, hence entropy will be
increased.
87. Answer (1)
Since carbon and oxygen both have 2p1 and 2p
4
(n = 2) orbital electrons and can easily participate in
-bonding (parallel to plane of internuclear axis).
88. Answer (4)
C
Cl
Cl
ClCl
net
= 0
89. Answer (1)
1 amu = 1.66 × 10–24 g
12 amu = 1.99 × 10–23 g
90. Answer (2)
[ BIOLOGY
]
91. Answer (3)
92. Answer (2)
C – Higher is the category, greater is the difficulty of
determining the relationship to other texa at the
same level.
93. Answer (1)
IV. Nature of cell wall.
VIII. Mode of respiration.
94. Answer (2)
95. Answer (3)
2H+, 2e–, 4ATP
96. Answer (1)
97. Answer (3)
98. Answer (2)
99. Answer (3)
100. Answer (2)
101. Answer (2)
Natural system of classification given by Bentham
and Hooker.
It is based on external features
internal features
ultrastructure
anatomy
embryology and phytochemistry
102. Answer (2)
103. Answer (3)
104. Answer (3)
105. Answer (4)
The female gametophyte produces two or more
archegonia.
106. Answer (3)
107. Answer (1)
108. Answer (1)
Mimosa pudica – Leguminaceae (family)
characterised by pulvinus leaf base.
109. Answer (2)
110. Answer (2)
111. Answer (2)
112. Answer (3)
113. Answer (4)
114. Answer (4)
Male gamete (n) + Egg (n)
Male gamete (n) + Secondary nucleus (2n)
Syngamy + triple fusion = Double fertilisation
Zygote (2n)
PEN (3n)
Triple fusion
Syngamy
115. Answer (2)
116. Answer (4)
117. Answer (1)
III. Mechanical support to stem.
V. Resistant to the attacks of insects.
These features are related to heart wood.
118. Answer (2)
119. Answer (2)
A – 3-phosphoglyceric acid
B – Lactic acid
C – Ethyl alcohol (ethanol)
All India Aakash Test Series for Medical-2018 Test - 8 (Code-C) (Answers & Hints)
8/10
120. Answer (1)
121. Answer (1)
122. Answer (2)
B – Sequence of cytochromes for electron flow is
cyt b cyt c1 cyt c cyt a cyt a
3.
D – Cyt c is electron carrier between complex III
and IV.
123. Answer (2)
124. Answer (2)
Water potential for cell A,
w = DPD +
w = –8 bars
Water potential for cell B = s +
p =
w
So, w = –18 + 7 = –11 bars
Water potential for cell C,
DPD = OP – TP
= 6 – 3
= 3
w = –3 bars
So, direction of water flow
B w = –11
A
Cw = –3
w = –8
125. Answer (1)
126. Answer (3)
A B — V
127. Answer (4)
128. Answer (3)
129. Answer (3)
130. Answer (1)
In oocytes of some vertebrates lost for months or
years, true for diplotene stage.
131. Answer (3)
132. Answer (4)
a. Sugar moiety towards outer region.
b. Quasi-fluid nature of lipid enables lateral
movement of proteins within the overall bi-lipid
layer.
133. Answer (4)
Figure shown is lysosome.
134. Answer (1)
135. Answer (4)
Steroidal hormones secreted from smooth
endoplasmic reticulum (SER).
136. Answer (4)
A resting membrane, is said to be in polarised
state. In this, the outside of the membrane is
positively charged, and inside is negatively charged.
Outside has more Na+ ions and inside has more K+
ions. K+ ions leak/diffuse from inside to outside.
137. Answer (3)
7% of CO2 is transported as dissolved gas in
plasma. 70% of CO2 is transported as HCO
3
– in
RBC and plasma CO2 is mainly transported as
NaHCO3 in plasma. 20–25% is transported as
carbaminohemoglobin.
138. Answer (3)
Knee jerk reflex is simple reflex. It is monosynaptic
reflex, i.e., between the sensory and motor neuron
there is only one synapse, no interneuron are
present. Quadriceps femoris is extensor of thigh.
139. Answer (3)
A person with B blood group has B antigen and
anti-A antibodies. If he is B negative Rh antigen and
Rh antibodies are absent.
140. Answer (3)
Total fat consumption is 1 g, i.e., 1 × 9 = 9 K
calories are released.
Total calories from serving is 217 kcal.
Total fat 1 g × 9 = 9 kcal
Starch 43 g × 4 = 172
Sugar 3 g × 4 = 12
Protein 6 g × 4 = 24
= 217 kcal
Percentage of calories that come from fat
9100 4.1%
217
141. Answer (3)
If the level of cortisol rises in blood, then increase in
this level will exert a negative feedback control on
the hypothalamus, so less CRH is released Soless ACTH released So less cortisol till the
level is normalised.
Test - 8 (Code-C) (Answers & Hints) All India Aakash Test Series for Medical-2018
9/10
142. Answer (3)
Estrogen hormone is a steroid hormone which
directly enters the cell, no second messenger is
required. It binds with intracellular receptor in
nucleus to form hormone receptor complex which
binds with a specific DNA segment to stimulate
gene expression.
143. Answer (3)
Mitral valve is bicuspid valve between left atrium and
left ventricle. If we cut the chordae tendinae of mitral
valve, the valve will close, but during ventricular
systole, they will regurgitate into atria along with some
blood. So, the flow of blood would decrease in aorta.
144. Answer (4)
Endothermal organisms are warm blooded with a
constant body temperature. They have a higher
metabolic rate, so they eat more than ectotherms.
145. Answer (2)
The presence of true body cavity poses a problem
for direct exchange of oxygen and carbon dioxide
with environment. But it provides space for the
intestine to become longer for better digestion and
absorption.
146. Answer (3)
The only phylum in the kingdom animalia is phylum
porifera.
147. Answer (4)
During ventricular systole, the blood from the left
ventricle will flow into aorta, and the blood from right
ventricle will enter into pulmonary artery.
148. Answer (2)
a. Reabsorption is minimum in DLH.
b. Selective secretion of H+ and K+ ions occur in
PCT, DCT and CD.
c. Conditional reabsorption of Na+ and water occur
in DCT.
d. Filtrate becomes hypotonic in ALH.
149. Answer (3)
Aldosterone is produced by adrenal cortex in
response to low levels of sodium ions in the blood.
150. Answer (3)
Neutrophils are 60–65%, they help in phagocytosis,
but they are not precursor of macrophages.
Monocytes are precursor of macrophages.
151. Answer (3)
If we hold our breath for some time CO2 will build up
in the body, pH will decrease and the respiratory
rate would increase.
152. Answer (3)
If the oxygen hemoglobin dissociation curve shifts
towards RHS, it means binding has decreased
under the same pO2 because the secondary factors
have increased, causing dissociation of HbO2.
Strenuous exercise would increase lactic acid in
muscles and blood, pH would decrease.
153. Answer (3)
Estrogen promotes osteoblast activity.
154. Answer (2)
Knee joint is hinge joint, is formed between femur
and tibia, fibula does not take part.
155. Answer (4)
Periplaneta americana is a protostome with
determinate cleavage.
156. Answer (1)
In tight junction, the two adjacent cell membranes
are fused together to prevent the leaking of any
substance between the cells.
157. Answer (1)
Parathyroid gland secretes parathormone, which
increases the level of calcium ions in blood plasma.
158. Answer (3)
Lyases breakdown the covalent bond with the
removal of the group leaving double bond behind.
159. Answer (1)
160. Answer (1)
Haem is the prosthetic group for both catalase and
peroxidase.
For digestive enzyme, carboxypeptidase Zn++ is the
cofactor.
For tyrosine, copper is the cofactor.
161. Answer (3)
Adenylic acid is a nucleotide, AMP.
A is adenine
B is cytocine
C is ribose
D is phosphoric acid
E is guanine
All India Aakash Test Series for Medical-2018 Test - 8 (Code-C) (Answers & Hints)
10/10
� � �
AMP is
O
H
C1
Adenine
H
C
HO – P – O – CH2
OH
C2
H
OH
C3
HOH
O
162. Answer (3)
A is serine amino acid, it is alcoholic.
B is cysteine, it is sulphur containing amino acid.
C is tyrosine, it is aromatic and non-essential amino
acid.
D is glutamic, acidic amino acid.
163. Answer (4)
Negative feedback inhibition is responsible to
maintain homeostasis in the body. If the level of
hormone rises, it is detected and immediately
reversed, it is negative feedback inhibition.
Positive feedback are rare, the level of hormone
keeps rising but is not immediately reversed.
164. Answer (2)
Melatonin hormone controls sleep-wake cycle.
165. Answer (2)
Epiglottis closes the glottis at the time of swallowing
of food.
166. Answer (1)
Appendicular skeleton is present on the lateral sides
of axial skeleton. It includes the bones of the girdle
and limbs.
167. Answer (2)
The various levels of organisation are
Cellular level Tissue level Organ level Organ
system
168. Answer (3)
In fishes, middle ear is absent. So, they have lateral
line sense organs to detect the vibrations and
currents in water. Cochlea is for hearing.
Semicircular canals have sensory spots cristae with
sensory hair cells to detect dynamic equilibrium or
when a person is in motion.
169. Answer (3)
Birds are endothermal and reptiles are ectotherms.
170. Answer (3)
Sub-phylum vertebrata is divided into two divisions –
Agnatha (jawless vertebrates) and Gnathostomata
(jawed vertebrates).
171. Answer (2)
Ascidians are non-vertebrate chordates. They are
urochordates. In them, notochord is present only in
the larval tail not in adult, nor it is replaced by
vertebrae column.
172. Answer (3)
In ctenophores, the sexes are not separate. They
reproduce only sexually. They are exclusively
marine.
173. Answer (3)
174. Answer (4)
In Bufo and Rana, ureters carry both sperms and
urine.
175. Answer (3)
In echinoderms the endoskeleton is made up of
calcareous ossicles which are mesodermal in origin.
176. Answer (2)
In male frog, the copulatory pads are present in the
1st digit of forelimbs.
177. Answer (2)
Planarian has two way digestive system, as it has
blind sac type of body plan.
178. Answer (3)
The second heart sound 'dub' associated with the
closure of semilunar valves.
179. Answer (3)
Dark adaptation : Rods adapt later, cones adapt first.
180. Answer (1)
Test - 8 (Code-D) (Answers & Hints) All India Aakash Test Series for Medical-2018
1/10
1. (2)
2. (4)
3. (3)
4. (2)
5. (4)
6. (1)
7. (2)
8. (4)
9. (2)
10. (1)
11. (1)
12. (4)
13. (4)
14. (1)
15. (1)
16. (3)
17. (2)
18. (3)
19. (2)
20. (3)
21. (2)
22. (3)
23. (4)
24. (1)
25. (1)
26. (1)
27. (3)
28. (2)
29. (3)
30. (4)
31. (2)
32. (4)
33. (4)
34. (2)
35. (3)
36. (2)
37. (1)
38. (2)
39. (3)
40. (1)
41. (4)
42. (2)
43. (1)
44. (1)
45. (2)
46. (4)
47. (3)
48. (2)
49. (3)
50. (4)
51. (3)
52. (4)
53. (2)
54. (1)
55. (3)
56. (2)
57. (3)
58. (4)
59. (3)
60. (1)
61. (3)
62. (2)
63. (4)
64. (4)
65. (4)
66. (2)
67. (4)
68. (1)
69. (2)
70. (4)
71. (4)
72. (2)
73. (1)
74. (2)
75. (4)
76. (3)
77. (1)
78. (1)
79. (4)
80. (4)
81. (3)
82. (4)
83. (4)
84. (3)
85. (4)
86. (2)
87. (1)
88. (4)
89. (4)
90. (1)
91. (2)
92. (3)
93. (4)
94. (2)
95. (1)
96. (3)
97. (1)
98. (1)
99. (2)
100. (1)
101. (1)
102. (4)
103. (4)
104. (4)
105. (3)
106. (3)
107. (4)
108. (4)
109. (3)
110. (2)
111. (2)
112. (2)
113. (2)
114. (1)
115. (4)
116. (4)
117. (4)
118. (3)
119. (3)
120. (1)
121. (4)
122. (1)
123. (1)
124. (2)
125. (4)
126. (2)
127. (1)
128. (4)
129. (3)
130. (3)
131. (1)
132. (4)
133. (3)
134. (4)
135. (3)
136. (3)
137. (3)
138. (1)
139. (4)
140. (4)
141. (3)
142. (4)
143. (1)
144. (1)
145. (4)
146. (1)
147. (1)
148. (1)
149. (4)
150. (3)
151. (4)
152. (4)
153. (2)
154. (1)
155. (1)
156. (3)
157. (3)
158. (1)
159. (3)
160. (3)
161. (2)
162. (2)
163. (1)
164. (1)
165. (1)
166. (3)
167. (1)
168. (4)
169. (2)
170. (1)
171. (4)
172. (2)
173. (1)
174. (1)
175. (1)
176. (1)
177. (1)
178. (1)
179. (1)
180. (2)
ANSWERS
TEST - 8 (Code-D)
All India Aakash Test Series for Medical-2018
Test Date : 19-03-2017
All India Aakash Test Series for Medical-2018 Test - 8 (Code-D) (Answers & Hints)
2/10
Hints to Selected Questions
[ PHYSICS]
1. Answer (2)
P R2T4
Pnew
= 4 × 440 = 1760 watt
2. Answer (4)
1120 × 1 × (80 – 15) = m(540 + 20)
m = 130 g
3. Answer (3)
10 5
3 2 RT RT
W
5
6 RT
1
4
W
Q
4
QW
4. Answer (2)
11K
5. Answer (4)
W = WAB
+ WBC
0 0 0 0
0 0
3 5 72
2 2 2
P P P VV V
6. Answer (1)
U = U1 + U
2
= 5 3
2 42 2
RT RT
= 11RT
7. Answer (2)
14
e l ...(i)
2
3
4e
l ...(ii)
Solving,
2 13
1.05 cm2
e
l l
8. Answer (4)
2
2 1 10
1
10 logI
SL SLI
⎛ ⎞ ⎜ ⎟⎝ ⎠
30 – 3 = 27 dB
9. Answer (2)
vs = 20 cos60 = 10 m/s
340660 680 Hz
340 10
f
s
vf
v v
⎡ ⎤ ⎢ ⎥ ⎣ ⎦
10. Answer (1)
2
2K
= 4 m
So, L can be 3
, , , 22 2
etc.
11. Answer (1)
A = 2 2
1 2 1 22 cosA A A A
= 2 cos2
A
= 2A cos30°
= 3
2 32
A A
12. Answer (4)
2
av max;
4
Aa a A
T
av
max
2a
a
13. Answer (4)
Test - 8 (Code-D) (Answers & Hints) All India Aakash Test Series for Medical-2018
3/10
14. Answer (1)
22 2
2 2 2I MR R
TMgd MgR g
15. Answer (1)
1 2
0
2( )
At H H
A g
Here, T1 = T
2
H H
H
4H
H
= 4
16. Answer (3)
PA = ab = gb
PB = gh
PA – P
B = g(b – h)
17. Answer (2)
1000r3 = R3
R = 10r
Now,
2
2
1
101000
R
r
18. Answer (3)
P
V
V
PV
V
V = VT
PV P
V T T ⇒
19. Answer (2)
20. Answer (3)
T R3/2
3
2
T R
T R
21. Answer (2)
2R
Tg
22. Answer (3)
28 2 8 1; 0.5 m/s
8 8 8 8
x y
a a
2 2 25m/s
2x y
a a a
23. Answer (4)
2 2
0
1 3 1
2 4 2mv mv
⎛ ⎞ ⎜ ⎟⎝ ⎠
2 2
0
3
4v v
0
3
2v v
0
3
2
ve
v
24. Answer (1)
vP = 2v
C v
C = 3 m/s
25. Answer (1)
IZ
= IX + I
Y
=
2
212
ML
=
2
6
ML
26. Answer (1)
Centre of mass lies on the symmetric line.
27. Answer (3)
At equilibrium,
F = 0 x = ±1
28. Answer (2)
21(2 )
2mv mg R H
2 (2 )v g R H
29. Answer (3)
Work energy theorem,
21
2Pt mv
2Ptv
m
All India Aakash Test Series for Medical-2018 Test - 8 (Code-D) (Answers & Hints)
4/10
30. Answer (4)
W F s �� �
= ˆ ˆ ˆ ˆ(6 2 )(2 12 )i j i j
= 12 – 24
= –12 J
31. Answer (2)
Tension = Weight of the lower part
32. Answer (4)
2 2(20)tan 1
40 10
v
Rg
= 45°
33. Answer (4)
fL =
sN =
smg = 100 N
Body will remain static.
Static friction = f = F = 80 N
34. Answer (2)
6 sin60 4 sin30
10
g ga
a 3.2 m/s2
35. Answer (3)
Free body diagram :
F 2F
3 = 30 Ng
3F = 30 N
F = 10 N
36. Answer (2)
1 1 2 2F m a m a �
� �
37. Answer (1)
� � �
BA B Av v v
45°
45°
A
B
vB
–vA
vA
Cd
vBA
�
d
2
38. Answer (2)
T = 1 s
2 2(horizontal) 3 4 5 m/su
R = 5 m/s × 1 s = 5 m
39. Answer (3)
By comparison,
tan = 1
2 20.1
2 cos
g
u
u = 10 m/s
40. Answer (1)
2(2 )2
8t c
ta a ⇒
t = 2 s
v = 2t = 4 m/s
41. Answer (4)
T = 4 + 8 = 12 s
21
120 m2
Ts
av
12010 m/s
12v
42. Answer (2)
At v = 2, x = 1 m
2 8dv
v xdx
24 4 m/s
dva v x
dx
43. Answer (1)
v2 = u2 + 2as
or v2 = u2 + 2 (Area under a–x graph)
v2 = 21 + 2 × 30
v = 9 m/s
44. Answer (1)
45. Answer (2)
Test - 8 (Code-D) (Answers & Hints) All India Aakash Test Series for Medical-2018
5/10
[ CHEMISTRY]
46. Answer (4)
47. Answer (3)
1 amu = 1.66 × 10–24 g
12 amu = 1.99 × 10–23 g
48. Answer (2)
C
Cl
Cl
ClCl
net
= 0
49. Answer (3)
Since carbon and oxygen both have 2p1 and 2p4
(n = 2) orbital electrons and can easily participate in
-bonding (parallel to plane of internuclear axis).
50. Answer (4)
Hard boiling of an egg produces disorderness in
structure of protene inside the shell of egg.
For isothermal process,
2
1
VS nR ln
V
Since P2 < P
1 and V
2 > V
1, hence entropy will be
increased.
51. Answer (3)
On 10 times dilution, pH is increased by 1 unit.
52. Answer (4)
C2H5OH + 4I
2 + 6OH– CHI
3 + HCO
2
– + 5I– + 5H2O
53. Answer (2)
8Al 4Al2O3 + 24e–
54. Answer (1)
55. Answer (3)
Br — Br — Br
O
O
O
O
O
O
O
O
+6 +4 +6
Average oxidation number is 16
3
or 3x – 16 = 0
3x = +16
x = 16
3
56. Answer (2)
57. Answer (3)
58. Answer (4)
2
2 4 4
S2S
Ag SO 2Ag SO ���⇀
↽���
Ksp
= [Ag+]2[SO4
2–]
= (2S)2(S)
= 4S3
59. Answer (3)
CA of base is formed by accepting the H+ ion
NH2
–H+ NH3
60. Answer (1)
61. Answer (3)
Kb = 10–10, K
a = 10–4
pKa = –log(10–4) = 4
a
[X ]pH pK log
[HX]
[X ]pH 4 log
[HX]
pH = 4
62. Answer (2)
AB(g) ���⇀↽��� A(g) + B(g)
Initially : 1 0 0
At equilibrium : (1 – 0.33) 0.33 0.33
Total moles at equilibrium = 1.33
p
0.33 0.33P P
1.33 1.33K 0.122P
0.67P
1.33
⎡ ⎤⎢ ⎥ ⎢ ⎥⎢ ⎥⎢ ⎥⎣ ⎦
p
1K P
8
P = 8Kp
All India Aakash Test Series for Medical-2018 Test - 8 (Code-D) (Answers & Hints)
6/10
63. Answer (4)
(High volume) (Low volume)Ice Water���⇀
↽���
Melting of ice will be favoured by increase in
pressure on system.
64. Answer (4)
In nature, carbon exist as graphite allotrope.
65. Answer (4)
N2(g) + 2H
2(g) N
2H4(g)
Hf° N
2H4(g) = [BE of N N + 2BE of H – H]
– [BE of N – N + 4BE (N – H)]
= 941 + 2 × 436 – (159 + 4 × 398)
= 62 kJ/mol
66. Answer (2)
67. Answer (4)
n(n 2) B.M.
3(3 2)
15 B.M.
68. Answer (1)
More electron withdrawing groups increase the acidic
strength.
69. Answer (2)
Trans but-2-ene is highly stable alkene amongst all
of these.
70. Answer (4)
Addition follows Anti-Markownikoff’s rule due to
–I effect of –CF3.
71. Answer (4)
3° free radical is more stable.
72. Answer (2)
73. Answer (1)
74. Answer (2)
Hydrogen shows oxidation number of –1 in metal
hydrides.
75. Answer (4)
Higher the value of standard reduction potential,
higher is the oxidising power.
76. Answer (3)
H3BO
3 accepts one OH– ion.
77. Answer (1)
78. Answer (1)
2
20.8 mole0.4 mole
MgCl Mg 2Cl
2 2
4 4
0.2 mole 0.2 mole
MgSO Mg SO
Number of moles of Mg2+ = (0.4 + 0.2) = 0.6
79. Answer (4)
Na has low melting point and it spread over water.
80. Answer (4)
Cr (Z = 24) = 1s2, 2s2, 2p6, 3s2, 3p6, 4s1, 3d5
For s-orbital,
l = 0
Total number of electrons having l = 0 are 7.
81. Answer (3)
Gas [X],
x x x
x x
x
P M d RTd or P
RT M
Gas [Y],
y y y
y y
y
P M d RTd or P
RT M
According to the problem,
dx = 3d
y
My = 1.5M
x
or Mx =
1
1.5My
y y yx x
y x y y y
M 3d MP d RT1.5 4.5
P M d RT M d
82. Answer (4)
PV = nRT (Ideal gas equation)
83. Answer (4)
84. Answer (3)
Volume strength = 5.6 × N
=
8.5
175.6
560
1000
= 8.5 1000
5.617 560
= 5 V
Test - 8 (Code-D) (Answers & Hints) All India Aakash Test Series for Medical-2018
7/10
[ BIOLOGY
]
91. Answer (2)
Steroidal hormones secreted from smooth
endoplasmic reticulum (SER).
92. Answer (3)
93. Answer (4)
Figure shown is lysosome.
94. Answer (2)
a. Sugar moiety towards outer region.
b. Quasi-fluid nature of lipid enables lateral
movement of proteins within the overall bi-lipid
layer.
95. Answer (1)
96. Answer (3)
In oocytes of some vertebrates lost for months or
years, true for diplotene stage.
97. Answer (1)
98. Answer (1)
99. Answer (2)
100. Answer (1)
A B — V
101. Answer (1)
102. Answer (4)
Water potential for cell A,
w = DPD +
w = –8 bars
Water potential for cell B = s +
p =
w
So, w = –18 + 7 = –11 bars
Water potential for cell C,
DPD = OP – TP
= 6 – 3
= 3
w = –3 bars
So, direction of water flow
B w = –11
A
Cw = –3
w = –8
103. Answer (4)
104. Answer (4)
B – Sequence of cytochromes for electron flow is
cyt b cyt c1 cyt c cyt a cyt a
3.
D – Cyt c is electron carrier between complex III
and IV.
105. Answer (3)
106. Answer (3)
107. Answer (4)
A – 3-phosphoglyceric acid
B – Lactic acid
C – Ethyl alcohol (ethanol)
108. Answer (4)
109. Answer (3)
III. Mechanical support to stem.
V. Resistant to the attacks of insects.
These features are related to heart wood.
110. Answer (2)
111. Answer (2)
85. Answer (4)
86. Answer (2)
87. Answer (1)
88. Answer (4)
4KClO3
3KClO + KCl4
+5 +7 –1
Reduction
Oxidation
89. Answer (4)
90. Answer (1)
Number of moles of CaCO3
=
3100 10 g
100 g/mole
= 10–3 mole
Number of moles of O atoms = 3 × 10–3
Number of O atoms = 6.02 × 1023 × 3 × 10–3
= 18.06 × 1020
= 1.8 × 1021
All India Aakash Test Series for Medical-2018 Test - 8 (Code-D) (Answers & Hints)
8/10
112. Answer (2)
Male gamete (n) + Egg (n)
Male gamete (n) + Secondary nucleus (2n)
Syngamy + triple fusion = Double fertilisation
Zygote (2n)
PEN (3n)
Triple fusion
Syngamy
113. Answer (2)
114. Answer (1)
115. Answer (4)
116. Answer (4)
117. Answer (4)
118. Answer (3)
Mimosa pudica – Leguminaceae (family)
characterised by pulvinus leaf base.
119. Answer (3)
120. Answer (1)
121. Answer (4)
The female gametophyte produces two or more
archegonia.
122. Answer (1)
123. Answer (1)
124. Answer (2)
125. Answer (4)
Natural system of classification given by Bentham
and Hooker.
It is based on external features
internal features
ultrastructure
anatomy
embryology and phytochemistry
126. Answer (2)
127. Answer (1)
128. Answer (4)
129. Answer (3)
130. Answer (3)
131. Answer (1)
2H+, 2e–, 4ATP
132. Answer (4)
133. Answer (3)
IV. Nature of cell wall.
VIII. Mode of respiration.
134. Answer (4)
C – Higher is the category, greater is the difficulty of
determining the relationship to other texa at the
same level.
135. Answer (3)
136. Answer (3)
137. Answer (3)
Dark adaptation : Rods adapt later, cones adapt first.
138. Answer (1)
The second heart sound 'dub' associated with the
closure of semilunar valves.
139. Answer (4)
Planarian has two way digestive system, as it has
blind sac type of body plan.
140. Answer (4)
In male frog, the copulatory pads are present in the
1st digit of forelimbs.
141. Answer (3)
In echinoderms the endoskeleton is made up of
calcareous ossicles which are mesodermal in origin.
142. Answer (4)
In Bufo and Rana, ureters carry both sperms and
urine.
143. Answer (1)
144. Answer (1)
In ctenophores, the sexes are not separate. They
reproduce only sexually. They are exclusively
marine.
145. Answer (4)
Ascidians are non-vertebrate chordates. They are
urochordates. In them, notochord is present only in
the larval tail not in adult, nor it is replaced by
vertebrae column.
146. Answer (1)
Sub-phylum vertebrata is divided into two divisions –
Agnatha (jawless vertebrates) and Gnathostomata
(jawed vertebrates).
147. Answer (1)
Birds are endothermal and reptiles are ectotherms.
148. Answer (1)
In fishes, middle ear is absent. So, they have lateral
line sense organs to detect the vibrations and
currents in water. Cochlea is for hearing.
Semicircular canals have sensory spots cristae with
sensory hair cells to detect dynamic equilibrium or
when a person is in motion.
Test - 8 (Code-D) (Answers & Hints) All India Aakash Test Series for Medical-2018
9/10
149. Answer (4)
The various levels of organisation are
Cellular level Tissue level Organ level Organ
system
150. Answer (3)
Appendicular skeleton is present on the lateral sides
of axial skeleton. It includes the bones of the girdle
and limbs.
151. Answer (4)
Epiglottis closes the glottis at the time of swallowing
of food.
152. Answer (4)
Melatonin hormone controls sleep-wake cycle.
153. Answer (2)
Negative feedback inhibition is responsible to
maintain homeostasis in the body. If the level of
hormone rises, it is detected and immediately
reversed, it is negative feedback inhibition.
Positive feedback are rare, the level of hormone
keeps rising but is not immediately reversed.
154. Answer (1)
A is serine amino acid, it is alcoholic.
B is cysteine, it is sulphur containing amino acid.
C is tyrosine, it is aromatic and non-essential amino
acid.
D is glutamic, acidic amino acid.
155. Answer (1)
Adenylic acid is a nucleotide, AMP.
A is adenine
B is cytocine
C is ribose
D is phosphoric acid
E is guanine
AMP is
O
H
C1
Adenine
H
C
HO – P – O – CH2
OH
C2
H
OH
C3
HOH
O
156. Answer (3)
Haem is the prosthetic group for both catalase and
peroxidase.
For digestive enzyme, carboxypeptidase Zn++ is the
cofactor.
For tyrosine, copper is the cofactor.
157. Answer (3)
158. Answer (1)
Lyases breakdown the covalent bond with the
removal of the group leaving double bond behind.
159. Answer (3)
Parathyroid gland secretes parathormone, which
increases the level of calcium ions in blood plasma.
160. Answer (3)
In tight junction, the two adjacent cell membranes
are fused together to prevent the leaking of any
substance between the cells.
161. Answer (2)
Periplaneta americana is a protostome with
determinate cleavage.
162. Answer (2)
Knee joint is hinge joint, is formed between femur
and tibia, fibula does not take part.
163. Answer (1)
Estrogen promotes osteoblast activity.
164. Answer (1)
If the oxygen hemoglobin dissociation curve shifts
towards RHS, it means binding has decreased
under the same pO2 because the secondary factors
have increased, causing dissociation of HbO2.
Strenuous exercise would increase lactic acid in
muscles and blood, pH would decrease.
165. Answer (1)
If we hold our breath for some time CO2 will build up
in the body, pH will decrease and the respiratory
rate would increase.
166. Answer (3)
Neutrophils are 60–65%, they help in phagocytosis,
but they are not precursor of macrophages.
Monocytes are precursor of macrophages.
All India Aakash Test Series for Medical-2018 Test - 8 (Code-D) (Answers & Hints)
10/10
� � �
167. Answer (1)
Aldosterone is produced by adrenal cortex in
response to low levels of sodium ions in the blood.
168. Answer (4)
a. Reabsorption is minimum in DLH.
b. Selective secretion of H+ and K+ ions occur in
PCT, DCT and CD.
c. Conditional reabsorption of Na+ and water occur
in DCT.
d. Filtrate becomes hypotonic in ALH.
169. Answer (2)
During ventricular systole, the blood from the left
ventricle will flow into aorta, and the blood from right
ventricle will enter into pulmonary artery.
170. Answer (1)
The only phylum in the kingdom animalia is phylum
porifera.
171. Answer (4)
The presence of true body cavity poses a problem
for direct exchange of oxygen and carbon dioxide
with environment. But it provides space for the
intestine to become longer for better digestion and
absorption.
172. Answer (2)
Endothermal organisms are warm blooded with a
constant body temperature. They have a higher
metabolic rate, so they eat more than ectotherms.
173. Answer (1)
Mitral valve is bicuspid valve between left atrium and
left ventricle. If we cut the chordae tendinae of mitral
valve, the valve will close, but during ventricular
systole, they will regurgitate into atria along with some
blood. So, the flow of blood would decrease in aorta.
174. Answer (1)
Estrogen hormone is a steroid hormone which
directly enters the cell, no second messenger is
required. It binds with intracellular receptor in
nucleus to form hormone receptor complex which
binds with a specific DNA segment to stimulate
gene expression.
175. Answer (1)
If the level of cortisol rises in blood, then increase in
this level will exert a negative feedback control on
the hypothalamus, so less CRH is released Soless ACTH released So less cortisol till the
level is normalised.
176. Answer (1)
Total fat consumption is 1 g, i.e., 1 × 9 = 9 K
calories are released.
Total calories from serving is 217 kcal.
Total fat 1 g × 9 = 9 kcal
Starch 43 g × 4 = 172
Sugar 3 g × 4 = 12
Protein 6 g × 4 = 24
= 217 kcal
Percentage of calories that come from fat
9100 4.1%
217
177. Answer (1)
A person with B blood group has B antigen and
anti-A antibodies. If he is B negative Rh antigen and
Rh antibodies are absent.
178. Answer (1)
Knee jerk reflex is simple reflex. It is monosynaptic
reflex, i.e., between the sensory and motor neuron
there is only one synapse, no interneuron are
present. Quadriceps femoris is extensor of thigh.
179. Answer (1)
7% of CO2 is transported as dissolved gas in
plasma. 70% of CO2 is transported as HCO
3
– in
RBC and plasma CO2 is mainly transported as
NaHCO3 in plasma. 20–25% is transported as
carbaminohemoglobin.
180. Answer (2)
A resting membrane, is said to be in polarised
state. In this, the outside of the membrane is
positively charged, and inside is negatively charged.
Outside has more Na+ ions and inside has more K+
ions. K+ ions leak/diffuse from inside to outside.