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Expert Sheet 1 “Transposing a Linear Equation into Standard form”
Answer Key Example 1. Transpose the equation into standard
form.
2x + y = -8
-2x -2x
y = -2x – 8
Standard form: y = -2x – 8
m = -2
1 b = -8
m represents the slope
b represents the y-intercept
Example 2. Transform the equation into standard
form.
y = mx + b
12 + 3y = 9x
-12 -12
3y = 9x – 12
3 3 3
y = 3x – 4
Standard form: y = 3x – 4
m = 3
1 b = -4
m represents the slope
b represents the y-intercept
3.
6 + y = 3x
m = _______ b = ________
4.
3y = 4x – 9
m = _______ b = ________
5.
y + 2x = 10
m = _______ b = ________
6.
x – y = 4
m = _______ b = ________
7.
3x – 9y = 18
m = _______ b = ________
8.
x = 5y
*the y-intercept (b) is zero.
m = _______ b = ________
Lnhotsoubanh/jigsaw/linear
y = mx + b Steps:
1. Subtract 2x from
both sides.
Can’t combine -8 & -2x
*You want the “ y” to be by itself.
Steps:
1. Subtract 12 from both
sides. Can’t combine 9x & -12
2. Divide 3 to both sides.
* You want the “y” to be by itself.
3 -6
y = mx + b 3y = 4x – 9 3 3 3
y = 4x – 3
3
4 3 -3
y = mx + b y + 2x = 10 -2x -2x
y = -2x + 10
-2 10
y = mx + b x – y = 4
-x -x -y = -x + 4 -1 -1 -1
1 -4
y = mx + b
3x – 9y = 18 -3x -3x
-9y = -3x + 18 -9 -9 -9
y =
x – 2
1
3 -2
mx + b = y
x = 5y 5 5
y =
x
1
5 0
y = mx + b 6 + y = 3x -6 -6
y = 3x + 6
Expert Sheet 2
“Write an Equation of a Line”
Answer Key
Ex1. Write an equation of a line that has a slope of 5
2
and y intercept of 3.
y = mx + b
Equation: y =5
2x – 3
Steps to writing an Equation of a Line
Case 1. Given a Slope & a y-intercept
Substitute the slope (m) and
y-intercept (b) into the equation y = mx + b.
See example 1 and 2
Ex2. Write an equation of a line that has a slope of 1
and y intercept of 0.
y = mx + b (y-intercept is 0 so there is no “b”)
Equation: y = 1x or y = x
Ex3. Write an equation of a line that has a slope of 4 and x-intercept 3.
y = mx + b m = -4 b = ?
0 = -4(3) + b
0 = -12 + b
+12 +12
12 = b
so m = -4 and b = 12 therefore the equation is
Equation: y = -4x + 12
Steps to writing an Equation of a Line
Case 2. Given Slope & x-intercept
1. Substitute the slope (m) in the equation:
y = mx + b.
2. To find b, substitute the x-intercept coordinates (x, 0) in the equation y = mx +b.
See example 3
4. Write an equation of a line that has a slope of 2
3
and y intercept of 4.
Equation: _____________________________
5. Write an equation of a line that has a slope of zero
and a y-intercept of 8.
Equation: _____________________________
6. Write an equation of a line that has a slope of -1 and
a x-intercept of 3.
y = mx + b
0 = -1(3) + b
0 = -3 + b 3 = b
Equation: _____________________________
7. Write an equation of a line that has a slope of 6 and
a x-intercept of 0.
y = mx + b
0 = 6(0) + b
0 = b
Equation: _____________________________
Since the x-intercept is 3, the
coordinate is (3, 0). Substitute 3
in for x and 0 in for y in the equation y = mx + b
y = x + 4 y = 8
y = -x + 3 y = 6x
Expert Sheet 3
“Write an Equation of a Line, Given 2 Points”
Answer Key
Directions: Find the equation of a line that passes through the given points.
1.) (-3, -4) and (2, 11)
m = y1
- y2
x1
- x2
m = 35
15
23
114
y = mx + b 11 = 3(2) + b
11 = 6 + b
-6 -6
5 = b
Answer: y = 3x + 5
2.) (-6, -5) and (6, -13)
m = y1
- y2
x1
- x2
m = 3
2
12
8
66
135
y = mx + b
-5 = (-6) + b
-5 = 4 + b
-4 -4
-9 = b
Answer: y = x – 9
3.) (0, 2) and (6, 2)
m = y1
- y2
x1
- x2
m = 06
0
60
22
y = mx + b
2 = 0(0) + b 2 = 0 + b
2 = b
y = 0x + 2
Answer: y = 2 horizontal line, slope is zero
4.) (-10, 7) and (-10, -4)
m = y1
- y2
x1
- x2
m = undefined0
11
-10)10-
-4)7
(
(
Answer: x = -10
vertical slope, therefore there is no slope and no
y-intercept
(x, y) (0, 2)
(6, 2)
(x, y)
(-10, 7)
(-10, -4)
(x, y)
(-3, -4)
(2, 11)
(x, y)
(-6, -5) (6, -12)
(pick one of the points to
substitute in for x & y)
(pick one of the points to
substitute in for x & y)
(pick one of the points to
substitute in for x & y) (pick one of the points to
substitute in for x & y)
Expert Sheet 4
“Write an Equation of a Line, Given a Graph”
Answer Key
How to find the slope:
Pick 2 points on the line. Look at Line P. Count
the # of units going up to the other point then count the # of units going to the right of the other point.
How to find the y-intercept: It is the point that crosses the y-axis.
Example 1. Write the equation of line P in the graph.
Slope (m) = 2
1
y-intercept (b) = -1
Equation: y = 2x – 1
Example 2: Write the equation of line K in the graph.
Slope (m) = 0 y-intercept (b) = 3
y = 0x + 3 or y = 3
Equation: y = 3
Write the equation of lines in the graph.
3. Line A: ________________________
Slope (m) = ______ y-intercept = 5
4. Line B: ________________________
Slope (m) = undefined y-intercept = none
5. Line C: ________________________
Slope (m) = ______ y-intercept = -3
6. Line D: ________________________
Slope (m) = ______ y-intercept = 3
y
x -6 -4 -2 2 4 6
6
4
2
-2
-4
-6
Line P
Line K
Steps:
1. Find the slope of the
line.
2. Find the y-intercept of
the line. 3. Substitute the slope
and y-intercept into the equation y = mx + b
y
x -6 -4 -2 2 4 6
6 4
2
-2
-4
-6
Line A
Lin
e B
Line C
Line D
2
1
-1 5
y =
x = 4
y =
y =
4 2
= 2
1 3
Expert Sheet 5
“Write an Equation of a Line, Given a Table”
Answer Key
Example 1
(x, y)
y = mx + b Point (0, -6)
-6 = 2(0) + b
-6 = 0 + b
-6 = b
Function (equation): y = 2x – 6
Check by typing the equation y = 2x – 6 into your graphing calculator. Go to the table and check the
points.
x y
0 -6
1 -4
2 -2
3 0
4 2
Steps:
1. Find the pattern of the values in the x and y columns
in the table. The pattern is your slope, which is
represented by “m”.
Slope (m) = valus- xthe in pattern
values-y the in pattern 2
1
2. Pick any point from the table and substitute the
input(x) and the output(y) into the linear equation:
y = mx + b
3. Solve the equation to get the value of “b” which is the
y-intercept (where it crosses the y-axis).
4. To get the linear equation: find the slope (m) and the
y-intercept (b) and substitute them into the equation y = mx + b.
Example 2
(x, y) y = mx + b Point (-3, 6)
6 = 3
2 (-3) + b
6 = 2 + b
-2 -2
4 = b
Function (equation): y = 3
2x + 4
x y
-3 6
0 4
3 2
6 0
9 -2
Now it’s your turn:
3.
y = mx + b Point (2, 0)
0 = -4(2) + b
0 = -8 + b
+8 +8
8 = b
Function (equation): y = -4x + 4
x y
-2 16
2 0
6 -16
10 -32
14 -48
4.
(x, y)
y = mx + b Point (0, 1)
1 = 3
5 (0) + b
1 = 0 + b
1 = b
Function (equation): y = 3
5x + 1
x y
0 1
6 -9
12 -19
18 -29
24 -39
5.
(x, y)
y = mx + b Point (8, 37)
37 = 5(8) + b
37 = 40 + b -40 -40
-3 = b
Function (equation): y = 5x – 3
x y
8 37
13 62
18 87
23 112
28 137
+2
+2
+2
+2
+1
+1
+1
+1
-2
-2
-2
-2
+3
+3
+3
+3
Substitute (x, y) into the equation
y = mx + b
Substitute (x, y) into the equation
y = mx + b
=
Substitute
(x, y) into the equation y = mx + b
Substitute
(x, y) into the equation y = mx + b