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Announcements 10/19/12 Prayer Learn Smart – info in email Term project proposal due tomorrow Labs 4-5 also due tomorrow Exam 2: starting next Thurs a. Review session: Tues 5:30-7 pm, place TBA

Announcements 10/19/12

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Announcements 10/19/12. Prayer Learn Smart – info in email Term project proposal due tomorrow Labs 4-5 also due tomorrow Exam 2: starting next Thurs Review session: Tues 5:30-7 pm, place TBA. From warmup. Extra time on? The math Other comments? - PowerPoint PPT Presentation

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Page 1: Announcements 10/19/12

Announcements 10/19/12 Prayer Learn Smart – info in email Term project proposal due tomorrow Labs 4-5 also due tomorrow Exam 2: starting next Thurs

a. Review session: Tues 5:30-7 pm, place TBA

Page 2: Announcements 10/19/12

From warmup Extra time on?

a. The math

Other comments?a. As i almost always do the homework by myself i haven't

had the opportunity to find a partner for the term project. can we spend a minute or two in class and make sure there aren't others in my situation.

b. So im reading the proposal instructions. Can you explain a little more what calculations and predictions you would need?

c. Do I need a log of hours spent on the term project?d. I'd like it to be noted that there are now two discrepancies

in Dr. Durfee's book. The first being that he switched the coefficients for sin and cos, being the only person (as far as we can tell) who does this. Second, he believes the guitar is the ideal musical instrument. This is impossible seeing as the piano is the ideal musical instrument.

Page 3: Announcements 10/19/12

Review clicker question:

In the Fourier transform of a periodic function, which frequency components will be present?

a. Just the fundamental frequency, f0 = 1/period

b. f0 and potentially all integer multiples of f0

c. A finite number of discrete frequencies centered on f0

d. An infinite number of frequencies near f0, spaced infinitely close together

Page 4: Announcements 10/19/12

Summary of last time

0

0

1( )

L

a f x dxL

0

2 2( )cos

L

nnx

a f x dxL L

0

2 2( )sin

L

nnx

b f x dxL L

01 1

2 2( ) cos sinn n

n n

nx nxf x a a b

L L

The series

How to find the coefficients

0 1 0 1 0

2 0 2 0

3 0 3 0

( ) cos sin

cos 2 sin 2

cos 3 sin 3 ...

f x a a k x b k x

a k x b k x

a k x b k x

Written another waywith k0 = 2/L

Page 5: Announcements 10/19/12

The graphical “proof” that the functions integrate to zero

Mathematica: Graphical “proof”

(called “orthogonal” functions)

Page 6: Announcements 10/19/12

0N 1N 2N

3N 10N 500N

1 1 2sin

2

nx

n L

Sawtooth Wave, like HW 22-2

(The next few slides from Dr. Durfee)

Page 7: Announcements 10/19/12

The Spectrum of a Saw-tooth WaveThe Spectrum of a Saw-tooth Wave

0 10 20 30 40 50 60-0.4

-0.2

0

0.2

0.4

0.6

Am

plitu

de

[m]

k [rad/m]

Page 8: Announcements 10/19/12

The Spectrum of a Saw-tooth WaveThe Spectrum of a Saw-tooth Wave

0 10 20 30 40 50 600

0.1

0.2

0.3

0.4

0.5

0.6

Am

plitu

de [

m]

k [rad/m]0 10 20 30 40 50 60

-pi/2

-pi/4

0

Pha

se [

rad]

Page 9: Announcements 10/19/12

Electronic “Low-pass filter” “Low pass filter” = circuit which preferentially

lets lower frequencies through.

?Circuit

What comes out?

How to solve: (1) Decompose wave into Fourier series(2) Apply filter to each frequency individually(3) Add up results in infinite series again

Page 10: Announcements 10/19/12

Low-Pass Filter – before filterLow-Pass Filter – before filter

0 10 20 30 40 50 600

0.1

0.2

0.3

0.4

0.5

0.6

Am

plitu

de [

m]

k [rad/m]0 10 20 30 40 50 60

0

0.1

0.2

0.3

0.4

0.5

0.6

Am

plitu

de [

m]

k [rad/m]0 10 20 30 40 50 60

0

0.1

0.2

0.3

0.4

0.5

0.6

Am

plitu

de [

m]

k [rad/m]0 10 20 30 40 50 60

-pi

-3 pi/4

-pi/2

-pi/4

0

Pha

se [

rad]

Page 11: Announcements 10/19/12

Low-Pass Filter – after filterLow-Pass Filter – after filter

0 10 20 30 40 50 600

0.1

0.2

0.3

0.4

0.5

0.6

Am

plitu

de [

m]

k [rad/m]0 10 20 30 40 50 60

0

0.1

0.2

0.3

0.4

0.5

0.6

Am

plitu

de [

m]

k [rad/m]0 10 20 30 40 50 60

0

0.1

0.2

0.3

0.4

0.5

0.6

Am

plitu

de [

m]

k [rad/m]0 10 20 30 40 50 60

-pi

-3 pi/4

-pi/2

-pi/4

0

Pha

se [

rad]

Page 12: Announcements 10/19/12

Low Pass Filter (Theory)Low Pass Filter (Theory)

0 0.5 1 1.5 2 2.5 30

0.2

0.4

0.6

0.8

1

y an

d y fil

tere

d

[m]

x [m]

Page 13: Announcements 10/19/12

Actual Data from OscilloscopeActual Data from Oscilloscope

Page 14: Announcements 10/19/12

Periodic? “Any function periodic on a distance L can

be written as a sum of sines and cosines like this:”

What about nonperiodic functions? a. “Fourier series” vs. “Fourier transform”b. Special case: functions with finite domain

01 1

2 2( ) cos sinn n

n n

nx nxf x a a b

L L

Page 15: Announcements 10/19/12

HW 23-1

“Find y(x) as a sum of the harmonic modes of the string” Why?

Because you know how the string behaves for each harmonic—for fundamental mode, for example:

y(x,t) = Asin(x/L)cos(1t) --standing wave Asin(x/L) is the initial shape It oscillates sinusoidally in time at frequency 1

What’s y(x,t) for the second harmonic? If you can predict how each frequency component will behave, you can predict the behavior for any shape of wave! (You don’t actually have to do that for the HW problem, though.)

Page 16: Announcements 10/19/12

HW 23-1, cont.

So, how do we do it? Turn it into part of an infinite repeating

function! Thought question: Which of these two

infinite repeating functions would be the correct choice?(a) (b)

…and what’s the repetition period?

Page 17: Announcements 10/19/12

From Warmup What is the main goal of PpP section 6.6? Explain in

your own words what the point is.a. The point in this section was to come up with what

the string of a guitar looks like at any point in time [for a particular starting position]

How does Dr. Durfee achieve that goal? Explain in your own words what he is doing, mathematically.

a. [my answer] The process is to 1) write the initial shape as a sum of Fourier components, 2) attach the appropriate time dependence to each component, then 3) add the components back together to get the time dependence of the string as a whole.

Page 18: Announcements 10/19/12

Clicker question: Section 6.6 was all about the motion of a

guitar string. What was the string’s initial shape?

a. Rectified sine waveb. Sawtooth wavec. Sine waved. Square wavee. Triangle wave

Page 19: Announcements 10/19/12

What was section 6.6 all about, anyway?

What will guitar string look like at some later time?(assume h, L, and velocity v are known)

Plan: a. Figure out the frequency components in terms of

“harmonic modes of string”b. Figure out how each component changes in timec. Add up all components to get how the overall

string changes in time

h

L

initial shape:

Page 20: Announcements 10/19/12

Step 1: figure out the frequency components

a0 = ?

an = ?

bn = ?

h

L

h

L

2 2( )sin

" " " "

L

n

L

nxb f x dx

L L

integrate from –L to L:three regions

1

2 3

2 2

region1 region 2 region32 2

2 2 2 2sin sin sin

2 2 2 2

L L L

n

L L L

nx nx nxb mx b dx mx b dx mx b dx

L L L L

2 2

2 2

1 2 2 22 sin 0 sin 2 sin

L L L

n

L L L

h nx h nx h nxb x h dx x dx x h dx

L L L L L L L

Page 21: Announcements 10/19/12

Step 1: figure out the frequency components

h

L

h

L

3

2 2

32 cos sin4 4

n

n nh

bn

12 ( 1)

2 2

81 ; odd

nn

hb n

n

Page 22: Announcements 10/19/12

Step 2: figure out how each component changes

Fundamental: y = b1sin(x/L)cos(1t)

3rd harmonic: y = b3sin(3x/L)cos(3t)

5th harmonic: y = b5sin(5x/L)cos(5t)

1 = ? (assume velocity and L are known)

= 2f1 = 2(v/1) = 2v/(2L) = v/L

n = ?

h

L

Page 23: Announcements 10/19/12

Step 3: put together

Each harmonic has

y(x,t) = Asin(nx/L)cos(n1t)

= Asin(nx/L)cos(nvt/L)

h

L

12 ( 1)

2 21

odd

8( , 0) 1 sin

n

n

h n xf x t

Ln

12 ( 1)

2 21

odd

8( , ) 1 sin cos

n

n

h n x n vtf x t

L Ln

What does this look like? Mathematica!

Page 24: Announcements 10/19/12

Step 3: put together

Each harmonic has

y(x,t) = Asin(nx/L)cos(n1t)

= Asin(nx/L)cos(nvt/L)

h

L

12 ( 1)

2 21

odd

8( , 0) 1 sin

n

n

h n xf x t

Ln

12 ( 1)

2 21

odd

8( , ) 1 sin cos

n

n

h n x n vtf x t

L Ln

What does this look like? Mathematica!

Experiment!!

Page 25: Announcements 10/19/12

How about the pulse from HW 23-1?

Any guesses as to what will happen?

Page 26: Announcements 10/19/12

How about the pulse from HW 23-1?

Any guesses as to what will happen?

Experiment!!