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Algebra I
Quadratic & Non-Linear Functions
2015-11-04
www.njctl.org
http://www.njctl.org
3
Table of ContentsClick on the topic to go to that section
• Explain Characteristics of Quadratic Functions
• Graphing Quadratic Functions in Standard Form
• Transforming and Translating Quadratic Functions
• Key Terms
• Graphing Quadratic Functions in Vertex and Intercept Form
• Comparison of Types of Functions
4
Key Terms
Return to Tableof Contents
5
Axis of symmetry: The vertical line thatdivides a parabola intotwo symmetrical halves
Axis of Symmetry
6
Maximum: The y-value of thevertex if a < 0 and the parabola opens downward.
Minimum: The y-value of thevertex if a > 0 and theparabola opens upward.
Parabola: The curve resultof graphing aquadratic equation.
(+ a) Max
Min
(- a)
Parabolas
7
Quadratic Equation: An equation that can be written in the standard form ax2 + bx + c = 0. Where a, b and c are real numbers and a does not = 0.
Quadratic Function:Any function that can be written in the form y = ax2 + bx + c. Where a, b and c are real numbers and a does not equal 0.
Vertex: The highest or lowest point ona parabola.
Zero of a Function: An x value that makes the function equal zero.
Quadratics
8
Explain Characteristics of Quadratic Equations
Return to Tableof Contents
9
A quadratic equation is an equation of the form ax2 + bx + c = 0 , where a is not equal to 0.
The form ax2 + bx + c = 0 is called the standard form of the quadratic equation.
The standard form is not unique. For example, x2 – x + 1 = 0 can be written as the equivalent equation –x2 + x – 1 = 0.
Also, 4x2 – 2x + 2 = 0 can be written as the equivalent equation 2x2 – x + 1 = 0. Why is this equivalent?
Quadratics
10
Practice writing quadratic equations in standard form. (Simplify if possible.)
Write 2x2 = x + 4 in standard form.
Writing Quadratic Equations
Answ
er
11
Write 3x = –x2 + 7 in standard form.
Writing Quadratic Equations
Answ
er
12
Write 6x2 – 6x = 12 in standard form.
Writing Quadratic Equations
Answ
er
13
Write 3x – 2 = 5x in standard form.
Writing Quadratic Equations
Answ
er
14
Characteristics of Quadratic Functions
1. Standard form is y = ax2 + bx + c, where a ≠ 0.
y = –3x2 + 4x – 10
y = 5x2 – 9
y = x2 + 19
y = x2 + 5x – 2014
15
← upward→downward
2. The graph of a quadratic is a parabola, a u-shaped figure.
3. The parabola will open upward or downward.
Characteristics of Quadratic Functions
16
A parabola that opens upward contains a vertex that is a minimum point. A parabola that opens downward contains a vertex that is a maximum point.
4.
vertex
vertex
Characteristics of Quadratic Functions
17
5. The domain of a quadratic function is all real numbers.
Characteristics of Quadratic Functions
18
6. To determine the range of a quadratic function, ask yourself two questions:
> Is the vertex a minimum or maximum? > What is the y-value of the vertex?
If the vertex is a minimum, then the range is all real numbers greater than or equal to the y-value.
The range of this quadratic is [–6,∞ )
Characteristics of Quadratic Functions
19
If the vertex is a maximum, then the range is all real numbers less than or equal to the y-value.
The range of this quadratic is (–∞,10]
Characteristics of Quadratic Functions
20
–b2ax =
An axis of symmetry (also known as a line of symmetry) will divide the parabola into mirror images. The line of symmetry is always a vertical line of the form
7.
x=2
Characteristics of Quadratic Functions
y = 2x2 – 8x + 2 –(–8) 2(2)x = = 2 Teac
her N
otes
Remember "opposite of b." In this example, "b" is –8,
therefore the calculation is +8 divided by 4.
21
The x-intercepts are the points at which a parabola intersects the x-axis. These points are also known as zeroes, roots or solutions and solution sets. Each quadratic function will have two, one or no real x-intercepts.
8.
Characteristics of Quadratic Functions
22
1 True or False: The vertex is the highest or lowest value on the parabola.
True
False
23
2 If a parabola opens upward then...
A a>0
B a
24
3 The vertical line that divides a parabola into two symmetrical halves is called...
A discriminantB perfect squareC axis of symmetryD vertex
E slice
25
4 What is the equation of the axis of symmetry of the
parabola shown in the diagram below?
A x=0.5
B x=2
C x=4.5
D x=15
From the New York State Education Department. Office of Assessment Policy, Development and Administration. Internet. Available from www.nysedregents.org/IntegratedAlgebra; accessed 17, June, 2011.
26
5 The height, y, of a ball tossed into the air can be represented by the equation y = −x2 + 10x + 3, where x is the elapsed time. What is the equation of the axis of symmetry of this parabola?
A y=5B y=–5C x=5D x=–5
From the New York State Education Department. Office of Assessment Policy, Development and Administration. Internet. Available from www.nysedregents.org/IntegratedAlgebra; accessed 17, June, 2011.
27
6 What are the vertex and axis of symmetry of the parabola shown in the diagram below?
A vertex: (1,−4); axis of symmetry: x = 1
B vertex: (1,−4); axis of symmetry: x = −4
C vertex: (−4,1); axis of symmetry: x = 1
D vertex: (−4,1); axis of symmetry: x = −4
From the New York State Education Department. Office of Assessment Policy, Development and Administration. Internet. Available from www.nysedregents.org/IntegratedAlgebra; accessed 17, June, 2011.
28
7 What is the domain and range of the quadratic function?
A
B
C
D
29
8 The equation y = x2 + 3x − 18 is graphed on the set of axes below. Based on this graph, what are the roots of the equation x2 + 3x − 18 = 0?
A –3 and 6
B 0 and –18
C 3 and –6
D 3 and –18
From the New York State Education Department. Office of Assessment Policy, Development and Administration. Internet. Available from www.nysedregents.org/IntegratedAlgebra; accessed 17, June, 2011.
30
9 The equation y = − x2 − 2x + 8 is graphed on the set of axes below.
A 8 and 0
B 2 and –4
C 9 and –1
D 4 and –2
Based on this graph, what are the roots of the equation − x2 − 2x + 8 = 0?
From the New York State Education Department. Office of Assessment Policy, Development and Administration. Internet. Available from www.nysedregents.org/IntegratedAlgebra; accessed 17, June, 2011.
31
10 What is the domain and range of the quadratic function?
A
B
C
D
32
Graphing Quadratic Functions in
Standard Form
Return to Tableof Contents
33
Graph by Following Six Steps:
Step 1 - Find Axis of Symmetry
Step 2 - Find Vertex
Step 3 - Find Y intercept
Step 4 - Find two more points
Step 5 - Partially graph
Step 6 - Reflect
34
Axis of Symmetry
Step 1 - Find the Axis of Symmetry
What is the Axis of Symmetry?
Hint
The line that runs down the center of a parabola.
This line divides the graph into two perfect
halves.
35
Find the Axis of SymmetryGraph y = 3x2 – 6x + 1
Step 1
The axis of symmetryis x = 1.
Formula:a = 3b = -6
x = –b2a
x = –(–6) = 6 = 1 2(3) 6
36
y = 3(1)2 + –6(1) + 1y = 3 – 6 + 1y = –2Vertex = (1 , –2)
Find the vertex by substituting the value of x(the Axis of Symmetry) into the equation to get y.
Step 2
y = 3x2 – 6x + 1 a = 3, b = –6 and c = 1
37
y-intercept
What is they-intercept?
Find y-intercept.Step 3
Hint
The point where the line passes through the
y-axis. This occurs when the x-value is 0.
38
y = ax2 + bx + cy = 3x2 – 6x + 1
c = 1
The y-intercept is always the c value, because x = 0.
Step 3 - Find y-intercept.
Step 3Graph y = 3x2 – 6x + 1
The y-intercept is 1 and the graph passes through (0,1).
39
Step 4Graph y = 3x2 – 6x + 1
Step 4 - Find two pointsChoose different values of x and plug
in to the equation find points.Let's pick x = –1 and x = –2
y = 3x2 – 6x + 1y = 3(–1)2 – 6(–1) + 1y = 3 + 6 + 1y = 10(–1,10)
y = 3x2 – 6x + 1y = 3(–2)2 – 6(–2) + 1y = 3(4) + 12 + 1y = 25(–2,25)
40
Step 5
Step 5 - Graph the axis of symmetry, the vertex, the point containing the y-intercept and two other points.
41
(4,25)
Step 6Step 6 - Reflect the points across the axis of
symmetry. Connect the points with a smooth curve.
42
11 What is the axis of symmetry for y = x2 + 2x – 3 (Step 1)?
A 1
B –1
43
12 What is the vertex for y = x2 + 2x – 3 (Step 2)?
A (–1,–4)
B (1,–4)
C (–1,4)
44
13 What is the y-intercept for y = x2 + 2x – 3 (Step 3)?
A –3
B 3
45
14 What is an equation of the axis of symmetry of the parabola represented by y = −x2 + 6x − 4?
A x = 3
B y = 3
C x = 6
D y = 6
From the New York State Education Department. Office of Assessment Policy, Development and Administration. Internet. Available from www.nysedregents.org/IntegratedAlgebra; accessed 17, June, 2011.
46
Graph y = 2x2 – 6x + 4
Graph
47
Graph f(x) = –x2 – 4x + 5
Graph
48
Graph y = 3x2 – 7
Graph
49
On the set of axes below, solve the following systemof equations graphically for all values of x and y.
From the New York State Education Department. Office of Assessment Policy, Development and Administration. Internet. Available from www.nysedregents.org/IntegratedAlgebra; accessed 17, June, 2011
y = –x2 – 4x + 12 y = –2x + 4
Solve Equations
50
On the set of axes below, solve the followingsystem of equations graphically for all values of x and y.
y = x2 − 6x + 1y + 2x = 6
From the New York State Education Department. Office of Assessment Policy, Development and Administration. Internet. Available from www.nysedregents.org/IntegratedAlgebra; accessed 17, June, 2011.
Solve Equations
51
15 The graphs of the equations y = x2 + 4x – 1 and y + 3 = x are drawn on the same set of axes. At which point do the graphs intersect?
A (1,4)
B (1,–2)
C (–2,1)
D (–2,5)
From the New York State Education Department. Office of Assessment Policy, Development and Administration. Internet. Available from www.nysedregents.org/IntegratedAlgebra; accessed 17, June, 2011
52
Graphing Quadratic Functions in Vertex and Intercept Form
Return to Tableof Contents
53
Standard Form of a Quadratic Equation is y = ax2 + bx + c.
Vertex Form of a Quadratic Equation is y = a (x – h)2 + k, where (h, k) is the vertex and x = h is the axis of symmetry.
Intercept Form of a Quadratic Equation is y = a (x – p) (x – q), where (p, 0) and (q, 0) are the roots (or zeros) of the graph.
Quadratic Equation Forms
54
Graph in Vertex Form by Following Five Steps:
Step 1 - Draw the axis of symmetry, x = h
Step 2 - Plot the vertex, (h, k)
Step 3 - Find two more points
Step 4 - Partially graph
Step 5 - Reflect
Graph in Vertex Form
55
Step 1 - Find the Axis of SymmetryGraph y = 2(x – 4) 2 – 3
y = 2(x – 4) – 3
The axis of symmetry is x = 4.
Step 1
56
Plot the VertexGraph y = 2(x – 4)2 – 3
y = 2(x – 4)2 – 3
The Vertex is (4, –3).
Step 2
57
Find two points
Graph y = 2(x – 4)2 – 3
Choose different values of x and plug in to the equation to find points.
y = 2(x – 4)2 – 3y = 2(2 – 4)2 – 3y = 2(2)2 – 3y = 8 (2, 5)
y = 2(x – 4)2 – 3y = 2(3 – 4)2 – 3y = 2(1)2 – 3y = –1(3, –1)
Let's pick x = 2 and x = 3
Step 3
58
Step 4Graph the axis of symmetry,
the vertex, and two other points.
59
Reflect the points across the axis of symmetry. Connect the points with a smooth curve.
Step 5
60
16 What is the axis of symmetry of the equationy = –(x + 5)2 + 1?
61
17 What is the vertex of y = –(x + 5)2 + 1?A (5,1)
B (1,5)
C (–5,1)
D (5,–1)
62
18 What is the axis of symmetry of the equation ofy = .5(x - 7) 2 + 3?
63
Graph y = –(x + 5)2 + 1
Graph y
64
f(x)
Graph f(x) = .5(x – 5)2 + 3
Graph f(x)
65
Graph in Intercept Form by Following Four Steps
Graph in Intercept Form
Step 1 - Draw the axis of symmetryStep 2 - Find and Plot the vertexStep 3 - Plot the rootsStep 4 - Graph
66
–2 + 42
x =
Step 1 - Find the Axis of Symmetry Graph y = –1/3(x + 2)(x – 4)
Use the formula
The axis of symmetry isx = 1.
Graph in Intercept Form
x =p + q
2
67
Step 2 - Find and Plot the VertexGraph y = –1/3(x + 2)(x – 4)
y = –3 (x + 2) (x – 4)y = –3 (1 + 2) (1 – 4)y = –1/3 (3) (–3)y = 3
Graph in Intercept Form
68
Step 3 - Find and Plot the RootsGraph y = –1/3(x + 2)(x – 4)
y = a(x – p)(x – q)y = –1/3(x + 2)(x – 4)
p = –2 and q = 4
(–2, 0) and (4, 0) are the roots
Graph in Intercept Form
69
Step 4 - Connect the points with a smooth curve.
Graph in Intercept Form
70
19 What is the axis of symmetry of the equationy = 4(x – 5) (x + 4)?
71
20 What is the vertex of the equation y = 4(x – 5)(x + 4)?
A (0.5,–77)
B (0.5,–81)
C (0.5,81)
D (–81,0.5)
72
21 What are the roots of the equation y = 4(x–5)(x+4)?
A (0–5),(0,4)
B (0,5),(0,–4)
C (–5,0),(4,0)
D (5,0),(–4,0)
73
Graph y = 2(x–3)(x+5)
Graph in Intercept Form
74
Graph y = –.5(x–2)(x–8)
Graph in Intercept Form
75
f(x)
Graph f(x) = (x + 1)2 – 4
Graph in Intercept Form
76
f(x)
Graph f(x) = –0.5(x + 3)(x – 3)
Graph in Intercept Form
77
Transforming and TranslatingQuadratic Functions
Return to Tableof Contents
78
x x2
-3 9
-2 4
-1 1
0 0
1 1
2 4
3 9
The quadratic parent function is f(x) = x2. The graph of all other quadratic functions are transformations of the graph of f(x) = x2.
Quadratic Functions
y = x2
79
The quadratic parent function is f(x) = x 2.How is f(x) = x2 into f(x) = 2x 2?
x 2
-3 18
-2 8
-1 2
0 0
1 2
2 8
3 18
Quadratic Functions
y = x2
y = 2x2
80
x 0.5
-3 4.5
-2 2
-1 0.5
0 0
1 0.5
2 2
3 4.5
The quadratic parent function is f(x) = x 2. How is f(x) = x2 into f(x) = .5x 2?
Quadratic Functions
y = x2
y = x212
81
What does "a" do in y = ax2 + bx + c?
How does a>0 effect the parabola? How does a
82
What does "a" do in y = ax2 + bx + c?How does your conclusion about "a" change as a changes?
y = x2y = x212
y = 3x2
y = –1x2 y = –3x2 y = – x212
83
If the absolute value of a is > 1, then the graph of the function is narrower than the graph of the parent function.
If the absolute value of a is < 1, then the graph of the function is wider than the graph of the parent function.
If a > 0, the graph opens up.
If a < 0, the graph opens down.
What does "a" do in y = ax2 + bx + c?
84
0 1
parent function
narrowerwider
2
Consider an "absolute value" number line to compare a parabola to parent function.
Absolute Value
y = 0.5x2
y = x2
y = 1.75x2
85
22 Without graphing determine which direction does the parabola open and if the graph is wider or narrower than the parent function.
A up, wider
B up, narrower
C down, wider
D down, narrower
y = .3x2
86
23 Without graphing determine which direction does the parabola open and if the graph is wider or narrower than the parent function.
A up, wider
B up, narrower
C down, wider
D down, narrower
y = –4x2
87
24 Without graphing determine which direction does the parabola open and if the graph is wider or narrower than the parent function.
A up, wider
B up, narrower
C down, wider
D down, narrower
y = –4x2 + 100x + 45
88
y = – x223
25 Without graphing determine which direction does the parabola open and if the graph is wider or narrower than the parent function.
A up, wider
B up, narrower
C down, wider
D down, narrower
89
26 Without graphing determine which direction does the parabola open and if the graph is wider or narrower than the parent function.
A up, wider
B up, narrower
C down, wider
D down, narrower
y = – x275
90
What does "c" do in y = ax2 + bx + c?
y = x2 + 6
y = x2 + 3
y = x2
y = x2 – 2
y = x2 – 5y = x2 – 9
91
What does "c" do in y = ax2 + bx + c?
"c" moves the graph up or down the same value as "c."
"c" is the y-intercept, when the graph is in standard form.
92
27 Without graphing, what is the y-intercept ofthe given equation?
y = x2 + 17
93
28 Without graphing, what is the y-interceptof the given equation?
y = –x2 – 6
94
29 Without graphing, what is the y-interceptof the given function?
f(x) = –3x2 + 13x – 9
95
30 Without graphing, what is the y-interceptof the given equation?
y = 2x2 + 5x
96
31 Choose all that apply to the following quadratic:
A opens upB opens down
C wider than parent function
D narrower than parent function
E y-intercept of y = –4
F y-intercept of y = –2
G y-intercept of y = 0
H y-intercept of y = 2I y-intercept of y = 4
J y-intercept of y = 6
f(x) = –.7x2 – 4
97
32 Choose all that apply to the following quadratic:
A opens upB opens down
C wider than parent function
D narrower than parent function
E y-intercept of y = –4
F y-intercept of y = –2
G y-intercept of y = 0
H y-intercept of y = 2I y-intercept of y = 4
J y-intercept of y = 6
f(x) = x2 – 6x43
98
33 The diagram below shows the graph of y = –x2 – c.
A B C D
Which diagram shows the graph of y = x2 – c?
From the New York State Education Department. Office of Assessment Policy, Development and Administration. Internet. Available from www.nysedregents.org/IntegratedAlgebra; accessed 17, June, 2011.
99
What does "d" do in y = (x – d)2?
y = (x + 4)2 y = x2 y = (x - 4)2
100
"d" moves the graph left or right, the same value as "d."
In this form "d" is the x-intercept.
What does "d" do in y = (x – d)2?
101
34 Without graphing, what is the x-intercept of the given equation?
A (2, 0)
B (–2,0)
y = (x + 2)2
102
35 Without graphing, what is the x-interceptof the given function?
A (7,0)
B (–7,0)
f(x) = (x – 7)2
103
36 Without graphing, what is the x-interceptof the given function?
f(x) = (x + 11)2
104
37 For the following quadratic, choose all that apply...
A opens up
B opens down
C wider than the parent function
D narrower than the parent function
E x-intercept is (6,0)
F x-intercept is (–6,0)
G x-intercept is (–3,0)
H y-intercept is (0,6)
I y-intercept is (0,–6)
J y-intercept is (0,–3)
f(x) = –5x2 – 3x + 6
105
38 For the following quadratic, choose all that apply...
A opens up
B opens down
C wider than the parent function
D narrower than the parent function
E x-intercept is (6,0)
F x-intercept is (-6,0)G x-intercept is (-3,0)
H y-intercept is (0,6)
I y-intercept is (0,-6)
J y-intercept is (0.-3)
f(x) = (x + 6)214
106
39 For the following question, choose all that apply...
A opens up
B opens down
C wider thant the parent function
D narrower than the parent function
E vertex is (–5,9)
F vertex is (5,–9)
G vertex is (–5,–9)
H vertex is (–2,5)
f(x) = –2(x + 5)2 + 9
107
Return to Tableof Contents
Comparison of Types of Functions
108
Thus far we have learned:
1. The characteristics of a quadratic function. 2. How to graph a quadratic function. 3. Transformations and translations of quadratic
functions.
Next we will compare at least two different functions to each other. We will look at Quadratic, Linear, and Exponential Functions in terms of y-intercept, rate of change at an interval, maximum or minimum at an interval, and evaluate at a point.
Review
109
f(x)
x
x g(x)
–6 –2
–3 –0.5
0 1
4 3
In the next few questions we will compare key features of the two functions below. The linear function represented by the table and the quadratic function represented by the graph.
Comparison Functions
110
f(x)
x
x g(x)
–6 –2
–3 –0.5
0 1
4 3
Compare the y-intercepts of the functions.
The y-intercept of g(x) is (0,1) and f(x) is (0,–1)
g(x) > f(x)
Compare y-intercepts
111
f(x)
x
x g(x)
–6 –2
–3 –0.5
0 1
4 3
Compare the functions at f(2).
Referring to the graph for f(x), f(2) is approximately 3.Referring to the table of values for g(x) is between 1 and 3.
At f(2) g(x) < f(x)
Compare Functions
112
f(x)
x g(x)
–6 –2
–3 –0.5
0 2
4 3
Compare the rate of change over the interval –3 ≤ x ≤ 0
To find the rate of change of the functions,find the slope at the intervals.
Compare Rate of Change
x
113
At the interval g(x) > f(x)
= = =∆g(x)∆x
g(0) – g(–3)0 – (–3)
1 – (–0.5)0 + 3
12
= = = –1∆f(x)∆x
f(0) – f(–3)0 – (–3)
–1 –20 + 3
Compare Rate of ChangeCompare the rate of change over the interval –3 ≤ x ≤ 0
slope(m) = =∆y∆x
y2 – y1x2 – y1
114
40 Compare the y-intercepts of the functions.
A g(x)h(x)
C g(x)=h(x)
g(x)
x
x –2 0 2 5f(x) –13 –7 –1 3
115
41 Compare the y-intercepts of the functions.
A g(x)h(x)
C g(x)=h(x)
g(x)
x
x –2 0 2 5f(x) –13 –7 –1 3
116
42 Compare the rate of change of the functions over the interval –2≤ x ≤ 2.
A g(x)h(x)
C g(x)=h(x)
g(x)
x
x –2 0 2 5f(x) –13 –7 –1 3
117
43 Compare the y-intercepts of the functions.
A g(x)h(x)
C g(x)=h(x)
g(x)x
x –5 –1 1 3h(x) –13 –5 –1 3
118
44 Compare g(2) and h(2).
A g(x)h(x)
C g(x)=h(x)
g(x)x
x –5 –1 1 3h(x) –13 –5 –1 3
119
45 Compare the minimum value g(x) to f(x).
A g(x)f(x)
C g(x)=f(x)
g(x)
x
f(x) = (x – 3)(x + 4)14
Hin
t
120
46 Compare the maximum value of h(x) to f(x).
A h(x)f(x)
C h(x)=f(x)
h(x) = –7(x – 12)2 + 41
f(x) = –14x2 + 23x – 57
Hin
t
121
47 Compare the rate of change of the functionson the interval
A g(x)f(x)
C g(x)=f(x)
x –2 0 2 5f(x) –3 –1 1 4
122
In the next few questions we will compare key features of the two functions below. The linear function represented by the graph and the exponential function represented by the table.
x h(x)
0 1
1 3
2 9
3 27
Compare Functions
g(x)
x
123
x h(x)
0 1
1 3
2 9
3 27
Compare the y-intercepts of the functions.
The y-intercept of g(x) is (0,1). The y-intercept of h(x) is (0,1). The y-intercepts of the functions are equal.
g(x)
x
Compare y-intercepts
124
x h(x)
0 1
1 3
2 9
3 27
g(x)
Compare the rate of change over the interval 0 ≤ x ≤ 1.
Compare Rate of Change
125
Compare Rate of Change
Compare the rate of change over the interval 0 ≤ x ≤ 1.
At the interval g(x) > h(x)
= = =∆g(x)∆x
g(1) – g(0)1 – 0
4 – 11
3
= = = 2∆h(x)∆x
f(1) – f(0)1 – 0
3 – 11
126
x h(x)
0 1
1 3
2 9
3 27
g(x)
x
Compare the rate of change over the interval 1 ≤ x ≤ 2.
Compare Rate of Change
127
Compare Rate of Change
Compare the rate of change over the interval 1 ≤ x ≤ 2.
At the interval g(x) < h(x)
= = =∆g(x)∆x
g(2) – g(1)2 – 1
7 – 41
3
= = = 6∆h(x)∆x
h(2) – h(1)2 – 1
9 – 31
128
48 Compare the y-intercepts of the functions.
A g(x)f(x)
x –1 0 1 2f(x) 1.5 3 6 12
g(x)x
129
49 Compare the rate of change over the interval -2 ≤ x ≤ 0
A g(x)f(x)
x -2 0 2 4
f(x) 0.75 3 12 48
g(x)
x
130
50 Compare the rate of change over the interval 0 ≤ x ≤ 2
A g(x)f(x)
x -2 0 2 4
f(x) 0.75 3 12 48
g(x)x
131
51 Compare the y-intercepts of the functions.
A h(x)f(x)
f(x) = 1/5x +6
h(x)
x
132
52 Compare the rate of change over the interval 0 ≤ x ≤ 1
A h(x)f(x)
f(x) = 1/5x +6
h(x)
x
133
The next four problems are comparisons between linear, quadratic, and exponential functions.
Next Four Problems
134
g(x)
h(x)
f(x)
53 Compare the y-intercepts of the functions.
A g(x)
135
g(x)
h(x)
f(x)
54 Which function has the greatest rate of changeover the given interval?
A g(x) B h(x) C f(x)
–2 ≤ x ≤ –1
Answ
er
∆h(x)∆x
∆g(x)∆x
∆f(x)∆x
136
55 Which function has the greatest rate of changeover the given interval?
A g(x) B h(x) C f(x)
–1 ≤ x ≤ –1
g(x)
h(x)
f(x)
Answ
er
∆h(x)∆x
∆g(x)∆x
∆f(x)∆x
137
56 Which function has the greatest rate of changeover the given interval?
A g(x) B h(x) C f(x)
0 ≤ x ≤ 1
g(x)
h(x)
f(x)
Answ
er