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Algebra 2: Section 6.4 Factoring and Solving Polynomial Equations

Algebra 2: Section 6.4

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Page 1: Algebra 2: Section 6.4

Algebra 2: Section 6.4

Factoring and Solving Polynomial Equations

Page 2: Algebra 2: Section 6.4

Factoring Quadratics

1. 4x2 24x

4x(x 6)

Common Factor: 4x

Page 3: Algebra 2: Section 6.4

Factoring Quadratics

2. 2x2 11x 21

(2x_____)(x_____)

Two factors of -21 that when

FOI LED make the middle

term +11

(2x 3)(x 7)

Page 4: Algebra 2: Section 6.4

Factoring Quadratics

23. 4x 36 81x

(2x)2 2 2x 9 (9)2

(2x 9)2

Perfect Square Trinomial

Page 5: Algebra 2: Section 6.4

Sum and Difference of Cubes

a3 b3 (a b)(a2 ab b2)

a3 b3 (a b)(a2 ab b2)

x3 64 (x 4)(x2 4x 16)

27x3 8 (3x 2)(9x2 6x 4)

Page 6: Algebra 2: Section 6.4

Examples

4. 125 x3

x3 53

(x 5)(x2 5x 52)

(x 5)(x2 5x 25)

Rewrite as sum of cubes

(Changed order, standard)

Page 7: Algebra 2: Section 6.4

Factoring by Grouping(used when there are 4 terms)

• Factor common factor out of first two terms

and factor another common factor out of last

two terms

(may need to rearrange)

• Factor common binomial out of each ‘term’

Page 8: Algebra 2: Section 6.4

Examples

5. x2y2 3x2 4y2 12

x2(y2 3) 4(y2 3)

(y2 3)(x2 4)

(y2 3)(x 2)(x 2)

Difference of two squares

Page 9: Algebra 2: Section 6.4

Examples2 2 3 46. a 8 16b ab b

b2(a2 8ab 16b2)

b2(a 4b)(a 4b)

b2(a 4b)2

Page 10: Algebra 2: Section 6.4

Examples47. 25x 36

(5x2)2 (6)2

Difference of two squares

(5x2 6)(5x2 6)

Page 11: Algebra 2: Section 6.4

W hich method of factoring?

• 2 terms

• 3 terms

• 4 terms

• Diff. of Squares

• Sum or Diff. of Cubes

• Trial and Error

• Perfect Square Trinomial

• Grouping

Always look for common

factor!!

Page 12: Algebra 2: Section 6.4

Solving Polynomial Equations by

Factoring

(Examples)58. 2 18 0y y

42 ( 9) 0y y2 22 ( 3)( 3) 0y y y

Difference of two squares

2 22 0 3 0 3 0y or y or y

0 3 3y or y or y i

0 3y or yFor this assignment,

only concerned with

real solut ions

Page 13: Algebra 2: Section 6.4

More Examples5 29. 4 108 0x x

2 34 ( 27) 0x x2 24 ( 3)( 3 9) 0x x x x

Difference of two cubes

2 24 0 3 0 3 9 0x or x or x x

3 9 4(1)(9)0 3

2x or x or x

0 3x or xThis is going to be

imaginary.

The discriminant is

negative!

Page 14: Algebra 2: Section 6.4

Assignment

• p.349

# 33-85 all, 87, 88

(55 problems)

• Due W ednesday!