Upload
ariel-wheeler
View
221
Download
0
Tags:
Embed Size (px)
Citation preview
Learning Targets
• Language Goal: Students will be able describe an appropriate method for factoring a polynomial.
• Math Goal: Students will be able to combine methods for factoring a polynomial.
• Essential Question: Why is it important to have multiple methods to factor polynomials?
Example Type 1: Determining Whether a Polynomial Is Completely Factored
Tell whether the polynomial is completely factored. If not, factor it.
A. 2x(x² + 4) B. (2x + 6)(x + 5) C. 5x²(x – 1)
Example Type 1: Determining Whether a Polynomial Is Completely Factored
Tell whether the polynomial is completely factored. If not, factor it.
D. (4x + 4)(x + 1) E. 3x²(6x – 4) F. (x² + 1)(x – 4)
Example Type 1: Determining Whether a Polynomial Is Completely Factored
Tell whether the polynomial is completely factored. If not, factor it.
G. 3x(9x² – 4) H. 2(x³ – 2x² – 8x)
Factoring Polynomials
Step 1: Check for a greatest common factor.Step 2: Check for a pattern that fits the difference of two squares or a perfect-square trinomial.Step 3: - To factor x² + bx + c, look for two numbers whose sum is b and whose product is c. (Product Sum Method)- To factor ax² + bx + c, check factors of a and factors of c in the binomial factors. The sum of the products of the outer and inner terms should be b. (Boston MethodStep 4: Check for common factors
F act or i ng a P olynomi al
Is there a GCF?
No Yes
Is there a quadratic left? (Degree 2)
No Yes How many terms are
left?
3 2
Are they subtracted & perfect squares?
What value does a have?
No Yes
a ≠ 1 a = 1
Difference of Two Squares
Product Sum Rule Boston Method
Example Type 2: Factoring by GCF and Recognizing Patterns
Factor completely. Check your answer.A. B.
Example Type 2: Factoring by GCF and Recognizing Patterns
Factor completely. Check your answer.C. 2x²y – 2y³ D. 10x² + 48x + 32
Example Type 3: Factoring by Multiple Methods
Factor each polynomial completely.A. 2x² + 5x + 4 B. 3n – 15n³ + 12n²
𝑎𝑏−𝑎𝑐=𝑎(𝑏−𝑐)6 𝑥2 𝑦+10𝑥𝑦 2=2 𝑥𝑦 (3 𝑥+5 𝑦 )
𝑎2−𝑏2=(𝑎−𝑏)(𝑎+𝑏)𝑥2−9 𝑦2=(𝑥−3 𝑦 )(𝑥+3 𝑦 )
𝑎𝑥+𝑏𝑥+𝑎𝑦+𝑏𝑦=𝑥 (𝑎+𝑏 )+𝑦 (𝑎+𝑏)=(x+ y)(a+b)2 𝑥3+4 𝑥2+𝑥+2 𝑦=2 𝑥2 (𝑥+2 )+1 (𝑥+2 )=( x+2)(2𝑥2+1)