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Reaction Car. Alex Cabrera Spencer Allen Ryan Miller . Reaction Chemistry. NaHCO 3 (s) + HCl(aq ) NaCl(aq ) + H 2 O(l) + CO 2 (g) n =(PV)/(RT)=[(5atm)(.7 L)]/[(.0821 L-A/mol-K)(293 K)] n = .14 mol Thus, we want roughly .14 mol of each reactant - PowerPoint PPT Presentation
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ALEX CABRERASPENCER ALLEN
RYAN MILLER
REACTION CAR
Reaction Chemistry NaHCO3(s) + HCl(aq) NaCl(aq) + H2O(l) + CO2(g)
n=(PV)/(RT)=[(5atm)(.7 L)]/[(.0821 L-A/mol-K)(293 K)]n= .14 molThus, we want roughly .14 mol of each reactant
NaHCO3(s) + HCl(aq) (+20mL H2O)~.14 mol 12.1M(84 g/mol) ~.14 mol~12 g ~12 mL
NaCl(aq) + H2O(l) + CO2(g) ~.14 mol
Car Design Original Design:
Car Design Second design (significantly expanded back
axel):
Testing Results Initially we wanted to go the distance without
spewing, but it became apparent that our car was not going to do that very easily. After three tries of it going 2-4 ft, we decided to turn it around and let it spew. This made a significant difference, as can be seen on the next slide. We then, however, encountered a problem with it tipping. We compensated for this by expanding the back axel. This stopped it from tipping and we were able to achieve acceptable results. There was very little variation from our measurements, as it seemed to be the design of the car that largely affected the overall outcome.
Data and Plots
1 2 3 4 5 6 70
5
10
15
20
25
trial # vs distance (ft)
distance (ft)
trial
Conclusion Our redesigned back axel that saved us
on the first day was not enough for the finals. The axel had become slightly more bent, and instead of going straight, the car regularly veered off to the left. If we could have (or would have) replaced the back axel with less bent pieces, I feel that the car would have come much closer to the desired distance. As it was, the car was inconsistent and very hard to predict.