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albat ross D. exulans -- up to 12 kG and 3.6 m wingspan

Albatro ss D. exulans -- up to 12 kG and 3.6 m wingspan

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How do we understand the effects of differences in size on the structures and processes of organisms? In the previous two slides, body mass differed by: 12,000/0.6 = 2000X This is over 3 orders of magnitude!

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Page 1: Albatro ss D. exulans -- up to 12 kG and 3.6 m wingspan

albatross

D. exulans -- up to 12 kG and 3.6 m wingspan

Page 2: Albatro ss D. exulans -- up to 12 kG and 3.6 m wingspan

Hummingbird Bee hummingbird Mellisuga helena

0.6 g and 0.06 m wingspan

Source: http://www.birdlife.org/images/sized/450/b_bee_hummingbird.jpg.jpg

Page 3: Albatro ss D. exulans -- up to 12 kG and 3.6 m wingspan

How do we understand the effects of differences in size on the structures and processes of organisms?

In the previous two slides, body mass differed by:

12,000/0.6 = 2000X

This is over 3 orders of magnitude!

Page 4: Albatro ss D. exulans -- up to 12 kG and 3.6 m wingspan

Scaling

• A technique for determining how two phenotypic variables change with respect to each other.

• Most useful when the variables are considered over wide ranges of values.

• The variables can be morphological or process.

• Therefore, useful in answering large scale questions about biological design.

Page 5: Albatro ss D. exulans -- up to 12 kG and 3.6 m wingspan

Isometric and Allometric Scaling

When two variables have a linear relationship with respect to each other, we say that they scale isometrically. With respect to size this means that they are scale models of each other.

However, if the relationship is non-linear it means that the two organisms are not exact scale models of each other with respect to the variables of interest. We call this allometric scaling.

Page 6: Albatro ss D. exulans -- up to 12 kG and 3.6 m wingspan

Graphically

Page 7: Albatro ss D. exulans -- up to 12 kG and 3.6 m wingspan

Equations

Isometric: -- if similarity is maintained, a = 1

Y = mX1.0 + b

Allometric: -- here a has any value not close to 1.0

Y = mXa+ b

Generalized power function:

Y = mXa+ b

Page 8: Albatro ss D. exulans -- up to 12 kG and 3.6 m wingspan

Double log Plots of Scaling Relationships

log(Y) = slope log(X) + log (y-intercept)

log(Y) = b * log(X) + log(a)

Page 9: Albatro ss D. exulans -- up to 12 kG and 3.6 m wingspan

Metabolism and Body Size

Isometric:

log(Q) = 1.0*log(M) + log(a)

Allometric -- many possible versions differentiated from each other by their value of the coefficient of log(M).

Let’s use one that presupposes that metabolism is constrained by surface area. Why SA?

Page 10: Albatro ss D. exulans -- up to 12 kG and 3.6 m wingspan

Derivation of a SA Model Where SA is Expressed in Terms of Mass (volume)0.67

Volume L3 or V = k1*L3

L V0.334 or L= k1* V0.334

Volume1.0 Mass1.0 or V1.0 = k2* M1.0

L M0.334 or L = k3 * M0.334

SA L2 or SA = k3*L2

SA (M0.334)2 or SA = k4 * M0.67

Page 11: Albatro ss D. exulans -- up to 12 kG and 3.6 m wingspan

Double Log Plots of the Models

Page 12: Albatro ss D. exulans -- up to 12 kG and 3.6 m wingspan

Hemmingsen

Page 13: Albatro ss D. exulans -- up to 12 kG and 3.6 m wingspan

Explanations

Compromise between need to maintain a per unit tissue metabolic rate and the surface constraint.

Page 14: Albatro ss D. exulans -- up to 12 kG and 3.6 m wingspan

What happens to the metabolism of a unit mass of tissue with change in size?

Page 15: Albatro ss D. exulans -- up to 12 kG and 3.6 m wingspan

Given the Allometry, How Is it Best To Compare Animals to See if they Conform to the Allometry?

See how close they come to overall regression

“% expected”

Divide metabolic rate by mass raised to the expected scaling coefficient for the group -- thus, for most groups, divide by M0.75 or the “known” exponent for that group (known to the extent that different animals have been measured)