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Acids Acids & & Bases Bases Calculating pH and Calculating pH and Naming Naming

Acids & Bases

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Acids & Bases. Calculating pH and Naming. Finding the pH of Solutions. Self- ionization of water – the simple dissociation of water H 2 O H + + OH - Concentration of ea. ion in pure water: [H + ] = 1.0 x 10 -7 M + [OH - ] = 1.0 x 10 -7 M - PowerPoint PPT Presentation

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Page 1: Acids  &  Bases

Acids Acids & &

BasesBasesCalculating pH and Calculating pH and

NamingNaming

Page 2: Acids  &  Bases

Finding the pH of SolutionsSelf- ionization of water – the simple dissociation of water

H2O H+ + OH-

Concentration of ea. ion in pure water: [H+] = 1.0 x 10-7M + [OH-] = 1.0 x 10-7M

Ion-product constant for water (Kw), Where KWhere Kww = 1.0 x 10 = 1.0 x 10-14-14

KKww = [H = [H++] [OH] [OH--]]

Acid [H+] > [OH-] Base [H+] < [OH-]

Neutral [H+] = [OH-]

Page 3: Acids  &  Bases

pH Scale

pH = -log[H+]

pOH = -log[OH-]

pH + pOH = 14

Page 4: Acids  &  Bases

[OH-] pOH pH [H+]

1 x 10-14 14 0 1 x 100

1 x 10-13 13 1 1 x 10-1

1 x 10-12 12 2 1 x 10-2

1 x 10-11 11 3 1 x 10-3

1 x 10-10 10 Increasing acidity 4 1 x 10-4

1 x 10-9 9 5 1 x 10-5

1 x 10-8 8 6 1 x 10-6

1 x 10-7 7 Neutral 7 1 x 10-7

1 x 10-6 6 8 1 x 10-8

1 x 10-5 5 9 1 x 10-9

1 x 10-4 4 Increasing basicity 10 1 x 10-10

1 x 10-3 3 11 1 x 10-11

1 x 10-2 2 12 1 x 10-12

1 x 10-1 1 13 1 x 10-13

1 x 100 0 14 1 x 10-14

Page 5: Acids  &  Bases

Example1. If the [H+] in a solution is 1.0 x 10-5M, is the

solution acidic, basic or neutral?

1.0 x 10-5 M

What is the concentration of the [OH-]?Use the ion-product constant for water (Kw):

Kw = [H+] [OH-] 1.0 x 10-14 = [1.0 x 10-5] [OH-] 1.0 x 10-14 = [OH-] 1.0 x 10-5

1.0 x 10-(14-5)

pH 5 = acidic

1.0 x 10-9 OH-

Page 6: Acids  &  Bases

Examples2. If the pH is 9, what is the concentration of

the hydroxide ion?

Kw = [H+] [OH-]

1.0 x 10-14 = [1.0 x 10-9] [OH-]

1.0 x 10-5 = [OH-]

3. If the pOH is 4, what is the concentration of the hydrogen ion?

Kw = [H+] [OH-]

1.0 x 10-14 = [H+] [1.0 x 10-4]

1.0 x 10-10 = [H+]

14 = pH + pOH

14 = 9 + pOH

5 = pOH

14 = pH + pOH

14 = pH + 4

10 = pH

Page 7: Acids  &  Bases

Example

4. A solution has a pH of 4. Calculate the pOH, [H+] and [OH-]. Is it acidic, basic, or neutral?

– pOH = 14.00- 4 = 9

– acidic

M101][OH 9

M4101][H

Page 8: Acids  &  Bases

Fill in the chart.

[OH-] pOH pH [H+]

8

1x 10-12

10

1 x 10-3

5

1 × 10-1

1.0 X 10 -8

1.0 X 10 -2

1.0 X 10 -6

6

2 12

Page 9: Acids  &  Bases

Naming Acids

• Binary acids

– Contains 2 different elements: H and another

– Always has “hydro-” prefix

– Root of other element’s name

– Ending “-ic”

– Examples: HI, H2S, HBr

Page 10: Acids  &  Bases

Naming Acids

• Ternary Acids - Oxyacids

– Contains 3 different elements: H, O, and another

– No prefix

– Name of polyatomic ion

– Ending “–ic” for “-ate” and “–ous” for “-ite”

– Examples: HClO4, H3PO4, HNO2

Page 11: Acids  &  Bases

Practice

• H2SO3

– Sulfurous acid• HF

– Hydrofluoric acid

• H2Se

– Hydroselenic acid

• Perchloric acid

– HClO4

• Carbonic acid

– H2CO3

• Hydrobromic acid– HBr