25
Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand the concepts Science 10 CT05D01 Resource: Brown, Ford, Ryan, IB Chem

Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

Embed Size (px)

Citation preview

Page 1: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

Acid/Base Chemistry

Chapter 12 (Topic 5)

Please note that the chapter does not go in sequence with our lecture material, but you must still understand

the concepts

Science 10CT05D01Resource: Brown, Ford, Ryan, IB Chem

Page 2: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

Topic 05 – Acids/Bases

5.1 Solutions 5.2 Definitions of Acids and Bases 5.3 Properties of Acids and Bases 5.4 Calculating pH, pOH, H+, OH- 5.5 Neutralization equations 5.6 Titrations We will come back to Topic 04 (Redox)

following the completion of Acids/Bases

Page 3: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.1 - Solutions 5.1.1 Define solute, solvent, solution,

suspension, homogeneous, heterogeneous 5.1.2 Determine the molarity of solutions,

given any of the two variables (M = mol / L) L = dm3

5.1.3 Calculate the dilution or concentration of solutions (M1 x V1 = M2 x M2)

5.1.4 Solubility and solubility curves

Page 4: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.2 - Definitions of Acids and Bases

5.2.1 Arrhenius: Acids donate H+, Bases donate OH- ions in solution

5.2.2 Lowry/Bronsted: Acids donate a proton, Bases accept a proton (H+)

Page 5: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.3 Properties of Acids and Bases

5.3.1 Acids (donate H+, turn litmus red, corrode active metals, neutralize bases, taste sour)

5.3.2 Bases (donate OH-, turn litmus blue, denature protein, neutralize acids, taste bitter

Page 6: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.4 Calculating pH, pOH, H+, OH-

5.4.1 Calculate the concentration of ions (H+ and OH-) and acidity (pH and pOH) of strong acids and bases

5.4.2 Calculate the above of a mixture of strong acids and bases

Page 7: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.5 Neutralization equations

5.5.1 Balance simple acid base equations 5.5.2 Conjugate Acid/Base pairs

Page 8: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.6 Titrations

5.6.1 Complete titration calculations (MA x VA = MB x VB)

5.6.2 Identify the parts of a titration curve 5.6.3 Buffer action of weak acids and bases

Page 9: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.1 - Solutions

The solute is the material in the smaller amount that is being dissolved

The solvent is the material in the greater quantity in which the solute will dissolve. Water is the universal solvent, but other organic solvents such as ethanol are common as well

The Solution is a dissolved homogeneous mixture of two

compounds

Page 10: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.1 - Solutions

A suspension is found in a heterogeneous solution, that is due to the presence of insoluble particles added to the solvent material.

Turbulent water, and many powders (often protein shakes) can be insoluble

Page 11: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.1 - Concentration

The concentration of a solution is a measurement of the amount of solute present in a given quantity of solvent.

The solute must be soluble and the solvent a liquid (generally water)

The unit common for representing concentration is M or molar concentration The number of moles of solute in 1.0 L of

solution

Page 12: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.1 - Solutions

In order to solve for molarity we will often have to make mole conversions

Do you remember how to convert between moles and grams, grams and moles, mole and molecules, molecules and moles?

How do you calculate the molar mass of a compound?

What is avogadros number? How would you convert from mL to L, L to

mL?

Page 13: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

Moles to Mass

(use Molar Mass)

Moles to Volume

(Molar Volume of a gas 22.4)

Moles to Molecules

(use Avogadro’s Number)

Page 14: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

Simple Conversions:

80. g CuSO4

159.5 g CuSO4

1 mol CuSO4 = 0.50 mol

CuSO4

0.50 mol CuSO4

159.5 g CuSO41 mol CuSO4

= 80. g CuSO4

- Mole / Mass Conversions -

Use the Molar Mass of a substance to convert from Moles to Mass and Mass to Moles

Mass to Moles

Moles to Mass

Page 15: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

2 mol CuSO46.022x1023 (mc) CuSO4

1 mol CuSO4

= 1.2x1024 (mc) CuSO4

= 2 mol CuSO4

6.022x1023 (mc) CuSO4

1 mol CuSO4

1.2x1024 (mc) CuSO4

Simple Conversions:- Mole / Molecule Conversions -

Use Avogadro’s Number : 6.022 x 1023 molecules (mc) in one mole of the substance

Moles to (mc)

(mc) to Moles

Page 16: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.1 – Molarity Example

A 1.46 M glucose (C6H12O6) solution contains 1.46 moles of the solute in 1L of solution

Not all solutions are 1.0 L, what if I only have 500mL of the solution

It’s simple, you simply have half the volume so half the moles, molarity stays the same

Page 17: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.1 – Molarity Example

What is the molarity of a solution containing 1.25 moles sodium chloride in 345 mL of solution?

What is the molarity of a solution containing 3.0 g potassium chloride in 500 mL of solution

Page 18: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.1 – Dilution of Solutions

To dilute means to decrease the concentration by increasing the solvent amount Sweet tea is too strong, add water

To concentrate means to increase the concentration by decreasing the solvent amount, or adding more solute. Boil salt water Add more Gatorade mix to your drink

Page 19: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.1 – Dilution of Solutions

In chemical stockrooms, concentrated solutions are often stored and diluted when needed for laboratory purposes. These are called stock solutions.

Dilution is a procedure for preparing a less concentrated solution from a more concentrated solution

There is a simple dilution equation for this:

Where M = molarity, V = volume And 1 = concentrated, 2 = diluted

Page 20: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.1 – Dilution of Solutions

Suppose your teacher needs to prepare 1.0L of 0.400 M H2SO4 but currently has a large supply of 12.00 M H2SO4. How can this be achieved? Use the dilution equation, M1 = 12.00 M H2SO4

V1 = ? (trying to find how much) M2 = 0.400 M H2SO4

V2 = 1.0 L When you solve for V1 you will find that you

need to dilute 33 mL of the stock solution of 12.00 M H2SO4 to a volume of 1.0 L with water.

Page 21: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.1 - Types of solutionsSaturated Solution – contains the maximum amount of a solute that will dissolve in a given solvent at a specific temperatureUnsaturated Solution – contains less than solute than it has capacity to dissolve. Supersaturated Solution – contains more solute than is present in a saturated soln.

Page 22: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.1 - Crystallization

Crystallization is the process in which dissolved solute comes out of solution and forms crystalsUsually occurs with a drop in temperature

Page 23: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.1 - Changing the Temperature of Solutions

Remember, a saturated solution is defined at a ‘specific temperature.’If the temperature is changed, the solvent can hold differing amounts of solute. We can demonstrate how this might happen by using a solubility curve.

Page 24: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

TEMPERATURE

SOLUBILITY in grams/100 ml of water

Co KCl KNO3 NH3

0 28 15 90

10 30 23 70

20 33 33 52

30 35 46 42

40 38 62 34

50 40 80 28

60 44 110 23

70 47 130 18

80 50 - 15

90 54 - 10

100 57 - 7

Page 25: Acid/Base Chemistry Chapter 12 (Topic 5) Please note that the chapter does not go in sequence with our lecture material, but you must still understand

5.1 - Solubility Curves

Gases decrease in solubility with an increase in temperatureSolid and liquid solubility increases