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Acid Delution Calculations

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Acid Delution

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  • (Vol dilute) (% Acid in dilute) (Sp Gr dilute)

    (% Acid in strong) (Sp Gr strong)Volume of strong =

  • (Vol strong) (% Acid in strong) (Sp Gr strong)

    (% Acid in dilute) (Sp Gr dilute)Volume of dilute =

  • (Vol desired) (desired %) (Sp Gr desired)

    (Orig acid %) (Sp Gr orig acid)(Volume desired) -

    Volume of water necessary =

  • (Vol of desired) (desired %) (Sp Gr desired)

    (Orig acid %) (Sp Gr orig acid)-

    Volume of strong acid necessary =

    (Vol orig) (Orig %) (Sp Gr orig)

    (Strong %) (Sp Gr strong)

  • Density of Hydrochloric Acid Versus Percentage Composition.

  • SG = 145/(145-21.15) = 1.17

    SGsolution = 28%/2+1 = 1.14

    Be= 145-145/1.14 = 17.81

  • SG = x%/2+1 = 1.0749

    % = 2 (1.0749-1) = 15%

  • 5000*0.15*(0.15/2+1)Vstrong = ----------------------------- = 2172 gallons

    0.32*(0.32/2+1)

  • 15000*0.075*(0.075/2+1)Vstrong = ---------------------------------- = 3657 gallons

    0.28*(0.28/2+1)

  • SG = 7.5%/2+1=1.0375

    SG = 15%/2 +1 = 1.075

    gals = 3000 :1.0375/1.075 = 3108 gal

  • SG = 12.5%/2+1=1.0625

    SG = 145/(145-20.9) = 1.1684

    gals = 5000 :1.0625/1.1684 = 5498 gal

    Bbls = 5498/42 = 134 bbls

  • SG = 15%/2+1=1.075

    SG = 145/(145-21.5) = 1.1741

    gals = 5000 :1.1741/1.075 = 4578 gal

  • SG = 28%/2+1=1.14

    SG = 145/(145-21) = 1.1694

    gals = 7500 :1.14/1.1694 = 7693 gal

  • SG = 32%/2+1=1.16

    SG = 7.5%/2+1 = 1.0375

    bbl = 2500 :1.16/1.0375 = 224 bbl

    Bbls water = 250-224= 26bbls

  • SG = 15%/2+1=1.075

    SG = 145/(145-21.9) = 1.1779

    bbls = 450 :1.075/1.1779 = 493 bbls

  • SG = 28%/2+1=1.14

    SG = 10%/2+1= 1.05

    gals = 5000 :1.05/1.14 = 5429 gal

  • SG = 1.0749

    SG = 15%/2+1= 1.075

    gals = 20 gal

  • SG = 15%/2+1=1.075

    SG = 145/(145-22) = 1.1789

    gals = (3000-800) :1.1789/1.075 = 2006 galGals water = 3000-2006 = 1994 bbls

  • Raw acid required to mix 1000 gallons of 7.5% acid1000x0.075x (7.5%/2+1)

    = ---------------------------------- = 482.5 gallons0.15 x (15%/2+1)

    Gallons of water required = 1000 - 482.5 =517.5 gallons

    Note that when obtaining the volume of water required for proper dilution of the raw acid, that additives such as corrosion inhibitors are considered part of dilution water requirement.

    CI-22 = 3 gallonsFerrotrol 300L = 3 gallonsInflo = 10 gallons

    Gallons of water required = 517.5-3-3-10=501.5gallons

    Volume factor = 1500:1000 = 1.5

    CI-22 = 3 x1.5=4.5gallonsFerrotrol 300L = 3 x1.5= 4.5gallonsInflo = 10 x1.5= 15gallonsWater = 501.5 x1.5=752.25gallonsRaw Acid = 482.5 x1.5=723.75gallons

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