37
1 AC Power AC Power

AC Power

Embed Size (px)

DESCRIPTION

AC Power. AC Power. As in the case with DC power, the instantaneous electric power in an AC circuit is given by P = VI , but these quantities are continuously varying. Almost always the desired power in an AC circuit is the average power , which is given by. P avg = V I cos . - PowerPoint PPT Presentation

Citation preview

Page 1: AC Power

1

AC PowerAC Power

Page 2: AC Power

2

As in the case with DC power, the instantaneous electric power in an AC circuit is given by P = VI, but these quantities are continuously varying. Almost always the desired power in an AC circuit is the average power, which is given by

AC PowerAC Power

Pavg = V I cos

where is the phase angle between the current and the voltage and V and I are understood to be the effective or rms values of the voltage and current. The term cos   is called the "power factor" for the circuit.

Page 3: AC Power

3

Instantaneous Power

As in DC circuits, the instantaneous electric power in an AC circuit is given by P=VI where V and I are the instantaneous voltage and current.

then the instantaneous power at any time t can be expressed as

Since

Page 4: AC Power

4

the power becomes:

Averaging this power over a complete cycle gives the average power.

Average PowerAverage PowerNormally the average power is the power of interest in AC circuits. Since the expression for the instantaneous power is a continuously varying one with time, the average must be obtained by integration. Averaging over one period T of the sinusoidal function will give the average power. The second term in the power expression above averages to zero since it is an odd function of t. The average of the first term is given by

                                                 

Page 5: AC Power

5

Since the rms voltage and current are given by               

the average power can be expressed as                       

and

Page 6: AC Power

6

Average Power Integral

Finding the value of the average power for sinusoidal voltages involves the integral

                                                                                                  The period T of the sinusoid is related to the angular frequency   and angle   by                                                       

Using these relationships, the integral above can be recast in the form:

Which can be shown using the trig identity:

                                              which reduces the integral to the value 1/2 since the second term on the right has an integral of zero over the full period.

Page 7: AC Power

7

RLC Series CircuitRLC Series Circuit

The RLC series circuit is a very important example of a resonant circuit. It has a minimum of impedance Z=R at the resonant frequency, and the phase angle is equal to zero at resonance.

Page 8: AC Power

8

Single-phase SystemSingle-phase System

The Sinusoidal voltage

v(t) = Vm sin twhere

Vm = the amplitude of the sinusoid

= the angular frequency in radian/s

t = timev(t)

Vm

-Vm

t

Page 9: AC Power

9

v(t)

Vm

-Vm

t

2

TT

1f

f2The angular frequency in radians per second

Page 10: AC Power

10

Single-phase SystemSingle-phase SystemA more general expression for the sinusoid (as shown in the figure):

v(t) = Vm sin (t + )

where is the phase anglev(t)

Vm

-Vm

t

V1 = Vm sin t

V2 = Vm sin t + )

Page 11: AC Power

11

Single-phase SystemSingle-phase System

A sinusoid can be expressed in either sine or cosine form. When comparing two sinusoids, it is expedient to express both as either sine or cosine with positive amplitudes. We can transform a sinusoid from sine to cosine form or vice versa using this relationship:

sin (ωt ± 180o) = - sin ωt

cos (ωt ± 180o) = - cos ωt

sin (ωt ± 90o) = ± cos ωt

cos (ωt ± 90o) = + sin ωt

Page 12: AC Power

12

Single-phase SystemSingle-phase System

Apparent Power, Reactive Power and Power FactorThe apparent power is the product of the rms values of voltage and current.

The reactive power is a measure of the energy exchange between the source and the load reactive part.

)sin( ivQ rmsrmsIV

rmsrmsIVS

Page 13: AC Power

13

Single-phase Single-phase SystemSystem

The power factor is the cosine of the phase difference between voltage and current.

The complex power:

)cos( ivfactor Power S

P

iv

jQP

rmsrms IV

Page 14: AC Power

14

Three-phase SystemThree-phase System

Page 15: AC Power

15

In a three phase system the source consists of three sinusoidal voltages. For a balanced source, the three sources have equal magnitudes and are phase displaced from one another by 120 electrical degrees.

A three-phase system is superior economically and advantage, and for an operating of view, to a single-phase system. In a balanced three phase system the power delivered to the load is constant at all times, whereas in a single-phase system the power pulsates with time.

Generation of Three-phaseGeneration of Three-phase

Page 16: AC Power

16

Generation of Three-phaseGeneration of Three-phase

Suppose three similar loops of wire with terminals R-R’, Y-Y’ and B-B’ are fixed to one another at angles of 120o

and rotating in a magnetic field.

R

R1

B

B1

Y

Y1

N S

Page 17: AC Power

17

Generation of Three-phaseGeneration of Three-phase

The instantaneous e.m.f. generated in phase R, Y and B:vR = VR sin t

vY = VY sin (t -120o)

vB = VB sin (t -240o) = VBsin (t +120o)

v(t)

t

vR

vY vB

Page 18: AC Power

18

Generation of Three-phaseGeneration of Three-phase

Phase sequences:(a) RYB or positive sequence

120o

-120o

120oVR

VY

VB

o

)rms(YY 120VV

o

)rms(RR 0VV

o

)rms(B

o

)rms(BB

120V

240VV

VR leads VY, which in turn leads VB

This sequence is produced when the rotor rotates in the counterclockwise direction

Page 19: AC Power

19

Generation of Three-phaseGeneration of Three-phase

(b) RBY or negative sequence

o

)rms(BB 120VV

o

)rms(RR 0VV

o

)rms(Y

o

)rms(YY

120V

240VV

120o

-120o

120oVR

VB

VY

VR leads VB, which in turn leads VY

This sequence is produced when the rotor rotates in the clockwise direction

Page 20: AC Power

20

Star and Delta ConnectionStar and Delta Connection

Page 21: AC Power

21

Star Connection

Three wire system R

Y

B

ZR

Page 22: AC Power

22

Four wire system

VRN

VBN VYN

ZR

R

BN

Y

Page 23: AC Power

23

Wye connection of Load

Z1

Z3

Z2

R

B

Y

NLoad

Z3

R

Y

B

Load

N

Page 24: AC Power

24

Delta Connection

R

Y

B

Y

B

R

Page 25: AC Power

25

Zc

Za

Zb

R

B

Y

Load

Za

R

Y

B

Load

Delta connection of load

Page 26: AC Power

26

N

R

Y

B

VRY

VYB

VBR

VYN

VBN

VRN

IR

IY

IB

Line-to-neutral voltages:

240V

120V

0V

phaseBN

phaseYN

phaseRN

V

V

V

linephase

linephase

V

II

V

# Reference: VRN

# Positive sequence

Wye Connection

Page 27: AC Power

27

N

R

Y

B

VRY

VYB

VBR

VYN

VBN

VRN

IR

IY

IB

303

120j1200j0

1200

seph

oooophase

phasephase

YNRNRY

aV

V

VV

VVV

)sin()(cos()sin(cos

The two other can be calculated similarly.

Page 28: AC Power

28

BNBNBR VVV

The line to line voltages

1503

2103

903

303

phase

phaseBR

phaseYB

phaseRY

V

VV

VV

VV

BNYNYB VVV YNRNRY VVV

Page 29: AC Power

29

VRY

VBR

VYB

VRY

R

Y

BV

YB

VBR

Delta Connection

Line-to-line currents:

240II

120II

0II

phaseBR

phaseYB

phaseRY

linephase

linephase

II

VV

# Reference: IRY

# Positive sequence.

Page 30: AC Power

30

30I3

120j1200j0I

120I0I

III

seph

oooophase

phasephase

BRRYR

a

sin(cos)sin(cos

The two other can be calculated similarly.

Page 31: AC Power

31

YBBRB III

903

2703

1503

303

phase

phaseB

phaseY

phaseR

I

II

II

II

RYYBY III BRRYR III

The line currents:

Page 32: AC Power

32

30°

-120°

VBR VRY

VYB

VYN

VRN

VBN

-VYN

• Phasor diagram is used to visualize the system voltages• Wye system has two type of voltages: Line-to-neutral, and line-to-line• The line-to-neutral voltages are shifted with 120 degrees• The line-to-line voltage leads the line to neutral voltage with 30 degrees• The line-to-line voltage is times the line-to-neutral voltage

Vector diagram

Page 33: AC Power

33

TNB SUPPLY SYSTEMTNB SUPPLY SYSTEM

Voltage 3 phase, 50 Hz

The main transmission and substation network are: - 275 kV - 132 kV - 66 kV

The distribution are: - 33 kV - 22 kV - 11 kV - 6.6 kV - 415 volts - 240 volts (single phase) drawn from 415 volts 3 phase (phase voltage), between line (R, Y, B) and Neutral (N)

Page 34: AC Power

34

SYSTEMSYSTEM

The low voltage system (415/240 V) is 3-phase four wire.The low voltage system is a mixture of overhead lines and under ground cables.

The high voltage and extra high voltage system is 3-phase three wire Configuration. Overhead line and under ground cable system are used.

Supply Method (two types of premises)Supply Method (two types of premises)

1. Single consumer such as private dwelling house, workshop, factory, etc

a. Single phase, two wire, 240 V, up to 12 kVA max demandb. Three phase, four wire, 415 V, up to 45 kVA max demandc. Three phase, four wire, C. T. metered 415 V, up to 1,500 kVA max demand

Page 35: AC Power

35

2. Multi tenanted premises, such as high rises flats, commercial, office blocks, etc

- Low Voltage

a. Three phase, three wires, 6,600 and 11,000 V for load of 1, 500 kVA max demand and above, whichever voltage is available

b. Three phase, three wires, 22,000 and 33,000 V for load of 5,000 kVA max demand and above, whichever voltage is available

c. Three phase, three wires, 66,000 V, 132,000 V and 275,000 for exceptionally large load of above 20 MVA max demand

Three phase, four wire, C.T. metered 415 V, up to 1,500 kVA maxdemand

- High Voltage and Extra High Voltage

Page 36: AC Power

36

Standby Supply

Standby generator(s) to be used by the consumer in his premises, inaccordance with the relevant by-laws, may be provided by the consumer

The generator(s) shall remain a separate system from the TNB’s Distribution system and should be certified and registered by Suruhanjaya Tenaga (formerly JBE)

This may be used in place of the TNB’s supply source through a suitable,Approved change over facility under emergency conditions.

Page 37: AC Power

37

Beban

Berubah setiap masa, hari, minggu dan bulan.

Beban mempengaruhi penjanaan tenaga.

Penjanaan tenaga berdasarkan permintaan beban yang lepas.

Lengkuk beban berubah dalam sehari.