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AC Power. AC Power. As in the case with DC power, the instantaneous electric power in an AC circuit is given by P = VI , but these quantities are continuously varying. Almost always the desired power in an AC circuit is the average power , which is given by. P avg = V I cos . - PowerPoint PPT Presentation
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AC PowerAC Power
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As in the case with DC power, the instantaneous electric power in an AC circuit is given by P = VI, but these quantities are continuously varying. Almost always the desired power in an AC circuit is the average power, which is given by
AC PowerAC Power
Pavg = V I cos
where is the phase angle between the current and the voltage and V and I are understood to be the effective or rms values of the voltage and current. The term cos is called the "power factor" for the circuit.
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Instantaneous Power
As in DC circuits, the instantaneous electric power in an AC circuit is given by P=VI where V and I are the instantaneous voltage and current.
then the instantaneous power at any time t can be expressed as
Since
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the power becomes:
Averaging this power over a complete cycle gives the average power.
Average PowerAverage PowerNormally the average power is the power of interest in AC circuits. Since the expression for the instantaneous power is a continuously varying one with time, the average must be obtained by integration. Averaging over one period T of the sinusoidal function will give the average power. The second term in the power expression above averages to zero since it is an odd function of t. The average of the first term is given by
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Since the rms voltage and current are given by
the average power can be expressed as
and
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Average Power Integral
Finding the value of the average power for sinusoidal voltages involves the integral
The period T of the sinusoid is related to the angular frequency and angle by
Using these relationships, the integral above can be recast in the form:
Which can be shown using the trig identity:
which reduces the integral to the value 1/2 since the second term on the right has an integral of zero over the full period.
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RLC Series CircuitRLC Series Circuit
The RLC series circuit is a very important example of a resonant circuit. It has a minimum of impedance Z=R at the resonant frequency, and the phase angle is equal to zero at resonance.
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Single-phase SystemSingle-phase System
The Sinusoidal voltage
v(t) = Vm sin twhere
Vm = the amplitude of the sinusoid
= the angular frequency in radian/s
t = timev(t)
Vm
-Vm
t
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v(t)
Vm
-Vm
t
2
TT
1f
f2The angular frequency in radians per second
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Single-phase SystemSingle-phase SystemA more general expression for the sinusoid (as shown in the figure):
v(t) = Vm sin (t + )
where is the phase anglev(t)
Vm
-Vm
t
V1 = Vm sin t
V2 = Vm sin t + )
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Single-phase SystemSingle-phase System
A sinusoid can be expressed in either sine or cosine form. When comparing two sinusoids, it is expedient to express both as either sine or cosine with positive amplitudes. We can transform a sinusoid from sine to cosine form or vice versa using this relationship:
sin (ωt ± 180o) = - sin ωt
cos (ωt ± 180o) = - cos ωt
sin (ωt ± 90o) = ± cos ωt
cos (ωt ± 90o) = + sin ωt
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Single-phase SystemSingle-phase System
Apparent Power, Reactive Power and Power FactorThe apparent power is the product of the rms values of voltage and current.
The reactive power is a measure of the energy exchange between the source and the load reactive part.
)sin( ivQ rmsrmsIV
rmsrmsIVS
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Single-phase Single-phase SystemSystem
The power factor is the cosine of the phase difference between voltage and current.
The complex power:
)cos( ivfactor Power S
P
iv
jQP
rmsrms IV
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Three-phase SystemThree-phase System
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In a three phase system the source consists of three sinusoidal voltages. For a balanced source, the three sources have equal magnitudes and are phase displaced from one another by 120 electrical degrees.
A three-phase system is superior economically and advantage, and for an operating of view, to a single-phase system. In a balanced three phase system the power delivered to the load is constant at all times, whereas in a single-phase system the power pulsates with time.
Generation of Three-phaseGeneration of Three-phase
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Generation of Three-phaseGeneration of Three-phase
Suppose three similar loops of wire with terminals R-R’, Y-Y’ and B-B’ are fixed to one another at angles of 120o
and rotating in a magnetic field.
R
R1
B
B1
Y
Y1
N S
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Generation of Three-phaseGeneration of Three-phase
The instantaneous e.m.f. generated in phase R, Y and B:vR = VR sin t
vY = VY sin (t -120o)
vB = VB sin (t -240o) = VBsin (t +120o)
v(t)
t
vR
vY vB
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Generation of Three-phaseGeneration of Three-phase
Phase sequences:(a) RYB or positive sequence
120o
-120o
120oVR
VY
VB
o
)rms(YY 120VV
o
)rms(RR 0VV
o
)rms(B
o
)rms(BB
120V
240VV
VR leads VY, which in turn leads VB
This sequence is produced when the rotor rotates in the counterclockwise direction
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Generation of Three-phaseGeneration of Three-phase
(b) RBY or negative sequence
o
)rms(BB 120VV
o
)rms(RR 0VV
o
)rms(Y
o
)rms(YY
120V
240VV
120o
-120o
120oVR
VB
VY
VR leads VB, which in turn leads VY
This sequence is produced when the rotor rotates in the clockwise direction
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Star and Delta ConnectionStar and Delta Connection
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Star Connection
Three wire system R
Y
B
ZR
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Four wire system
VRN
VBN VYN
ZR
R
BN
Y
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Wye connection of Load
Z1
Z3
Z2
R
B
Y
NLoad
Z3
R
Y
B
Load
N
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Delta Connection
R
Y
B
Y
B
R
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Zc
Za
Zb
R
B
Y
Load
Za
R
Y
B
Load
Delta connection of load
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N
R
Y
B
VRY
VYB
VBR
VYN
VBN
VRN
IR
IY
IB
Line-to-neutral voltages:
240V
120V
0V
phaseBN
phaseYN
phaseRN
V
V
V
linephase
linephase
V
II
V
# Reference: VRN
# Positive sequence
Wye Connection
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N
R
Y
B
VRY
VYB
VBR
VYN
VBN
VRN
IR
IY
IB
303
120j1200j0
1200
seph
oooophase
phasephase
YNRNRY
aV
V
VV
VVV
)sin()(cos()sin(cos
The two other can be calculated similarly.
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BNBNBR VVV
The line to line voltages
1503
2103
903
303
phase
phaseBR
phaseYB
phaseRY
V
VV
VV
VV
BNYNYB VVV YNRNRY VVV
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VRY
VBR
VYB
VRY
R
Y
BV
YB
VBR
Delta Connection
Line-to-line currents:
240II
120II
0II
phaseBR
phaseYB
phaseRY
linephase
linephase
II
VV
# Reference: IRY
# Positive sequence.
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30I3
120j1200j0I
120I0I
III
seph
oooophase
phasephase
BRRYR
a
sin(cos)sin(cos
The two other can be calculated similarly.
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YBBRB III
903
2703
1503
303
phase
phaseB
phaseY
phaseR
I
II
II
II
RYYBY III BRRYR III
The line currents:
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30°
-120°
VBR VRY
VYB
VYN
VRN
VBN
-VYN
• Phasor diagram is used to visualize the system voltages• Wye system has two type of voltages: Line-to-neutral, and line-to-line• The line-to-neutral voltages are shifted with 120 degrees• The line-to-line voltage leads the line to neutral voltage with 30 degrees• The line-to-line voltage is times the line-to-neutral voltage
Vector diagram
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TNB SUPPLY SYSTEMTNB SUPPLY SYSTEM
Voltage 3 phase, 50 Hz
The main transmission and substation network are: - 275 kV - 132 kV - 66 kV
The distribution are: - 33 kV - 22 kV - 11 kV - 6.6 kV - 415 volts - 240 volts (single phase) drawn from 415 volts 3 phase (phase voltage), between line (R, Y, B) and Neutral (N)
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SYSTEMSYSTEM
The low voltage system (415/240 V) is 3-phase four wire.The low voltage system is a mixture of overhead lines and under ground cables.
The high voltage and extra high voltage system is 3-phase three wire Configuration. Overhead line and under ground cable system are used.
Supply Method (two types of premises)Supply Method (two types of premises)
1. Single consumer such as private dwelling house, workshop, factory, etc
a. Single phase, two wire, 240 V, up to 12 kVA max demandb. Three phase, four wire, 415 V, up to 45 kVA max demandc. Three phase, four wire, C. T. metered 415 V, up to 1,500 kVA max demand
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2. Multi tenanted premises, such as high rises flats, commercial, office blocks, etc
- Low Voltage
a. Three phase, three wires, 6,600 and 11,000 V for load of 1, 500 kVA max demand and above, whichever voltage is available
b. Three phase, three wires, 22,000 and 33,000 V for load of 5,000 kVA max demand and above, whichever voltage is available
c. Three phase, three wires, 66,000 V, 132,000 V and 275,000 for exceptionally large load of above 20 MVA max demand
Three phase, four wire, C.T. metered 415 V, up to 1,500 kVA maxdemand
- High Voltage and Extra High Voltage
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Standby Supply
Standby generator(s) to be used by the consumer in his premises, inaccordance with the relevant by-laws, may be provided by the consumer
The generator(s) shall remain a separate system from the TNB’s Distribution system and should be certified and registered by Suruhanjaya Tenaga (formerly JBE)
This may be used in place of the TNB’s supply source through a suitable,Approved change over facility under emergency conditions.
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Beban
Berubah setiap masa, hari, minggu dan bulan.
Beban mempengaruhi penjanaan tenaga.
Penjanaan tenaga berdasarkan permintaan beban yang lepas.
Lengkuk beban berubah dalam sehari.