AAT 1/7-8

Unit 3, Lesson 3, Inv 1

Warm Up

• ½ sheet of paper when you walked in! • First 15 minutes!

Solving for Maximum Value (p.209)Reasoning:1. Distributive

Property2. The function gives

height, height is zero when gymnast is on the trampoline3. Substitution

substitute the factored form for h(t)

Solving for Max Value ContinuedReasoning:4. Zero product rule

(product is zero when one of the factors is zero)

5. Multiplication and Addition properties of equality (solve for t)

6. Parabolas have an axis of symmetry – the maximum value should be the midpoint between t=0 and t=1.5

7. Translation of function notation into words

f(x) =x(x-5)

a. Find the zeros – or find all x for which f(x) = 0

b. Sketch a graph

c. Produce the graph on a calculator

Zeros:x = 0 or (x-5) = 0x=0, x=5

Group Work

• #2 DO: b – h

• #3 a-e (p. 210) – Follow the same

steps but now you will have three zeros

a. Find the zeros – or find all x for which f(x) = 0

b. Sketch a graph

c. Produce the graph on a calculator

Write the equation from zerosZeros:f(4) = 0, f(1) = 0

Equation:f(x) = (x )(x )(x ) = 0 when x=4 (x ) = 0 when x=1(x – 4) = 0 when x=4 (x – 1) = 0 when x=1

f(x) = (x – 4 )(x – 1)

#4,5

OTL

• OYO Page 212 and factoring worksheet• Quiz Th/F