7/18/2019 A riddle

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Greetings from/to Sherlock Holmes!

M. N. G. Einstein∗

22. June, 2015

With all the stupid articles on Facebook and those wannabee puzzles, which occur

often enough, I thought of something, that is really pretentious. Here is a

Riddle. Which simple assertions can be made of:

limk→∞

sin(y   logg(n

k))

with  ∞ > n  ∈ N   ,  ∞ > y  ∈ R  and g > 1. One can also take, equivalent, a look at

the function:

limk→∞

sin(y   logg(1

k))

with  g > 1.

Help:

limx→0+ logg x = −∞

for  g > 1.

It is neither about the value nor about the exact calculation of the result, but

what three things, can be found out, about the function in question, simply just

through a logic consideration:

1. ?

2. ?

3. ?

Because how did Hercule Poirot used to say: “ . . . it was not luck, mon Colonel, it

was the small grey cells, which allowed me to solve this matter!“ So, what do the

small grey cells tell you?

∗To answer those question ahead, that will definitely come, yes I am able to compute each

such term with almost no exception!

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