9-Wastewater Sludge Characteristics

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    Characteristics of Wastewater

    Treatment Sludge

    By

    Ricardo B. Jacquez

    Professor

    CAGE Department

    NMSUAssistant: Maung Myint

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    Important Relations for Sludge Calculations

    Ws = weight of the dry solids

    Wf = weight of the fixed solids

    Wv = weight of the volatile solids

    Ss = specif ic gravity o f dry so l ids

    Sf = specific gravity of fixed solids (2.5)

    Sv = specific gravity of volatile solids (1.2)

    v

    v

    f

    f

    s

    s

    S

    W

    S

    W

    S

    W

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    Sludge volume = V

    Ws= weight of dry solid [lb or gm]r = unit weight of water = 62.4 lb/ft3 = 1000 kg/m3

    Swet.sludge = specific gravity of wet sludge

    sludgewet

    Srsolid

    WsV

    .100

    %

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    Sources of wastewater sludge

    Primary clarifier

    Secondary clarifiers:

    activated sludgebio-towers

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    Typical domestic wastewater sludge,

    Ws=1

    Wf=0.3 Wv=0.7

    Sf=2.5 Sv=1.2

    42.12.1

    7.0

    5.2

    3.01

    s

    s

    v

    v

    f

    f

    s

    s

    SS

    S

    W

    S

    W

    S

    W

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    Typical sludge has 96.5% water, 3.5% solid,

    and specific gravity of solid=1.42.

    Determine the specific gravity of typical wetsludge?

    0.101.142.1/5.31/5.96 5.35.96

    /%/%

    %%

    .

    .

    sludgewet

    sludgewet

    S

    SssludgeinsolidSwwater

    sludgeinsolidwaterS

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    Primary clarifier solids

    Mp=E Q [MGD] SS [mg/L] 8.34 [lb/MG(mg/L)]

    Mp = mass of primary solids, [lb/day]

    E = efficiency of primary clarifier (see Fig)SS = suspended solid concentration in influent

    [mg/L]

    Q = flow rate [MGD]

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    (from Peavy, Rowe, and Tchobanoglous, 1985, p. 228)

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    Secondary clarifier solids

    Ms=YQ[MGD] BODR [mg/L] 8.34[lb/MG mg/L]

    Ms=mass of secondary solids [lb/day]Y =yield coefficient (see Fig. 5-37)

    BODR=BOD removed [mg/L]

    Q = flow rate [MGD]

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    Volume of sludge

    sludgewetofgravityspecif icS

    gallbwaterofweightunitr

    daygalsludgeofvolumeV

    SrwaterMMV

    Srsolid

    MMV

    sludgewet

    sludgewet

    SP

    sludgewet

    SP

    .

    .

    .

    ]/34.8[

    ]/[

    )100/%100(

    )100/(%

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    Typical solids content of sludge

    Type of sludge Sludge concentration %

    Un-thickened Thickened

    Separate

    Primary sludge 2.5 - 5.5 8 - 10

    Trickling-filter sludge 4 - 7 7 - 9

    Activated sludge 0.5 - 1.2 2.5 - 3.3

    Pure O2

    sludge 0.8 - 3 2.5 - 9

    Combined

    Primary and trickling-

    filter sludge 3 - 6 7 - 9

    Primary and modified-

    aeration 3 - 4 8.3 - 11.6

    Primary and air-activated sludge 2.6 - 4.8 4.6 - 9

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    Ex. Reduction of volume by sludge thickening

    A wastewater-treatment plant consists of

    primary treatment units followed by an

    activated-sludge secondary system. The

    primary and secondary sludges are mixed,

    thickened in a gravity thickener, and sent to

    further treatment. A schematic of the system isshown in the next slide.

    Influent SS=200mg/L Primary sludge =5%

    Influent BOD=225mg/L

    Effluent BOD=20mg/L Thickened sludge=4%

    Flow Q = 5 MGD Secondary sludge=0.75%

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    Primary clarifier diameter = 82 ft

    Aeration volume = 102,400 cft = 766,180 gal

    Influent Primary Aeration Secondary

    clarifier clarifier

    Sludge return

    Liquid

    Return Thickener Thickened sludgeto sludge-treatment facilities

    MLSS in aerator 3,500 mg/L

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    1. Mass and volume of primary sludge

    a) area of primary clarifier = A = 3.14 D2/4

    A = 3.14 (82 ft)2

    / 4 = 5,283 ft2

    b) overflow rate = Q/A = 5.0 x 106/5283 ft2

    =950 gpd/ft2 (42 m/s)

    c) from Fig. 5-13, the efficiency of clarifier isEss = 58% EBOD = 32%

    d) mass of primary solids removed is Mp

    Mp=Ess Q SS

    =0.58(5 MGD)(200 mg/L)(8.34lb/MG mg/L)

    Mp=4,840 lb/day

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    e) volume of primary sludge

    daygalV

    gallb

    dlbV

    Srsolid

    MV

    sludgewet

    P

    /600,11

    )0.1(/34.8)100/5(

    /840,4

    )100/(% .

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    2. Mass of secondary solids

    b) from Fig. 13.1 (text, pg 651), Y=0.48

    c) mass of secondary solid Ms

    Ms=Y BOD5

    Q

    =0.48(5MGD)133mg/L(8.34lb/MG mg/L)

    Ms = 2,660 lb/day

    29.0/3500766.0

    /22532.015

    /

    LmgMG

    LmgMGD

    M

    F

    masssludge

    dayappliedBOD

    M

    F

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    d) volume of secondary sludge

    3a. Total mass of solids MT=Mp +Ms

    MT= 4,840 + 2,660 = 7,500 lb/day

    3b. Total volume of sluge VT =Vp +Vs

    VT= 11,600+ 42,600 = 54,200 gal/d

    daygalV

    gallb

    dlbV

    Srsolid

    MV

    sludgewet

    s

    /600,42

    )0.1(/34.8)100/75.0(

    /660,2)100/(% .

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    4a) mass of solids sent to sludge treatment

    Neglect the solids in the thickener

    supernatant, the mass of solids in thethickened sludge is equal to 7,500 lb/day.

    4b) volume of thickened sludge

    daygalV

    gallb

    dlbV

    Srsolid

    MV

    sludgethickened

    thickened

    /500,22

    )0.1(/34.8)100/4(

    /500,7

    )100/(% .

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    5. Volume reduction (%) by thickening

    %58100200,54

    500,22200,54

    100

    reductionvolume

    V

    VVreductionvolume

    T

    thickenedT