8 July Quantitative Aptitude II

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    Quantitative aptitude

    Afterschoool developing change makers

    CENTRE FOR SOCIALENTREPRENEURSHIP

    PGPSE PROGRAMME OPEN FOR ALLFREE FOR ALL

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    Quantitative aptitudeDr. T.K. Jain.

    AFTERSCHOOOL

    Centre for social entrepreneurship

    Bikaner

    M: 9414430763

    [email protected]

    www.afterschool.tk

    www.afterschoool.tk

    http://www.afterschool.tk/http://www.afterschoool.tk/http://www.afterschoool.tk/http://www.afterschool.tk/
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    10 persons spent Rs. 35 each. 11th

    spent Rs. 20 more than average of

    all. How much money was spent?Money spent by 10 = 35*10 =350.

    Let us assume their average to be X.

    X = [350 +(X+20)] / 11

    11X = 350+X+20

    10X = 370 or X = 37.

    Thus money spent by 11th is 57. thus total

    money spent is 350+57 = 407 answer.

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    What is the least number to be

    multiplied to 6125 to make it cube

    is ?Let us find factors of 6125:

    = 5*5*5*7*7.

    Thus we have three 5 and two 7. In orderto make it cube, we shall multiply it by 7.

    answer.

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    Average of 7 numbers is 45. if

    average of first 5 is 30 and that of

    last 3 is 60. find the forth number, ifit is 17 more than 5th number.

    Total of first 5= 150

    Total of last 3 = 180 thus their total is330 Fifth number has been countedtwice.

    Total of 7 numbers is : 315. 5th number is : 330-315 =1 5.Thus fourth number is 15+17 = 32

    answer.

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    6 years ago the average of a family

    of 6 members was 21 years. A baby

    was born in between and theaverage age of family increased by 3

    years. What is the age of baby?

    Total age of family 6 years back = 6*21 =126. Add 6*6 in it = 126+36 = 162

    However, their total age is : 7*24=168.

    Thus the age of baby is : 168-162 = 6years.

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    What is the largest number which

    will divide 39,73 and 90 and leave

    same remainder in every case?To solve this question, find the difference

    between the numbers:

    The difference is 73-39 = 3490-73 = 17.

    Find HCF of 17 &34 = 17

    Answer = 17.

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    What remainder will you get

    when you divide 2^63 by 5? Unit digits in power of 2 are as under: 2^1 = 2, 2^2 = 4, 2^3 = 8, 2^4 = 16, 2^5 = 32,

    2^6=64, 2^7 = 128 or 8 2,4,8,6,2,4,8,6, and so on when the power is

    1,2,3,4,5, and so on. The power repeatsafter every 4 digits. Divide 63 by 4, we get 3as remainder. At 3rd level we have

    remainder 8. Thus when power will be 63,unit digit will be 8. thus remainer will be 8-5= 3 answer.

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    What remainder will you get

    when you divide 2^13 by 5?As per the last solution, we shall find the

    order. 13 divided by 4 gives remainder 1

    which gives us unit value as 2. thusremainder will be 2 answer.

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    A^3B =220 and BC^2 = 880. what is

    C? (ABC are positive numbers)220 is not divisible by 2^3 or 3^3 or 4^3

    or 5^3. thus A^3 = 1. or A = 1.

    Thus B = 220.Thus C^2 = 4.

    Thus C = 2 answer.

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    2X+9Y is divisible by 13. (X , Y are

    positive numbers). Which of the

    following is divisible by 13? 4X +13Y, 5X+7Y+4, 3X-7Y+2, 4X+7Y+9

    Solution: when we assume value of X = 2,

    and Y = 1, the equation is divisible by 13.similarly, when we take value of X = 4 and Y

    = 2, the equation is divisible by 13.

    4X+7Y +9 is divisible by 13 with the values

    X = 4 and Y =2. (thus this is answer).

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    ere s one num er w c s ormeby writing one digit 6 times. Such

    number is always divisible by which

    prime numbers?3, 11 , 13,For 11 we take alternate digits thus all

    such numbers will be divisible by 11. (for finding divisibility by 3, we take

    numbers in groups of 3 digits) thus thenumber will always be divisible by 13. It

    may be any number as : 111111,222222, 333333 etc.

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    Find HCF of 2/3, 8/9 & 16/81?Find HCF of 2,8 and 16. = 2

    Find LCM of 3,9 and 81. = 81

    The answer: 2/81 answer.

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    Bankers gain on a sum due 5 years

    hence at 10% per annum is 450.

    what is bankers discount andamount of bill?

    Bankers discount true discount =bankers gain.

    Let us assume amount is Rs. 1000. Bankers discount = 1000*10*5/100 = 500 True discount = amt present value Present value = (1000*100) / (100+10*5)=

    100000/150 = 666. thus true discount = 333. Bankers gain is 167. 1000/167*450 = 2700 Bankers discount = 2700*10*5/100 = 1350.

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    ABOUT A FTERSCH OOOLAfterschoool conducts three year integrated PGPSE (after

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    Why such a programme? To promote people to take up entrepreneurship

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    Who are our supporters?Afterschoolians, our past beneficiaries,

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    About AFTERSCHOOOL PGPSE the best

    programme for developing great entrepreneurs

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    Workshops from

    AFTERSCHOOOL

    IIF, Delhi CIPS, Jaipur ICSI Hyderabad Branch Gyan Vihar, Jaipur Apex Institute of Management, Jaipur Aravali Institute of Management, Jodhpur Xavier Institute of Management,

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    Salient features:

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    Components

    Pedagogy curriculum and approach based on IIM Ahmedabad and ISBHyderabad (the founder is alumnus from IIMA & ISB Hyderabad)

    Meditation, spiritualisation, and self development Essential softwares for business Business plan, Research projects Participation in conferences / seminars Workshops on leadership, team building etc. Written submissions of research projects/articles / papers Interview of entrepreneurs, writing biographies of entrepreneurs Editing of journals / newsletters

    Consultancy / research projects Assignments, communication skill workshops Participation in conferences and seminars Group discussions, mock interviews, self development diaryng Mind Power Training & writing workshop (by Dr. T.K.Jain)

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    Pedagogy

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    Branches

    AFTERSCHOOOL will shortly open itsbranches in important cities in Indiaincluding Delhi, Kota, Mumbai, Gurgaonand other important cities.Afterschooolians will be responsible formanaging and developing these

    branches and for promoting socialentrepreneurs.

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    Case Studies

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    Basic values at afterschoool

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