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7/27/2019 7H0011X0 W&C Tech Handbook Sec 18
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18. FORMULAS
AND CONSTANTS18.1 Electrical Properties of Circuits 29
18.2 Resistance and Weight of Conductors 29
18.3 Resistance, Inductance and Capacitance in AC Circuits 29
18.4 Series and Parallel Connections 29
18.5 Engineering Notation 29
18.6 Diameter of Multiconductor Cables 29
18.7 Determination of Largest Possible Conductor in Cable Interstices 30
18.8 Conductor Diameter from Wire Diameter 30
18.9 Coaxial Capacitance 30
18.10 Inductive Reactance 30
18. Formulas and Constant
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18.1 ELECTRICAL PROPERTIES OF CIRCUITS
Table 18.1Electrical Properties of Circuits
cos Power factor of load (pf)V Volts between conductorsEff. Efficiency of motorI Current (amperes)
kw
KilowattskVA Kilovoltampereshp Horsepower
Alternating Current Direct Current
Desired Data Single Phase Three Phase
Kilowatts(kw)
I V cos 1,000
1.73 I V cos 1,000
I V1,000
Kilovolt-amperes(kVA)
I V1,000
1.73 I V1,000
I V1,000
Horsepoweroutput
I V cos Eff.746
1.73 I V cos Eff.746
I V Eff.746
Amperes (I) whenhorsepoweris known
hp 746V cos Eff.
hp 7461.73 V cos Eff.
hp 746
V Eff.
Amperes (I) whenkilowatts are
known
kw 1,000V cos
kw 1,0001.73 V cos
kw 1,000V
Amperes (I) whenkilovolt-amperesare known
kVA 1,000V
kVA 1,0001.73 V
kVA 1,000V
|18. Formulas and Constants
296 |
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18.2 RESISTANCE AND WEIGHT OF CONDUCTORS
The resistance and weight of any uncoated copper wire at 20C (68F) having a conductivity of 100 percent IACS may be calculated from the following formula
Ohms per 1,000 feet
Pounds per 1,000 feet Area in sq. in. 3,854.09 or area in cmils 0.0030269
18.3 RESISTANCE, INDUCTANCE AND CAPACITANCE IN AC CIRCUITS
Table 18.2Resistance, Inductance and Capacitance in AC Circuits
V Voltage in volts I Current in amperes L Inductance in henries f Frequency in cycles per secondR Resistance in ohms C Capacitance in farads 3.1416
18. Formulas and Constant
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or
0.0081455
Cross-sectional area in sq. in.
10371.176
Cross-sectional area in cmils
If Circuit Contains Reactance Impedance V for Current I Power Factor
Resistance (R)Only
O R IR 1
Inductance (L)Only
2fL 2fL I2fL O
Capacitance (C)Only
12fC
12fC
I1 1
2fCO
Resistance andInductance inSeries (R and L)
2fL R2 (2fL)2 IR2 (2fL)2R
R2 (2fL)2
Resistance andCapacitance inSeries (R and C)
12fC
Resistance,Inductance andCapacitance inSeries (R, L and C)
2fL 1 1
2fC2fL
1 12fC( )
2
( )2
R2 + 2fL 1 1
2fC
( )2
12fC
( )2
R2 + 2fL 1
2fCR
R2 + ( )2
12fCR2 +I ( )
2
12fCR2 +
R
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|18. Formulas and Constants
298 |
R R1 R2 R3 +
1 1 1 1__ __ __ __R
R1
R2
R3
1 1 1 1__ __ __ __C
C1
C2
C3
1 1 1 1__ __ __ __L
L1
L2
L3
L L1 L2 L3 +
C C1 C2 C3 +
18.4 SERIES AND PARALLEL CONNECTIONS
Table 18.3Series and Parallel Connections
Resistance Inductance Capacitance(R) (L) (C)
Series
Parallel
18.5 ENGINEERING NOTATION
Table 18.4Engineering Notation
Multiplying Factor
Prefix Symbol Scientific Conventional
tera T 1012
1,000,000,000,000giga G 10
91,000,000,000
mega M 106
1,000,000
kilo k 103
1,000hecto h 10
2100
deca da 10
1
10deci d 10
-10.1
centi c 10-2
0.01milli m 10
-30.001
micro 10-6
0.000001nano n 10
-90.000000001
pico p 10-12
0.000000000001
femto f 10-15
0.000000000000001atto a 10
-180.000000000000000001
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18. Formulas and Constant
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Table 18.5Engineering Notation
e 2.7183
3.1416
2 1.4142
3 1.7321
/4 0.7854
1/C one conductor
3/C three conductor
greater than
less than or equal to
less than
greater than or equal to
18.6 DIAMETER OF MULTICONDUCTOR CABLES
To calculate the overall diameter of a group of round conductors of uniform diameters twisted together, multipy the diameter of an individual conductorby the applicable factor below.
Table 18.6Diameter of Multiconductor Cables
Number of Conductors Factor
1 1.0002 2.0003 2.155
4 2.4145 2.7006 3.000
7 3.0008 3.3109 3.610
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|18. Formulas and Constants
300 |
18.7 DETERMINATION OF LARGEST POSSIBLE CONDUCTOR IN CABLE INTERSTICES
The following factors permit the calculation of the maximum size conductor that will fit into the interstices (open spaces) of various conductorconfigurations, while keeping within a circumscribing circle. Multiply the diameter of one main conductor by the factor from the chart below to obtainthe largest diameter that will fit into the interstices.
Table 18.7Determination of Largest Possible Conductor in Cable Interstices
Number of Conductors Factor
2 0.6673 0.4834 0.4145 0.3776 0.354
18.8 CONDUCTOR DIAMETER FROM WIRE DIAMETER
To calculate the nominal diameter of any concentric-lay-stranded conductor made from round wires of uniform diameters, multiply the diameter of anindividual wire by the applicable factor below:
Table 18.8Concentric Stranded Conductor Diameter from Wire Diameter
Number of Wires Factor to Calculatein Conductor Conductor Diameter
3 2.1557 3.00012 4.155
19 5.00037 7.00061 9.000
91 11.00127 13.00169 15.00
217 17.00
271 19.00
For a greater number of wires use the formula: Conductor Diameter Wire Diameter 1.332 No. of Wires
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18.9 COAXIAL CAPACITANCE
C
Where:C is capacitance in picofarads per foote is the dielectric constant (also known as SIC)t is insulation thickness in milsd is diameter over the conductor (diameter under the insulation) in mils
Other forms of this equation include:
C1
or
C2
Where:C
1is capacitance in microfarads per 1,000 ft.
C2
is capacitance in microfarads per kilometere is the dielectric constantD is diameter over the insulationd is diameter under the insulation
18.10 INDUCTIVE REACTANCE
The inductive reactance of a shielded 3-conductor medium-voltage power cable at 60 Hz can be calculated with the following formulas:
XL 0.023 Ln ( ) ohms/1,000 ft.
or
XL 0.0754 Ln ( ) ohms/km
Where:GMD geometric mean distance (equivalent conductor spacing)GMR geometric mean radius of conductor
For conductors in a triplexed configuration, GMD is equal to the center-to-center spacing. For round, concentric stranded conductors, GMR rangesfrom 0.363d for a 7-wire strand up to 0.386d for a 61-wire strand where d is the diameter of the conductor.
GMDGMR
GMDGMR
Dd
0.0556e
Ln ( )
D
d
0.0169e
Ln
( )
7.354eLog
10(1 + 2t/d)
18. Formulas and Constant
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