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Mark Scheme (Results)
January 2011
O Level
GCE O Level Pure Mathematics (7362/01)
Edexcel Limited. Registered in England and Wales No. 4496750 Registered Office: One90 High Holborn, London WC1V 7BH
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January 2011
All the material in this publication is copyright © Edexcel Ltd 2011
GCE AO Level Pure Mathematics (7362) Paper 1 January 2011
1
Pure Mathematics 7362, Mark Scheme January 2011 Paper 1 Question Number Scheme Marks
1 2
2
cos3d 2 cos3 3 sin 3d
y x xy x x x xx
=
= −
M1 A1 A1
(3) 2 sin 52 sin
4.6 5.75.7sin 52sin
4.677.5
B
B
B
=
=
=
M1 A1 A1 (3)
3
( )( )
2 2
2 2
2 2
8 2 3 4 2( 8) 3( 8) 42 2 12 0 2 30 100 0
6 0 15 50 03 2 0 ( 5)( 10) 03 5
2 10
x x x or y y yx x or y y
x x or y yx x or y y
x yx y
+ = + − = − + − −
+ − = − + =
+ − = − + =
+ − = − − =
= − == =
M1 A1 M1A1 A1 (5)
4 (a) (i) 1y = − (ii) 3x = (b) (i) ( )0 2 3 5 (or 5,0 )y x x= = − =
(ii) ( )2 2 23 3 30 1 1 (or 0, 1 )x y −= = − = − −
x-3 -2 -1 1 2 3 4 5 6 7
y
-5
-4
-3
-2
-1
1
2
3
4
(5, 0)
(0, -5/3)
(c)
B1B1 B1 B1 B1 curve B1 asymptotes B1 intercepts
(7)
GCE AO Level Pure Mathematics (7362) Paper 1 January 2011
2
Question Number Scheme Marks
5 ( )( )( )( )
( )( )
2
2
e 2 ed(a) d 2
e 2 1 2 1
22*
kx kx
kx
k xyx x
kx k y kx kxx
+ −=
+
+ − + −= =
++
alternative
( )( ) ( )
( )( )( ) ( )
2 1
2
d 2 2d
( 2 1)1 2 22
*
kx kx
kx
y e x ke xx
e y kx kk xxx
− −= − + + +
+ −= − + + =
++
( )12
2 1d 1 5(b) 0 d 2 2 4
3 *
kyx yx
k
−= = = × =
=
( )
d 5 4d 4 5
1 42 5
(c) 0 grad normal 0 10 5 8 (oe)
yxx
y xy x
= = = −
− = − −
− = −
M1A1A1 M1A1 M1A1 A1 B1 M1 A1 (11)
6
2 0 6 2(a) gradient 16 2 4 0 4 0
2 oe 1 2
y x or
y x y x
− − −= = =
− − −− = = +
( ) ( )(b) is 0, 2 2 f 0 *A r⇒ = = 3 2(c) : 6 4 4 4 2
1 16 4 4 15 : 1 3 3 1 2 6 3 9 3 3
B p qp q p q
D x y p qp q
p p q
= − − += − − + == = − − = − − +
+ == = =
( ) ( ){ }( )
4 2 4 2
4 3 2
0
4 3 2
0
4 4 43 2 3 34 2 4 20 0 0
(d) 2 3 3 2 d
3 4 d
2 2 2
64 64 32 32 8 8 (64 64 24 8) 32
x x x x
x x x x x
x x x x
x x or x x x
or
+ − − − +
= − + +
⎡ ⎤ ⎡ ⎤ ⎡ ⎤= − + + + − − − +⎣ ⎦ ⎣ ⎦ ⎣ ⎦= − + + = + − − − + =
∫∫
M1 A1 B1 M1 A1 M1A1 M1 M1A1 M1A1 (12)
GCE AO Level Pure Mathematics (7362) Paper 1 January 2011
3
Question Number Scheme Marks
7
( )( )
5 5
3
3
55
5
2 2 2 25
2
(a) 16807 16807 7(b) 7 1 6
6 1 317
log 5 12 12log5 3log(c) 12log 5 3 3log log 5 log log log5
4 log 5 1 12 3(log ) 12(log5) 3(log )
log 5 0.25 4 (lo
pp
p
p
m mn
n
por p orp p
or p or p
or
= = =
− =
+= =
= = =
= = =
= =
( ) ( ) ( )
1 12 2
2 2 25
5
2 2
125
4 4 4 4 4 4 4
4 4
g ) 4(log5) (log )
log 5 0.5 2 log 2log5 log
5 or 5 5 or 5 25 or (d) log 3 log 2 log 3 log 4 log 3 log 8 log 3 4log 3 log 16
p
p or p
or p or p
p p or p pp p
− −
=
= ± ± = ± =
= = = == =
+ + + + + +
= + +
( )
1 14 4 4 42 2
4 4 43 4
4 4 4 4 4
4 4 4 4 435184
4 4 481
1 log 3 log 3 1 log 3 1 log 3 4log 3 2log 4 1 3 4log 3
log (3 6 12 24) log (4 3 ) 3log 4 4log 3 3 4log 3 log 3 log 6 log 12 log 24 4log 3
log log 4 3log 4 3(e) l
*or
oror
+ + + + + +
= + + = +
× × × = × = + = ++ + + −
= = = =
4 4 4
4 4 4 44 4 4 4
4 4
4 4 44
4 4
3 44 4 4
og 3log 4log 3 4log 4log 3 log log 3 3
log log 3 3 3 log (3 6 12 24) 3 log 3log
log (5184) 3 log5184 5184 51 log 3 4
x xx x x
or x x xor x x
x
xx x
+ == = =
= = =× × × = + +
= +
= ⇒ = ⇒ =84 81 3
64x= ⇒ =
M1A1 M1 A1 M1 A1 M1 A1
M1 M1A1 M1
M1A1
(14)
GCE AO Level Pure Mathematics (7362) Paper 1 January 2011
4
Question Number Scheme Marks
8
( ) ( )( )
( )( )
2 2
2 2 2 12
2 2 2 2 21 12 2
2 2 2 12
1 12 2
(a) cos 2 cos sin
(i) cos 2 1 sin sin sin 1 cos 2
1 cos 2 ((cos sin ) (cos sin )) sin
(ii) cos 2 cos 1 cos cos cos 2 1
cos 2 1 ((co
*
*or
or
θ θ θ
θ θ θ θ θ
θ θ θ θ θ θ
θ θ θ θ θ
θ
= −
= − − = −
− = + − − =
= − + = +
+ =
( ) ( )( )
( )
2 2 2 2 2
4 2
21 12 2
2
12
2
s sin ) (cos sin )) cos
(b) 8sin 4sin 5 8 ( 1 cos 2 ) 4 1 cos 2 5
2 1 2cos 2 cos 2 2 2cos 2 5
1 6cos 2 2 cos 4 1 cos 4 6cos 2
cos4 6cos 2 (2cos 2 1)
*or
θ θ θ θ θ
θ θ
θ θ
θ θ θ
θ θ θ θ
θ θ θ
− + + =
+ −
= × − + × − −
= − + + − −
= − − + × + = −
− = −
( )
2
2 2 2
2 4 2
4 2
4 2
12
6(1 2sin )2(1 2sin ) 1 6 12sin2(1 4sin 4sin ) 7 12sin8sin 4sin 5
(c) 4sin 2sin 3cos 2 2.4 cos 4 6cos 2 5 3cos 2 2.4 cos 4 0.2 4 1.772, 4.511
*
θ
θ θ
θ θ θ
θ θ
θ θ θθ θ θ
θ θ
− −
= − − − +
= − + − +
= + −
+ + =
− + + =
= − =
( )4
8
4 2 2
4 2 2
14
0.443, 1.13 4sin 2sin 3(1 2sin ) 2.4
4sin 4sin 0.6 0, sin 0.184 or 0.816 sin 0.429 or 0.903 0.443, 1.13
(d) 4 cos 4 6cos 2 d 4 sin 4 3si
or
π
π
θ
θ θ θ
θ θ θθ θ
θ θ θ θ
=
+ + − =
− + = == ± ± =
− = −∫ [ ]
( )( )( )
4
8
1 14 2 4 2 4
214 2
n 2
4 sin 3sin sin 3sin
4 3 3
13 6 2 13, 6m n
π
π
π π π
θ
π= − − −
= − − + ×
= − + = − =
M1A1 A1 M1
M1 M1 A1
M1
M1
A1A1 M1A1 M1 B1 A1
(16)
GCE AO Level Pure Mathematics (7362) Paper 1 January 2011
5
Question Number Scheme Marks
9 ( )
( )( )
( )
1 11 2 2
55
1 12 2
2
42
12
12
1
(a) : through ,6
grad. grad perp 1 perp. bisector: 6
(b) : through 1,6 grad 2 grad perp perp. bisector: 6 1
(c) :
l
PQ
y x
lQR
y x
l
=
= −
− = − −
−
= =
= −
− = − +
( )( )
1
1 1 1 12 22 2 2 2
1 12 2
2
1
7 4 3 7 3, 4 lies on
: 5 4 1 5 3, 4 lies on 1 , 3, 4 eliminate , 4, 3(d) length 5 area 5 25(e) is perp. bisector
**
y x l
l y x lor x x y or x y x
PS
lπ π
+ = + = ∴
+ = + = ∴
= = = = =
=
= =
( )
2 22
1 13 2 2
of 3 ( 2) 5
is perp. bisector of 3 4 =5 radius circle passes through and .(f) passes through midpoint of ie 1 ,8
PQ or QS PS QS
l QR or RS RS QSSQ SR Q Rl PR
= − − = ∴ =
= + ∴ == = ∴
B1 M1 A1ft B1 B1 B1 B1 M1A1 A1 M1A1 M1 A1 M1A1 (16)
GCE AO Level Pure Mathematics (7362) Paper 1 January 2011
6
Question Number Scheme Marks
10
( )
( )( )
4 3 753 4 4
3 154 4
1212 2
43
(a) 8 5 3 4 19th term 18 18 25 18 4th term 3 4 5 3 19th term 5 4th term (b) 2 11
300 6 2 11 300
*
a d d
d d
a
a d a dd a
a d a a or da d a a a or d
S a d
a or
+ = +
== + = + × = + =
= + = + = + =
∴ = ×
= +
= + × ( )
( )( )
( )
34
43
2
2
6 2 11 300 12 88 3 (c) 4
(d) 2000 6 4 1
2 2000 0
1 1 16000 critical value(s) 31.4 31.94
greatest 31
* 300 9 66 4, 3 *
d
a
p
da a a
d
p
p p
p
or d d d a= × +
= + == =
> + −
+ − <
− ± += −
=
= + ⇒ = =
M1 A1 M1A1 M1A1 A1 B1 M1 A1 M1A1 A1ft (13)
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