8
452 Chapter 6 Rational Exponents and Radical Functions 6.6 Solve Radical Equations Before You solved polynomial equations. Now You will solve radical equations. Why? So you can calculate hang time, as in Ex. 60. Key Vocabulary radical equation extraneous solution, p. 52 Equations with radicals that have variables in their radicands are called radical equations. An example of a radical equation is 3 Ï } 2x 1 7 5 3. KEY CONCEPT For Your Notebook Solving Radical Equations To solve a radical equation, follow these steps: STEP 1 Isolate the radical on one side of the equation, if necessary. STEP 2 Raise each side of the equation to the same power to eliminate the radical and obtain a linear, quadratic, or other polynomial equation. STEP 3 Solve the polynomial equation using techniques you learned in previous chapters. Check your solution. E XAMPLE 1 Solve a radical equation Solve 3 Ï } 2x 1 7 5 3. 3 Ï } 2x 1 7 5 3 Write original equation. ( 3 Ï } 2x 1 7 ) 3 5 3 3 Cube each side to eliminate the radical. 2x 1 7 5 27 Simplify. 2x 5 20 Subtract 7 from each side. x 5 10 Divide each side by 2. CHECK Check x 5 10 in the original equation. 3 Ï } 2(10) 1 7 0 3 Substitute 10 for x. 3 Ï } 27 0 3 Simplify. 3 5 3 Solution checks. GUIDED PRACTICE for Example 1 Solve the equation. Check your solution. 1. 3 Ï } x 2 9 5 21 2. Ï } x 1 25 5 4 3. 2 3 Ï } x 2 3 5 4

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Page 1: 6.6 Solve Radical Equations - San Dieguito Union High ...teachers.sduhsd.net/dpillsbury/IM1 Honors/Module 11/Radical... · Solving Radical Equations ... EXAMPLE 3 Standardized Test

452 Chapter 6 Rational Exponents and Radical Functions

6.6 Solve Radical Equations

Before You solved polynomial equations.

Now You will solve radical equations.

Why? So you can calculate hang time, as in Ex. 60.

Key Vocabulary • radical equation• extraneous

solution, p. 52

Equations with radicals that have variables in their radicands are called

radical equations. An example of a radical equation is 3 Ï}

2x 1 7 5 3.

KEY CONCEPT For Your Notebook

Solving Radical Equations

To solve a radical equation, follow these steps:

STEP 1 Isolate the radical on one side of the equation, if necessary.

STEP 2 Raise each side of the equation to the same power to eliminate the radical and obtain a linear, quadratic, or other polynomial equation.

STEP 3 Solve the polynomial equation using techniques you learned in previous chapters. Check your solution.

E X A M P L E 1 Solve a radical equation

Solve 3 Ï}

2x 1 7 5 3.

3 Ï}

2x 1 7 5 3 Write original equation.

( 3 Ï}

2x 1 7 )3 5 33 Cube each side to eliminate the radical.

2x 1 7 5 27 Simplify.

2x 5 20 Subtract 7 from each side.

x 5 10 Divide each side by 2.

CHECK Check x 5 10 in the original equation.

3 Ï}

2(10) 1 7 0 3 Substitute 10 for x.

3 Ï}

27 0 3 Simplify.

3 5 3 ✓ Solution checks.

✓ GUIDED PRACTICE for Example 1

Solve the equation. Check your solution.

1. 3 Ï}

x 2 9 5 21 2. Ï}

x 1 25 5 4 3. 2 3 Ï}

x 2 3 5 4

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Page 2: 6.6 Solve Radical Equations - San Dieguito Union High ...teachers.sduhsd.net/dpillsbury/IM1 Honors/Module 11/Radical... · Solving Radical Equations ... EXAMPLE 3 Standardized Test

6.6 Solve Radical Equations 453

E X A M P L E 2 Solve a radical equation given a function

WIND VELOCITY In a hurricane, the mean sustained wind velocity v (in meters per second) is given by

v(p) 5 6.3 Ï}

1013 2 p

where p is the air pressure (in millibars) at the center of the hurricane. Estimate the air pressure at the center of a hurricane when the mean sustained wind velocity is 54.5 meters per second.

Solution

v(p) 5 6.3 Ï}

1013 2 p Write given function.

54.5 5 6.3 Ï}

1013 2 p Substitute 54.5 for v(p).

8.65 ø Ï}

1013 2 p Divide each side by 6.3.

(8.65)2 ø ( Ï}

1013 2 p )2 Square each side.

74.8 ø 1013 2 p Simplify.

2938.2 ø 2p Subtract 1013 from each side.

938.2 ø p Divide each side by 21.

c The air pressure at the center of the hurricane is about 938 millibars.

✓ GUIDED PRACTICE for Example 2

4. WHAT IF? Use the function in Example 2 to estimate the air pressure at the center of a hurricane when the mean sustained wind velocity is 48.3 meters per second.

ANOTHER WAY

For alternative methods for solving the problem in Example 2, turn to page 460 for the Problem Solving Workshop.

RATIONAL EXPONENTS When an equation contains a power with a rational exponent, you can solve the equation using a procedure similar to the one for solving radical equations. In this case, you first isolate the power and then raise each side of the equation to the reciprocal of the rational exponent.

Solution

4x2/3 5 36 Write original equation.

x2/3 5 9 Divide each side by 4.

(x2/3)3/2 5 93/2 Raise each side to the power 3 } 2

.

x 5 27 Simplify.

c The correct answer is D. A B C D

E X A M P L E 3 Standardized Test Practice

What is the solution of the equation 4x2/3 5 36?

A 3 B 6 C 21 D 27

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Page 3: 6.6 Solve Radical Equations - San Dieguito Union High ...teachers.sduhsd.net/dpillsbury/IM1 Honors/Module 11/Radical... · Solving Radical Equations ... EXAMPLE 3 Standardized Test

454 Chapter 6 Rational Exponents and Radical Functions

E X A M P L E 4 Solve an equation with a rational exponent

Solve (x 1 2)3/4 2 1 5 7.

(x 1 2)3/4 2 1 5 7 Write original equation.

(x 1 2)3/4 5 8 Add 1 to each side.

F (x 1 2)3/4 G 4/3 5 84/3 Raise each side to the power 4 } 3

.

x 1 2 5 (81/3)4 Apply properties of exponents.

x 1 2 5 24 Simplify.

x 1 2 5 16 Simplify.

x 5 14 Subtract 2 from each side.

c The solution is 14. Check this in the original equation.

E X A M P L E 5 Solve an equation with an extraneous solution

Solve x 1 1 5 Ï}

7x 1 15 .

x 1 1 5 Ï}

7x 1 15 Write original equation.

(x 1 1)2 5 ( Ï}

7x 1 15 )2 Square each side.

x2 1 2x 1 1 5 7x 1 15 Expand left side and simplify right side.

x2 2 5x 2 14 5 0 Write in standard form.

(x 2 7)(x 1 2) 5 0 Factor.

x 2 7 5 0 or x 1 2 5 0 Zero-product property

x 5 7 or x 5 22 Solve for x.

CHECK

Check x 5 7 in the original equation. Check x 5 22 in the original equation.

x 1 1 5 Ï}

7x 1 15

7 1 1 0 Ï}

7(7) 1 15

8 0 Ï}

64

8 5 8 ✓

x 1 1 5 Ï}

7x 1 15

22 1 1 0 Ï}}

7(22) 1 15

21 0 Ï}

1

21 Þ 1

c The only solution is 7. (The apparent solution 22 is extraneous.)

✓ GUIDED PRACTICE for Examples 3 and 4

Solve the equation. Check your solution.

5. 3x3/2 5 375 6. 22x3/4 5 216 7. 2 2 } 3

x1/5 5 22

8. (x 1 3)5/2 5 32 9. (x 2 5)4/3 5 81 10. (x 1 2)2/3 1 3 5 7

EXTRANEOUS SOLUTIONS Raising each side of an equation to the same power may introduce extraneous solutions. When you use this procedure, you should always check each apparent solution in the original equation.

REVIEW FACTORING

For help with factoring, see p. 252.

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Page 4: 6.6 Solve Radical Equations - San Dieguito Union High ...teachers.sduhsd.net/dpillsbury/IM1 Honors/Module 11/Radical... · Solving Radical Equations ... EXAMPLE 3 Standardized Test

6.6 Solve Radical Equations 455

Solve Ï}

x 1 2 1 1 5 Ï}

3 2 x .

Solution

METHOD 1 Solve using algebra.

Ï}

x 1 2 1 1 5 Ï}

3 2 x Write original equation.

( Ï}

x 1 2 1 1)2 5 ( Ï}

3 2 x )2 Square each side.

x 1 2 1 2 Ï}

x 1 2 1 1 5 3 2 x Expand left side and simplify right side.

2 Ï}

x 1 2 5 22x Isolate radical expression.

Ï}

x 1 2 5 2x Divide each side by 2.

( Ï}

x 1 2 )2 5 (2x)2 Square each side again.

x 1 2 5 x2 Simplify.

0 5 x2 2 x 2 2 Write in standard form.

0 5 (x 2 2)(x 1 1) Factor.

x 2 2 5 0 or x 1 1 5 0 Zero-product property

x 5 2 or x 5 21 Solve for x.

Check x 5 2 in the original equation. Check x 5 21 in the original equation.

Ï}

x 1 2 1 1 5 Ï}

3 2 x

Ï}

2 1 2 1 1 0 Ï}

3 2 2

Ï}

4 1 1 0 Ï}

1

3 Þ 1

Ï}

x 1 2 1 1 5 Ï}

3 2 x

Ï}

21 1 2 1 1 0 Ï}

3 2 (21)

Ï}

1 1 1 0 Ï}

4

2 5 2 ✓

c The only solution is 21. (The apparent solution 2 is extraneous.)

METHOD 2 Use a graph to solve the equation.

Use a graphing calculator to graph y1 5 Ï

}

x 1 2 1 1 and y2 5 Ï}

3 2 x . Then find the intersection points of the two

graphs by using the intersect feature. You will find that the only point of intersection is (21, 2). Therefore, 21 is the only solution of the equation

Ï}

x 1 2 1 1 5 Ï}

3 2 x .

E X A M P L E 6 Solve an equation with two radicals

SQUARING TWICE When an equation contains two radicals, you may need to square each side twice in order to eliminate both radicals.

✓ GUIDED PRACTICE for Examples 5 and 6

Solve the equation. Check for extraneous solutions.

11. x 2 1 } 2

5 Î}

1 } 4

x 12. Ï}

10x 1 9 5 x 1 3

13. Ï}

2x 1 5 5 Ï}

x 1 7 14. Ï}

x 1 6 2 2 5 Ï}

x 2 2

IntersectionX=-1 Y=2

REVIEW FOIL METHOD

For help with multiplying algebraic expressions usingthe FOIL method,see p. 245.

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456 Chapter 6 Rational Exponents and Radical Functions

6.6 EXERCISES

1. VOCABULARY Copy and complete: When you solve an equation algebraically, an apparent solution that must be rejected because it does not satisfy the original equation is called a(n) ? solution.

2. ★ WRITING A student was asked to solve Ï}

3x 2 1 2 Ï}

9x 2 5 5 0. His first step was to square each side. While trying to isolate x, he gave up in frustration. What could the student have done to avoid this situation?

EQUATIONS WITH SQUARE ROOTS Solve the equation. Check your solution.

3. Ï}

5x 1 1 5 6 4. Ï}

3x 1 10 5 8 5. Ï}

9x 1 11 5 14

6. Ï}

2x 2 2 } 3

5 0 7. 22 Ï}

24x 1 13 5 211 8. 8 Ï}

10x 2 7 5 9

9. Ï}

x 2 25 1 3 5 5 10. 24 Ï}

x 2 6 5 220 11. Ï}

22x 1 3 2 2 5 10

12. ★ MULTIPLE CHOICE What is the solution of Ï}

8x 1 3 5 3?

A 2 3 } 4

B 0 C 3 } 4

D 9 } 8

EQUATIONS WITH CUBE ROOTS Solve the equation. Check your solution.

13. 3 Ï}

x 2 10 5 23 14. 3 Ï}

x 2 16 5 2 15. 3 Ï}

12x 2 13 5 27

16. 3 3 Ï}

16x 2 7 5 17 17. 25 3 Ï}

8x 1 12 5 28 18. 3 Ï}

4x 1 5 5 1 } 2

19. 3 Ï}

x 2 3 1 2 5 4 20. 3 Ï}

4x 1 2 2 6 5 210 21. 24 3 Ï}

x 1 10 1 3 5 15

22. ★ OPEN-ENDED MATH Write a radical equation of the form 3 Ï}

ax 1 b 5 c that has 23 as a solution. Explain the method you used to find your equation.

EQUATIONS WITH RATIONAL EXPONENTS Solve the equation. Check your solution.

23. 2x2/3 5 32 24. 1 } 2

x5/2 5 16 25. 9x2/5 5 36

26. (8x)4/3 1 44 5 300 27. 1 } 7

(x 1 9)3/2 5 49 28. (x 2 5)5/3 2 73 5 170

29. 1 1 } 3

x 2 11 2 1/2

5 5 30. (5x 2 19)5/6 5 32 31. (3x 1 43)2/3 1 22 5 38

ERROR ANALYSIS Describe and correct the error in solving the equation.

32. 3 Ï

} x 1 2 5 4

( 3 Ï}

x 1 2)3 5 43

x 1 8 5 64

x 5 56

33. (x 1 7)1/2 5 5

F (x 1 7)1/2 G 2 5 5

x 1 7 5 5

x 5 22

EXAMPLES3 and 4

on pp. 453–454 for Exs. 23–33

EXAMPLE 1

on p. 452for Exs. 3–21

HOMEWORKKEY

5 WORKED-OUT SOLUTIONSon p. WS1 for Exs. 5, 13, and 59

★ 5 STANDARDIZED TEST PRACTICEExs. 2, 12, 22, 43, 44, 59, and 60

SKILL PRACTICE

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6.6 Solve Radical Equations 457

56. MAXIMUM SPEED In an amusement park ride called the Sky Flyer,a rider suspended by a cable swings back and forth like a pendulumfrom a tall tower. A rider’s maximum speed v (in meters per second)occurs at the bottom of each swing and can be approximated by

v 5 Ï}

2gh where h is the height (in meters) at the top of each swing and g is the acceleration due to gravity (g ø 9.8 m/sec2). If a rider’s maximum speed was 15 meters per second, what was the rider’s height at the top of the swing?

EXAMPLE 5

on p. 454for Exs. 34–44

EXAMPLE 6

on p. 455for Exs. 45–52

SOLVING RADICAL EQUATIONS Solve the equation. Check for extraneous solutions.

34. x 2 6 5 Ï}

3x 35. x 2 10 5 Ï}

9x 36. x 5 Ï}

16x 1 225

37. Ï}

21x 1 1 5 x 1 5 38. Ï}

44 2 2x 5 x 2 10 39. Ï}

x2 1 4 5 x 1 5

40. x 2 2 5 Î} 3 } 2

x 2 2 41. 4 Ï}

3 2 8x2 5 2x 42. 3 Ï}

8x3 2 1 5 2x 2 1

43. ★ MULTIPLE CHOICE What is (are) the solution(s) of Ï}

32x 2 64 5 2x?

A 4 B 216 C 4, 216 D 1, 3

44. ★ SHORT RESPONSE Explain how you can tell that Ï}

x 1 4 5 25 has no solution without solving it.

EQUATIONS WITH TWO RADICALS Solve the equation. Check for extraneous solutions.

45. Ï}

4x 1 1 5 Ï}

x 1 10 46. 3 Ï}

12x 2 5 2 3 Ï}

8x 1 15 5 0

47. Ï}

3x 2 8 1 1 5 Ï}

x 1 5 48. Î} 2 } 3

x 2 4 5 Î} 2 } 5

x 2 7

49. Ï}

x 1 2 5 2 2 Ï}

x 50. Ï}

2x 1 3 1 2 5 Ï}

6x 1 7

51. Ï}

2x 1 5 5 Ï}

x 1 2 1 1 52. Ï}

5x 1 6 1 3 5 Ï}

3x 1 3 1 4

SOLVING SYSTEMS Solve the system of equations.

53. 3 Ï}

x 1 5 Ï}

y 5 31 54. 5 Ï}

x 2 2 Ï}

y 5 4 Ï}

2

5 Ï}

x 2 5 Ï}

y 5 215 2 Ï}

x 1 3 Ï}

y 5 13 Ï}

2

55. CHALLENGE Give an example of a radical equation that has two extraneous solutions.

EXAMPLE 2

on p. 453for Exs. 56–57

PROBLEM SOLVING

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458 Chapter 6 Rational Exponents and Radical Functions

57. BURNING RATE A burning candle has a radius of r inches and was initially h0 inches tall. After t minutes, the height of the candle has been reduced to h inches. These quantities are related by the formula

r 5 Î} kt } π(h0 2 h)

where k is a constant. How long will it take for the entire candle to burn if its radius is 0.875 inch, its initial height is 6.5 inches, and k 5 0.04?

58. CONSTRUCTION The length l (in inches) of a standard nail can be modeled by l 5 54d 3/2 where d is the diameter (in inches) of the nail. What is the

diameter of a standard nail that is 3 inches long?

59. ★ SHORT RESPONSE Biologists have discovered that the shoulder height h (in centimeters) of a male African elephant can be modeled by

h 5 62.5 3 Ï} t 1 75.8

where t is the age (in years) of the elephant. Compare the ages of two elephants, one with a shoulder height of 150 centimeters and the other with a shoulder height of 250 centimeters.

60. ★ EXTENDED RESPONSE “Hang time” is the time you are suspended in the air during a jump. Your hang time t (in seconds) is given by the function

t 5 0.5 Ï}

h where h is the height of the jump (in feet). A basketball player jumps and has a hang time of 0.81 second. A kangaroo jumps and has a hang time of 1.12 seconds.

a. Solve Find the heights that the basketball player and the kangaroo jumped.

b. Calculate Double the hang times of the basketball player and the kangaroo and calculate the corresponding heights of each jump.

c. Interpret If the hang time doubles, does the height of the jump double? Explain.

at classzone.com

61. MULTI-STEP PROBLEM The Beaufort wind scale was devised to measure wind speed. The Beaufort numbers B, which range from 0 to 12, can be modeled by

B 5 1.69 Ï}

s 1 4.25 2 3.55

where s is the speed (in miles per hour) of the wind.

a. Find the wind speed that corresponds to the Beaufort number B 5 0.

b. Find the wind speed that corresponds to the Beaufort number B 5 12.

c. Write an inequality that describes the range of wind speeds represented by the Beaufort model.

Beaufort Wind Scale

Beaufort number Force of wind

0 Calm

3 Gentle breeze

6 Strong breeze

9 Strong gale

12 Hurricane

5 WORKED-OUT SOLUTIONSon p. WS1

h

★ 5 STANDARDIZED TEST PRACTICE

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6.6 Solving Radical Equations 459

62. CHALLENGE You are trying to determine a truncated pyramid’s height, which cannot be measured directly. The height h and slant height l of the truncated pyramid are related by the formula shown below.

l 5 Î}}

h2 1 1 } 4

(b2 2 b1)2

In the given formula, b1 and b2 are the side lengths of the upper and lower bases of the pyramid, respectively. If l 5 5, b1 5 2, and b2 5 4, what is the height of the pyramid?

EXTRA PRACTICE for Lesson 6.6, p. 1015 ONLINE QUIZ at classzone.com

Graph the function. Then state the domain and range. (p. 446)

1. y 5 4 Ï}

x 2. y 5 Ï}

x 1 3 3. g(x) 5 Ï}

x 1 2 2 5

4. y 5 2 1 } 2

3 Ï}

x 5. f(x) 5 3 Ï}

x 2 4 6. y 5 3 Ï}

x 2 3 1 2

Solve the equation. Check for extraneous solutions. (p. 452)

7. Ï}

6x 1 15 5 9 8. 1 } 4

(7x 1 8)3/2 5 54 9. 3 Ï}

3x 1 5 1 2 5 5

10. x 2 3 5 Ï}

10x 2 54 11. Ï}

4x 2 4 5 Ï}

5x 2 1 2 1 12. 3 Î} 4 } 5

x 2 9 5 3 Ï}

x 2 6

13. ASTRONOMY According to Kepler’s third law of planetary motion, the function P 5 0.199a3/2 relates a planet’s orbital period P (in days) to the length a (in millions of kilometers) of the orbit’s minor axis. The orbital period of Mars is about 1.88 years. What is the length of the orbit’s minor axis? (p. 452)

QUIZ for Lessons 6.5–6.6

2

4

5 h

Evaluate the expression. Tell which properties of exponents you used. (p. 330)

63. 43 p 42 64. (322)3 65. (25)(25)24

66. (1023)21 67. 824 p 83 68. 60 p 64 p 624

Graph the function. (p. 337)

69. f(x) 5 2x3 70. f(x) 5 x4 2 9 71. f(x) 5 x3 1 2

72. f(x) 5 x4 2 8x2 2 48 73. f(x) 5 2 1 } 3

x3 1 x 74. f(x) 5 x5 2 2x 2 4

Evaluate the expression without using a calculator. (p. 414)

75. 163/2 76. 1 } 825/3

77. 22561/4

78. 425/2 79. 312523/5 80. 1 } 274/3

PREVIEW

Prepare for Lesson 7.1 in Exs. 63–68.

MIXED REVIEW

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