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6.2d4 Volume by Slicing

6.2d4 Volume by Slicing. Revolve the area bound by the x-axis the curve f(x) = -(x - 1) 2 + 4 and the x-axis

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Page 1: 6.2d4 Volume by Slicing. Revolve the area bound by the x-axis the curve f(x) = -(x - 1) 2 + 4 and the x-axis

6.2d4Volume by Slicing

Page 2: 6.2d4 Volume by Slicing. Revolve the area bound by the x-axis the curve f(x) = -(x - 1) 2 + 4 and the x-axis

• Revolve the area bound by the x-axis the curve f(x) = -(x - 1)2 + 4 and the x-axis

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Page 3: 6.2d4 Volume by Slicing. Revolve the area bound by the x-axis the curve f(x) = -(x - 1) 2 + 4 and the x-axis

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• Revolve the area bound by the x-axis the curve f(x) = -(x - 1)2 + 4 and the x-axis

• Make a paper thin slice at x = 2, we’ll say 0.01 units wide, calculate the volume of that slice.

Page 4: 6.2d4 Volume by Slicing. Revolve the area bound by the x-axis the curve f(x) = -(x - 1) 2 + 4 and the x-axis

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• Revolve the area bound by the x-axis the curve f(x) = -(x - 1)2 + 4 and the x-axis

• Make a paper thin slice at x = 2, we’ll say 0.01 units wide, calculate the volume of that slice.

• Vslice = πr2 w

• Vslice = π32 0.01

• Vslice = 0.09π

Page 5: 6.2d4 Volume by Slicing. Revolve the area bound by the x-axis the curve f(x) = -(x - 1) 2 + 4 and the x-axis

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• Revolve the area bound by the x-axis the curve f(x) = -(x - 1)2 + 4 and the x-axis

Make a paper thin slice at x = k, we’ll say 0.01 units wide, calculate the volume of that slice.• Vslice = πr2 w

• r = y-value at the slice• r = y = -(x – 1)2 + 4,• x = k… r = -(k – 1)2 + 4• Vslice = π(-(k – 1)2 + 4)2 0.01

Page 6: 6.2d4 Volume by Slicing. Revolve the area bound by the x-axis the curve f(x) = -(x - 1) 2 + 4 and the x-axis

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• Revolve the area bound by the x-axis the curve f(x) = -(x - 1)2 + 4 and the x-axis

• Generically, we can say the volume of the slice at a given x value with width Δx is…

• Vslice = π(-(x – 1)2 + 4)2 w• If you make all of the

slices infinitely thin and add them together, they become an integral distance in the direction that you are adding the slices

Page 7: 6.2d4 Volume by Slicing. Revolve the area bound by the x-axis the curve f(x) = -(x - 1) 2 + 4 and the x-axis

The same principal is true for other slice shapes.

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4• The area bounded by f(x) = -(x - 1)2 + 4 is the base of an object.

• If you sliced this object vertically, it would have a cross sectional area of a square.

• Find the volume of the slice at x = 2

• V = Lwh = b2w

• V = 32 * 0.01• V = 0.09

Page 8: 6.2d4 Volume by Slicing. Revolve the area bound by the x-axis the curve f(x) = -(x - 1) 2 + 4 and the x-axis

• The area bounded by the x-axis and the curve f(x) = -(x - 1)2 + 4 is the base of an object with a vertical cross section that is a square.

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4• Find the total volume

Page 9: 6.2d4 Volume by Slicing. Revolve the area bound by the x-axis the curve f(x) = -(x - 1) 2 + 4 and the x-axis

• The area bounded by the x-axis and the curve f(x) = -(x - 1)2 + 4 is the base of an object with a vertical cross section that is a semicricle.

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4• Find the total volume• What is the volume of

a single slice?

• Which terms becomes an integral distance as I make slices infinitely thin?

Page 10: 6.2d4 Volume by Slicing. Revolve the area bound by the x-axis the curve f(x) = -(x - 1) 2 + 4 and the x-axis

• The area bounded by the x-axis and the curve f(x) = -(x - 1)2 + 4 is the base of an object with a vertical cross section that is a semicricle.

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4• Find the total volume

• What’s constant?

• What does r = ?

Page 11: 6.2d4 Volume by Slicing. Revolve the area bound by the x-axis the curve f(x) = -(x - 1) 2 + 4 and the x-axis

• The area bounded by the x-axis and the curve f(x) = -(x - 1)2 + 4 is the base of an object with a vertical cross section that is an isosceles right triangle.

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• Find the total volume• What is the volume of

a single slice?

• Which terms becomes an integral distance as I make slices infinitely thin?

Page 12: 6.2d4 Volume by Slicing. Revolve the area bound by the x-axis the curve f(x) = -(x - 1) 2 + 4 and the x-axis

• The area bounded by the x-axis and the curve f(x) = -(x - 1)2 + 4 is the base of an object with a vertical cross section that is an isosceles right triangle.

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• Find the total volume

• What’s constant?

• What does b = ?