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    Name:______________________ ( ) Class:________

    Marks:_______/70

    SPRINGFIELD SECONDARY SCHOOLBETTER SELF FOR BETTER TOMORROW

    Mid-Year Examination 2010

    ADDITIONAL MATHEMATICS 4039/01

    Paper 1

    Sec 4 Normal Academic

    7 May 2010 1 hour 45 minutes

    Additional Materials: Writing Paper

    ___________________________________________________________________________

    READ THESE INSTRUCTIONS FIRST

    Write your name, register number and class in the spaces at the top of this page, on all the

    work you hand in.

    Write in dark blue or black pen on both sides of the paper.

    You may use a soft pencil for any diagrams, graphs, tables or rough working.

    Do not use paper clips, highlighters, glue or correction fluid.

    Answerall questions.

    Write your answers on the Writing Paper provided.

    Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place in the

    case of angles in degrees, unless a different level of accuracy is specified in the question.

    The use of electronic calculator is expected, where appropriate.

    You are reminded of the need for clear presentation in your answers.

    At the end of the examination, fasten all your work securely together.

    The number of marks is given in brackets [ ] at the end of each question or part question.

    The total number of marks for this paper is 70.

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    Do not turn over this question paper until you are told to do so.

    ___________________________________________________________________________

    This question paper consists of 5 printed pages

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    Mathematical Formulae

    1. ALGEBRA

    Quadratic Equation

    For the equation 02 =++ cbxax ,

    a

    acbbx

    2

    42 =

    Binomial Expansion

    ( ) nrrnnnnn bbar

    nba

    nba

    naba ++

    ++

    +

    +=+ ......

    21

    221

    where n is a positive integer and!

    )1)...(1(

    )!(!

    !

    r

    rnnn

    rnr

    n

    r

    n +=

    =

    2. TRIGONOMETRY

    Identities

    1cossin 22 =+ AAAA 22 tan1sec +=

    cosec 2 A = 1 + cot 2 ABABABA sincoscossin)sin( =BABABA sinsincoscos)cos( =

    BA

    BABA

    tantan1

    tantan)tan(

    =

    AAA cossin22sin =

    AAAAA

    2222

    sin211cos2sincos2cos===

    A

    AA

    2tan1

    tan22tan

    =

    Formulae for ABC

    C

    c

    B

    b

    A

    a

    sinsinsin==

    Abccba cos2222+=

    Abc sin2

    1=

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    Answer all questions.

    1 (i) Write down the inverse of the matrix .67

    34

    [2]

    (ii) Hence solve the simultaneous equations

    .01667

    ,0743

    =++=++

    yx

    xy[3]

    2 Find the range of values ofx for which2

    2

    59x

    x

    +. [4]

    3 Find the range of values ofkfor which the liney = k 3x does not intersect the [4]

    curvexy = 3.

    4 (a) The coefficient ofx4 in the expansion of (1 +px)(1 2x)8 is -224.

    Find the value ofp. [4]

    (b) Find the term independent ofx in the expansion6

    5 2

    x

    x [4]

    5. The acute angleA is such that2

    3cos =A .

    Express in the formb

    a, where a and b are integers,

    (i) Asin , [1]

    (ii) cotA . [2]

    6. It is given that .3cos4)(f xx =

    (i) State the amplitude of f. [1]

    (ii) State the period of f, for x0 . [1]

    (iii) Sketch the graph of )(f xy = for x0 .[3]

    7 (i) Solve the equation, 12sin2 = , for 3600 x [3]

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    (ii) Show that sin)90cos( =+ [3]

    8 Solutions to this question by accurate drawing will not be accepted.

    The diagram above, not drawn to scale, shows a circle with centre C(2, 3) and

    radius 5 units. The circle cuts thex-axis atA andB.

    The perpendicular bisector ofA and Ccuts thex-axis atD.Find

    (i) the equation of the circle, [1]

    (ii) the coordinates ofA, [3]

    (iii) the midpoint ofAC, [1]

    (iv) the gradient ofAC, [1]

    (v) the coordinates ofD. [3]

    9 Differentiate the following with respect tox.

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    (i) 23

    410

    xx

    [2]

    (ii) 2)43(7

    x [2]

    10. Find the equation of the normal to the curvex

    xy4

    += , at the pointPwhere [4]

    x = 4.

    11. A curve has the equation 2634 23 += xxxy .

    (i) Find the coordinates of the stationary points. . [5]

    (ii) Determine the nature of each of these stationary points. [3]

    12. Evaluate the following

    (i)4

    11

    0

    dxx [2]

    (ii) dxx

    x )1(3

    1

    2 + [3]

    13. The gradient of the tangent at a point on a curve is given by 22 +xx . [5]

    Find the equation of the curve which passes through the point (2, 1).

    End of Paper

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    Springfield Secondary School

    Mathematics Department

    Marking Scheme

    Test : Mid Year Exam 2010 Paper 1

    Level: Sec 4 NA A.Maths

    Q Marking points Mark

    Awarded

    Total

    1. (i)Inverse =

    47

    36

    2124

    1

    =3

    1

    47

    36

    B1

    (determinant)

    B1 (order in

    matrix)

    [2]

    (ii)

    =

    =

    =+=+

    5

    2

    16

    7

    47

    36

    3

    1

    1667734

    y

    x

    y

    x

    yxyx M1

    M1

    A1

    [3]

    2.

    521

    )5)(12(0

    5920

    259

    2

    2

    +

    +

    x

    xx

    xx

    xx

    M1

    M1

    A2

    [4]

    3.

    366

    0)6)(6(

    036

    0)3)(3(4)(

    04

    033

    3)3(

    2

    2

    2

    2

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    Q Marking points Mark

    Awarded

    Total

    rr xxr

    )2()(6 165

    Power ofx: 30- 5r- r= 0 r= 5

    Term independent ofx: (-2)5

    = -32

    M1

    M1A1

    5. (i)

    2

    1sin =A B1 [1]

    (ii)

    3

    tan

    1cot

    =

    =A

    AM1

    A1

    [2]

    6. (i) Amplitude = 1 B1 [1]

    (ii)Period =

    3

    2 B1 [1]

    (iii

    )

    B1 y=cosx

    B1 correct -

    scale

    B1 correct-

    frequency

    [3]

    8. (i)

    =

    =

    ==

    255,195,75,15

    510,390,150,302

    30,2

    12sin0

    basicangle M1

    M1

    A1

    [3]

    (ii)

    sin

    sin0

    sin90sincos90cos

    ==

    M1M1

    A1

    [3]

    1

    0.

    (i) 222 5)3()2( =+ yx B1 [1]

    (ii)

    0)A(-2,

    2-or)(6

    16)2(

    25)30()2(2

    22

    rejectx

    x

    x

    ==

    =+M1

    M1

    A1

    [3]

    (iii

    )

    (iv)

    1.5),0(:Midpt B1

    B1

    [1]

    [1]

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    Q Marking points Mark

    Awarded

    Total

    Grad of AC=

    4

    3

    )2(2

    03

    =

    (v)

    Grad of line passing through D =

    3

    4

    Equation of line: c =1.5, y = 5.13

    4+ x

    D: ( 1.125, 0)

    M1

    M1

    A1

    [3]

    9 (i)

    3

    2

    32

    8

    10

    3

    d

    d

    8

    10

    3

    d

    d

    x

    x

    x

    y

    xx

    x

    y

    +=

    += M1

    A1

    [2]

    (ii)

    3

    4

    2

    )43(

    42

    d

    d

    )43(

    )]3)(43(2[7)0()43(

    d

    d

    =

    =

    xx

    y

    x

    xx

    x

    y M1

    A1

    [2]

    1

    0

    3

    110

    3

    4-

    3

    110

    )4(3

    45

    3

    4-

    3

    4-normalofgrad

    4

    3)4(

    41 2

    +=

    =

    +=

    +=

    =

    ==

    =

    xy

    c

    c

    cxy

    atxdx

    dy

    xdx

    dy

    M1

    M1

    [4]

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    Q Marking points Mark

    Awarded

    Total

    1

    1

    M1

    A1

    (i)

    3)-(1,and)4

    12,

    2

    1(-

    3-or4

    12y

    1or2

    1

    )1)(12(0

    6612 2

    =

    =

    +=

    =

    x

    xx

    xxdx

    dy

    M1

    M1

    A1

    A1, A1

    [5]

    (ii)

    )(min,1

    )(max,2

    1

    624

    2

    2

    2

    2

    2

    2

    ptpositivedx

    ydxAt

    ptnegativedx

    ydxAt

    xdx

    yd

    ==

    ==

    =M1

    A1

    A1

    [3]

    1

    2

    (i)

    (ii)

    3

    24

    12

    1

    3

    1

    2

    3

    1

    31

    2)

    1(

    1

    3

    8

    1

    0

    1

    84

    1

    0

    1

    2

    2

    2

    2

    =

    =

    =+

    =

    =

    x

    xdx

    xx

    xxdx

    M1

    A1

    M1

    M1

    A1

    [2]

    [3]

    1

    3

    3

    12

    23

    3

    1

    )2(22

    2

    3

    21),1,2(

    223

    )2(

    23

    23

    23

    2

    ++=

    =

    ++=

    ++=

    +=

    xxx

    y

    c

    cpt

    cxxxy

    dxxxy M1

    M1

    M1

    M1

    A1

    [5]