15
No. of Printed Pages : 15 CHE-01/02 B.Sc. Examination June, 2017 CHE-01 : ATOMS AND MOLECULES AND CHE-02 : INORGANIC CHEMISTRY Instructions : (i) Students registered for both CHE-01 and CHE-02 courses should answer both the question papers in two separate answer books entering their enrolment number, course code and course title clearly on both the answer books. (ii) Students who have registered for CHE-01 or CHE-02 should answer the relevant question paper after entering their enrolment number, course code and course title on the answer book. 41. .7r trftar Tft.7w.t. -01/02 , 2017 Tft:RW.t.-01 : 3117 3T9 741.7V.t.-02 : 31-Wret fT (i) J1 €014 Fffc 1V.I. -01 3rk Z4? - . 74.1. -02 0-I c'1,11 31,54.1-17-- 41 drH 30 77-37- 07T drH yr - R77311 # 3777 375 - A71*,EnT4 -- A-xf W3 - u217 weshg (ii) G‹.9,civ E91 Rt.cfv.i. -01 zIT #t.q=4.1. -02 a -Fll fc:Iq Mff 370- dt ,11- -WV-77 drk, .ern-r TF/WT 31V 7T 3 ,73 7 :17* 11/deishq W3 - ff 2 77 tl/qe/A5g qrq H/Y)-f//'/ , G‹,i , c/V / CHE-01/02 1 P.T.O.

41. .7r trftar Tft.7w.t

  • Upload
    others

  • View
    2

  • Download
    0

Embed Size (px)

Citation preview

No. of Printed Pages : 15

CHE-01/02

B.Sc. Examination June, 2017

CHE-01 : ATOMS AND MOLECULES AND

CHE-02 : INORGANIC CHEMISTRY Instructions : (i) Students registered for both CHE-01 and CHE-02

courses should answer both the question papers in two separate answer books entering their enrolment number, course code and course title clearly on both the answer books.

(ii) Students who have registered for CHE-01 or CHE-02 should answer the relevant question paper after entering their enrolment number, course code and course title on the answer book.

41. .7r trftar Tft.7w.t. -01/02

, 2017

Tft:RW.t.-01 : 3117 3T9

741.7V.t.-02 : 31-Wret

fT

(i) J1 €014 Fffc1V.I. -01 3rk Z4? -. 74.1. -02 0-I

c'1,11 31,54.1-17--41 drH 3077-37-07T drH

yr-R77311 # 3777 375-A71*,EnT4--A-xf W3 - u217 weshg

(ii)

G‹.9,civ

E91 Rt.cfv.i. -01 zIT #t.q=4.1. -02 a-Fll fc:Iq

Mff 370- dt,11- -WV-77 drk, .ern-rTF/WT

31V 7T 3 ,73 7:17* 11/deishq W3 - ff 277 tl/qe/A5g qrq

H/Y)-f//'/ , G‹,i,c/V /

CHE-01/02 1 P.T.O.

CHE-01

BACHELOR OF SCIENCE (B.Sc.)

Term-End Examination

June, 2017

CHEMISTRY

CHE-01 : ATOMS AND MOLECULES

Time : 1 hour Maximum Marks : 25

Note : Answer all the five questions.

Use the following data wherever required :

Planck's constant, h t 6.626 x 10-34 Js

Velocity of light, c = 2.988 x 108 ms-1

Avogadro's constant, NA = 6.022 x 1023 mol-1

1. Answer any two parts : 2

(a) Why is the wave nature of matter not

apparent in our daily observations ?

(b) Explain the meaning of yi 2 .

(c) Calculate the formal charges on carbon and

oxygen in carbon monoxide molecule.

2. Answer any two parts : 4

(a) State the conditions that must be met by a

wave function for it to be well-behaved.

(b) Calculate the bond order of the N2 molecule

by writing its molecular orbital configuration.

CHE-01 2

(c) An organic compound has a Amax of 400 nm.

The absorbance of a 2.4 x 10-5 M solution of

this compound was found to be 0.60. If a test

solution of the same compound showed an

absorbance of 0.84 at 400 nm, find out its

concentration (thickness of the cell is 1 cm).

3. Answer any two parts : 6

(a) Draw the resonance structures of a nitrate

ion.

(b) Calculate the percentage ionic character in

HC1 given that its bond distance is 127.5 pm,

charge on H and Cl is 1.6 x 10 -19 C and observed dipole moment is 3.57 x 10 -39 Cm.

(c) Give any three advantages of nuclear fusion

over nuclear fission.

4. Answer any two parts : 8

(a) Write Lewis formula and then apply VSEPR

theory to predict the shape of CO3 or

C103.

(b) Draw the Born-Haber cycle of BaC1 2.

(c) Write the postulates of Bohr's atomic model.

CHE-01 3 P.T.O.

5. Answer any one part : 5

(a) The lowest wave number absorption line

in the rotational spectrum of 111 19F is at

4111 cm-1 . Calculate :

(i) The moment of inertia of HF. 2

(ii) The bond length of HF. 3

(b) (i) Which of the following can exhibit

optical activity ? Explain giving reasons

for each case. 3

CH3

Br — C — Cl

CH3 — CH2 - Br

H

CH3

CI C — NH2

CI — C — NH2

CH3

(ii) How many normal modes of vibration are

possible for carbon dioxide and sulphur

dioxide ? 2

CHE-01

141.7w.t.-01

1I1 i-itoch (1.7.41•141.)

trftur

2017

141'.7V.t.-01 : wig NI 3117 39

tziqe/ : 1 Tref 3irt*ff74r 31 J : 25

4-12- : ea ;Rj J711 007- /

34e -73-7-4-?77 7.:

h = 6.626 x 10-34 Js

Nchlkl 1T, c = 2.988 x 108 ms-1-

31T4171T f:Kiclieb, NA = 6.022 x 1023 mor1

1. -4-;t 0. WI* 371k tr4 : 2

() 3fra-R-4 -kT116 A TA srfR 33-r9Tm ereil t ?

N) * 342f AT cell(911*W-4 I

(71) *T-4q 1-1)-1)4k1I8 3Tuj tr-{ tb14-a- 31*4-11 air 1-111ch1-1 tif-A7 I

2. -441- q"?' WI* .371k tr-A-R : 4

14*f(-w 3Tra-Frt

(IN) N2 3.71 31UJ 14- 171- Ritgebk

31-1-4V *11-4 I

CHE-01 5 P.T.O.

(1T) ct>1.1P.h AI T Amax 400 nm t I T(=f

z111T1c * 2.4 x 10-5 M fdazR 3-1-4TifuTiT

0.60 1TRIT TRIT I qr< *4 Aft tr.#4-PIT

1-4-0-4q. W. 400 nm tfT 3-T-4-TiliTk 0.84 -51 <5.1T t,

1Tr— t 411(1 W-A7 Ocl 4t

1 amt. ) I

3. f*-74. .31-R :

(*) 3TFR 4t 343-4t -IkT.4-11 447R I

(T4) HC1 A -5f741ff 31T1* 1-iRcbc-M *1177,

-RIFT TrIfT 3-TT-07V- 127.5 pm,

(H) Ofiq- (Cl) tfT 31147F

1.6 x 10-19 C W?-TT .ralT -bp 311E0

3.57 x 10-30 Cm I

(Tr) -rrii- r-zr A TflIA'rzi.

41-1 -13T 4-d-r-

I

4. -Wei- 0. ITTril* .371k trA7 :

() qPzi fORER VSEPR

3T1t4rT ' CO - 312141 010 3 Al 31*

1:0T:114 W-A-

(U) BaC12 '4541 31AM *1177

(TT) gilt * IRTITUJ 1-115c1 * aftleral IFfuR

CHE-01 6

5. WI 7W ii-Fr 3rR 7 : 5

() 1H 19F * sklifq P4-4 1:1 14 1F1 TIT fife

3Td7TITIuT ltgI 41.11 cm 1 7 t I 1-IkchiCii

(i) HF 3-7 * R.-R zi5c-c1-3Tqui I

2

(ii) HF 3T9 3-IT4V -44 I

3

NO (i) P-14-1FORgi 14 ch1-1-call-i-A Tdvi Tp4—d-f

-51-41* *T Tr-*-- t ? .5k-- * ic-K chikui

ki l-iSil 1 I

CH3

Br — C — Cl CH3 — CH2 — Br

H

3

CH3

CI — C — NH2

Cl — C — NH2

CH3

(ii) chi -I sl 3Ti r 3 k1c,-4, slpfr-4-R--4-

* R-11-*---d-t -11-11.4-1 4)44 Nt.TT141-1-4 t ? 2

CHE-01

7 P.T.O.

I CHE-02 I BACHELOR OF SCIENCE (B.Sc.)

Term-End Examination

June, 2017

CHEMISTRY

CHE-02 : INORGANIC CHEMISTRY

Time : 2 hours Maximum Marks : 50

Note :

(i) Attempt all the five questions.

(ii) All questions carry equal marks.

1. Answer, in brief, any ten of the following : 10x1.10

(a) Write . the valence shell electronic

configuration of the atom whose atomic

number is 24.

(b) Which of the following has the highest

electron affinity ?

F, Cl, Br, I

(c) Which one is more stable, Cr2+ or Cr3+

(d) What is the oxidation state of iron in K4[Fe(CN)6] ?

(e) Name the element which was discovered

extraterrestrially before being found on the

Earth.

CHE-02 8

(0 Which of the atoms having the electronic configuration [Ne] 3s2 3p2 or [Ne] 3s2 3p3 will have higher first ionization energy ?

(g) Name the oxide of nitrogen which is isoelectronic with CO 2 .

(h) Give one industrial use of hydrogen.

(i) Of 11+, IF and H, which has the largest size ?

(j) Which one of the following compounds is acidic in nature ?

B(OH)3, Al(OH)3, Ga(OH)3

(k) Of BeCO3 and BaCO3, which one is thermally more stable ?

(1) Which compound of silicon is used as a dehydrating agent ?

(m) Which one of Ce(III) and Ce(IV) acts as an oxidising agent ?

(n) Name the metal ion present in chlorophyll.

(o) Name the process used for refining of nickel.

2. Answer any five parts, in brief : 5x2=10

(a) Name and state the rule or principle which is violated in any one of the following electronic configurations :

(i) 1s2 2s3 (ii) 1s2 2s2 2px2 2pyl

(b) Alkali metals are good conductors of heat and electricity. Explain.

CHE-02 9 P:T.O.

(e) Why is water a liquid and H 2S a gas at room temperature ? Explain.

(d) Electron affinity of nitrogen is lower than that of its neighbouring elements, carbon and oxygen. Explain.

(e) Second ionization energy of an atom is always higher than its first ionization energy. Explain.

(f) What are the ortho and para forms of hydrogen ?

(g) Xenon forms the compound Xe + [PtF6] -. Will

nitrogen form the compound N2+ [PtF6] - ?

The first ionization energies of xenon and

nitrogen are 1170 kJ mol-1 and

1403 kJ mol-1 , respectively.

3. (a) Answer any two parts : 2x3=6

(i) Silicon tetrachloride is readily hydrolysed while carbon tetrachloride is inert to hydrolysis. Explain.

(ii) Draw the structures of N 205, H4P207

and H2S05 .

(iii) Complete the following chemical equations :

B2H6 + NH3 ->

PC1 6 + ROH

NC13 + H2O

(b) Give one method of preparation of diborane and discuss its structure. 4

OR Describe the contact process for the manufacture of sulphuric acid. 4

CHE-02 10

4. (a) Answer any three parts of the following.: 3x2=6

(i) Draw the structure of solid Se0 2 .

(ii) Give the structure of XeF 2 molecule

using VSEPR theory.

(iii) Which of the halogens is the strongest oxidizing agent ? Justify your answer.

(iv) Explain why TiO2 is white but TiC13 is

coloured. The atomic number of Ti is 22.

(v) Why is carbon a preferred reducing agent in commercial metallurgy ? Explain.

(vi) Give the geometrical isomers of diamminedichloroplatinum(II).

(b) What is lanthanide contraction ? Give its consequences. 4

OR

The complex ion ElsTiC14] 2- is paramagnetic

whereas the complex ion [Ni(CN) 4] 2- is

diamagnetic. Explain on the basis of Crystal

Field Theory. The atomic number of nickel

is 28. 4

5. Write short notes on any two of the following : 2x5=10

(a) Anomalous behaviour of lithium

(b) Pyrometallurgy

(c) Interhalogen compounds

CHE-02

11 P.T.O.

icien (1. -crg Ift.)

fllict triluT

Tq, 2017

.11t1.1 la id

f. .t. -02 : 31-*1-41:

cLisiel :2 : 50

W FP# 377* sirR 07*7 /

(ii) Mit 37-r7 37T. H411.1 ff

1. PiHrokgd A 14 TR. *44q 4 ,37ik tr-A7 : 10x1=10

TRIN 5bilig) 24 alc4 trt-grruj .1 4131cbc11 ch

1-4- rf-fr fo-FuR

414 ftt:Wt 41j-m .3-04d4-1 ?

F, Cl, Br, I

(IT) ll 3T1T- -Rrpft t, cr 2+ 342T-q-r cr3+ ?

(v) K4 [Fe(cN)6] 4 (.,4 4=1- 34 ,444.1 31-4T-211 cv_41 ?

dra -wr f 1-4317 1-1-M- tit 77

tr-0 3,t-d-ftu A .13-1'7T Trzrr 24-r

CHE-02

12

[Ne] 3s2 3p2 34,21-4r [Ne] 3s 2 3p3 *c)cta-:ich

fTti .41(4 T-1-Trfrop11 A A i i 1 3E2114

374-4q simcidk tiff ?

-11131-1 * Mr BTU CO2-FAR

ki4-11.41 t

1.1.-1* 3fterrr- ztrzOr -> .3cwut tr-A7 I

H+ ,11- * H 14 14, 1--14-*-T aTTT17 kiel4 ?

oRgd A-F.1TO 4 A chl-i-Trr -) ami ?

B(OH)3 , Al(OH)3, Ga(OH)3

(Z) BeCO 3 3TlZ BaCO 3 4 A, 1-1-1-AT -) *TA

P.Trzft ?

(z) 1 4;14.)-1 1 11-1-AT 411-Tr- cbRch *

Netlit 4 oiqi ?

() Ce(III) 31t ce(v) A A 3TTTEFI-WI{

dt 0e4ciit WW1 ?

(d) cto t 410 4 tug 3Trzr4 .WE 4f1T fAR

070 frk-. 711ITq cht4 fffru-R I

2. 141 ew NITA 44414 A .371k : 5><2.10

1:11 1-1 -417:1 -r-AR *-2R .NTrTf PHR-iRgo A .4 64 *(c1- 1;1-1.4,141-R:1 4*F :

(i) is2 2s3

(ii) 1.32 2s2 2px2

( -13. ) ffR tire *41 * TErtz =1.N7

CHE-02

13 P.T.O.

(TT) 'Mg. Ar15id A H2s 241 ?

TcrEz

(Er) -4gaT -pck trOft dr4 44q A 31-fq44q 1 qci-n fiPrd-( *th t ITurlsz 4r—A7

icRTiruj 1014 31N-44 3TT*1 72TTE

311744 4),111. Trk4 3-cac14. *th t I PTGZ *1-NR

(") *3I A tt-r t?

() 4414 Xe[PtF 61 - zirTf* W4T-41 * I cN ►

N2+ [PtF6I - tiTT* 'M-471ft ?

Al 312TIT 374-41 4)\71i(1 Sko-RI: 1170 kJ mo1-1

1403 kJ mor l t I

3. (*) 4 I1P-4* 31-R &—A7 : 2x3=6

(i) 4Ickilfls aTrurt Ao-3Ttiv-z4 di t ch14-1 4 ► etcl)fl8 Ac1-37TER7

34-4 t Tcruz 4=rr-qR

(ii) N205, H4P207 31 H2S05

(1(1:111

.friv

1H116-1 kwitiPet, (ii-fichkuil Tui : B2H6 + NH3 —>

PC1 5 + ROH

NC13 + H2O

-T-4-41- *i ► lea tr-A-R A ITA')

rad*-11 At* I 4 altrIT

w-4-41Rai 31 .1 fir Nsbi4 lu

SRI 4

CHE-02 14

4. () (go 4 F1-Tml : 3x2.6

(i) ci)ti SeO2 1' A41--$ I

(ii) VSEPRThtff 3clz1)1T XeF2 39

tvl•W I

(hi) ch1 -1 -#1 51elOc1 4-1 3friTit ~Fi 1c ? 3TEr4 siT-R 41-

(iv) TErEz

rtf, TiO2 147 J TiC13 kl

trp:rrs shi-Iich 22

t I

(v) 3Tcrwr 4

atzrar eteil 1 Atc11 ? TcrEz *CR7

(vi) ,-eiAcfle4

tr--4 I

A7-4-qT-0 Trfq4 ? 4au11 44

I 4

3121M

N c1 3-174 [NiC14] 2

a-Tro:F [Ni(cN)41 2 urciiicnq t-d-r t Icd

Id 3TraR IR Txry tRTITS 5#) 1-IIch 28* I 4

5. P1 4-.11Z-iRgc1 4 T)- Tr( 41-41 uieu

1-0 11§ Tr, : 2x5=10

() diNT411 34-rd oe4c4ik

iTrq-41-1 4

(TO 34dtl-t017-4 zrfft

CHE-02 15

10,000