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Heejin's 3-D plot and tangential plane example. In order to plot a tangential plane of a 3-D plot at a nominal point, you need to determine the gradients in each direction (i.e., x and y direction) and translate to the nominal point. The translation equation is z z o fx x o y y o , ( ) = The example I showed in the class coincidently had the same value of offset that would be provided by translating in x, y, and z direction. The correct solution is presented in the following. zxy , ( ) x 2 3 y 2 2 + := a x zxy , ( ) d d substitute x 2 = , y 1 = , 4 3 := b y zxy , ( ) d d substitute x 2 = , y 1 = , 1 := This is what I did in the class: Tangential plane with correct translation: zz x y , ( ) ax by + z21 , ( ) := zzz x y , ( ) a x 2 ( ) b y 1 ( ) + z21 , ( ) + := z21 , ( ) 1.833 = <=== Lucky ===> 2 a 1b z21 , ( ) + 1.833 = z zz , z zzz , If you still don't understand my point, please send me an email to [email protected] or come by my office in Room 312, Carpenter.

3d Plot Tangential Plane

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3D plot in MathCad

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  • Heejin's 3-D plot and tangential plane example.

    In order to plot a tangential plane of a 3-D plot at a nominal point, you need to determine thegradients in each direction (i.e., x and y direction) and translate to the nominal point. Thetranslation equation is

    z zo f x xo y yo, ( )=The example I showed in the class coincidently had the same value of offset that would beprovided by translating in x, y, and z direction. The correct solution is presented in thefollowing.

    z x y, ( ) x2

    3y2

    2+:=

    axz x y, ( )d

    dsubstitute x 2=, y 1=, 4

    3:=

    byz x y, ( )d

    dsubstitute x 2=, y 1=, 1:=

    This is what I did in the class: Tangential plane with correct translation:

    zz x y, ( ) a x b y+ z 2 1, ( ):= zzz x y, ( ) a x 2( ) b y 1( )+ z 2 1, ( )+:=

    z 2 1, ( ) 1.833= 2 a 1b z 2 1, ( )+ 1.833=

    z zz, z zzz,

    If you still don't understand my point, please send me an email to [email protected] or comeby my office in Room 312, Carpenter.