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3.7 Absolute value
DAY 2
Solve for x----no notes on this slide (just watch).
|x| = 5
|x + 2| = 5
x = 5 or x = -5
x + 2 = 5 or x + 2 = -5
x = 3 - 2 -2 - 2 -2
x = -7 check
|3 + 2| = 5 |-7 + 2| = 5check
Solve for x---again no notes on this slide.
|x + 4| = 7x + 4 = 7 or x + 4 = -7
x = 3 -4 -4
Check with the original equation.
|(x) + 4 | = 7
Check with the original equation.
- 4 -4 x = -11
| (x) + 4 | = 7|(-11) + 4 | = 7
|-7 | = 7|(3) + 4 | = 7|7 | = 7
Your answers are:
3, -11
Solve for x
|2x + 5| = 132x + 5 = 13 or 2x + 5 = -13
2x = 8 - 5 -5
Check with the original equation
|2(4) + 5 | = 13Check with the original equation
x= 4
- 5 -5 2x = -18
x= -9
|2(-9) + 5 | = 13|-18 + 5 | = 13
|-13 | = 13|8 + 5 | = 13|13 | = 13
Your answers are:
4, -9
|-2x + 5| - 4 = 9
-2x + 5 = 13 or -2x + 5 = -13
-2x = 8 -5 -5
Check with the original equation.
|-2(-4) + 5 | - 4 = 9
Check with the original equation.
- 5 - 5 -2x = -18
|-2(9) +5 | - 4 =9|(-18) + 5 | -4 = 9
|-13 | -4 = 9|(8) + 5 | - 4 = 9|13 | - 4 = 9
Solve for x
|-2x + 5| =13
The answers are -4, 9 x = -4 x = 9
13 -4 = 9
+9+9|-2x - 6| - 9 = 11
-2x – 6 = 20 or -2x - 6 = -20
-2x = 26 +6 +6
Check with the original equation.
|-2(-13) - 6 | - 9 = 11
Check with the original equation.
+6 +6 -2x = -14
|-2(7) - 6| -9 = 11|(-14) -6 | -9 = 11
|-20 | - 9 = 11|(26) - 6 | - 9 = 11
|20 | - 9 = 11
Solve for x
|-2x - 6| =20
The answers are -13, 7 x = -13 x = 7
20 - 9 = 11
Solve for x 2|x + 4| = 14
x + 4 = 7 or x + 4 = -7
x = 3 -4 -4
Check with the original equation.
2|(x) + 4 | = 14
Check with the original equation.
- 4 -4 x = -11
2| (x) + 4 | = 142|(-11) + 4 | = 14
2|-7 | = 142|(3) + 4 | = 142|7 | = 14
Your answers are:
3, -11
2 2
|x + 4| = 7
|x| + 2 = 7
Solve for x and then graph the solutions.
- 2 -2
|x| = 5
x =5 or x = -5
-5 0 5
|x| > 2
Solve for x and then graph the solutions.
-5 0 5
Assignment: page 211:17-20, 26-28,31, 49,53-55
| A| < b | A| > b
-5 0 5
-b < A < b
Solving absolute value inequalities
A < -b or A > b
| x – 1 | < 2 -2 < x – 1 < 2
-2 < x – 1 and x -1 < 2+1 + 1
-1 < x
+1 + 1
x < 3
| x – 1 | > 2
x – 1 < -2 OR x -1 > 2+1 + 1
x < -1
+1 + 1
x > 3
-5 0 5
Solve and graph the following: |2x + 1| > 9
| A| < b | A| > b
-b < A < b A < -b or A > b|2x + 1| > 9
2x + 1 < -9 OR 2x +1 > 9 -1 -1
2x < -10 x < -5
-1 -12x > 8 x > 4
-10 -5 0 5 10
Assignment: page 211: 24-30 evens; 32-40 all; 50-60 evens
If it says graph, graph it